Question

Difficulty: MediumCircle Geometry

Points AA, BB, and CC lie on a circle. The measure of minor arc ABAB is 110110^\circ and the measure of minor arc BCBC is 130130^\circ. What is the measure of the inscribed angle ABC\angle ABC, in degrees?

  1. A
    120
  2. B
    50
  3. 60Answer
  4. D
    55

Answer

60
The measure of the major arc ABCABC is the sum of the minor arcs ABAB and BCBC, which is 110+130=240110^\circ + 130^\circ = 240^\circ. The remaining minor arc ACAC has a measure of 360240=120360^\circ - 240^\circ = 120^\circ. By the inscribed angle theorem, the measure of the inscribed angle ABC\angle ABC is half the measure of its intercepted arc, minor arc ACAC. Therefore, the measure of ABC\angle ABC is 1202=60\frac{120^\circ}{2} = 60^\circ.

Step-by-Step Solution

1
Calculate the measure of the major arc ABCABC by adding the measures of the two adjacent minor arcs ABAB and BCBC.
The measure of arc ABCABC is 110+130=240110^\circ + 130^\circ = 240^\circ.
Since points AA, BB, and CC are in order on the circle, the major arc connecting AA and CC through BB is the sum of the arcs ABAB and BCBC.
2
Find the measure of the remaining minor arc ACAC.
The measure of minor arc ACAC is 360240=120360^\circ - 240^\circ = 120^\circ.
A full circle measures 360360^\circ. Subtracting the major arc ABCABC from 360360^\circ yields the measure of the minor arc ACAC.
3
Apply the inscribed angle theorem to find the measure of angle ABCABC.
The measure of angle ABCABC is 1202=60\frac{120^\circ}{2} = 60^\circ.
The inscribed angle theorem states that the measure of an inscribed angle is half the measure of its intercepted arc. Angle ABCABC intercepts the minor arc ACAC.

Key Concept

The measure of an inscribed angle is half the measure of its intercepted arc.
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