Question

Difficulty: MediumQuadratic Functions and Graphs

For the quadratic function ff, the table shows some values of xx and their corresponding values of f(x)f(x).

xxf(x)f(x)
111515
3333
551515

What is the value of f(0)f(0)?

Answer: 30

Answer

30
Since the function values at x=1x = 1 and x=5x = 5 are both 1515, the axis of symmetry of the quadratic function must be located at the midpoint of these values, which is x=3x = 3. The vertex of the function must therefore have an xx-coordinate of 33. From the table, f(3)=3f(3) = 3, which means the vertex is (3,3)(3, 3). The vertex form of the quadratic function is f(x)=a(x3)2+3f(x) = a(x - 3)^2 + 3. To find the value of aa, substitute the point (1,15)(1, 15) into the equation: 15=a(13)2+315 = a(1 - 3)^2 + 3, which simplifies to 15=4a+315 = 4a + 3, giving a=3a = 3. The equation of the function is f(x)=3(x3)2+3f(x) = 3(x - 3)^2 + 3. Substituting x=0x = 0 yields f(0)=3(03)2+3=3(9)+3=30f(0) = 3(0 - 3)^2 + 3 = 3(9) + 3 = 30.

Step-by-Step Solution

1
Find the axis of symmetry.
The axis of symmetry is x=3x = 3.
Since f(1)=15f(1) = 15 and f(5)=15f(5) = 15, the function values are equal at these points. Because a quadratic function is symmetric, the axis of symmetry is the midpoint of these two xx-values: 1+52=3\frac{1 + 5}{2} = 3.
2
Identify the vertex.
The vertex is (3,3)(3, 3).
The vertex of a quadratic function lies on its axis of symmetry. Since the axis of symmetry is x=3x = 3, the xx-coordinate of the vertex is 33. From the table, f(3)=3f(3) = 3, so the vertex is (3,3)(3, 3).
3
Write the function in vertex form and solve for the leading coefficient.
f(x)=3(x3)2+3f(x) = 3(x - 3)^2 + 3
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex. Substituting (3,3)(3, 3), we get f(x)=a(x3)2+3f(x) = a(x - 3)^2 + 3. Using the point (1,15)(1, 15) from the table, we substitute x=1x = 1 and f(x)=15f(x) = 15: 15=a(13)2+315=4a+312=4aa=315 = a(1 - 3)^2 + 3 \Rightarrow 15 = 4a + 3 \Rightarrow 12 = 4a \Rightarrow a = 3.
4
Evaluate the function at x=0x = 0.
f(0)=30f(0) = 30
Substitute x=0x = 0 into the function: f(0)=3(03)2+3=3(9)+3=27+3=30f(0) = 3(0 - 3)^2 + 3 = 3(9) + 3 = 27 + 3 = 30.

Key Concept

Quadratic Functions and Graphs
Rate this question