Question

Difficulty: MediumData Distributions and Measures

The daily electricity consumption, in kilowatt-hours (kWh), of a household was recorded for 7 consecutive days: 1212, 1212, 1313, 1414, 1414, 1515, and 4545. If the household's electricity consumption of 45 kWh45\text{ kWh} on the seventh day is removed from the dataset, which of the following statements best describes the effect on the mean and the median of the dataset?

  1. The mean decreases by a greater amount than the median.Answer
  2. B
    The median decreases by a greater amount than the mean.
  3. C
    The mean decreases, but the median increases.
  4. D
    The mean increases, but the median decreases.

Answer

The mean decreases by a greater amount than the median.
The correct answer is correct because calculating the original mean yields 17.86 kWh\approx 17.86\text{ kWh} and the original median yields 14 kWh14\text{ kWh}. After removing the outlier (45 kWh45\text{ kWh}), the mean decreases to 13.33 kWh\approx 13.33\text{ kWh} (a change of 4.53 kWh4.53\text{ kWh}) and the median decreases to 13.5 kWh13.5\text{ kWh} (a change of 0.5 kWh0.5\text{ kWh}). Comparing these changes shows the mean decreased by a larger amount.

Step-by-Step Solution

1
Calculate the mean and median of the original 7-day dataset.
The original mean is 12+12+13+14+14+15+457=125717.86 kWh\frac{12 + 12 + 13 + 14 + 14 + 15 + 45}{7} = \frac{125}{7} \approx 17.86\text{ kWh}. The sorted dataset is 12,12,13,14,14,15,4512, 12, 13, 14, 14, 15, 45, so the median is the middle value, which is 14 kWh14\text{ kWh}.
This establishes baseline values for the two measures.
2
Calculate the mean and median after removing the outlier of 45 kWh45\text{ kWh}.
The new mean is 12+12+13+14+14+156=80613.33 kWh\frac{12 + 12 + 13 + 14 + 14 + 15}{6} = \frac{80}{6} \approx 13.33\text{ kWh}. The new sorted dataset is 12,12,13,14,14,1512, 12, 13, 14, 14, 15, so the median is the average of the two middle values: 13+142=13.5 kWh\frac{13 + 14}{2} = 13.5\text{ kWh}.
This provides the new values for comparison.
3
Compare the changes in the mean and the median.
The mean decreased by 17.8613.33=4.53 kWh17.86 - 13.33 = 4.53\text{ kWh}. The median decreased by 1413.5=0.5 kWh14 - 13.5 = 0.5\text{ kWh}. The decrease in the mean is greater.
This confirms the statement that describes the relative changes.

Key Concept

Effect of outliers on mean and median
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