Question

Difficulty: HardQuadratic Functions and Graphs

A parabola in the xyxy-plane has vertex (2,11)(2, 11) and passes through the point (5,7)(5, -7). The equation of the parabola is y=ax2+bx+cy = ax^2 + bx + c, where aa, bb, and cc are constants. What is the value of a+b+ca + b + c?

Answer: 9

Answer

The value of a+b+ca + b + c is 99.
The correct value of a+b+ca + b + c is 99. This is found by writing the parabola's equation in vertex form as y=2(x2)2+11y = -2(x - 2)^2 + 11 and expanding it to standard form y=2x2+8x+3y = -2x^2 + 8x + 3, which gives the coefficients a=2a = -2, b=8b = 8, and c=3c = 3. Alternatively, substituting x=1x = 1 directly into the vertex form gives f(1)=a(1)2+b(1)+c=2(12)2+11=9f(1) = a(1)^2 + b(1) + c = -2(1 - 2)^2 + 11 = 9.

Step-by-Step Solution

1
Write the equation of the parabola in vertex form using the given vertex (2,11)(2, 11).
y=a(x2)2+11y = a(x - 2)^2 + 11
The vertex form of a quadratic function is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
2
Substitute the coordinates of the point (5,7)(5, -7) into the vertex form equation to solve for the constant aa.
a=2a = -2
Since the point (5,7)(5, -7) lies on the parabola, substituting x=5x = 5 and y=7y = -7 allows us to solve the linear equation 7=a(52)2+11-7 = a(5 - 2)^2 + 11 for aa.
3
Expand the vertex form equation y=2(x2)2+11y = -2(x - 2)^2 + 11 into standard form y=ax2+bx+cy = ax^2 + bx + c to identify the coefficients aa, bb, and cc.
y=2x2+8x+3y = -2x^2 + 8x + 3, which gives a=2a = -2, b=8b = 8, and c=3c = 3.
Expanding the squared term and distributing the coefficient 2-2 converts the equation to standard form, making it easy to read off the coefficients.
4
Calculate the sum of the coefficients a+b+ca + b + c.
a+b+c=9a + b + c = 9
Adding the identified coefficients: 2+8+3=9-2 + 8 + 3 = 9.

Key Concept

Writing and converting quadratic functions between vertex form y=a(xh)2+ky = a(x - h)^2 + k and standard form y=ax2+bx+cy = ax^2 + bx + c.

Alternative Method

Instead of expanding the vertex form equation to find the individual coefficients aa, bb, and cc, recognize that the expression a+b+ca + b + c is equal to f(1)f(1) for the quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c. After finding a=2a = -2 using the vertex form f(x)=a(x2)2+11f(x) = a(x - 2)^2 + 11, directly evaluate f(1)=2(12)2+11=9f(1) = -2(1 - 2)^2 + 11 = 9.
Estimated Time:2m 30s
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