In conservation chemistry, researchers analyzing seventeenth-century European oil paintings noticed that yellow paint layers containing lead-tin yellow (type I) show significantly less degradation in high-humidity environments than do those containing type II lead-tin yellow. The researchers determined that type I lead-tin yellow contains a high crystalline silicon dioxide fraction, which forms a protective matrix around the lead carboxylate complexes that are prone to moisture-induced degradation. Conversely, type II lead-tin yellow lacks this high crystalline silicon dioxide content, leaving its carboxylate complexes fully exposed to ambient water molecules.
Which choice most logically completes the text?
- Asuggest that seventeenth-century artists intentionally selected type I pigments to ensure the long-term durability of their paintings.
- Bprove more resilient to moisture-induced degradation because they lack lead carboxylate complexes.
- experience higher rates of pigment degradation than will paintings containing type I lead-tin yellow.Answer
- Drequire conservation treatments that artificially introduce crystalline silicon dioxide into the existing paint layers.
Answer
The correct answer states that paintings containing type II lead-tin yellow pigments will experience higher rates of pigment degradation than will paintings containing type I lead-tin yellow.
The passage explains that type I lead-tin yellow contains crystalline silicon dioxide, which forms a protective matrix around the moisture-sensitive lead carboxylate complexes, resulting in less degradation in humid environments. In contrast, type II lead-tin yellow lacks this protective silicon dioxide content, leaving its carboxylate complexes exposed. Therefore, it logically follows that when exposed to humidity, paintings with type II pigments will experience higher rates of pigment degradation than those containing the protected type I pigments.
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