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Question 1981Question

A hybrid car's fuel tank has a capacity of 1212 gallons. When driving on a highway, the amount of fuel in the tank decreases at a constant rate. After driving for 1.51.5 hours, 9.69.6 gallons of fuel remain in the tank. If the amount of fuel in the tank, FF, in gallons, after driving for tt hours is modeled by a linear equation, what is the value of FF when t=4t = 4?

Show answer & explanation

Answer: 5.6

Answer

The amount of fuel remaining in the tank after driving for 44 hours is 5.65.6 gallons.
The amount of fuel in the tank, FF, and the driving time, tt, share a linear relationship. The initial amount of fuel at t=0t = 0 is 1212 gallons, representing the vertical intercept. The fuel decreases at a constant rate, which is the slope of the line. Over a period of 1.51.5 hours, the amount of fuel decreases by 129.6=2.412 - 9.6 = 2.4 gallons. The rate of decrease is 2.41.5=1.6\frac{2.4}{1.5} = 1.6 gallons per hour, so the slope is 1.6-1.6. The linear model is F=1.6t+12F = -1.6t + 12. Substituting t=4t = 4 into this equation yields F=1.6(4)+12=6.4+12=5.6F = -1.6(4) + 12 = -6.4 + 12 = 5.6 gallons.

Step-by-Step Solution

1
Calculate the constant rate of fuel consumption (the slope of the linear relationship).
The rate of consumption is 1.61.6 gallons per hour.
Since the fuel decreases at a constant rate, the change in fuel divided by the change in time gives the rate of consumption. In 1.51.5 hours, the fuel decreases from 1212 gallons to 9.69.6 gallons, which is a decrease of 129.6=2.412 - 9.6 = 2.4 gallons. Thus, the rate of consumption is 2.4 gallons1.5 hours=1.6\frac{2.4\text{ gallons}}{1.5\text{ hours}} = 1.6 gallons per hour.
2
Write the linear equation modeling the fuel remaining in the tank, FF, as a function of time, tt.
F=1.6t+12F = -1.6t + 12
The initial amount of fuel when t=0t = 0 is 1212 gallons, which represents the vertical intercept (b=12b = 12). The fuel decreases at a constant rate of 1.61.6 gallons per hour, which represents a slope of m=1.6m = -1.6.
3
Substitute t=4t = 4 into the linear equation to find the value of FF.
F=5.6F = 5.6
Evaluating the equation at t=4t = 4 yields F=1.6(4)+12=6.4+12=5.6F = -1.6(4) + 12 = -6.4 + 12 = 5.6.

Key Concept

Linear Equations in Two Variables
Question 1982Question

The table below shows some values for a cubic polynomial function gg.

xxg(x)g(x)
1-100
111616
3300

In the xyxy-plane, the graph of y=g(x)y = g(x) is tangent to the xx-axis at x=3x = 3. What is the value of g(0)g(0)?

Show answer & explanation

Answer: 18

Answer

18
The correct value of g(0)g(0) is 18. By using the fact that g(1)=0g(-1) = 0, we establish (x+1)(x + 1) as a factor. The tangency at x=3x = 3 tells us that (x3)2(x - 3)^2 is a factor. Writing the function as g(x)=a(x+1)(x3)2g(x) = a(x + 1)(x - 3)^2 and substituting g(1)=16g(1) = 16 gives 8a=16    a=28a = 16 \implies a = 2. Evaluating g(0)g(0) yields 2(1)(9)=182(1)(9) = 18.

Step-by-Step Solution

1
Determine the factors of the cubic polynomial g(x)g(x) using the given zeros and the tangency condition.
The factors are (x+1)(x + 1) and (x3)2(x - 3)^2, so the function is of the form g(x)=a(x+1)(x3)2g(x) = a(x + 1)(x - 3)^2.
Since g(1)=0g(-1) = 0, x=1x = -1 is a root of the polynomial. The graph being tangent to the xx-axis at x=3x = 3 indicates that x=3x = 3 is a root with a multiplicity of at least 2. Since g(x)g(x) is a cubic polynomial (degree 3), the multiplicity of the root at x=3x = 3 must be exactly 2.
2
Use the table value g(1)=16g(1) = 16 to solve for the constant coefficient aa.
a=2a = 2
Substituting x=1x = 1 into g(x)=a(x+1)(x3)2g(x) = a(x + 1)(x - 3)^2 gives g(1)=a(1+1)(13)2=8ag(1) = a(1 + 1)(1 - 3)^2 = 8a. Setting this equal to the table value of 16 yields 8a=168a = 16, which simplifies to a=2a = 2.
3
Evaluate the polynomial at x=0x = 0 using the fully determined function g(x)=2(x+1)(x3)2g(x) = 2(x + 1)(x - 3)^2.
18
To find g(0)g(0), substitute x=0x = 0 into the expression: g(0)=2(0+1)(03)2=2(1)(9)=18g(0) = 2(0 + 1)(0 - 3)^2 = 2(1)(9) = 18.

Key Concept

Identifying polynomial factors from graphs and tables, and analyzing root multiplicity (tangency vs. crossing).
Question 1983Question

A right circular cylinder has a volume of 20 cubic inches20\text{ cubic inches}. If the radius of the cylinder is tripled and its height remains the same, what is the volume, in cubic inches, of the new cylinder?

Show answer & explanation

Answer: 180

Answer

180
The volume of a right circular cylinder is calculated using the formula V=πr2hV = \pi r^2 h. When the radius rr is tripled to 3r3r and the height hh remains constant, the volume is multiplied by 32=93^2 = 9. Thus, the new volume is 99 times the original volume of 2020 cubic inches, which equals 180180 cubic inches.

Step-by-Step Solution

1
Write down the formula for the volume of a right circular cylinder.
V=πr2hV = \pi r^2 h
To identify how the volume of a cylinder relates to its radius and height.
2
Determine the effect of tripling the radius on the volume formula.
Vnew=π(3r)2h=9πr2hV_{\text{new}} = \pi (3r)^2 h = 9\pi r^2 h
Substituting the new radius 3r3r into the formula shows that the new volume is 9 times the original volume.
3
Substitute the original volume of 2020 cubic inches into the expression for the new volume.
Vnew=9×20=180V_{\text{new}} = 9 \times 20 = 180
Since the original volume πr2h\pi r^2 h equals 2020, we multiply this value by 9 to find the new volume.

Key Concept

Volume of a cylinder and dimensional scaling
Estimated Time:45s
Question 1984Question

The quadratic equation x212x+4=0x^2 - 12x + 4 = 0 has solutions x1x_1 and x2x_2. What is the value of 1x1+1x2\frac{1}{x_1} + \frac{1}{x_2}?

Show answer & explanation

Answer: 3

Answer

The correct answer is 3.
By writing the expression 1x1+1x2\frac{1}{x_1} + \frac{1}{x_2} with a common denominator, we get x1+x2x1x2\frac{x_1 + x_2}{x_1 x_2}. For the quadratic equation x212x+4=0x^2 - 12x + 4 = 0, Vieta's formulas give the sum of the roots x1+x2=12x_1 + x_2 = 12 and the product of the roots x1x2=4x_1 x_2 = 4. Substituting these values into the fraction yields 124=3\frac{12}{4} = 3.

Step-by-Step Solution

1
Find a common denominator to combine the terms in the given expression.
1x1+1x2=x1+x2x1x2\frac{1}{x_1} + \frac{1}{x_2} = \frac{x_1 + x_2}{x_1 x_2}
To express the target quantity in terms of the sum and product of the quadratic solutions.
2
Apply Vieta's formulas to find the sum and product of the solutions from the quadratic equation x212x+4=0x^2 - 12x + 4 = 0.
x1+x2=12x_1 + x_2 = 12 and x1x2=4x_1 x_2 = 4
For any quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is ba-\frac{b}{a} and the product is ca\frac{c}{a}.
3
Substitute the sum and product values into the combined fraction.
124=3\frac{12}{4} = 3
To compute the numerical value of the expression.

Key Concept

Sum and product of solutions of a quadratic equation
Question 1985Question

The graph of the quadratic function ff in the xyxy-plane has xx-intercepts at (2,0)(-2, 0) and (8,0)(8, 0). If the maximum value of f(x)f(x) is 2525, what is the value of f(0)f(0)?

Show answer & explanation

Answer: 16

Answer

16
The axis of symmetry of the quadratic function ff lies halfway between the xx-intercepts x=2x = -2 and x=8x = 8, which is at x=2+82=3x = \frac{-2 + 8}{2} = 3. Since the function has a maximum value of 2525, this maximum must occur at the vertex, giving the vertex coordinates (3,25)(3, 25). In vertex form, the function is f(x)=a(x3)2+25f(x) = a(x - 3)^2 + 25. Substituting the xx-intercept (8,0)(8, 0) into the function yields 0=a(83)2+250 = a(8 - 3)^2 + 25, which simplifies to 25a=2525a = -25, or a=1a = -1. Therefore, the equation of the function is f(x)=(x3)2+25f(x) = -(x - 3)^2 + 25. Evaluating this at x=0x = 0 gives f(0)=(03)2+25=9+25=16f(0) = -(0 - 3)^2 + 25 = -9 + 25 = 16.

Step-by-Step Solution

1
Find the xx-coordinate of the vertex (axis of symmetry)
x=3x = 3
The axis of symmetry of a parabola is located exactly halfway between its xx-intercepts: x=2+82=3x = \frac{-2 + 8}{2} = 3.
2
Determine the vertex coordinates
(3,25)(3, 25)
The maximum value of the quadratic function occurs at its vertex, so the yy-coordinate of the vertex is the maximum value 2525.
3
Write the vertex form of the quadratic function
f(x)=a(x3)2+25f(x) = a(x - 3)^2 + 25
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex.
4
Solve for the leading coefficient aa
a=1a = -1
Substitute the xx-intercept (8,0)(8, 0) into the vertex form: 0=a(83)2+25    25a=25    a=10 = a(8 - 3)^2 + 25 \implies 25a = -25 \implies a = -1.
5
Find the value of f(0)f(0)
f(0)=16f(0) = 16
Substitute x=0x = 0 into the function: f(0)=(03)2+25=9+25=16f(0) = -(0 - 3)^2 + 25 = -9 + 25 = 16.

Key Concept

Using xx-intercepts and the maximum value to determine the vertex and equation of a quadratic function.
Question 1986Question

If xx satisfies the equation below, what is the value of x+5x + 5?

x4=4x+5x - 4 = \sqrt{4x + 5}
Show answer & explanation

Answer: 16

Answer

The correct answer is 16.
Squaring both sides of the equation x4=4x+5x - 4 = \sqrt{4x + 5} results in (x4)2=4x+5(x - 4)^2 = 4x + 5, which expands to x28x+16=4x+5x^2 - 8x + 16 = 4x + 5. Subtracting 4x+54x + 5 from both sides gives the quadratic equation x212x+11=0x^2 - 12x + 11 = 0. Factoring this quadratic equation yields (x11)(x1)=0(x - 11)(x - 1) = 0, giving candidate solutions of x=11x = 11 and x=1x = 1. Checking these solutions in the original equation shows that x=11x = 11 is valid (7=77 = 7), whereas x=1x = 1 is extraneous (3=3-3 = 3 is false). Therefore, the only real solution is x=11x = 11, and the value of the expression x+5x + 5 is 11+5=1611 + 5 = 16.

Step-by-Step Solution

1
Square both sides of the equation to remove the radical.
(x4)2=4x+5(x - 4)^2 = 4x + 5
Squaring a square root isolates the expression under the radical.
2
Expand the squared binomial on the left side.
x28x+16=4x+5x^2 - 8x + 16 = 4x + 5
Applying the distributive property to (x4)(x4)(x - 4)(x - 4) yields x28x+16x^2 - 8x + 16.
3
Rearrange the equation to set it equal to zero.
x212x+11=0x^2 - 12x + 11 = 0
Subtracting 4x+54x + 5 from both sides simplifies the equation into standard quadratic form.
4
Factor the quadratic equation.
(x11)(x1)=0(x - 11)(x - 1) = 0
Finding two numbers that multiply to 11 and add to -12 gives -11 and -1.
5
Solve for the candidate values of x.
x=11x = 11 and x=1x = 1
Setting each factor equal to zero yields the possible solutions.
6
Check the candidate values in the original equation to identify any extraneous solutions.
x=11x = 11 is valid; x=1x = 1 is extraneous.
Substituting x=1x = 1 results in 3=3-3 = 3, which is false because the principal square root is always non-negative.
7
Evaluate the target expression using the valid solution.
11+5=1611 + 5 = 16
The question asks for the value of x+5x + 5, so we substitute the only valid solution, x=11x = 11.

Key Concept

Solving radical equations by squaring both sides and checking for extraneous solutions.
Question 1987Question

A municipal parking garage tracked the charging times of 200200 electric vehicles over a one-week period. The vehicles were classified by type—Battery Electric Vehicles (BEVs) or Plug-in Hybrid Electric Vehicles (PHEVs)—and by the time of day they primarily charged: Daytime (6:00 AM to 6:00 PM) or Nighttime (6:00 PM to 6:00 AM). The results are summarized in the table below.

Vehicle TypeDaytime ChargingNighttime ChargingTotal
BEV45457575120120
PHEV555525258080
Total100100100100200200

If one of these electric vehicles is selected at random, and it is found to have charged during the nighttime, what is the probability that the vehicle is a PHEV?

Show answer & explanation

Answer: 14\frac{1}{4}

Answer

14\frac{1}{4}
The correct answer is the simplified fraction representing the number of nighttime-charging PHEVs (2525) divided by the total number of nighttime-charging vehicles (100100), which is 25100=14\frac{25}{100} = \frac{1}{4}.

Step-by-Step Solution

1
Identify the total number of vehicles in the restricted sample space.
The total number of vehicles that charged during the nighttime is 100100.
The question specifies that the vehicle 'is found to have charged during the nighttime', which limits the denominator to the 'Nighttime Charging' column total.
2
Determine the number of favorable outcomes within this restricted sample space.
The number of PHEVs that charged during the nighttime is 2525.
We need to find the count in the intersection of the 'PHEV' row and the 'Nighttime Charging' column.
3
Calculate the conditional probability as a fraction.
The probability is 25100=14\frac{25}{100} = \frac{1}{4}.
Dividing the number of favorable vehicles (2525) by the conditional total (100100) yields the final probability, which simplifies to 14\frac{1}{4}.

Key Concept

Conditional probability calculations from a two-way table involve restricting the sample space to a specific row or column total rather than the grand total.
Estimated Time:1m 30s
Question 1988Question

A right circular cone has a volume of 24 cubic centimeters24\text{ cubic centimeters}. A second right circular cone has a base radius that is 33 times the base radius of the first cone, and a height that is half the height of the first cone. What is the volume, in cubic centimeters, of the second cone?

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Answer: 108

Answer

108
The volume of a cone is proportional to the square of its radius and directly proportional to its height. Tripling the radius increases the volume by a factor of 32=93^2 = 9. Halving the height reduces the volume by a factor of 12\frac{1}{2}. Combining these changes scales the original volume by 9×12=4.59 \times \frac{1}{2} = 4.5. Multiplying the original volume of 2424 by 4.54.5 gives the correct volume of 108108.

Step-by-Step Solution

1
Write down the formula for the volume of a right circular cone.
V=13πr2hV = \frac{1}{3}\pi r^2 h
This establishes the relationship between volume, radius, and height.
2
Express the volume of the second cone (V2V_2) in terms of the dimensions of the first cone (rr and hh).
V2=13π(3r)2(12h)V_2 = \frac{1}{3}\pi (3r)^2 \left(\frac{1}{2}h\right)
The radius of the second cone is 3r3r and the height is 12h\frac{1}{2}h.
3
Simplify the expression for the second cone's volume to find the scale factor relative to the first cone.
V2=13π(9r2)(12h)=92(13πr2h)=4.5V1V_2 = \frac{1}{3}\pi (9r^2) \left(\frac{1}{2}h\right) = \frac{9}{2} \left(\frac{1}{3}\pi r^2 h\right) = 4.5 V_1
Squaring the radius multiplier of 3 gives a factor of 9, and the height multiplier of 0.5 gives a factor of 0.5, resulting in a combined scaling factor of 4.5.
4
Calculate the final volume using the volume of the first cone (V1=24V_1 = 24).
V2=4.5×24=108V_2 = 4.5 \times 24 = 108
Multiplying the original volume of 24 cm324\text{ cm}^3 by the overall scale factor of 4.54.5 yields the new volume.

Key Concept

Dimensional scaling of three-dimensional solids
Question 1989Question

If 92x+1=(127)x29^{2x + 1} = \left(\frac{1}{27}\right)^{x - 2}, what is the value of xx?

Show answer & explanation

Answer: 47\frac{4}{7}

Answer

47\frac{4}{7}
The correct answer is 47\frac{4}{7}. By rewriting both sides of the equation with a common base of 33, the equation becomes 32(2x+1)=33(x2)3^{2(2x + 1)} = 3^{-3(x - 2)}. Applying the power of a power rule gives 34x+2=33x+63^{4x + 2} = 3^{-3x + 6}. Since the bases are equal, the exponents must be equal, giving 4x+2=3x+64x + 2 = -3x + 6. Solving for xx results in 7x=47x = 4, which gives x=47x = \frac{4}{7}.

Step-by-Step Solution

1
Rewrite each side of the equation with a common base of 33.
9=329 = 3^2 and 127=33\frac{1}{27} = 3^{-3}, so the equation becomes (32)2x+1=(33)x2(3^2)^{2x + 1} = (3^{-3})^{x - 2}.
Before solving an exponential equation, it is helpful to express the bases in terms of their common prime base.
2
Apply the exponent power rule (am)n=amn(a^m)^n = a^{mn} to simplify the exponents.
32(2x+1)=33(x2)    34x+2=33x+63^{2(2x + 1)} = 3^{-3(x - 2)} \implies 3^{4x + 2} = 3^{-3x + 6}.
Simplifying the expressions on both sides allows for equating the exponents directly.
3
Set the exponents equal to each other and solve the resulting linear equation.
4x+2=3x+6    7x=4    x=474x + 2 = -3x + 6 \implies 7x = 4 \implies x = \frac{4}{7}.
Since the bases are equal, the powers can only be equal if their exponents are equal.

Key Concept

Solving exponential equations by expressing bases in terms of a common base and equating the exponents.
Estimated Time:1m 30s
Question 1990Question

A city reservoir contains water that is released at a constant rate for river conservation. The volume of water, WW, in millions of gallons, remaining in the reservoir dd days after the release begins is modeled by the equation W=2401.8dW = 240 - 1.8d. What is the best interpretation of the number 1.81.8 in this context?

Show answer & explanation

Answer: The volume of water in the reservoir decreases by 1.8 million gallons each day.

Answer

The volume of water in the reservoir decreases by 1.8 million gallons each day.
The equation W=2401.8dW = 240 - 1.8d is in slope-intercept form, where the slope is 1.8-1.8 and the yy-intercept is 240240. The slope represents the rate of change of the remaining volume of water with respect to time. A slope of 1.8-1.8 indicates that the volume of water, WW, decreases by 1.81.8 million gallons for every 11 day increase in the number of days, dd.

Step-by-Step Solution

1
Identify the variables and constants in the given linear model.
In W=2401.8dW = 240 - 1.8d, WW is the remaining volume in millions of gallons, dd is the time in days, 240 is the y-intercept (initial volume), and -1.8 is the slope (rate of change).
Understanding the components of a linear equation y=mx+by = mx + b helps isolate the meaning of each constant.
2
Interpret the meaning of the slope in the context of the variables and units.
The coefficient of dd is -1.8, which represents a rate of change of -1.8 million gallons per day.
The slope is the change in the dependent variable (WW, in millions of gallons) per unit change in the independent variable (dd, in days).
3
Relate the negative sign to the physical context.
A negative slope of -1.8 means that the volume decreases by 1.8 million gallons for each elapsed day.
In context, a constant release of water leads to a decrease in the remaining volume.

Key Concept

Interpreting slope in a linear relationship context
Estimated Time:1m 30s
Question 1991Question

In a laboratory experiment, a wet soil sample has a mass of 800800 grams. During a drying process, the sample loses 20%20\% of its mass. After the drying process, a nutrient solution is added, which increases the sample's mass by 15%15\% of its dried mass. What is the final mass, in grams, of the soil sample after the solution is added?

Show answer & explanation

Answer: 736

Answer

736
To find the final mass of the soil sample, first calculate the mass after it loses 20%20\% of its initial 800800 grams: 800×(10.20)=640800 \times (1 - 0.20) = 640 grams. Next, calculate the final mass after a 15%15\% increase is applied to this intermediate mass: 640×(1+0.15)=736640 \times (1 + 0.15) = 736 grams. This shows that the final mass of the sample is 736736 grams.

Step-by-Step Solution

1
Calculate the mass of the soil sample after losing 20%20\% of its initial mass of 800800 grams.
Dried mass = 800×(10.20)=640800 \times (1 - 0.20) = 640 grams.
This establishes the intermediate baseline mass before the nutrient solution is added.
2
Calculate the final mass of the soil sample after a 15%15\% increase is applied to the dried mass of 640640 grams.
Final mass = 640×(1+0.15)=736640 \times (1 + 0.15) = 736 grams.
The 15%15\% increase must be calculated using the dried mass of 640640 grams as the new base.

Key Concept

Multi-step percent change and identifying the correct base value for sequential percentage increases or decreases.

Alternative Method

You can express the sequential percent changes as a single product: 800×0.80×1.15800 \times 0.80 \times 1.15. Multiplying these values directly yields 800×0.92=736800 \times 0.92 = 736 grams.
Estimated Time:1m 15s
Question 1992Question

A botanist conducted an experiment to study the germination rates of seeds in two different soil mixtures, Mixture A and Mixture B. The results of the experiment are partially shown in the table below, where xx is a positive constant.

Soil MixtureGerminatedDid Not Germinate
Mixture Axx1212
Mixture B3030x+6x + 6

Of the seeds in the experiment that did not germinate, the probability that the seed was planted in Mixture A is 13\frac{1}{3}. Given that a seed selected at random from the experiment germinated, what is the probability that it was planted in Mixture A?

Show answer & explanation

Answer: 0.375

Answer

3/8 (or 0.375)
To find the probability that a germinated seed was planted in Mixture A, we must first solve for the variable xx. The number of seeds in Mixture A that did not germinate is 1212, and the total number of seeds that did not germinate is 12+(x+6)=x+1812 + (x + 6) = x + 18. We are given that the probability a non-germinated seed was planted in Mixture A is 13\frac{1}{3}. Setting up the equation: 12x+18=13\frac{12}{x + 18} = \frac{1}{3} yields x+18=36x + 18 = 36, so x=18x = 18. Substituting this value back into the table, the number of germinated seeds in Mixture A is 1818. The total number of germinated seeds is the sum of germinated seeds in Mixture A and Mixture B: 18+30=4818 + 30 = 48. Thus, the probability that a germinated seed was planted in Mixture A is 1848\frac{18}{48}, which simplifies to 38\frac{3}{8} (or 0.3750.375).

Step-by-Step Solution

1
Set up the conditional probability equation for seeds that did not germinate to find xx.
x=18x = 18
From the table, the number of seeds in Mixture A that did not germinate is 1212, and the number of seeds in Mixture B that did not germinate is x+6x + 6. The total number of seeds that did not germinate is 12+(x+6)=x+1812 + (x + 6) = x + 18. The probability that a seed that did not germinate was from Mixture A is 12x+18=13\frac{12}{x + 18} = \frac{1}{3}. Solving this equation gives 36=x+1836 = x + 18, which simplifies to x=18x = 18.
2
Find the number of germinated seeds in Mixture A and the total number of germinated seeds.
Mixture A germinated = 1818, Total germinated = 4848
Substituting x=18x = 18, the number of germinated seeds in Mixture A is 1818. The number of germinated seeds in Mixture B is given as 3030. The total number of germinated seeds is 18+30=4818 + 30 = 48.
3
Calculate the conditional probability that a germinated seed was planted in Mixture A.
38\frac{3}{8} or 0.3750.375
The probability is the number of germinated seeds in Mixture A divided by the total number of germinated seeds, which is 1848=38\frac{18}{48} = \frac{3}{8}, or 0.3750.375 as a decimal.

Key Concept

Conditional Probability in Two-Way Tables
Question 1993Question

A right circular cylinder has a height of 1212 and a base radius of rr. A sphere has a radius of rr. If the volume of the cylinder is equal to the volume of the sphere, what is the value of rr?

Show answer & explanation

Answer: 9

Answer

9
The volume of a cylinder is given by V=πr2hV = \pi r^2 h and the volume of a sphere is given by V=43πr3V = \frac{4}{3}\pi r^3. Given that the cylinder's height is 1212, its volume is 12πr212\pi r^2. Setting the volumes equal yields 12πr2=43πr312\pi r^2 = \frac{4}{3}\pi r^3. Since rr is a non-zero radius, we can divide both sides by πr2\pi r^2, resulting in 12=43r12 = \frac{4}{3}r. Multiplying both sides by 34\frac{3}{4} gives r=9r = 9.

Step-by-Step Solution

1
State the standard volume formulas for a right circular cylinder and a sphere.
Vcylinder=πr2hV_{\text{cylinder}} = \pi r^2 h and Vsphere=43πr3V_{\text{sphere}} = \frac{4}{3}\pi r^3
These formulas are needed to express the volumes of both solids in terms of rr.
2
Equate the volume of the cylinder to the volume of the sphere and substitute the given height of 1212.
12πr2=43πr312\pi r^2 = \frac{4}{3}\pi r^3
The problem states that the volume of the cylinder is equal to the volume of the sphere.
3
Divide both sides of the equation by πr2\pi r^2.
12=43r12 = \frac{4}{3}r
Simplifies the equation to a first-degree equation in terms of rr.
4
Solve for rr by multiplying both sides of the simplified equation by the reciprocal of 43\frac{4}{3}, which is 34\frac{3}{4}.
r=9r = 9
Isolates the variable rr to find the correct value.

Key Concept

Equating the volumes of geometric solids to solve for an unknown dimension.
Estimated Time:1m 30s
Question 1994Question

An object is launched from a platform. The function h(t)=5t2+30t+12h(t) = -5t^2 + 30t + 12 models the height of the object, in meters, tt seconds after it was launched. What is the maximum height, in meters, reached by the object?

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Answer: 57

Answer

The maximum height reached by the object is 57 meters.
The given function h(t)=5t2+30t+12h(t) = -5t^2 + 30t + 12 represents a parabola opening downward because the coefficient of t2t^2 is negative. The maximum value of this function occurs at its vertex. The time tt at the vertex is determined using the formula t=b2a=302(5)=3t = -\frac{b}{2a} = -\frac{30}{2(-5)} = 3 seconds. Substituting t=3t = 3 back into the function yields the maximum height: h(3)=5(3)2+30(3)+12=45+90+12=57h(3) = -5(3)^2 + 30(3) + 12 = -45 + 90 + 12 = 57 meters.

Step-by-Step Solution

1
Identify the coefficients of the quadratic function in standard form h(t)=at2+bt+ch(t) = at^2 + bt + c.
a=5a = -5, b=30b = 30, and c=12c = 12.
These coefficients are needed to calculate the vertex of the parabola.
2
Calculate the time tt at which the maximum height occurs using the vertex formula t=b2at = -\frac{b}{2a}.
t=302(5)=3t = -\frac{30}{2(-5)} = 3 seconds.
Since the leading coefficient a=5a = -5 is negative, the parabola opens downward, meaning its vertex represents the maximum value.
3
Substitute t=3t = 3 back into the height function to find the maximum height.
h(3)=5(3)2+30(3)+12=45+90+12=57h(3) = -5(3)^2 + 30(3) + 12 = -45 + 90 + 12 = 57 meters.
Evaluating the function at the time of the vertex gives the corresponding maximum height.

Key Concept

The maximum value of a quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c (where a<0a < 0) is the vertical coordinate of its vertex, which occurs at x=b2ax = -\frac{b}{2a}.
Question 1995Question

A researcher at a university wants to estimate the average number of hours that students at the university spend studying per week. The researcher randomly selects 200200 students from a database of all students enrolled at the university to participate in a survey. Which of the following is the largest population to which the results of the survey can be most reasonably generalized?

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Answer: All students enrolled at the university

Answer

All students enrolled at the university
The correct option is the one stating that the results can be generalized to all students enrolled at the university. In an observational study or survey, results can be generalized to the population from which the sample was randomly selected. Here, the database used for selection included all students enrolled at the university, making them the target population.

Step-by-Step Solution

1
Identify the population from which the sample was drawn.
The sample of 200200 students was randomly selected from a database containing all students enrolled at the university.
Generalization of survey results requires that the sample be randomly selected from the target population.
2
Determine the scope of the generalization based on the random sampling design.
The results can be generalized to the entire population of students enrolled at the university, but not to broader populations (like all college students in the nation) or restricted biased subgroups.
Random selection ensures that the sample is representative of the population from which it was drawn.

Key Concept

Generalizing results from a random sample to the parent population
Question 1996Question

The graph of the function ff in the xyxy-plane has a vertex at (2,7)(-2, 7). The function gg is defined by g(x)=f(x+3)+12g(x) = f(-x + 3) + 12. If the vertex of the graph of y=g(x)y = g(x) is the point (a,b)(a, b), what is the value of a+ba + b?

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Answer: 24

Answer

24
The vertex of the parent function f(x)f(x) is at (2,7)(-2, 7), which means f(2)=7f(-2) = 7. The transformed function is g(x)=f(x+3)+12g(x) = f(-x + 3) + 12. The vertex of g(x)g(x) occurs when the input to ff, which is x+3-x + 3, is equal to 2-2. Solving x+3=2-x + 3 = -2 gives x=5-x = -5, or x=5x = 5, so the x-coordinate of the vertex of g(x)g(x) is a=5a = 5. To find the y-coordinate bb, we evaluate g(5)=f((5)+3)+12=f(2)+12=7+12=19g(5) = f(-(5) + 3) + 12 = f(-2) + 12 = 7 + 12 = 19. Therefore, the vertex of the graph of y=g(x)y = g(x) is (5,19)(5, 19), so a=5a = 5 and b=19b = 19. The value of a+ba + b is 5+19=245 + 19 = 24.

Step-by-Step Solution

1
Find the x-coordinate of the vertex of the transformed function g(x)g(x) by setting the inner expression equal to the x-coordinate of the original vertex.
a=5a = 5
The vertex of f(x)f(x) is located at x=2x = -2. For g(x)=f(x+3)+12g(x) = f(-x + 3) + 12, the vertex occurs when the input to ff, x+3-x + 3, is equal to 2-2. Solving x+3=2-x + 3 = -2 yields x=5x = 5.
2
Find the y-coordinate of the vertex of g(x)g(x) by evaluating g(5)g(5).
b=19b = 19
Substituting x=5x = 5 into the definition of g(x)g(x) gives g(5)=f(2)+12g(5) = f(-2) + 12. Since the vertex of ff is at (2,7)(-2, 7), f(2)=7f(-2) = 7. Thus, g(5)=7+12=19g(5) = 7 + 12 = 19.
3
Calculate the sum of the coordinates aa and bb.
24
The vertex of g(x)g(x) is (5,19)(5, 19), so a=5a = 5 and b=19b = 19. The sum a+ba + b is 5+19=245 + 19 = 24.

Key Concept

Determining the coordinates of a transformed vertex using function notation.
Question 1997Question

A shipping container initially holds 450 packages. A crew unloads the container at a rate of 15 packages per hour, while an automated sorting machine unloads packages at a rate of xx packages per hour. The number of packages remaining in the container after 8 hours must be at most 130. The inequality 4508(15+x)130450 - 8(15 + x) \leq 130 models this scenario. What is the minimum possible value of xx?

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Answer: 25

Answer

The minimum possible value of xx is 25.
To find the minimum possible value of xx, solve the inequality 4508(15+x)130450 - 8(15 + x) \leq 130. First, distribute the 8-8 to obtain 4501208x130450 - 120 - 8x \leq 130. Simplify the constant terms on the left side to get 3308x130330 - 8x \leq 130. Subtract 330 from both sides, yielding 8x200-8x \leq -200. Finally, divide both sides by 8-8 and reverse the inequality sign because of the division by a negative number, which results in x25x \geq 25. The minimum possible value of xx is 25.

Step-by-Step Solution

1
Distribute the factor of 8-8 to both terms inside the parentheses.
4501208x130450 - 120 - 8x \leq 130
To remove the parentheses and prepare to combine like terms.
2
Subtract 120 from 450 to simplify the constants on the left side.
3308x130330 - 8x \leq 130
To simplify the left side of the inequality before isolating the variable.
3
Subtract 330 from both sides of the inequality.
8x200-8x \leq -200
To isolate the variable term on the left-hand side.
4
Divide both sides by 8-8 and reverse the direction of the inequality symbol.
x25x \geq 25
Dividing by a negative value reverses the inequality sign. Since xx must be greater than or equal to 25, the minimum possible value is 25.

Key Concept

Solving multi-step linear inequalities in one variable, including distributing coefficients and reversing the inequality sign when multiplying or dividing by a negative number.
Question 1998Question

A sphere has a surface area of 144π144\pi square inches. What is the volume, in cubic inches, of the sphere?

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Answer: 288π288\pi

Answer

The volume of the sphere is 288π288\pi cubic inches.
The surface area of a sphere is given by A=4πr2A = 4\pi r^2, where rr is the radius. Setting this equal to the given surface area yields 4πr2=144π4\pi r^2 = 144\pi, which simplifies to r2=36r^2 = 36, meaning the radius of the sphere is 66 inches. The volume of a sphere is given by V=43πr3V = \frac{4}{3}\pi r^3. Substituting r=6r = 6 into this formula gives V=43π(63)=43π(216)=288πV = \frac{4}{3}\pi (6^3) = \frac{4}{3}\pi (216) = 288\pi cubic inches.

Step-by-Step Solution

1
Set the formula for the surface area of a sphere, A=4πr2A = 4\pi r^2, equal to the given surface area of 144π144\pi.
4πr2=144π4\pi r^2 = 144\pi, which simplifies to r2=36r^2 = 36.
To find the square of the radius of the sphere.
2
Take the square root of both sides to find the radius rr.
r=6r = 6.
The radius of a sphere must be a positive number.
3
Substitute the radius r=6r = 6 into the formula for the volume of a sphere, V=43πr3V = \frac{4}{3}\pi r^3.
V=43π(63)=43π(216)=288πV = \frac{4}{3}\pi(6^3) = \frac{4}{3}\pi(216) = 288\pi.
To compute the final volume of the sphere.

Key Concept

The volume of a sphere can be calculated by first finding its radius from its surface area using the formulas A=4πr2A = 4\pi r^2 and V=43πr3V = \frac{4}{3}\pi r^3.
Question 1999Question

In the xyxy-plane, the graph of the quadratic function f(x)=x2+bx+cf(x) = -x^2 + bx + c, where bb and cc are constants, has its vertex at (4,25)(4, 25). If the positive xx-intercept of the graph of ff is (d,0)(d, 0), what is the value of dd?

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Answer: 9

Answer

The value of dd is 99.
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x-h)^2 + k, where (h,k)(h, k) is the vertex. Since the vertex is (4,25)(4, 25) and the coefficient of x2x^2 is 1-1, the function is f(x)=(x4)2+25f(x) = -(x-4)^2 + 25. Setting f(x)=0f(x) = 0 to find the xx-intercepts yields (x4)2+25=0-(x-4)^2 + 25 = 0, which simplifies to (x4)2=25(x-4)^2 = 25. Taking the square root of both sides gives x4=5x - 4 = 5 or x4=5x - 4 = -5. Solving these equations gives x=9x = 9 or x=1x = -1. The positive xx-intercept is (9,0)(9, 0), so the value of dd is 99.

Step-by-Step Solution

1
Write the function in vertex form.
f(x)=(x4)2+25f(x) = -(x-4)^2 + 25
The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x-h)^2 + k, where (h,k)(h, k) is the vertex. Here, the vertex is (4,25)(4, 25) and the coefficient of x2x^2 is 1-1, so a=1a = -1, h=4h = 4, and k=25k = 25.
2
Set f(x)=0f(x) = 0 to find the xx-intercepts.
(x4)2+25=0-(x-4)^2 + 25 = 0
The xx-intercepts of a graph are the points where the function value is equal to 0.
3
Solve the equation for xx.
x=9x = 9 or x=1x = -1
Rearranging the equation gives (x4)2=25(x-4)^2 = 25. Taking the square root of both sides gives x4=5x-4 = 5 or x4=5x-4 = -5, which solves to x=9x = 9 or x=1x = -1.
4
Identify the positive xx-intercept coordinate dd.
d=9d = 9
The question asks for the positive xx-intercept (d,0)(d, 0), which corresponds to x=9x = 9.

Key Concept

Vertex form of a quadratic function and finding xx-intercepts
Question 2000Question

A dataset consists of 10 positive integers: 4,6,8,8,10,12,12,14,164, 6, 8, 8, 10, 12, 12, 14, 16, and xx. If the median of the dataset is equal to the mean of the dataset, and x>16x > 16, what is the value of xx?

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Answer: 20

Answer

20
The correct answer is 20. When the 10 positive integers are sorted in ascending order, the condition x>16x > 16 ensures that xx is the largest value and occupies the final position: 4,6,8,8,10,12,12,14,16,x4, 6, 8, 8, 10, 12, 12, 14, 16, x. The median of this 10-value dataset is the average of the 5th and 6th values, which are 10 and 12. Thus, the median is 10+122=11\frac{10 + 12}{2} = 11. The mean of the dataset is the sum of the 10 values divided by 10. The sum of the 9 known values is 4+6+8+8+10+12+12+14+16=904 + 6 + 8 + 8 + 10 + 12 + 12 + 14 + 16 = 90, so the mean is 90+x10\frac{90 + x}{10}. Setting the mean equal to the median gives the equation 90+x10=11\frac{90 + x}{10} = 11. Multiplying both sides by 10 gives 90+x=11090 + x = 110, and subtracting 90 yields x=20x = 20. This value is consistent with the condition x>16x > 16.

Step-by-Step Solution

1
Sort the dataset including the variable xx.
The sorted dataset of 10 integers is 4,6,8,8,10,12,12,14,16,x4, 6, 8, 8, 10, 12, 12, 14, 16, x.
Since x>16x > 16, it must be the largest value in the dataset and will be positioned at the end of the sorted list.
2
Find the median of the sorted dataset.
The median is 11.
For an even number of values (10), the median is the average of the two middle values (the 5th and 6th values), which are 10 and 12: (10+12)/2=11(10 + 12) / 2 = 11.
3
Find the sum of the known values and write an expression for the mean.
The mean is 90+x10\frac{90 + x}{10}.
The sum of the 9 known integers is 4+6+8+8+10+12+12+14+16=904 + 6 + 8 + 8 + 10 + 12 + 12 + 14 + 16 = 90. Adding xx gives a total sum of 90+x90 + x, and dividing by the total count of 10 gives the mean.
4
Equate the mean to the median and solve for xx.
x=20x = 20
Setting the mean expression equal to the median yields 90+x10=11\frac{90 + x}{10} = 11. Multiplying by 10 gives 90+x=11090 + x = 110, which solves to x=20x = 20.

Key Concept

Calculating and equating the mean and median of a dataset containing a variable.
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