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Question 61Question

In the system of equations below, what is the value of xx?

3xy=73x - y = 7
x+y=5x + y = 5
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Answer: 3

Answer

The value of xx is 33.
Adding the two equations eliminates yy, resulting in 4x=124x = 12. Dividing by 44 gives x=3x = 3.

Step-by-Step Solution

1
Add the two equations to eliminate yy.
4x=124x = 12
Adding the equations (3xy)+(x+y)=7+5(3x - y) + (x + y) = 7 + 5 eliminates yy because y+y=0-y + y = 0.
2
Solve for xx.
x=3x = 3
Divide both sides of the equation 4x=124x = 12 by 44.

Key Concept

Solving a system of linear equations by elimination.
Question 62Question

If 35p4=8\frac{3}{5}p - 4 = 8, what is the value of pp?

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Answer: 20

Answer

20
To solve the equation 35p4=8\frac{3}{5}p - 4 = 8, we perform inverse operations to isolate pp. First, add 4 to both sides of the equation to get 35p=12\frac{3}{5}p = 12. Next, multiply both sides by the reciprocal of the coefficient of pp, which is 53\frac{5}{3}. This gives p=12×53=20p = 12 \times \frac{5}{3} = 20. Substituting 20 back into the original equation confirms it is the correct solution.

Step-by-Step Solution

1
Add 4 to both sides of the equation.
35p=12\frac{3}{5}p = 12
To isolate the term containing the variable pp.
2
Multiply both sides of the equation by 53\frac{5}{3}.
p=20p = 20
To solve for pp by multiplying by the reciprocal of its coefficient.

Key Concept

Solving one-variable linear equations using inverse operations.
Question 63Question

In the equation below, kk is a constant.

13(2kx9)56(x+4)=112\frac{1}{3}(2kx - 9) - \frac{5}{6}(x + 4) = \frac{11}{2}

If the equation has no solution, what is the value of kk?

Show answer & explanation

Answer: 1.25

Answer

1.25 (or 5/4)
The correct answer is 1.25 (or 5/4). A linear equation in one variable of the form Ax+B=CAx + B = C has no solution if the variable terms on both sides of the equation are equal (meaning A=0A = 0) and the constant terms are unequal (BCB \neq C). Expanding the left side of the given equation yields 23kx356x103=112\frac{2}{3}kx - 3 - \frac{5}{6}x - \frac{10}{3} = \frac{11}{2}. Combining the constant terms gives (23k56)x193=112\left(\frac{2}{3}k - \frac{5}{6}\right)x - \frac{19}{3} = \frac{11}{2}. Setting the coefficient of xx to 00 yields 23k56=0\frac{2}{3}k - \frac{5}{6} = 0. Solving for kk gives k=56×32=54k = \frac{5}{6} \times \frac{3}{2} = \frac{5}{4}, which is equivalent to 1.25. Since the remaining constant terms are unequal (193112-\frac{19}{3} \neq \frac{11}{2}), the equation has no solution when k=1.25k = 1.25.

Step-by-Step Solution

1
Expand the expression on the left side of the equation
23kx356x103=112\frac{2}{3}kx - 3 - \frac{5}{6}x - \frac{10}{3} = \frac{11}{2}
Apply the distributive property to remove the parentheses.
2
Group the xx terms and combine the constants on the left side
(23k56)x193=112\left(\frac{2}{3}k - \frac{5}{6}\right)x - \frac{19}{3} = \frac{11}{2}
Simplify the equation by combining like terms: 3103=93103=193-3 - \frac{10}{3} = -\frac{9}{3} - \frac{10}{3} = -\frac{19}{3}.
3
Set the coefficient of the xx term equal to 00
23k56=0\frac{2}{3}k - \frac{5}{6} = 0
For a linear equation to have no solution, the variable terms on both sides of the equation must cancel out (meaning the coefficient of the variable must be 00), while the remaining constant terms must not be equal (193112-\frac{19}{3} \neq \frac{11}{2}).
4
Solve the resulting equation for kk
k=1.25k = 1.25
Add 56\frac{5}{6} to both sides to get 23k=56\frac{2}{3}k = \frac{5}{6}, then multiply by the reciprocal of 23\frac{2}{3}, which gives k=56×32=1512=54=1.25k = \frac{5}{6} \times \frac{3}{2} = \frac{15}{12} = \frac{5}{4} = 1.25.

Key Concept

Conditions for a linear equation in one variable to have no solution
Question 64Question

A rectangle has a length of 2x+52x + 5 centimeters and a width of x2x - 2 centimeters. If the perimeter of the rectangle is 4242 centimeters, what is the value of xx?

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Answer: 6

Answer

6
The correct answer is 6. The perimeter of a rectangle is calculated using the formula P=2l+2wP = 2l + 2w. Substituting the given expressions for length and width yields the linear equation 2(2x+5)+2(x2)=422(2x + 5) + 2(x - 2) = 42. Distributing the 2 gives 4x+10+2x4=424x + 10 + 2x - 4 = 42. Combining like terms on the left side simplifies this to 6x+6=426x + 6 = 42. Subtracting 6 from both sides yields 6x=366x = 36. Finally, dividing both sides by 6 gives the value x=6x = 6.

Step-by-Step Solution

1
Write the perimeter equation in terms of xx.
2(2x+5)+2(x2)=422(2x + 5) + 2(x - 2) = 42
The perimeter of a rectangle is the sum of all its sides, represented by the formula P=2l+2wP = 2l + 2w.
2
Distribute the 2 into the parentheses.
4x+10+2x4=424x + 10 + 2x - 4 = 42
Applying the distributive property yields 2(2x+5)=4x+102(2x + 5) = 4x + 10 and 2(x2)=2x42(x - 2) = 2x - 4.
3
Combine like terms on the left side.
6x+6=426x + 6 = 42
Grouping the variable terms gives 4x+2x=6x4x + 2x = 6x, and grouping the constant terms gives 104=610 - 4 = 6.
4
Subtract 6 from both sides of the equation.
6x=366x = 36
This isolates the variable term on the left side of the equation.
5
Divide both sides of the equation by 6.
x=6x = 6
Dividing by the coefficient of xx solves for the variable.

Key Concept

Solving linear equations in one variable by applying the distributive property and combining like terms.
Question 65Question

In the equation below, cc is a constant.

3c(2x1)2(x+4c)5=2x3\frac{3c(2x - 1) - 2(x + 4c)}{5} = 2x - 3

If the equation has no solution for xx, what is the value of cc?

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Answer: 2

Answer

The correct answer is 2.
To find the value of cc that results in no solution, we first clear the fraction by multiplying both sides of the equation by 5, giving 3c(2x1)2(x+4c)=10x153c(2x - 1) - 2(x + 4c) = 10x - 15. Next, we expand the terms to get 6cx3c2x8c=10x156cx - 3c - 2x - 8c = 10x - 15, and group the xx terms and constant terms: (6c2)x11c=10x15(6c - 2)x - 11c = 10x - 15. For a linear equation to have no solution, the coefficients of xx on both sides must be equal while the constant terms must be different. Setting the coefficients equal gives 6c2=106c - 2 = 10, which solves to c=2c = 2. Checking the constant terms when c=2c = 2, we get 11(2)=22-11(2) = -22 on the left and 15-15 on the right. Since 2215-22 \neq -15, the equation has no solution, confirming c=2c = 2 is correct.

Step-by-Step Solution

1
Multiply both sides of the equation by 5 to eliminate the denominator.
3c(2x1)2(x+4c)=10x153c(2x - 1) - 2(x + 4c) = 10x - 15
Clearing the denominator simplifies the equation into standard polynomial terms.
2
Distribute the terms on the left side of the equation.
6cx3c2x8c=10x156cx - 3c - 2x - 8c = 10x - 15
Applying the distributive property expands the expression so terms can be grouped.
3
Group the xx terms and constant terms on the left side.
(6c2)x11c=10x15(6c - 2)x - 11c = 10x - 15
Putting the equation in the standard form Ax+B=Cx+DAx + B = Cx + D allows us to easily set up the conditions for no solution.
4
Set the coefficients of xx on both sides equal to each other.
6c2=106c - 2 = 10, which simplifies to 6c=126c = 12, and thus c=2c = 2.
For the equation to have no solution, the variable terms on both sides must cancel each other out.
5
Verify that the constant terms are not equal when c=2c = 2.
The left-side constant is 11(2)=22-11(2) = -22, and the right-side constant is 15-15. Since 2215-22 \neq -15, the equation has no solution.
If the constant terms were equal, the equation would have infinitely many solutions instead of no solution.

Key Concept

Identifying conditions for a linear equation in one variable to have no solution.

Alternative Method

Instead of clearing the fraction first, write the left side of the equation as (6c25)x11c5(\frac{6c - 2}{5})x - \frac{11c}{5}. For there to be no solution, the coefficient of xx on the left side, 6c25\frac{6c - 2}{5}, must equal the coefficient of xx on the right side, which is 2. Solving 6c25=2\frac{6c - 2}{5} = 2 gives 6c2=10    c=26c - 2 = 10 \implies c = 2.
Estimated Time:2m 30s
Question 66Question

A linear function ff has a slope of 23\frac{2}{3}. The function gg is defined by g(x)=f(x+4)3g(x) = f(x + 4) - 3. If the graph of y=g(x)y = g(x) in the xyxy-plane has an xx-intercept at (5,0)(5, 0), what is the xx-intercept of the graph of y=f(x)y = f(x)?

Show answer & explanation

Answer: 4.5

Answer

4.5
The correct answer is 4.54.5 (or 92\frac{9}{2}). By using the function transformation relation, we find g(5)=f(9)3=0g(5) = f(9) - 3 = 0, which yields f(9)=3f(9) = 3. With a slope of 23\frac{2}{3}, the equation of the line is f(x)=23x3f(x) = \frac{2}{3}x - 3. Setting f(x)=0f(x) = 0 yields the xx-intercept at x=4.5x = 4.5.

Step-by-Step Solution

1
Use the definition of function gg and its given xx-intercept to find a point on the graph of ff.
f(9)=3f(9) = 3
Since the graph of y=g(x)y = g(x) has an xx-intercept at (5,0)(5, 0), we know g(5)=0g(5) = 0. Substituting x=5x = 5 into the definition g(x)=f(x+4)3g(x) = f(x + 4) - 3 gives g(5)=f(5+4)3=f(9)3g(5) = f(5 + 4) - 3 = f(9) - 3. Since g(5)=0g(5) = 0, it follows that f(9)3=0f(9) - 3 = 0, or f(9)=3f(9) = 3.
2
Determine the equation of the linear function ff using its slope and the point identified in Step 1.
f(x)=23x3f(x) = \frac{2}{3}x - 3
The function ff is linear with a slope of 23\frac{2}{3} and passes through the point (9,3)(9, 3). Using the point-slope formula, we get f(x)3=23(x9)f(x) - 3 = \frac{2}{3}(x - 9), which simplifies to f(x)=23x3f(x) = \frac{2}{3}x - 3.
3
Find the xx-intercept of the graph of y=f(x)y = f(x) by setting f(x)=0f(x) = 0.
x=4.5x = 4.5 (or 92\frac{9}{2})
To find the xx-intercept, set f(x)=0f(x) = 0. This gives 23x3=0\frac{2}{3}x - 3 = 0. Adding 33 to both sides and multiplying by 32\frac{3}{2} yields x=92x = \frac{9}{2}, which is equal to 4.54.5.

Key Concept

Linear Functions and Graphs

Alternative Method

Alternatively, we can write the equation of ff in slope-intercept form as f(x)=23x+bf(x) = \frac{2}{3}x + b. Then the definition of g(x)g(x) becomes g(x)=23(x+4)+b3=23x+83+b3=23x+b13g(x) = \frac{2}{3}(x + 4) + b - 3 = \frac{2}{3}x + \frac{8}{3} + b - 3 = \frac{2}{3}x + b - \frac{1}{3}. Since the graph of gg has an xx-intercept at (5,0)(5, 0), we substitute x=5x = 5 and g(5)=0g(5) = 0 to get 23(5)+b13=0\frac{2}{3}(5) + b - \frac{1}{3} = 0, which simplifies to 3+b=03 + b = 0, so b=3b = -3. This gives f(x)=23x3f(x) = \frac{2}{3}x - 3. Finally, the xx-intercept is found by solving 23x3=0\frac{2}{3}x - 3 = 0, resulting in x=4.5x = 4.5.
Estimated Time:2m 0s
Question 67Question

If 23(x4)=6\frac{2}{3}(x - 4) = 6, what is the value of xx?

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Answer: 13

Answer

13
To solve the linear equation 23(x4)=6\frac{2}{3}(x - 4) = 6, multiply both sides of the equation by 32\frac{3}{2} to isolate x4x - 4. This yields x4=9x - 4 = 9. Adding 44 to both sides of the equation isolates xx and gives the value x=13x = 13.

Step-by-Step Solution

1
Multiply both sides of the equation 23(x4)=6\frac{2}{3}(x - 4) = 6 by the reciprocal of the fraction, which is 32\frac{3}{2}.
x4=9x - 4 = 9
Multiplying a fraction by its reciprocal simplifies it to 1, leaving the term in parentheses isolated on the left side.
2
Add 44 to both sides of the equation x4=9x - 4 = 9.
x=13x = 13
Adding 44 isolates the variable xx on the left side.

Key Concept

Solving a one-variable linear equation using inverse operations.
Question 68Question

A food truck sells tacos and burritos. On Tuesday, the food truck sold a total of 120 tacos and burritos. The number of tacos sold, tt, was 20 more than the number of burritos sold, bb. This situation is represented by the system of equations below:

t+b=120t + b = 120
t=b+20t = b + 20

How many burritos did the food truck sell on Tuesday?

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Answer: 50

Answer

The food truck sold 50 burritos on Tuesday.
To find the number of burritos sold, bb, we substitute t=b+20t = b + 20 into the first equation t+b=120t + b = 120, giving (b+20)+b=120(b + 20) + b = 120. Combining like terms yields 2b+20=1202b + 20 = 120. Subtracting 20 from both sides results in 2b=1002b = 100. Finally, dividing both sides by 2 gives b=50b = 50. Thus, the food truck sold 50 burritos on Tuesday.

Step-by-Step Solution

1
Substitute the expression for tt from the second equation into the first equation
(b+20)+b=120(b + 20) + b = 120
To eliminate the variable tt and set up an equation with only one variable, bb.
2
Combine like terms on the left side of the equation
2b+20=1202b + 20 = 120
To simplify the equation for solving.
3
Subtract 20 from both sides of the equation
2b=1002b = 100
To isolate the variable term on one side of the equation.
4
Divide both sides of the equation by 2
b=50b = 50
To solve for the variable bb representing the number of burritos.

Key Concept

Solving systems of linear equations using the substitution method
Question 69Question

In the equation 3(4x+b)2(x5)=2(5x+8)3(4x + b) - 2(x - 5) = 2(5x + 8), bb is a constant. If the equation has infinitely many solutions for xx, what is the value of bb?

Show answer & explanation

Answer: 2

Answer

The value of bb is 2.
Distributing the constants in the equation 3(4x+b)2(x5)=2(5x+8)3(4x + b) - 2(x - 5) = 2(5x + 8) yields 12x+3b2x+10=10x+1612x + 3b - 2x + 10 = 10x + 16. Combining like terms on the left side simplifies the equation to 10x+3b+10=10x+1610x + 3b + 10 = 10x + 16. For a linear equation in one variable to have infinitely many solutions, both sides of the equation must be identical. Since the coefficients of xx are equal (10=1010 = 10), the constant terms must also be equal: 3b+10=163b + 10 = 16. Solving for bb yields 3b=63b = 6, which simplifies to b=2b = 2.

Step-by-Step Solution

1
Distribute the constants through the parentheses on both sides of the equation 3(4x+b)2(x5)=2(5x+8)3(4x + b) - 2(x - 5) = 2(5x + 8).
12x+3b2x+10=10x+1612x + 3b - 2x + 10 = 10x + 16
To eliminate parentheses and allow grouping of like terms.
2
Combine like terms on the left side of the equation.
10x+3b+10=10x+1610x + 3b + 10 = 10x + 16
To simplify the left-hand expression into the standard linear form.
3
Equate the constant terms on both sides of the equation.
3b+10=163b + 10 = 16
A linear equation in one variable has infinitely many solutions when both sides are identical. Since the coefficients of the variable xx are both 10, the constant terms must be equal.
4
Solve for bb by isolating it.
b=2b = 2
Subtracting 10 from both sides gives 3b=63b = 6, and dividing by 3 yields the final value.

Key Concept

Determining conditions for a linear equation in one variable to have infinitely many solutions (identity).
Question 70Question

In the xyxy-plane, line ll passes through the points (2,3)(-2, -3) and (2,5)(2, 5). Line kk is parallel to line ll and has a yy-intercept of (0,1)(0, -1). If the point (a,9)(a, 9) lies on line kk, what is the value of aa?

Show answer & explanation

Answer: 5

Answer

The value of aa is 55.
To find the value of aa, we first determine the slope of line ll using the two given points, (2,3)(-2, -3) and (2,5)(2, 5). The slope mm is given by 5(3)2(2)=84=2\frac{5 - (-3)}{2 - (-2)} = \frac{8}{4} = 2. Since line kk is parallel to line ll, it has the same slope of 22. The yy-intercept of line kk is (0,1)(0, -1), so the equation of line kk is y=2x1y = 2x - 1. To find the value of aa, we substitute the point (a,9)(a, 9) into this equation: 9=2a19 = 2a - 1. Solving for aa gives 10=2a10 = 2a, which simplifies to a=5a = 5.

Step-by-Step Solution

1
Calculate the slope of line ll using the two given points.
The slope of line ll is 22.
Using the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} with the points (2,3)(-2, -3) and (2,5)(2, 5), we get m=5(3)2(2)=84=2m = \frac{5 - (-3)}{2 - (-2)} = \frac{8}{4} = 2.
2
Find the equation of line kk.
The equation of line kk is y=2x1y = 2x - 1.
Line kk is parallel to line ll, so it has the same slope, m=2m = 2. Its yy-intercept is (0,1)(0, -1), which gives the equation y=2x1y = 2x - 1 in slope-intercept form.
3
Solve for aa by substituting the point (a,9)(a, 9) into the equation of line kk.
The value of aa is 55.
Substituting x=ax = a and y=9y = 9 into y=2x1y = 2x - 1 gives 9=2a19 = 2a - 1. Solving for aa yields 10=2a10 = 2a, or a=5a = 5.

Key Concept

Linear Functions and Graphs
Question 71Question

In the xyxy-plane, line l1l_1 passes through the origin and has a positive slope mm, where m>1m > 1. Line l2l_2 is perpendicular to line l1l_1 and has a yy-intercept of (0,10)(0, 10). The two lines intersect at point PP. If the distance from point PP to the yy-axis is 44, what is the value of mm?

Show answer & explanation

Answer: 2

Answer

2
The equation of line l1l_1 is y=mxy = mx and the equation of line l2l_2 is y=1mx+10y = -\frac{1}{m}x + 10. Setting these equal gives the xx-coordinate of their intersection as x=10mm2+1x = \frac{10m}{m^2 + 1}. Since the distance from the intersection point to the yy-axis is 44, we have 10mm2+1=4\frac{10m}{m^2 + 1} = 4. Solving this quadratic equation yields m=2m = 2 or m=12m = \frac{1}{2}. Given that m>1m > 1, the correct value is 22.

Step-by-Step Solution

1
Write the equations of lines l1l_1 and l2l_2.
Line l1l_1 has a slope of mm and passes through (0,0)(0,0), so its equation is y=mxy = mx. Line l2l_2 is perpendicular to l1l_1, so its slope is 1m-\frac{1}{m}. Since its yy-intercept is (0,10)(0,10), its equation is y=1mx+10y = -\frac{1}{m}x + 10.
Setting up the equations of the lines allows us to find their point of intersection.
2
Find the xx-coordinate of the intersection point PP.
Equating the two expressions for yy gives mx=1mx+10mx = -\frac{1}{m}x + 10. Multiplying both sides by mm yields m2x=x+10mm^2 x = -x + 10m, which simplifies to (m2+1)x=10m(m^2 + 1)x = 10m, or x=10mm2+1x = \frac{10m}{m^2 + 1}.
The intersection point PP must satisfy both equations simultaneously.
3
Solve for mm using the distance from PP to the yy-axis.
The distance from P(x,y)P(x,y) to the yy-axis is given by x|x|. Since m>1m > 1, xx is positive, so the distance is 10mm2+1=4\frac{10m}{m^2 + 1} = 4. This simplifies to 10m=4m2+410m = 4m^2 + 4, or 4m210m+4=04m^2 - 10m + 4 = 0. Dividing by 22 gives 2m25m+2=02m^2 - 5m + 2 = 0. Factoring the quadratic yields (2m1)(m2)=0(2m - 1)(m - 2) = 0, giving solutions of m=12m = \frac{1}{2} and m=2m = 2. Since m>1m > 1, the slope of l1l_1 must be 22.
Applying the given distance constraint and slope condition determines the unique value of mm.

Key Concept

The relationship between the equations of perpendicular lines and their point of intersection in the coordinate plane.
Question 72Question

If 3(2n+4)=423(2n + 4) = 42, what is the value of nn?

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Answer: 5

Answer

5
To solve the linear equation 3(2n+4)=423(2n + 4) = 42, first divide both sides of the equation by 3, which simplifies it to 2n+4=142n + 4 = 14. Next, subtract 4 from both sides of the equation to isolate the term with the variable, giving 2n=102n = 10. Finally, divide both sides of the equation by 2 to solve for the variable, which yields n=5n = 5.

Step-by-Step Solution

1
Divide both sides of the equation by 3.
2n+4=142n + 4 = 14
To simplify the equation by eliminating the outer constant multiplier.
2
Subtract 4 from both sides of the equation.
2n=102n = 10
To isolate the variable term on one side of the equation.
3
Divide both sides of the equation by 2.
n=5n = 5
To find the value of nn.

Key Concept

Solving a linear equation in one variable using inverse operations.
Estimated Time:45s
Question 73Question

In the xyxy-plane, the graph of the linear function ff is perpendicular to the line with equation y=2x7y = 2x - 7. If the region in the first quadrant bounded by the graph of ff, the xx-axis, and the yy-axis has an area of 3636, what is the xx-intercept of the graph of ff?

Show answer & explanation

Answer: 12

Answer

The xx-intercept of the graph of ff is 1212.
The correct answer is 1212. Since the graph of ff is perpendicular to the line y=2x7y = 2x - 7, its slope is 12-\frac{1}{2}. The equation of the line is f(x)=12x+bf(x) = -\frac{1}{2}x + b, which has a yy-intercept of (0,b)(0, b) and an xx-intercept of (2b,0)(2b, 0). In the first quadrant, these intercepts form a right triangle with the axes, having legs of length bb and 2b2b. The area of this triangle is 12(2b)(b)=b2\frac{1}{2}(2b)(b) = b^2. Setting the area equal to 3636 gives b2=36b^2 = 36, so b=6b = 6 (since b>0b > 0). The xx-intercept is 2b=2(6)=122b = 2(6) = 12.

Step-by-Step Solution

1
Find the slope of the perpendicular line ff.
The slope of ff is 12-\frac{1}{2}.
Perpendicular lines in the coordinate plane have slopes that are negative reciprocals of each other. The given line has a slope of 22, so the slope of ff must be 12-\frac{1}{2}.
2
Express the yy-intercept and xx-intercept of ff in terms of a single variable.
The yy-intercept is (0,b)(0, b) and the xx-intercept is (2b,0)(2b, 0), where b>0b > 0.
The equation of ff can be written as f(x)=12x+bf(x) = -\frac{1}{2}x + b. Setting x=0x = 0 gives the yy-intercept bb. Setting f(x)=0f(x) = 0 and solving for xx gives the xx-intercept 2b2b.
3
Set up the area equation for the triangle in the first quadrant.
The area is represented by b2=36b^2 = 36.
The region bounded by the graph of ff and the coordinate axes in the first quadrant forms a right triangle with perpendicular sides of lengths bb and 2b2b. The area of this triangle is 12×base×height=12×2b×b=b2\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2b \times b = b^2.
4
Solve for bb and calculate the xx-intercept.
The xx-intercept is 1212.
Solving b2=36b^2 = 36 with the condition b>0b > 0 yields b=6b = 6. The xx-intercept is 2b2b, which equals 2(6)=122(6) = 12.

Key Concept

Using perpendicular slopes and intercepts of linear functions to analyze geometric areas in the coordinate plane.
Estimated Time:2m 0s
Question 74Question

A commercial drone delivery service charges a flat rate of 15.5015.50 dollars per delivery plus a fuel surcharge of 1.801.80 dollars per mile. During a promotional event, the service offers a 20%20\% discount off the fuel surcharge only. If the total cost for a specific delivery during this promotion was 27.0227.02 dollars, how many miles did the drone travel for this delivery?

Show answer & explanation

Answer: 8

Answer

8
The correct answer is 8. The promotional fuel surcharge is reduced by 20%20\% from the normal 1.801.80 dollars per mile, resulting in a rate of 1.80×(10.20)=1.441.80 \times (1 - 0.20) = 1.44 dollars per mile. The linear equation modeling the total cost for a delivery of mm miles during the promotion is 15.50+1.44m=27.0215.50 + 1.44m = 27.02. Subtracting 15.5015.50 from both sides gives 1.44m=11.521.44m = 11.52. Dividing both sides by 1.441.44 yields the distance m=8m = 8 miles.

Step-by-Step Solution

1
Determine the discounted fuel surcharge per mile.
The discounted surcharge is 1.441.44 dollars per mile.
A 20%20\% discount is applied to the original 1.801.80 dollars per mile fuel surcharge: 1.80×(10.20)=1.441.80 \times (1 - 0.20) = 1.44.
2
Set up the linear equation representing the total promotional cost.
15.50+1.44m=27.0215.50 + 1.44m = 27.02, where mm represents the number of miles traveled.
The total cost is the sum of the flat rate of 15.5015.50 dollars and the promotional fuel surcharge of 1.441.44 dollars per mile multiplied by the number of miles.
3
Subtract the flat rate from both sides of the equation.
1.44m=11.521.44m = 11.52
To isolate the term with the variable mm, subtract the flat rate of 15.5015.50 from the total promotional cost of 27.0227.02.
4
Solve for the distance by division.
m=8m = 8
Divide both sides of the equation by the promotional rate per mile, 1.441.44, to find the number of miles.

Key Concept

Formulating and solving a multi-step linear equation in one variable with decimals and percentages to represent a real-world scenario.
Question 75Question

A local municipal water utility charges a flat monthly service fee plus a constant rate for each hundred cubic feet (HCF) of water consumed. During one month, a household that consumed 12 HCF of water was charged 46.00 dollars. Another household that consumed 18 HCF of water was charged 61.00 dollars. What is the flat monthly service fee, in dollars, charged by the utility?

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Answer: 16

Answer

The flat monthly service fee is 16 dollars.
By modeling the relationship as a linear function y=mx+by = mx + b, where xx is the consumption in HCF and yy is the total charge in dollars, we use the points (12,46)(12, 46) and (18,61)(18, 61) to find the slope m=61461812=2.5m = \frac{61 - 46}{18 - 12} = 2.5. Substituting m=2.5m = 2.5 and the point (12,46)(12, 46) back into the linear equation gives 46=2.5(12)+b46 = 2.5(12) + b, which simplifies to 46=30+b46 = 30 + b. Solving for bb gives 16, representing the flat service fee.

Step-by-Step Solution

1
Set up a system of points representing the linear relationship between water consumed and monthly charge.
Two coordinate points are established: (12,46)(12, 46) and (18,61)(18, 61), where the first coordinate is the consumption in HCF and the second is the charge in dollars.
Since the utility charges a flat fee plus a constant rate, the relationship is linear and can be solved using coordinate points.
2
Find the constant rate per HCF (the slope of the line).
The slope mm is calculated as 61461812=156=2.5\frac{61 - 46}{18 - 12} = \frac{15}{6} = 2.5 dollars per HCF.
The slope represents the constant rate of change in total cost per HCF of water consumed.
3
Determine the flat monthly service fee (the y-intercept of the line).
Using the slope-intercept equation y=mx+by = mx + b with point (12,46)(12, 46) and m=2.5m = 2.5 yields 46=2.5(12)+b    46=30+b    b=1646 = 2.5(12) + b \implies 46 = 30 + b \implies b = 16.
The y-intercept represents the cost when consumption is zero, which is the flat monthly service fee.

Key Concept

Finding the y-intercept of a linear function from two points.
Estimated Time:1m 30s
Question 76Question

A scientist is measuring the temperature of a sample that is being heated at a constant rate. At a starting time of 00 minutes, the temperature of the sample is 12C12^\circ\text{C}. After 88 minutes of heating, the temperature of the sample is 44C44^\circ\text{C}. If the temperature of the sample increases linearly with time, what is the temperature of the sample, in degrees Celsius, after 1515 minutes of heating?

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Answer: 72

Answer

72
The rate of temperature change is 441280=4C\frac{44 - 12}{8 - 0} = 4^\circ\text{C} per minute. Using the slope-intercept form, the temperature TT after tt minutes can be represented by the function T(t)=4t+12T(t) = 4t + 12. Substituting 1515 for tt yields T(15)=4(15)+12=60+12=72T(15) = 4(15) + 12 = 60 + 12 = 72.

Step-by-Step Solution

1
Calculate the constant rate of temperature change (slope).
4 degrees Celsius per minute
To find how much the temperature increases each minute, divide the total change in temperature by the total change in time: 441280=328=4\frac{44 - 12}{8 - 0} = \frac{32}{8} = 4.
2
Set up the linear function for temperature T(t)T(t) over time tt.
T(t)=4t+12T(t) = 4t + 12
The initial temperature at t=0t = 0 is 12C12^\circ\text{C}, which represents the vertical intercept. The constant rate of change is 4C4^\circ\text{C} per minute.
3
Find the temperature at t=15t = 15 minutes.
72
Substitute 1515 for tt in the equation: T(15)=4(15)+12=60+12=72T(15) = 4(15) + 12 = 60 + 12 = 72.

Key Concept

Linear Functions and Rates of Change
Estimated Time:1m 0s
Question 77Question

If 2x+7=152x + 7 = 15, what is the value of 4x34x - 3?

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Answer: 13

Answer

13
To find the value of the expression, first solve the linear equation for the variable. Subtracting 7 from both sides of the equation yields 2x=82x = 8. Dividing both sides of the equation by 2 yields x=4x = 4. Substituting this value back into the expression yields 4(4)3=163=134(4) - 3 = 16 - 3 = 13. Alternatively, since 2x=82x = 8, multiplying both sides by 2 gives 4x=164x = 16. Subtracting 3 from both sides of this relation yields 4x3=163=134x - 3 = 16 - 3 = 13.

Step-by-Step Solution

1
Subtract 7 from both sides of the equation
2x=82x = 8
To isolate the variable term on one side of the equation
2
Divide both sides by 2
x=4x = 4
To solve for the variable
3
Substitute the value of the variable into the target expression
1313
To find the final evaluated value requested by the question

Key Concept

Solving a linear equation in one variable and evaluating an expression
Question 78Question

A chemist mixes two saline solutions. Solution A is 12%12\% salt by mass, and Solution B is 30%30\% salt by mass. The mass of Solution B used in the mixture is 20 grams more than 13\frac{1}{3} of the mass of Solution A used. If the resulting mixture is 18%18\% salt by mass, what is the mass, in grams, of Solution A used?

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Answer: 120

Answer

The mass of Solution A used is 120 grams.
The correct answer is 120. By setting the mass of Solution A to xx, the mass of Solution B is 13x+20\frac{1}{3}x + 20. Equating the total salt content from both individual solutions to the total salt content of the final mixture gives the linear equation 0.12x+0.30(13x+20)=0.18(x+13x+20)0.12x + 0.30\left(\frac{1}{3}x + 20\right) = 0.18\left(x + \frac{1}{3}x + 20\right). Simplifying both sides yields 0.22x+6=0.24x+3.60.22x + 6 = 0.24x + 3.6. Solving this equation gives 0.02x=2.40.02x = 2.4, which simplifies to x=120x = 120.

Step-by-Step Solution

1
Define the variable xx as the mass, in grams, of Solution A used in the mixture, and express the mass of Solution B in terms of xx.
Mass of Solution A = xx grams; Mass of Solution B = 13x+20\frac{1}{3}x + 20 grams.
To set up expressions representing the mass of each solution in the mixture.
2
Calculate the mass of salt contributed by each solution and write an expression for the total mass of salt.
Salt from Solution A = 0.12x0.12x grams; Salt from Solution B = 0.30(13x+20)=0.10x+60.30\left(\frac{1}{3}x + 20\right) = 0.10x + 6 grams; Total salt = 0.22x+60.22x + 6 grams.
To find the total amount of salt before mixing.
3
Express the total mass of the mixture and the total salt content using the final mixture's percentage.
Total mass of mixture = 43x+20\frac{4}{3}x + 20 grams; Total salt in final mixture = 0.18(43x+20)=0.24x+3.60.18\left(\frac{4}{3}x + 20\right) = 0.24x + 3.6 grams.
To write the total salt content in terms of the final mixture's concentration.
4
Equate the two expressions for the total mass of salt and solve the linear equation for xx.
0.22x+6=0.24x+3.6    2.4=0.02x    x=1200.22x + 6 = 0.24x + 3.6 \implies 2.4 = 0.02x \implies x = 120.
To find the mass of Solution A that satisfies the mixture conditions.

Key Concept

Setting up and solving a linear equation in one variable from a mixture word problem.
Question 79Question

For the linear function ff, the table below displays selected values of xx and their corresponding function values f(x)f(x).

xxf(x)f(x)
2-211
2299
441313

What is the value of f(10)f(10)?

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Answer: 25

Answer

The value of f(10)f(10) is 25.
The correct answer is 25. By using the points (2,1)(-2, 1) and (2,9)(2, 9), the slope of the linear function is calculated as m=912(2)=2m = \frac{9 - 1}{2 - (-2)} = 2. Substituting this slope and the point (2,9)(2, 9) into the slope-intercept form, f(x)=2x+bf(x) = 2x + b, gives 9=2(2)+b9 = 2(2) + b, which resolves to b=5b = 5. Thus, the linear function is defined by f(x)=2x+5f(x) = 2x + 5. Evaluating the function at x=10x = 10 yields f(10)=2(10)+5=25f(10) = 2(10) + 5 = 25.

Step-by-Step Solution

1
Calculate the slope of the linear function using two coordinate pairs.
Slope m=2m = 2
The slope of a linear function can be determined by the formula m=f(x2)f(x1)x2x1m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}. Substituting (2,1)(-2, 1) and (2,9)(2, 9) yields m=912(2)=84=2m = \frac{9 - 1}{2 - (-2)} = \frac{8}{4} = 2.
2
Find the y-intercept of the function to write its equation.
f(x)=2x+5f(x) = 2x + 5
Substituting the slope m=2m = 2 and the point (2,9)(2, 9) into the slope-intercept form f(x)=mx+bf(x) = mx + b gives 9=2(2)+b9 = 2(2) + b, which simplifies to b=5b = 5.
3
Evaluate the function for the input value 10.
f(10)=25f(10) = 25
Substituting x=10x = 10 into the linear function equation f(x)=2x+5f(x) = 2x + 5 yields f(10)=2(10)+5=25f(10) = 2(10) + 5 = 25.

Key Concept

Determining a linear function from a table of values and using it to find specific outputs.
Estimated Time:1m 30s
Question 80Question

If 56(y2)13(2y5)=32\frac{5}{6}(y - 2) - \frac{1}{3}(2y - 5) = \frac{3}{2}, what is the value of 4y4y?

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Answer: 36

Answer

The correct answer is 36.
To solve the equation 56(y2)13(2y5)=32\frac{5}{6}(y - 2) - \frac{1}{3}(2y - 5) = \frac{3}{2}, we first clear the fractions by multiplying the entire equation by the least common denominator, 6, which yields 5(y2)2(2y5)=95(y - 2) - 2(2y - 5) = 9. Distributing the terms on the left side gives 5y104y+10=95y - 10 - 4y + 10 = 9. Combining like terms simplifies this to y=9y = 9. The question asks for the value of 4y4y, so we multiply 99 by 44 to get the final answer of 3636.

Step-by-Step Solution

1
Multiply both sides of the equation by the least common denominator, which is 6.
5(y2)2(2y5)=95(y - 2) - 2(2y - 5) = 9
Multiplying by 6 eliminates the fractions, simplifying the equation.
2
Distribute the coefficients across the parentheses.
5y104y+10=95y - 10 - 4y + 10 = 9
Expanding the terms allows like terms to be combined in the next step.
3
Combine the variable terms and constant terms on the left side of the equation.
y=9y = 9
Combining 5y4y5y - 4y yields yy, and combining 10+10-10 + 10 yields 00, isolating the variable.
4
Multiply the value of yy by 4.
4y=364y = 36
The question asks for the value of 4y4y rather than just yy.

Key Concept

Solving a linear equation in one variable by clearing fractions and combining like terms.
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