Unit Conversions

23 questions

Question 1Question

A laboratory dispensing pump releases a liquid solution at a constant rate of 0.75 deciliters per minute0.75\text{ deciliters per minute}. If 1 deciliter=100 milliliters1\text{ deciliter} = 100\text{ milliliters}, what is the pump's dispensing rate, in milliliters per second?

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Answer: 1.25

Answer

The correct answer is 1.25. The pump dispenses 1.25 milliliters per second.
To find the dispensing rate in milliliters per second, we first convert the volume from deciliters to milliliters. Multiplying 0.75 deciliters0.75\text{ deciliters} by 100 milliliters per deciliter100\text{ milliliters per deciliter} gives 75 milliliters per minute75\text{ milliliters per minute}. Next, to convert minutes to seconds, we divide the rate by 6060 (since 1 minute=60 seconds1\text{ minute} = 60\text{ seconds}), which yields 7560=1.25 milliliters per second\frac{75}{60} = 1.25\text{ milliliters per second}.

Step-by-Step Solution

1
Convert the dispensing rate from deciliters per minute to milliliters per minute using the conversion factor 1 deciliter=100 milliliters1\text{ deciliter} = 100\text{ milliliters}.
0.75 deciliters/minute×100 milliliters/deciliter=75 milliliters/minute0.75\text{ deciliters/minute} \times 100\text{ milliliters/deciliter} = 75\text{ milliliters/minute}
This converts the volume unit from deciliters to milliliters.
2
Convert the rate from milliliters per minute to milliliters per second by dividing by 6060, since there are 60 seconds60\text{ seconds} in 1 minute1\text{ minute}.
75 milliliters/minute÷60 seconds/minute=1.25 milliliters/second75\text{ milliliters/minute} \div 60\text{ seconds/minute} = 1.25\text{ milliliters/second}
This converts the time unit from minutes to seconds, yielding the final rate.

Key Concept

Unit Conversions

Alternative Method

Alternatively, you can convert the units in a single dimensional analysis step: 0.75 dL/min×100 mL1 dL×1 min60 s=7560 mL/s=1.25 mL/s0.75 \text{ dL/min} \times \frac{100 \text{ mL}}{1 \text{ dL}} \times \frac{1 \text{ min}}{60 \text{ s}} = \frac{75}{60} \text{ mL/s} = 1.25 \text{ mL/s}.
Estimated Time:1m 30s
Question 2Question

A toy train moves along a track at a constant rate of 1515 feet per second. What is the train's speed, in yards per second? (Given that 1 yard=3 feet1\text{ yard} = 3\text{ feet})

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Answer: 5

Answer

5
The correct answer is 5. To convert the speed from feet per second to yards per second, divide the rate of 1515 feet per second by the conversion factor of 33 feet per yard. This yields 55 yards per second.

Step-by-Step Solution

1
Identify the given rate and the conversion factor.
The given rate is 15 feet per second15\text{ feet per second}, and the conversion factor is 1 yard=3 feet1\text{ yard} = 3\text{ feet}.
This establishes the relationship between the current unit (feet) and the target unit (yards).
2
Convert the speed by dividing by the conversion factor.
15 feet1 second×1 yard3 feet=5 yards per second\frac{15\text{ feet}}{1\text{ second}} \times \frac{1\text{ yard}}{3\text{ feet}} = 5\text{ yards per second}.
Dividing the speed in feet per second by 3 converts the distance unit from feet to yards, resulting in the correct rate of 5 yards per second.

Key Concept

Unit Conversions
Estimated Time:45s
Question 3Question

A garden hose discharges water at a constant rate of 88 quarts per minute. What is this rate, in gallons per hour? (Given that 1 gallon=4 quarts1\text{ gallon} = 4\text{ quarts})

Show answer & explanation

Answer: 120

Answer

120
To convert the discharge rate from quarts per minute to gallons per hour, we first convert quarts to gallons. Since 1 gallon=4 quarts1\text{ gallon} = 4\text{ quarts}, we divide the rate of 88 quarts per minute by 44 to get 22 gallons per minute. Next, to convert minutes to hours, we multiply this rate by 6060 (since there are 6060 minutes in 1 hour1\text{ hour}). This gives 2×60=1202 \times 60 = 120 gallons per hour.

Step-by-Step Solution

1
Convert quarts per minute to gallons per minute
22 gallons per minute
Since 1 gallon=4 quarts1\text{ gallon} = 4\text{ quarts}, divide the flow rate of 88 quarts per minute by the conversion factor of 44 to find the rate in gallons per minute: 8 quarts/min4 quarts/gallon=2 gallons/min\frac{8\text{ quarts/min}}{4\text{ quarts/gallon}} = 2\text{ gallons/min}.
2
Convert gallons per minute to gallons per hour
120120 gallons per hour
Since there are 6060 minutes in an hour, multiply the rate of 22 gallons per minute by 6060 to find the total gallons discharged in one hour: 2 gallons/min×60 min/hour=120 gallons/hour2\text{ gallons/min} \times 60\text{ min/hour} = 120\text{ gallons/hour}.

Key Concept

Unit Conversions
Question 4Question

A 3D printer extrudes plastic filament at a constant rate of 88 millimeters per second. What is this rate, in meters per hour?

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Answer: 28.828.8

Answer

The rate is 28.828.8 meters per hour.
To convert the rate from millimeters per second to meters per hour, we apply the unit conversion factors. We convert millimeters to meters by dividing by 10001000, and convert seconds to hours by multiplying by 36003600. This gives: 8 mm/s×1 m1000 mm×3600 s1 hour=8×3.6=28.8 meters per hour8\text{ mm/s} \times \frac{1\text{ m}}{1000\text{ mm}} \times \frac{3600\text{ s}}{1\text{ hour}} = 8 \times 3.6 = 28.8\text{ meters per hour}.

Step-by-Step Solution

1
Convert the length unit from millimeters to meters.
Since 1 meter=1000 millimeters1\text{ meter} = 1000\text{ millimeters}, a rate of 8 millimeters per second8\text{ millimeters per second} is equal to 81000=0.008 meters per second\frac{8}{1000} = 0.008\text{ meters per second}.
To convert from a smaller unit (millimeters) to a larger unit (meters), divide by the conversion factor of 10001000.
2
Convert the time unit from seconds to hours.
Since 1 hour=3600 seconds1\text{ hour} = 3600\text{ seconds}, a rate of 0.008 meters per second0.008\text{ meters per second} is equal to 0.008×3600=28.8 meters per hour0.008 \times 3600 = 28.8\text{ meters per hour}.
To find the distance printed in one hour, multiply the distance printed in one second by the number of seconds in one hour (36003600).

Key Concept

Unit Conversions

Alternative Method

We can combine the conversion steps into a single conversion factor: 3600 seconds/hour1000 millimeters/meter=3.6 (meters \cdotseconds) / (millimeters \cdothour)\frac{3600\text{ seconds/hour}}{1000\text{ millimeters/meter}} = 3.6\text{ (meters \cdot seconds) / (millimeters \cdot hour)}. Multiplying the rate of 8 mm/s8\text{ mm/s} by 3.63.6 gives the rate directly as 28.8 m/h28.8\text{ m/h}.
Estimated Time:1m 0s
Question 5Question

A bakery recipe requires 1212 ounces of butter to make one batch of bread. How many pounds of butter are needed to make 88 batches of bread? (Given that 1 pound=16 ounces1\text{ pound} = 16\text{ ounces})

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Answer: 6

Answer

The bakery needs 66 pounds of butter.
The total amount of butter needed for 88 batches is calculated by multiplying the butter required for one batch by the number of batches: 8×12=968 \times 12 = 96 ounces. Given that 1 pound=16 ounces1\text{ pound} = 16\text{ ounces}, we convert ounces to pounds by dividing the total ounces by 1616. Therefore, 96÷16=696 \div 16 = 6 pounds of butter are needed.

Step-by-Step Solution

1
Calculate the total ounces of butter needed.
9696 ounces
Since each batch requires 1212 ounces, 88 batches require 8×12=968 \times 12 = 96 ounces.
2
Convert the total ounces to pounds.
66 pounds
Divide the total number of ounces by the conversion factor (1616 ounces per pound): 9616=6\frac{96}{16} = 6.

Key Concept

To convert a quantity from a smaller unit to a larger unit, multiply the initial quantity by the number of groups to find the total in the smaller unit, and then divide by the conversion factor that relates the two units.
Question 6Question

An agricultural drone sprays liquid fertilizer at a rate of 1.51.5 fluid ounces per square yard. The drone travels at a constant speed of 4.54.5 miles per hour, spraying a continuous path that is exactly 66 feet wide. Which of the following is closest to the rate at which the drone sprays the fertilizer, in gallons per minute? (Given that 1 mile=5,280 feet1\text{ mile} = 5,280\text{ feet}, 1 yard=3 feet1\text{ yard} = 3\text{ feet}, and 1 gallon=128 fluid ounces1\text{ gallon} = 128\text{ fluid ounces})

Show answer & explanation

Answer: 3.09

Answer

The rate of 3.093.09 gallons per minute is closest to the drone's fertilizer spraying rate.
The correct answer is 3.093.09 because converting the speed of 4.54.5 miles per hour gives 396396 feet per minute. Multiplying this by the width of 66 feet results in 2,3762,376 square feet per minute. Dividing this by 99 converts the rate to 264264 square yards per minute. Multiplying by the spray density of 1.51.5 fluid ounces per square yard gives 396396 fluid ounces per minute. Finally, dividing by 128128 fluid ounces per gallon yields approximately 3.093.09 gallons per minute.

Step-by-Step Solution

1
Convert the speed of the drone from miles per hour to feet per minute.
4.5 miles/hour=396 feet/minute4.5\text{ miles/hour} = 396\text{ feet/minute}
To find the rate of area covered per minute, the speed must first be expressed in feet per minute. Multiply 4.54.5 by 5,2805,280 to convert to feet per hour, then divide by 6060 to convert to feet per minute: 4.5×5,28060=396\frac{4.5 \times 5,280}{60} = 396.
2
Calculate the area covered by the drone per minute in square feet.
396 feet/minute×6 feet=2,376 square feet/minute396\text{ feet/minute} \times 6\text{ feet} = 2,376\text{ square feet/minute}
Multiplying the travel speed in feet per minute by the path width of 66 feet gives the area covered per minute in square feet.
3
Convert the area rate from square feet per minute to square yards per minute.
2,376 square feet/minute÷9=264 square yards/minute2,376\text{ square feet/minute} \div 9 = 264\text{ square yards/minute}
Since 1 yard=3 feet1\text{ yard} = 3\text{ feet}, a square yard is 3×3=93 \times 3 = 9 square feet. Therefore, divide the area in square feet by 99 to convert to square yards.
4
Determine the fertilizer spray rate in fluid ounces per minute.
264 square yards/minute×1.5 fluid ounces/square yard=396 fluid ounces/minute264\text{ square yards/minute} \times 1.5\text{ fluid ounces/square yard} = 396\text{ fluid ounces/minute}
Multiplying the area covered per minute by the spray density yields the volume of fertilizer sprayed per minute.
5
Convert the spray rate from fluid ounces per minute to gallons per minute.
396 fluid ounces/minute÷1283.09 gallons/minute396\text{ fluid ounces/minute} \div 128 \approx 3.09\text{ gallons/minute}
Since 1 gallon=128 fluid ounces1\text{ gallon} = 128\text{ fluid ounces}, divide the fluid ounces per minute by 128128 to find the rate in gallons per minute.

Key Concept

Unit conversions involving compound rates and area scaling.
Estimated Time:3m 0s
Question 7Question

During a science experiment, a liquid is cooled at a constant rate of 0.50.5 degrees Celsius per minute. What is the cooling rate of the liquid, in degrees Celsius per hour?

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Answer: 30

Answer

The cooling rate of the liquid is 3030 degrees Celsius per hour.
To find the cooling rate in degrees Celsius per hour, we multiply the rate per minute by the conversion factor. There are 6060 minutes in 11 hour. Multiplying 0.50.5 degrees Celsius per minute by 6060 minutes per hour yields 3030 degrees Celsius per hour.

Step-by-Step Solution

1
Identify the initial cooling rate per minute.
0.50.5 degrees Celsius per minute
This is the rate given in the problem statement.
2
Convert minutes to hours by multiplying the rate by 6060.
3030 degrees Celsius per hour
An hour contains 6060 minutes, so the total temperature decrease in one hour will be 6060 times the decrease in one minute.

Key Concept

Unit conversions involving rates
Question 8Question

A deep space satellite transmits data to a ground station at a constant rate of 1.61.6 megabits per second. The transmitted data consists of actual scientific data and protocol overhead. The protocol overhead accounts for 25%25\% of the total transmitted bits, meaning the actual scientific data constitutes only 75%75\% of the total transmitted bits. The ground station needs to receive 55 scientific data files, each with a size of 1.081.08 gigabytes. How many hours will it take to transmit all 55 files? (Given that 1textbyte=8textbits1\\text{ byte} = 8\\text{ bits}, 1textmegabit=106textbits1\\text{ megabit} = 10^6\\text{ bits}, and 1textgigabyte=109textbytes1\\text{ gigabyte} = 10^9\\text{ bytes}.)

Show answer & explanation

Answer: 10

Answer

It will take 10 hours to transmit all 5 files.
The correct answer is 10. To find this, first calculate the total size of the scientific files: 5 files * 1.08 gigabytes per file = 5.4 gigabytes. Convert this to bytes: 5.4 * 10^9 bytes. Convert bytes to bits: 5.4 * 10^9 * 8 = 43.2 * 10^9 bits. Since protocol overhead is 25%, the scientific data is 75% of the total transmitted bits, so the total bits transmitted is 43.2 * 10^9 / 0.75 = 57.6 * 10^9 bits. The transmission rate is 1.6 megabits per second, or 1.6 * 10^6 bits per second. The transmission time in seconds is 57.6 * 10^9 / (1.6 * 10^6) = 36,000 seconds. Converting seconds to hours: 36,000 / 3,600 = 10 hours.

Step-by-Step Solution

1
Calculate the total size of the scientific files in gigabytes.
5.45.4 gigabytes
To find the total amount of scientific data that must be received.
2
Convert the total scientific data size from gigabytes to bytes and then to bits.
43.2times10943.2 \\times 10^9 bits
The transmission rate is given in megabits per second, so the data size must be converted to bits for unit consistency. Since 1textGB=109textbytes1\\text{ GB} = 10^9\\text{ bytes} and 1textbyte=8textbits1\\text{ byte} = 8\\text{ bits}, we have 5.4times109times8=43.2times1095.4 \\times 10^9 \\times 8 = 43.2 \\times 10^9 bits.
3
Calculate the total number of bits transmitted, including protocol overhead.
57.6times10957.6 \\times 10^9 bits
Since protocol overhead is 25%25\%, the scientific data is only 75%75\% of the total bits transmitted. Thus, we divide the scientific bits by 0.750.75 to find the total bits transmitted: frac43.2times1090.75=57.6times109\\frac{43.2 \\times 10^9}{0.75} = 57.6 \\times 10^9 bits.
4
Calculate the transmission time in seconds.
36,00036,000 seconds
Divide the total bits by the transmission rate in bits per second (1.6textMbps=1.6times1061.6\\text{ Mbps} = 1.6 \\times 10^6 bits per second): frac57.6times1091.6times106=36,000\\frac{57.6 \\times 10^9}{1.6 \\times 10^6} = 36,000 seconds.
5
Convert the transmission time from seconds to hours.
1010 hours
Since there are 3,6003,600 seconds in one hour, divide the total seconds by 3,6003,600: frac36,0003,600=10\\frac{36,000}{3,600} = 10.

Key Concept

Multi-step dimensional analysis and compound rate conversions incorporating percentage overhead

Alternative Method

Instead of converting units step-by-step, dimensional analysis can be set up as a single product of conversion factors: 5 files * (1.08 GB / 1 file) * (10^9 bytes / 1 GB) * (8 bits / 1 byte) * (1 total bit / 0.75 scientific bits) * (1 second / 1.6 * 10^6 bits) * (1 hour / 3600 seconds) = 10 hours.
Estimated Time:3m 0s
Question 9Question

An industrial printing press uses ink at a constant rate of 0.050.05 milliliters per square centimeter of printed paper. The press prints a continuous roll of paper that is 4040 centimeters wide at a constant speed of 22 meters per second. At this rate, how many liters of ink does the press use during 11 hour of continuous printing?

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Answer: 1440

Answer

1440
The correct answer is 1440. First, convert the speed of the paper from meters per second to centimeters per second: 2 m/s×100 cm/m=200 cm/s2 \text{ m/s} \times 100 \text{ cm/m} = 200 \text{ cm/s}. Next, find the rate at which the paper surface area is printed: 40 cm×200 cm/s=8,000 cm2/s40 \text{ cm} \times 200 \text{ cm/s} = 8,000 \text{ cm}^2/\text{s}. Multiply this by the ink usage rate to find milliliters of ink per second: 8,000 cm2/s×0.05 mL/cm2=400 mL/s8,000 \text{ cm}^2/\text{s} \times 0.05 \text{ mL/cm}^2 = 400 \text{ mL/s}. Since there are 3,6003,600 seconds in 11 hour, the press uses 400 mL/s×3,600 s=1,440,000 mL400 \text{ mL/s} \times 3,600 \text{ s} = 1,440,000 \text{ mL} of ink per hour. Finally, convert milliliters to liters: 1,440,000 mL÷1,000 mL/L=1,4401,440,000 \text{ mL} \div 1,000 \text{ mL/L} = 1,440 liters.

Step-by-Step Solution

1
Convert the speed of the paper from meters per second to centimeters per second.
200 cm/s200 \text{ cm/s}
To align the speed unit with the paper width unit (40 cm40 \text{ cm}).
2
Calculate the surface area of paper printed per second.
8,000 cm2/s8,000 \text{ cm}^2/\text{s}
Multiply the width of the paper (40 cm40 \text{ cm}) by the converted speed (200 cm/s200 \text{ cm/s}).
3
Calculate the volume of ink used per second in milliliters.
400 mL/s400 \text{ mL/s}
Multiply the area printed per second (8,000 cm2/s8,000 \text{ cm}^2/\text{s}) by the ink consumption rate (0.05 mL/cm20.05 \text{ mL/cm}^2).
4
Convert the ink volume rate from per second to per hour.
1,440,000 mL/h1,440,000 \text{ mL/h}
Multiply the rate per second by 3,6003,600, since there are 3,6003,600 seconds in 11 hour.
5
Convert the final volume from milliliters to liters.
1440
Divide the total milliliters (1,440,0001,440,000) by 1,0001,000, since 11 liter is equal to 1,0001,000 milliliters.

Key Concept

Multi-step dimensional analysis and compound unit conversion (length, area, volume, and time).
Question 10Question

A solar power station consists of solar panels that generate electricity at a constant rate of 15 watts15\text{ watts} per square foot of panel surface area (where 1 watt=1 joule per second1\text{ watt} = 1\text{ joule per second}). The panels have a total surface area of 12,000 square yards12,000\text{ square yards}. How many megajoules (MJ) of energy do the panels generate in 2 hours2\text{ hours}? (Given that 1 yard=3 feet1\text{ yard} = 3\text{ feet} and 1 MJ=1,000,000 joules1\text{ MJ} = 1,000,000\text{ joules})

Show answer & explanation

Answer: 11,66411,664

Answer

The solar panels generate 11,66411,664 megajoules of energy in 2 hours2\text{ hours}.
To find the energy generated, first convert the area from square yards to square feet. Since 1 yard=3 feet1\text{ yard} = 3\text{ feet}, 1 square yard=(3 feet)2=9 square feet1\text{ square yard} = (3\text{ feet})^2 = 9\text{ square feet}. Multiplying 12,000 square yards12,000\text{ square yards} by 99 gives 108,000 square feet108,000\text{ square feet}. The power generated is 108,000 square feet×15 watts/square foot=1,620,000 watts108,000\text{ square feet} \times 15\text{ watts/square foot} = 1,620,000\text{ watts}, which is 1,620,000 joules per second1,620,000\text{ joules per second}. In 2 hours2\text{ hours}, which is 2×3,600=7,200 seconds2 \times 3,600 = 7,200\text{ seconds}, the total energy generated is 1,620,000 joules/second×7,200 seconds=11,664,000,000 joules1,620,000\text{ joules/second} \times 7,200\text{ seconds} = 11,664,000,000\text{ joules}. Since 1 MJ=1,000,000 joules1\text{ MJ} = 1,000,000\text{ joules}, this is equivalent to 11,664 MJ11,664\text{ MJ}.

Step-by-Step Solution

1
Convert the surface area of the solar panels from square yards to square feet.
Since 1 yard=3 feet1\text{ yard} = 3\text{ feet}, 1 square yard=32=9 square feet1\text{ square yard} = 3^2 = 9\text{ square feet}. Therefore, the total area in square feet is 12,000×9=108,000 square feet12,000 \times 9 = 108,000\text{ square feet}.
To apply the generation rate given in watts per square foot, the area must be in square feet.
2
Determine the total rate of energy generation in joules per second.
The total power generated is 108,000 square feet×15 watts per square foot=1,620,000 watts108,000\text{ square feet} \times 15\text{ watts per square foot} = 1,620,000\text{ watts}. Since 1 watt=1 joule per second1\text{ watt} = 1\text{ joule per second}, this equals 1,620,000 joules per second1,620,000\text{ joules per second}.
This calculates the total energy produced by the entire solar farm every second.
3
Convert the total time from hours to seconds.
2 hours×60 minutes/hour×60 seconds/minute=7,200 seconds2\text{ hours} \times 60\text{ minutes/hour} \times 60\text{ seconds/minute} = 7,200\text{ seconds}.
To find the total energy generated, the rate (joules per second) must be multiplied by the duration in seconds.
4
Calculate the total energy generated in joules, then convert it to megajoules (MJ).
Total energy in joules is 1,620,000 joules/second×7,200 seconds=11,664,000,000 joules1,620,000\text{ joules/second} \times 7,200\text{ seconds} = 11,664,000,000\text{ joules}. Converting to megajoules: 11,664,000,000 joules÷1,000,000 joules/MJ=11,664 MJ11,664,000,000\text{ joules} \div 1,000,000\text{ joules/MJ} = 11,664\text{ MJ}.
This yields the final quantity of energy in the requested units.

Key Concept

Multi-step unit conversions involving area scaling, compound rates, and time conversions.
Estimated Time:2m 30s
Question 11Question

A manufacturing plant uses a machine lubricant at a constant rate of 0.080.08 fluid ounces per second of operation. The plant operates the machinery for 88 hours per day, 55 days a week. The lubricant is purchased in drums, where each drum contains 1515 gallons of lubricant. How many drums of lubricant does the plant use in a period of 55 weeks? (Note: 1 gallon=128 fluid ounces1\text{ gallon} = 128\text{ fluid ounces})

Show answer & explanation

Answer: 30

Answer

The plant uses 30 drums of lubricant in 5 weeks.
To find the number of drums, calculate the total seconds of operation: 5 weeks * 5 days/week * 8 hours/day * 3,600 seconds/hour = 720,000 seconds. Multiply this by the consumption rate of 0.08 fluid ounces/second to get 57,600 fluid ounces. Convert this to gallons by dividing by 128 fluid ounces/gallon to get 450 gallons. Finally, divide by 15 gallons/drum to find that 30 drums are used.

Step-by-Step Solution

1
Calculate the total number of operational seconds in the 5-week period.
720000 seconds720{}000\text{ seconds}
Multiply 5 weeks by 5 days per week, 8 hours per day, and 3,600 seconds per hour: 5×5×8×3600=7200005 \times 5 \times 8 \times 3{}600 = 720{}000.
2
Calculate the total volume of lubricant used in fluid ounces.
57600 fluid ounces57{}600\text{ fluid ounces}
Multiply the rate of 0.08 fluid ounces per second0.08\text{ fluid ounces per second} by the total operational seconds: 720000×0.08=57600720{}000 \times 0.08 = 57{}600.
3
Convert the total fluid ounces to gallons.
450 gallons450\text{ gallons}
Divide the total fluid ounces by the conversion factor of 128 fluid ounces per gallon128\text{ fluid ounces per gallon}: 57600/128=45057{}600 / 128 = 450.
4
Calculate the total number of drums needed.
30 drums30\text{ drums}
Divide the total gallons by the capacity of a single drum (15 gallons15\text{ gallons}): 450/15=30450 / 15 = 30.

Key Concept

Multi-step dimensional analysis and unit conversion under compound rates
Question 12Question

A cargo ship travels at a constant speed of 24 knots24\text{ knots}. The ship's engine consumes fuel at a constant rate of 23 liters per minute23\text{ liters per minute}. The fuel has a density of 0.80 grams per milliliter0.80\text{ grams per milliliter}. Given that 1 knot=1.15 miles per hour1\text{ knot} = 1.15\text{ miles per hour} and 1 metric ton=1,000 kilograms1\text{ metric ton} = 1,000\text{ kilograms}, what is the ship's fuel consumption rate in metric tons per mile?

Show answer & explanation

Answer: 0.04

Answer

0.04
The correct answer is obtained by first converting the ship's speed to miles per hour (24×1.15=27.6 mph24 \times 1.15 = 27.6\text{ mph}). Next, the fuel usage is converted to liters per hour (23×60=1,380 L/hr23 \times 60 = 1,380\text{ L/hr}). Using the density conversion where 0.80 g/mL0.80\text{ g/mL} is equal to 0.80 kg/L0.80\text{ kg/L}, the fuel consumption is converted to mass (1,380×0.80=1,104 kg/hr1,380 \times 0.80 = 1,104\text{ kg/hr}), which is equivalent to 1.1041.104 metric tons per hour. Finally, dividing the fuel rate by the speed gives the rate per mile: 1.104/27.6=0.041.104 / 27.6 = 0.04 metric tons per mile.

Step-by-Step Solution

1
Convert the speed of the cargo ship from knots to miles per hour.
24 knots×1.15 miles per hour per knot=27.6 miles per hour24\text{ knots} \times 1.15\text{ miles per hour per knot} = 27.6\text{ miles per hour}
To match the final unit of miles, we convert knots to miles per hour.
2
Convert the fuel consumption rate from liters per minute to liters per hour.
23 liters/minute×60 minutes/hour=1,380 liters/hour23\text{ liters/minute} \times 60\text{ minutes/hour} = 1,380\text{ liters/hour}
Since speed is in miles per hour, we convert the fuel consumption to a per-hour rate.
3
Convert the volume consumption rate to a mass consumption rate using the density.
1,380 liters/hour×0.80 kilograms/liter=1,104 kilograms/hour1,380\text{ liters/hour} \times 0.80\text{ kilograms/liter} = 1,104\text{ kilograms/hour}
Density of 0.80 g/mL0.80\text{ g/mL} is equivalent to 0.80 kg/L0.80\text{ kg/L} because there are 1,0001,000 grams in a kilogram and 1,0001,000 milliliters in a liter.
4
Convert the mass rate from kilograms per hour to metric tons per hour.
1,104 kilograms/hour1,000 kilograms/metric ton=1.104 metric tons/hour\frac{1,104\text{ kilograms/hour}}{1,000\text{ kilograms/metric ton}} = 1.104\text{ metric tons/hour}
To match the final unit of metric tons, we divide the kilograms by 1,0001,000.
5
Calculate the fuel consumption rate in metric tons per mile by dividing the hourly fuel consumption by the hourly speed.
1.104 metric tons/hour27.6 miles/hour=0.04 metric tons/mile\frac{1.104\text{ metric tons/hour}}{27.6\text{ miles/hour}} = 0.04\text{ metric tons/mile}
Dividing the rate of fuel consumed per hour by the distance traveled per hour gives the fuel consumed per mile.

Key Concept

Unit conversions with compound rates and density scaling
Estimated Time:2m 30s
Question 13Question

An industrial water filtration system filters water at a constant rate of 0.5 liters per second0.5\text{ liters per second}. The system consumes a chemical powder at a rate of 2.5 milligrams2.5\text{ milligrams} per gram of impurities removed from the water. If the water contains an average of 0.12 grams0.12\text{ grams} of impurities per liter, how many grams of the chemical powder does the system consume during 4 hours4\text{ hours} of continuous operation?

Show answer & explanation

Answer: 2.16

Answer

The system consumes 2.16 grams2.16\text{ grams} of chemical powder during the 44 hours of operation.
The correct answer is 2.162.16. First, convert the 44 hours of continuous operation into seconds: 4×3,600=14,4004 \times 3,600 = 14,400 seconds. Next, multiply this duration by the filtration rate to find the total water filtered: 14,400×0.5=7,20014,400 \times 0.5 = 7,200 liters. Multiply the volume by the impurity concentration to find the total mass of impurities: 7,200×0.12=8647,200 \times 0.12 = 864 grams. Then, find the mass of chemical powder consumed: 864×2.5=2,160864 \times 2.5 = 2,160 milligrams. Finally, convert milligrams to grams by dividing by 1,0001,000, resulting in 2.162.16 grams.

Step-by-Step Solution

1
Convert the operating time from hours to seconds.
14,400 seconds14,400\text{ seconds}
Since the filtration rate is given in liters per second, the total operating time must be converted from hours to seconds to align units. There are 3,6003,600 seconds in one hour.
2
Calculate the total volume of water filtered during the operation.
7,200 liters7,200\text{ liters}
Multiply the operating time in seconds by the filtration rate of 0.50.5 liters per second.
3
Calculate the total mass of impurities removed from the filtered water.
864 grams864\text{ grams}
Multiply the total volume of filtered water by the concentration rate of 0.120.12 grams of impurities per liter.
4
Determine the mass of chemical powder consumed in milligrams.
2,160 milligrams2,160\text{ milligrams}
Multiply the total mass of impurities in grams by the consumption rate of 2.52.5 milligrams of chemical powder per gram of impurities.
5
Convert the mass of chemical powder from milligrams to grams.
2.16 grams2.16\text{ grams}
Divide the mass in milligrams by 1,0001,000 because there are 1,0001,000 milligrams in one gram.

Key Concept

Dimensional analysis and multi-step unit conversion involving rates
Question 14Question

A 3D printer uses a plastic filament at a constant rate of 2.5 grams2.5\text{ grams} per minute of printing time. The filament has a density of 1.25 grams per cubic centimeter1.25\text{ grams per cubic centimeter}. If the printer runs continuously for 4 hours4\text{ hours}, what is the total volume, in cubic centimeters, of the filament used?

Show answer & explanation

Answer: 480

Answer

480
The correct answer is 480. First, convert the printing time from hours to minutes: 4 hours multiplied by 60 minutes per hour equals 240 minutes. Next, calculate the total mass of the filament used by multiplying the printing time by the usage rate: 240 minutes multiplied by 2.5 grams per minute equals 600 grams. Finally, convert the mass to volume by dividing the mass by the density: 600 grams divided by 1.25 grams per cubic centimeter equals 480 cubic centimeters.

Step-by-Step Solution

1
Convert the printing time from hours to minutes.
240 minutes240\text{ minutes}
Since the filament consumption rate is given in grams per minute, the total time must be in minutes. Multiplying 4 hours4\text{ hours} by 60 minutes per hour60\text{ minutes per hour} yields 240 minutes240\text{ minutes}.
2
Calculate the total mass of the filament used.
600 grams600\text{ grams}
Multiplying the total printing time of 240 minutes240\text{ minutes} by the consumption rate of 2.5 grams per minute2.5\text{ grams per minute} gives a total mass of 600 grams600\text{ grams}.
3
Calculate the total volume of the filament used.
480 cubic centimeters480\text{ cubic centimeters}
Divide the total mass of 600 grams600\text{ grams} by the density of 1.25 grams per cubic centimeter1.25\text{ grams per cubic centimeter} to find the volume: 6001.25=480 cubic centimeters\frac{600}{1.25} = 480\text{ cubic centimeters}.

Key Concept

Multi-unit dimensional analysis involving rates, time, and density.
Question 15Question

An electric vehicle consumes 0.350.35 kilowatt-hours (kWh\text{kWh}) of electricity per mile traveled. The vehicle travels at a constant speed of 4848 miles per hour. What is the vehicle's rate of electricity consumption, in kWh\text{kWh} per minute?

Show answer & explanation

Answer: 0.28

Answer

0.28
To find the rate of electricity consumption in kilowatt-hours (kWh\text{kWh}) per minute, we must convert the given rate of 0.35 kWh0.35\text{ kWh} per mile into kWh\text{kWh} per minute. First, convert the speed of 48 miles per hour48\text{ miles per hour} to miles per minute: 48 miles60 minutes=0.8 miles per minute\frac{48\text{ miles}}{60\text{ minutes}} = 0.8\text{ miles per minute}. Next, multiply the energy consumed per mile by the distance traveled per minute: 0.35 kWh per mile×0.8 miles per minute=0.28 kWh per minute0.35\text{ kWh per mile} \times 0.8\text{ miles per minute} = 0.28\text{ kWh per minute}. Therefore, the vehicle's rate of electricity consumption is 0.28 kWh0.28\text{ kWh} per minute.

Step-by-Step Solution

1
Convert the vehicle's speed from miles per hour to miles per minute.
0.80.8 miles per minute
Since there are 60 minutes in 1 hour, dividing the speed in miles per hour by 60 gives the speed in miles per minute: 48 miles1 hour×1 hour60 minutes=0.8 miles per minute\frac{48\text{ miles}}{1\text{ hour}} \times \frac{1\text{ hour}}{60\text{ minutes}} = 0.8\text{ miles per minute}.
2
Calculate the rate of electricity consumption in kWh per minute.
0.280.28 kWh per minute
Multiply the consumption rate per mile by the distance traveled per minute: 0.35 kWh per mile×0.8 miles per minute=0.28 kWh per minute0.35\text{ kWh per mile} \times 0.8\text{ miles per minute} = 0.28\text{ kWh per minute}.

Key Concept

Unit conversion involving rates and compound units.

Alternative Method

First, find the total electricity consumed in one hour of driving by multiplying the consumption rate per mile by the miles traveled in one hour: 0.35 kWh per mile×48 miles=16.8 kWh0.35\text{ kWh per mile} \times 48\text{ miles} = 16.8\text{ kWh}. Then, convert this hourly rate to a minute rate by dividing by 60 minutes: 16.8 kWh60 minutes=0.28 kWh per minute\frac{16.8\text{ kWh}}{60\text{ minutes}} = 0.28\text{ kWh per minute}.
Estimated Time:1m 15s
Question 16Question

An aquarium filter recirculates water at a constant rate of 250250 milliliters per second. The filter cartridge must be replaced after it has processed a total of 540540 cubic meters of water. For how many hours of continuous operation can the filter run before the cartridge must be replaced? (1 cubic meter=1,000 liters1\text{ cubic meter} = 1,000\text{ liters})

Show answer & explanation

Answer: 600

Answer

The filter can run for 600600 hours of continuous operation before the cartridge must be replaced.
To find the number of hours the filter can run, we first convert the flow rate to cubic meters per hour. The flow rate of 250250 milliliters per second is equal to 0.250.25 liters per second. Multiplying by 3,6003,600 seconds per hour gives a flow rate of 900900 liters per hour. Since 1 cubic meter=1,000 liters1\text{ cubic meter} = 1,000\text{ liters}, 900900 liters per hour is equivalent to 0.90.9 cubic meters per hour. Finally, dividing the total capacity of 540540 cubic meters by the flow rate of 0.90.9 cubic meters per hour yields a duration of 600600 hours.

Step-by-Step Solution

1
Convert the water recirculating rate from milliliters per second to liters per second.
0.250.25 liters per second
To express the flow rate in terms of liters before converting to cubic meters.
2
Convert the rate from liters per second to liters per hour.
900900 liters per hour
To align the time unit of the rate with the requested time unit (hours).
3
Convert the rate from liters per hour to cubic meters per hour.
0.90.9 cubic meters per hour
To match the volume unit of the filter cartridge capacity (cubic meters).
4
Divide the total cartridge capacity by the hourly flow rate of the filter.
600600 hours
To find the total duration of continuous operation before replacement.

Key Concept

Unit Conversions
Question 17Question

A wind turbine generates electricity at a constant rate of 1.5 megawatt-hours (MWh)1.5\text{ megawatt-hours (MWh)} per day. If 1 megawatt-hour1\text{ megawatt-hour} is equivalent to 3.6 gigajoules (GJ)3.6\text{ gigajoules (GJ)}, how many gigajoules of energy does the wind turbine generate in 8 hours8\text{ hours}?

Show answer & explanation

Answer: 1.8

Answer

1.8
The correct answer is 1.8. To find the total energy generated in gigajoules over 8 hours, the daily rate of 1.5 MWh1.5\text{ MWh} is first converted to an hourly rate by dividing by 24 hours, yielding 0.0625 MWh0.0625\text{ MWh} per hour. Multiplying this rate by 8 hours results in 0.5 MWh0.5\text{ MWh} of energy generated. Finally, multiplying the energy in MWh by the conversion factor of 3.6 GJ3.6\text{ GJ} per MWh yields 1.8 GJ1.8\text{ GJ}.

Step-by-Step Solution

1
Convert the daily generation rate of 1.5 MWh1.5\text{ MWh} to an hourly generation rate by dividing by 24 hours.
0.0625 MWh per hour0.0625\text{ MWh per hour}
Since there are 24 hours in a day, dividing the daily rate by 24 yields the rate of energy generated per hour.
2
Multiply the hourly generation rate by 8 hours to find the total energy generated in megawatt-hours.
0.5 MWh0.5\text{ MWh}
Multiplying the rate per hour by the duration of 8 hours gives the cumulative energy generated over that period.
3
Convert the energy generated from megawatt-hours to gigajoules by multiplying by the conversion factor of 3.6 GJ3.6\text{ GJ} per MWh.
1.8 GJ1.8\text{ GJ}
Multiplying the energy in MWh by 3.6 GJ/MWh3.6\text{ GJ/MWh} converts the unit to gigajoules.

Key Concept

Unit Conversions
Question 18Question

An agricultural drone sprays a liquid fertilizer at a constant rate of 120120 milliliters per second. The drone flies at a constant speed, covering 1.51.5 hectares per hour. If the drone operates continuously at this rate, how many liters of fertilizer are sprayed per hectare?

(Note: 11 liter = 1,0001,000 milliliters)

Show answer & explanation

Answer: 288

Answer

The drone sprays 288 liters of fertilizer per hectare.
To find the number of liters sprayed per hectare, the rate of spraying must be converted from milliliters per second to liters per hour, and then divided by the coverage rate of hectares per hour. First, multiply the spray rate of 120120 milliliters per second by the number of seconds in an hour (3,6003,600 seconds) to find that the drone sprays 432,000432,000 milliliters per hour. Next, convert this volume to liters by dividing by 1,0001,000 milliliters per liter, which gives 432432 liters per hour. Finally, divide this hourly spray volume by the coverage rate of 1.51.5 hectares per hour to obtain 288288 liters per hectare.

Step-by-Step Solution

1
Calculate the volume of fertilizer sprayed in one hour in milliliters.
120 mL/s×3,600 s/h=432,000 mL/h120\text{ mL/s} \times 3,600\text{ s/h} = 432,000\text{ mL/h}
There are 3,6003,600 seconds in one hour, so multiplying the per-second rate by 3,6003,600 gives the volume sprayed per hour.
2
Convert the hourly volume from milliliters to liters.
432,000 mL/h1,000 mL/L=432 L/h\frac{432,000\text{ mL/h}}{1,000\text{ mL/L}} = 432\text{ L/h}
Since 11 liter is equivalent to 1,0001,000 milliliters, divide the volume in milliliters by 1,0001,000 to get the volume in liters.
3
Calculate the volume of fertilizer sprayed per hectare.
432 L/h1.5 hectares/h=288 L/hectare\frac{432\text{ L/h}}{1.5\text{ hectares/h}} = 288\text{ L/hectare}
Divide the total liters sprayed in one hour by the total hectares covered in that same hour to find the rate per hectare.

Key Concept

Unit conversion involving compound rates of volume, time, and area.
Question 19Question

A paper mill machine produces paper at a constant rate of 2424 square feet per second. If 1 square yard=9 square feet1\text{ square yard} = 9\text{ square feet}, how many square yards of paper does the machine produce in 1515 minutes?

Show answer & explanation

Answer: 2,400

Answer

2,400
The correct answer of 2,400 is found by first converting the time of 15 minutes to seconds: 15×60=90015 \times 60 = 900 seconds. Next, calculate the total area produced in square feet by multiplying the production rate by the time: 24×900=21,60024 \times 900 = 21,600 square feet. Finally, convert this area to square yards by dividing by 9: 21,600/9=2,40021,600 / 9 = 2,400 square yards.

Step-by-Step Solution

1
Convert the time from minutes to seconds.
15 minutes×60 seconds/minute=900 seconds15\text{ minutes} \times 60\text{ seconds/minute} = 900\text{ seconds}
The production rate is given in square feet per second, so the time duration must be in seconds.
2
Calculate the total area of paper produced in square feet.
24 square feet/second×900 seconds=21,600 square feet24\text{ square feet/second} \times 900\text{ seconds} = 21,600\text{ square feet}
Multiplying the rate by the total time gives the total amount produced in square feet.
3
Convert the total area from square feet to square yards.
21,600 square feet÷9 square feet/square yard=2,400 square yards21,600\text{ square feet} \div 9\text{ square feet/square yard} = 2,400\text{ square yards}
Since 1 square yard=9 square feet1\text{ square yard} = 9\text{ square feet}, dividing the total square feet by 9 converts the value to square yards.

Key Concept

Multi-step unit conversions involving rates of change and area scaling.
Question 20Question

A specialized laser cutter cuts steel sheet metal at a constant rate of 1818 inches per minute. At this rate, how many seconds does it take the laser cutter to cut a length of 66 feet of steel? (1 foot=12 inches1\text{ foot} = 12\text{ inches})

Show answer & explanation

Answer: 240

Answer

The correct answer is 240.
To find the number of seconds it takes the laser cutter to cut 66 feet of steel, we first convert the length to inches: 6 feet×12 inches/foot=72 inches6\text{ feet} \times 12\text{ inches/foot} = 72\text{ inches}. Next, we divide this length by the cutting rate to find the duration in minutes: 72 inches÷18 inches/minute=4 minutes72\text{ inches} \div 18\text{ inches/minute} = 4\text{ minutes}. Finally, we convert the minutes into seconds: $4\text{ minutes} \times 60\text{ seconds/minute} = 240\text{ seconds}.

Step-by-Step Solution

1
Convert the total cutting distance from feet to inches.
72 inches72\text{ inches}
Since the rate is given in inches per minute, we must convert the length from feet to inches to align the units. Knowing that 1 foot=12 inches1\text{ foot} = 12\text{ inches}, we multiply 66 by 1212.
2
Calculate the time in minutes to cut 72 inches72\text{ inches} at a rate of 18 inches/minute18\text{ inches/minute}.
4 minutes4\text{ minutes}
Dividing the total distance (72 inches72\text{ inches}) by the cutting rate (18 inches/minute18\text{ inches/minute}) yields the time in minutes.
3
Convert the time from minutes to seconds.
240 seconds240\text{ seconds}
Since 1 minute=60 seconds1\text{ minute} = 60\text{ seconds}, multiplying 44 minutes by 6060 gives the final time in seconds.

Key Concept

Performing multi-step unit conversions using rate and dimensional analysis.
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