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Difficulty: Very hardCoding and Decoding

In a certain code language, the word 'CRAFT' is coded as 'UGZSD' and the word 'BELONG' is coded as 'IPLNVD'. Based on the same logic, which of the following represents the correct code for the word 'TRUMPET'?

  1. VVROFTVAnswer
  2. B
    VTFORVV
  3. C
    VEROUTV
  4. D
    UVQNFSU

Answer

VVROFTV
The correct answer 'VVROFTV' is obtained by recognizing that 'TRUMPET' contains 22 vowels ('U' and 'E'). Each consonant (T, R, M, P, T) is shifted forward by +2+2 positions, while each vowel is replaced by its reverse alphabetical counterpart (U →\rightarrow F, E →\rightarrow V), resulting in 'VTFORVV'. Reversing this string produces 'VVROFTV'.

Step-by-Step Solution

1
Analyze the coding rules using the given examples 'CRAFT' and 'BELONG'
Rule 1: Count the number of vowels in the given word (e.g., 'CRAFT' has 11 vowel; 'BELONG' has 22 vowels).
Rule 2: Each consonant is shifted forward in the English alphabet by NN positions, where NN is the total count of vowels in that word.
Rule 3: Each vowel is replaced by its reverse alphabetical letter (where A↔ZA \leftrightarrow Z, B↔YB \leftrightarrow Y, etc., such that reverse position = 27−forward position27 - \text{forward position}).
Rule 4: The transformed sequence of letters is reversed from back to front.
Establishing the precise multi-step rule set explains both sample transformations.
2
Count vowels in the target word 'TRUMPET'
The word 'TRUMPET' contains 22 vowels ('U' and 'E'). Thus, for all consonants, N=2N = 2.
Determines the exact shift value needed for consonant transformations.
3
Apply transformations to each letter of 'TRUMPET'
• T (Consonant): 20+2=22→V20 + 2 = 22 \rightarrow V
• R (Consonant): 18+2=20→T18 + 2 = 20 \rightarrow T
• U (Vowel): 27−21=6→F27 - 21 = 6 \rightarrow F
• M (Consonant): 13+2=15→O13 + 2 = 15 \rightarrow O
• P (Consonant): 16+2=18→R16 + 2 = 18 \rightarrow R
• E (Vowel): 27−5=22→V27 - 5 = 22 \rightarrow V
• T (Consonant): 20+2=22→V20 + 2 = 22 \rightarrow V
Transformed string: VTFORVV
Executes positional shifts for consonants and reverse indexing for vowels.
4
Reverse the transformed letter string
Reversing 'VTFORVV' yields 'VVROFTV'.
Completes the final step of the coding algorithm.

Key Concept

Multi-Rule Alphanumeric and Reverse Alphabetical Coding
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Topics

Coding and Decoding

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