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Difficulty: HardAnalogy and Classification
In a certain pattern of letter series analogy, the letter-group MASTER\text{MASTER} is coded as IVGHZN\text{IVGHZN}. Following the same two-step structural logic, which of the following letter-groups will replace the question mark (??) in the analogy below?
MASTER:IVGHZN::PRACTICE:?\text{MASTER} : \text{IVGHZN} :: \text{PRACTICE} : ?
  1. A
    \text{KIZGXRXV}
  2. \text{VXGRZXIK}Answer
  3. C
    \text{FDJUDBSQ}
  4. D
    \text{UWQFWYHJ}

Answer

The correct letter-group that completes the analogy is \text{VXGRZXIK}.
The term \text{VXGRZXIK} correctly satisfies both operations governing the analogy: reversing the letter order of \text{PRACTICE} to get \text{ECITCARP}, and replacing each letter with its opposite alphabet partner (27−position27 - \text{position}).

Step-by-Step Solution

1
Analyze the relationship between the first pair, \text{MASTER} and \text{IVGHZN}.
First, reversing the order of letters in \text{MASTER} gives \text{R E T S A M}. Next, replacing each letter with its reverse-alphabet complement (where position pp becomes 27−p27 - p) yields: R(18)→I(9)\text{R}(18) \rightarrow \text{I}(9), E(5)→V(22)\text{E}(5) \rightarrow \text{V}(22), T(20)→G(7)\text{T}(20) \rightarrow \text{G}(7), S(19)→H(8)\text{S}(19) \rightarrow \text{H}(8), A(1)→Z(26)\text{A}(1) \rightarrow \text{Z}(26), and M(13)→N(14)\text{M}(13) \rightarrow \text{N}(14), resulting in \text{IVGHZN}.
This establishes the complete two-step rule: reverse word order, then convert each letter to its mirror alphabet pair.
2
Apply Step 1 of the rule (reversing the sequence) to the target word \text{PRACTICE}.
Reversing \text{PRACTICE} yields the letter sequence: \text{E C I T C A R P}.
Word reversal must be executed prior to applying positional shifts or letter substitutions.
3
Apply Step 2 of the rule (mirror letter substitution) to \text{E C I T C A R P}.
Converting each letter using 27−p27 - p:
- E(5)→27−5=22=V\text{E} (5) \rightarrow 27 - 5 = 22 = \text{V}
- C(3)→27−3=24=X\text{C} (3) \rightarrow 27 - 3 = 24 = \text{X}
- I(9)→27−9=18=R\text{I} (9) \rightarrow 27 - 9 = 18 = \text{R}
- T(20)→27−20=7=G\text{T} (20) \rightarrow 27 - 20 = 7 = \text{G}
- C(3)→27−3=24=X\text{C} (3) \rightarrow 27 - 3 = 24 = \text{X}
- A(1)→27−1=26=Z\text{A} (1) \rightarrow 27 - 1 = 26 = \text{Z}
- R(18)→27−18=9=I\text{R} (18) \rightarrow 27 - 18 = 9 = \text{I}
- P(16)→27−16=11=K\text{P} (16) \rightarrow 27 - 16 = 11 = \text{K}
Combining these yields \text{VXGRZXIK}.
Substituting every reversed character with its exact reverse-alphabet pair completes the logical transformation.

Key Concept

Multi-step letter analogy involving word reversal and reverse-alphabet complement mapping.
Estimated Time:1m 30s
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Topics

Analogy and Classification

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