Question

Difficulty: HardInterpreting Laboratory Results

A hospital ward team is evaluating a 74-year-old female who was admitted three days ago for an acute exacerbation of chronic systolic heart failure. Since admission, she has received continuous intravenous bumetanide. Over the past 24 hours, her urine output has significantly decreased, and routine morning laboratory studies reveal an acute rise in her serum creatinine from a baseline of 1.1 mg/dL1.1 \text{ mg/dL}.

The following laboratory values are obtained:

ParameterValue
Serum sodium136 mEq/L136 \text{ mEq/L}
Serum potassium3.8 mEq/L3.8 \text{ mEq/L}
Serum chloride98 mEq/L98 \text{ mEq/L}
Blood urea nitrogen (BUN)72 mg/dL72 \text{ mg/dL}
Serum creatinine2.4 mg/dL2.4 \text{ mg/dL}
Urine sodium45 mEq/L45 \text{ mEq/L}
Urine creatinine60 mg/dL60 \text{ mg/dL}
Urine urea nitrogen450 mg/dL450 \text{ mg/dL}

Due to the confounding effect of ongoing loop diuretic therapy, the standard fractional excretion of sodium (FENa) may be misleading. The attending physician asks for the calculation of the most appropriate alternative diagnostic index to differentiate between prerenal azotemia and intrinsic acute tubular necrosis in this specific clinical context.

What is the value of this alternative index (expressed as a percentage)?

Answer: 25 %

Answer

25
The correct answer is 25. The patient has acute kidney injury in the setting of active loop diuretic therapy (bumetanide), which makes the fractional excretion of sodium (FENa) unreliable. The most appropriate alternative index is the fractional excretion of urea (FEUrea). Using the formula FEUrea=Urine Urea×Serum CrSerum BUN×Urine Cr×100\text{FE}_{\text{Urea}} = \frac{\text{Urine Urea} \times \text{Serum Cr}}{\text{Serum BUN} \times \text{Urine Cr}} \times 100, the calculation is 450×2.472×60×100=25%\frac{450 \times 2.4}{72 \times 60} \times 100 = 25\%.

Step-by-Step Solution

1
Determine the appropriate diagnostic index for acute kidney injury in a patient on active loop diuretic therapy.
The fractional excretion of urea (FEUrea) should be used instead of the fractional excretion of sodium (FENa).
Loop diuretics inhibit sodium reabsorption in the thick ascending limb, which falsely elevates urinary sodium excretion and FENa, rendering it unreliable for differentiating prerenal azotemia from acute tubular necrosis.
2
Recall the formula for the fractional excretion of urea.
FEUrea=Urine Urea×Serum CrSerum Urea×Urine Cr×100\text{FE}_{\text{Urea}} = \frac{\text{Urine Urea} \times \text{Serum Cr}}{\text{Serum Urea} \times \text{Urine Cr}} \times 100
This formula calculates the clearance of urea relative to the clearance of creatinine.
3
Insert the provided laboratory values into the formula.
FEUrea=450×2.472×60×100\text{FE}_{\text{Urea}} = \frac{450 \times 2.4}{72 \times 60} \times 100
Substituting urine urea nitrogen (450 mg/dL450 \text{ mg/dL}), serum creatinine (2.4 mg/dL2.4 \text{ mg/dL}), BUN/serum urea (72 mg/dL72 \text{ mg/dL}), and urine creatinine (60 mg/dL60 \text{ mg/dL}).
4
Perform the final arithmetic calculation.
10804320×100=0.25×100=25%\frac{1080}{4320} \times 100 = 0.25 \times 100 = 25\%
This yields the final percentage required by the question, correctly pointing to a prerenal etiology (value < 35%).

Key Concept

In patients receiving diuretic therapy, the fractional excretion of urea (FEUrea) is the most accurate diagnostic index to differentiate prerenal azotemia from acute tubular necrosis. A value less than 35% indicates a prerenal etiology.
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