Question

Difficulty: HardInterpreting Laboratory Results

A 45-year-old man is brought to the emergency department after being rescued from a remote hiking trail. He was lost for two days without access to food or water. On presentation, he is lethargic and confused. Vital signs show a temperature of 37.8∘C37.8^\circ\text{C} (100.0∘F100.0^\circ\text{F}), pulse of 118/min118/\text{min}, blood pressure of 92/58 mmHg92/58\text{ mmHg}, and respiratory rate of 16/min16/\text{min}. Physical examination reveals dry mucous membranes, decreased skin turgor, and delayed capillary refill. His estimated premorbid weight is 70 kg70\text{ kg}.

Initial laboratory evaluation reveals the following:

TestResultReference Range
Serum Sodium154 mEq/L154\text{ mEq/L}136−145 mEq/L136-145\text{ mEq/L}
Serum Potassium4.1 mEq/L4.1\text{ mEq/L}3.5−5.0 mEq/L3.5-5.0\text{ mEq/L}
Serum Chloride118 mEq/L118\text{ mEq/L}95−105 mEq/L95-105\text{ mEq/L}
Serum Bicarbonate25 mEq/L25\text{ mEq/L}22−28 mEq/L22-28\text{ mEq/L}
Blood Urea Nitrogen50 mg/dL50\text{ mg/dL}7−18 mg/dL7-18\text{ mg/dL}
Serum Creatinine1.9 mg/dL1.9\text{ mg/dL}0.6−1.2 mg/dL0.6-1.2\text{ mg/dL}
Serum Glucose98 mg/dL98\text{ mg/dL}70−110 mg/dL70-110\text{ mg/dL}

Based on the patient's presentation and laboratory results, what is his estimated free water deficit in liters? (Assume a target normal serum sodium of 140 mEq/L140\text{ mEq/L}.)

Answer: 4.2 Liters

Answer

4.2
The patient is experiencing severe hypovolemic hypernatremia due to unreplaced sensible and insensible free water losses in the setting of environmental exposure. To properly direct intravenous fluid resuscitation (typically with 5%5\% dextrose in water or enteral free water), the free water deficit must be calculated. The standard formula is: Free Water Deficit=TBW×(Measured Na+Target Na+−1)\text{Free Water Deficit} = \text{TBW} \times \left( \frac{\text{Measured } Na^+}{\text{Target } Na^+} - 1 \right). First, calculate Total Body Water (TBW), which is approximately 60%60\% (0.60.6) of lean body weight in a young or middle-aged adult male. TBW=0.6×70 kg=42 L\text{TBW} = 0.6 \times 70\text{ kg} = 42\text{ L}. Next, insert the measured sodium (154 mEq/L154\text{ mEq/L}) and the target normal sodium (140 mEq/L140\text{ mEq/L}) into the formula: 42×(154140−1)=42×(1.1−1)=42×0.1=4.2 Liters42 \times \left(\frac{154}{140} - 1\right) = 42 \times (1.1 - 1) = 42 \times 0.1 = 4.2\text{ Liters}.

Step-by-Step Solution

1
Determine the patient's estimated Total Body Water (TBW).
For an adult male, TBW=0.6×body weight (kg)\text{TBW} = 0.6 \times \text{body weight (kg)}. Therefore, 0.6×70 kg=42 L0.6 \times 70\text{ kg} = 42\text{ L}.
Free water deficit calculations rely on the patient's total body water, which varies by sex and age (0.60.6 for adult men, 0.50.5 for adult women and elderly men, 0.450.45 for elderly women).
2
Calculate the ratio of measured serum sodium to the target normal serum sodium.
154 mEq/L140 mEq/L=1.1\frac{154\text{ mEq/L}}{140\text{ mEq/L}} = 1.1.
This ratio determines the proportional deficit of free water relative to the body's solute concentration.
3
Apply the free water deficit formula.
Deficit=TBW×(1.1−1)=42×0.1=4.2 Liters\text{Deficit} = \text{TBW} \times (1.1 - 1) = 42 \times 0.1 = 4.2\text{ Liters}.
Multiplying the TBW by the excess sodium fraction yields the absolute volume of free water that has been lost.

Key Concept

Calculating free water deficit in hypernatremia
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