Question

Difficulty: HardInterpreting Laboratory Results

A 32-year-old woman is evaluated in the emergency department for sudden-onset severe shortness of breath and right-sided chest pain that worsens with deep inspiration. She recently returned from a 14-hour international flight. Her medical history is unremarkable, and her only medication is an oral contraceptive pill. On physical examination, her lungs are clear to auscultation bilaterally. Her right calf is mildly swollen and tender.

Vital signs:
Temperature: 37.1∘C37.1^\circ\text{C} (98.8∘F98.8^\circ\text{F})
Blood pressure: 118/74 mmHg118/74\text{ mmHg}
Pulse: 115/min115/\text{min}
Respiratory rate: 26/min26/\text{min}

An arterial blood gas is obtained while the patient is breathing room air at sea level:
pH: 7.527.52
PaCO2PaCO_2: 28 mmHg28\text{ mmHg}
PaO2PaO_2: 56 mmHg56\text{ mmHg}
HCO3−HCO_3^-: 22 mEq/L22\text{ mEq/L}

To further evaluate the pathophysiology of her hypoxemia, the physician decides to calculate the alveolar-arterial (A-a) oxygen gradient. Assume the partial pressure of inspired oxygen (PiO2PiO_2) is 150 mmHg150\text{ mmHg} and the respiratory quotient (R) is 0.80.8.

Based on the laboratory results, what is the patient's calculated A-a gradient?

Answer: 59 mmHg

Answer

59
The correct calculation of the A-a gradient requires two steps. First, the alveolar oxygen tension (PAO2P_AO_2) is determined using the alveolar gas equation: PAO2=PiO2−PaCO2RP_AO_2 = PiO_2 - \frac{PaCO_2}{R}. Given a PiO2PiO_2 of 150 mmHg150\text{ mmHg} and an R of 0.80.8, the equation becomes 150−280.8=150−35=115 mmHg150 - \frac{28}{0.8} = 150 - 35 = 115\text{ mmHg}. Second, the measured arterial oxygen tension (PaO2P_aO_2 of 56 mmHg56\text{ mmHg}) is subtracted from the calculated PAO2P_AO_2. Thus, 115−56=59 mmHg115 - 56 = 59\text{ mmHg}. This significantly elevated A-a gradient, combined with the clinical presentation of sudden-onset pleuritic chest pain, tachypnea, and a swollen right calf following prolonged immobilization, is highly indicative of a pulmonary embolism causing ventilation-perfusion (V/Q) mismatch.

Step-by-Step Solution

1
Calculate the partial pressure of oxygen in the alveoli (PAO2P_AO_2).
PAO2=115 mmHgP_AO_2 = 115\text{ mmHg}
The alveolar gas equation estimates PAO2P_AO_2 as PiO2−PaCO2RPiO_2 - \frac{PaCO_2}{R}. Substituting the given values: PAO2=150−280.8=150−35=115 mmHgP_AO_2 = 150 - \frac{28}{0.8} = 150 - 35 = 115\text{ mmHg}.
2
Calculate the alveolar-arterial (A-a) oxygen gradient.
59 mmHg59\text{ mmHg}
The A-a gradient is the difference between the alveolar and arterial oxygen tensions (PAO2−PaO2P_AO_2 - P_aO_2). Substituting the calculated and measured values: 115−56=59 mmHg115 - 56 = 59\text{ mmHg}.

Key Concept

The alveolar-arterial (A-a) oxygen gradient helps differentiate causes of hypoxemia; an elevated gradient (> 10-15 mmHg in young adults) in the setting of respiratory alkalosis strongly suggests ventilation-perfusion (V/Q) mismatch, commonly seen in pulmonary embolism.
Estimated Time:1m 30s
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