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Question 1541Question →

A 64-year-old man is evaluated in the intensive care unit for a progressive decline in urine output. Three days ago, he underwent an emergent exploratory laparotomy for a perforated duodenal ulcer. His postoperative course was complicated by hypotension requiring vasopressor support for 24 hours, but he is currently hemodynamically stable. His urine output over the last 8 hours has been 120 mL.

Laboratory studies are obtained and reveal the following:

Serum chemistry
Sodium: 140140 mEq/L
Potassium: 4.84.8 mEq/L
Chloride: 105105 mEq/L
Bicarbonate: 2020 mEq/L
BUN: 4242 mg/dL
Creatinine: 2.02.0 mg/dL (baseline was 0.90.9 mg/dL)

Urine studies
Sodium: 7070 mEq/L
Creatinine: 5050 mg/dL
Osmolality: 310310 mOsm/kg H2OH_2O

Based on these laboratory results, what is the patient's fractional excretion of sodium (FENa)? Give your answer as a percentage.

Show answer & explanation

Answer: 2

Answer

2.0
The correct calculation for the fractional excretion of sodium (FENa) uses the formula: (UNa×PCr)/(PNa×UCr)×100(U_{Na} \times P_{Cr}) / (P_{Na} \times U_{Cr}) \times 100. Plugging in the patient's values gives (70×2.0)/(140×50)×100=140/7000×100=2.0%(70 \times 2.0) / (140 \times 50) \times 100 = 140 / 7000 \times 100 = 2.0\%. A FENa of 2.0%2.0\% or greater in this clinical context (recent prolonged hypotension leading to ischemic injury) strongly suggests acute tubular necrosis (ATN).

Step-by-Step Solution

1
Recall the formula for calculating the fractional excretion of sodium (FENa).
FENa=UNa×PCrPNa×UCr×100FENa = \frac{U_{Na} \times P_{Cr}}{P_{Na} \times U_{Cr}} \times 100
FENa is a key clinical index utilized to determine if acute kidney injury is prerenal or secondary to intrinsic renal disease, such as acute tubular necrosis.
2
Identify the relevant serum and urine values from the laboratory results.
Urine sodium (UNaU_{Na}) = 7070 mEq/L; Serum creatinine (PCrP_{Cr}) = 2.02.0 mg/dL; Serum sodium (PNaP_{Na}) = 140140 mEq/L; Urine creatinine (UCrU_{Cr}) = 5050 mg/dL.
These specific variables are necessary to accurately complete the calculation.
3
Substitute the extracted values into the formula.
FENa=70×2.0140×50×100FENa = \frac{70 \times 2.0}{140 \times 50} \times 100
Preparing the mathematical equation for simplification.
4
Calculate the products in the numerator and the denominator.
Numerator (70×2.070 \times 2.0) = 140140. Denominator (140×50140 \times 50) = 70007000.
Simplifying the equation to a single fraction.
5
Divide the numerator by the denominator and multiply by 100100 to obtain the final percentage.
140/7000=0.02140 / 7000 = 0.02. Multiplying by 100100 yields 2.0%2.0\%.
Generates the final FENa percentage.

Key Concept

The fractional excretion of sodium (FENa) is calculated using the formula (UNa×PCr)/(PNa×UCr)×100(U_{Na} \times P_{Cr}) / (P_{Na} \times U_{Cr}) \times 100. It is a vital laboratory calculation used to distinguish between prerenal azotemia (typically <1%<1\%) and intrinsic renal disease like acute tubular necrosis (typically >2%>2\%).
Question 1542Question →

A 28-year-old woman is evaluated in the outpatient clinic for a 6-month history of amenorrhea and bilateral nipple discharge. She also reports increasing fatigue, constipation, and an 8-kg8\text{-kg} (17.6-lb17.6\text{-lb}) weight gain over this period. Her only medication is a daily multivitamin. Vital signs are temperature 36.2∘C36.2^\circ\text{C} (97.2∘F97.2^\circ\text{F}), blood pressure 112/74 mm Hg112/74\text{ mm Hg}, pulse 54/min54\text{/min}, and respiratory rate 12/min12\text{/min}. Physical examination reveals a delayed relaxation phase of the deep tendon reflexes. A milky discharge can be easily expressed from both breasts.

Laboratory studies show the following:

TestResultReference Range
Serum β\beta-hCG<2 mIU/mL<2\text{ mIU/mL}<5 mIU/mL<5\text{ mIU/mL}
Serum prolactin82 ng/mL82\text{ ng/mL}4−23 ng/mL4-23\text{ ng/mL}
Serum thyroid-stimulating hormone (TSH)22.4 \muU/mL22.4\text{ \mu U/mL}0.4−4.0 \muU/mL0.4-4.0\text{ \mu U/mL}
Serum free thyroxine (T4)0.4 ng/dL0.4\text{ ng/dL}0.9−1.7 ng/dL0.9-1.7\text{ ng/dL}

Based on the provided laboratory results, which of the following mechanisms is most likely responsible for this patient's elevated prolactin level?

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Answer: Stimulation of lactotrophs by a hypothalamic releasing hormone

Answer

The correct answer is stimulation of lactotrophs by a hypothalamic releasing hormone (specifically, thyrotropin-releasing hormone), which is elevated due to primary hypothyroidism.
The correct answer identifies the physiologic pleiotropy of thyrotropin-releasing hormone (TRH). The patient's laboratory results demonstrate primary hypothyroidism (low free T4, high TSH). In primary hypothyroidism, the failure of the thyroid gland leads to a lack of negative feedback from peripheral thyroid hormones. This causes the hypothalamus to increase its production and secretion of TRH. TRH acts on the anterior pituitary gland, where it serves as a potent stimulatory factor for two distinct cell types: thyrotrophs (to secrete TSH) and lactotrophs (to secrete prolactin). The resulting TRH-induced hyperprolactinemia commonly presents with amenorrhea and galactorrhea. Normalizing the thyroid function with levothyroxine will suppress TRH and resolve the hyperprolactinemia.

Step-by-Step Solution

1
Analyze the thyroid laboratory panel in the context of the clinical presentation.
The patient has a significantly elevated TSH and low free T4, confirming a diagnosis of primary hypothyroidism, which explains her fatigue, bradycardia, weight gain, and delayed reflexes.
Establishing the primary diagnosis is necessary before interpreting secondary laboratory abnormalities.
2
Evaluate the secondary laboratory abnormalities and reproductive symptoms.
The patient has moderate hyperprolactinemia with a negative pregnancy test, which accounts for her amenorrhea and galactorrhea.
Identifying all abnormal values ensures a comprehensive diagnostic synthesis.
3
Connect the primary endocrine disorder to the secondary laboratory finding via pathophysiology.
In primary hypothyroidism, the lack of circulating T3 and T4 removes negative feedback on the hypothalamus, resulting in increased secretion of thyrotropin-releasing hormone (TRH). TRH physiologically stimulates the anterior pituitary to secrete both TSH and prolactin.
This establishes TRH-mediated lactotroph stimulation as the single underlying mechanism explaining the entire laboratory panel.

Key Concept

Primary hypothyroidism can cause secondary hyperprolactinemia because the resulting lack of negative feedback increases hypothalamic production of thyrotropin-releasing hormone (TRH), which physiologically stimulates both thyrotrophs (TSH) and lactotrophs (prolactin).
Question 1543Question →

A 3838-year-old woman is evaluated in the clinic for episodes of severe palpitations, pounding headaches, and profuse sweating. These episodes occur unexpectedly, last for 1515 to 2020 minutes, and resolve spontaneously. She has had four such episodes over the past month. During a recent episode, she was evaluated at an urgent care center where her blood pressure was 185/110 mmHg185/110\text{ mmHg} and her heart rate was 115/min115\text{/min}. Today, she feels well. Her blood pressure is 122/78 mmHg122/78\text{ mmHg} and heart rate is 72/min72\text{/min}. The physical examination is unremarkable. Which of the following is the most appropriate next step in laboratory evaluation?

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Answer: Measurement of plasma free metanephrines

Answer

The most appropriate next step in laboratory evaluation is the measurement of plasma free metanephrines.
The correct answer identifies the need for highly sensitive biochemical screening as the first step in diagnosing a suspected pheochromocytoma. This patient's episodic severe hypertension, accompanied by the classic triad of headache, sweating, and palpitations, strongly suggests this diagnosis. Measurement of plasma free metanephrines is highly sensitive and is the preferred initial laboratory evaluation.

Step-by-Step Solution

1
Analyze the patient's clinical presentation.
The patient presents with the classic triad of episodic headaches, sweating, and tachycardia (palpitations), accompanied by paroxysmal severe hypertension.
Identifying the classic clinical pattern is essential for formulating an accurate differential diagnosis.
2
Formulate the most likely diagnosis.
The clinical picture is highly suspicious for a pheochromocytoma, a catecholamine-secreting tumor of the adrenal medulla.
Pheochromocytomas release catecholamines episodically, leading to the paroxysmal symptoms described.
3
Determine the appropriate diagnostic sequence for the suspected condition.
The initial step is biochemical confirmation of catecholamine excess using a highly sensitive screening test.
Biochemical testing must precede imaging to confirm the diagnosis and prevent the discovery of incidental, non-functioning adrenal masses.
4
Select the best initial laboratory test.
Measurement of plasma free metanephrines or 24-hour urine fractionated metanephrines is the test of choice.
These tests have the highest sensitivity for detecting a pheochromocytoma.

Key Concept

The initial evaluation of a suspected pheochromocytoma requires biochemical confirmation of catecholamine excess, most commonly through the measurement of plasma free metanephrines, prior to any localizing imaging studies.
Estimated Time:1m 15s
Question 1544Question →

A 52-year-old woman is brought to the emergency department by her husband due to altered mental status and confusion. She has a history of type 2 diabetes mellitus and severe chronic osteoarthritis of the knees, for which she takes multiple over-the-counter analgesics. For the past three days, the patient has experienced severe nausea, tinnitus, and intractable nonbilious vomiting.

Vital signs show a temperature of 38.2°C (100.8°F), pulse of 118/min, blood pressure of 105/65 mm Hg, and respiratory rate of 26/min. Physical examination reveals dry mucous membranes, diffuse mild abdominal tenderness, and tachypnea with clear lungs bilaterally.

Laboratory results are as follows:

TestResultReference Range
Sodium142 mEq/L136-145 mEq/L
Potassium3.1 mEq/L3.5-5.0 mEq/L
Chloride92 mEq/L98-106 mEq/L
Bicarbonate14 mEq/L22-28 mEq/L
Blood urea nitrogen45 mg/dL7-18 mg/dL
Creatinine1.8 mg/dL0.6-1.2 mg/dL
Glucose110 mg/dL70-110 mg/dL
Albumin4.0 g/dL3.5-5.0 g/dL

Arterial blood gas (room air):

TestResultReference Range
pH7.497.35-7.45
PaCO219 mm Hg35-45 mm Hg
PaO295 mm Hg75-105 mm Hg

Based on the provided laboratory data, which of the following best characterizes this patient's acid-base status?

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Answer: High anion gap metabolic acidosis, metabolic alkalosis, and respiratory alkalosis

Answer

High anion gap metabolic acidosis, metabolic alkalosis, and respiratory alkalosis
The patient's laboratory values reveal three independent primary acid-base disturbances, known as a triple acid-base disorder. First, the anion gap is significantly elevated at 36 mEq/L (Normal = 12), diagnostic of a high anion gap metabolic acidosis (HAGMA). Second, the delta ratio is evaluated to detect hidden metabolic derangements: the ΔAG\Delta AG is 24 (36 - 12) and the ΔHCO3−\Delta HCO_3^- is 10 (24 - 14). The ratio of 24/1024 / 10 is 2.4. A delta ratio > 2.0 confirms a concurrent metabolic alkalosis, as the bicarbonate has not dropped proportionately to the accumulated acid (in this vignette, generated by severe vomiting). Finally, Winter's formula dictates that expected PaCO2=1.5(14)+8=29PaCO_2 = 1.5(14) + 8 = 29 mm Hg. Because the actual PaCO2PaCO_2 (19 mm Hg) is lower than the calculated expected range, an independent primary respiratory alkalosis is concurrently present. This specific triple disorder is a hallmark of combined salicylate toxicity (causing HAGMA and direct medullary respiratory alkalosis) and prolonged vomiting (causing metabolic alkalosis).

Step-by-Step Solution

1
Calculate the serum anion gap (AG) to identify the presence of a metabolic acidosis.
AG=Na+−(Cl−+HCO3−)=142−(92+14)=36AG = Na^+ - (Cl^- + HCO_3^-) = 142 - (92 + 14) = 36 mEq/L (Normal = 12).
An elevated anion gap reveals a primary high anion gap metabolic acidosis (HAGMA), regardless of the serum pH.
2
Calculate the delta ratio to identify any concurrent metabolic derangements.
ΔAG=36−12=24\Delta AG = 36 - 12 = 24. ΔHCO3−=24−14=10\Delta HCO_3^- = 24 - 14 = 10. Delta ratio = 24/10=2.424 / 10 = 2.4.
A delta ratio (ΔAG/ΔHCO3−\Delta AG / \Delta HCO_3^-) greater than 2.0 indicates that the drop in bicarbonate is much less than the rise in unmeasured anions, proving the presence of a concurrent metabolic alkalosis.
3
Apply Winter's formula to determine if respiratory compensation is appropriate.
Expected PaCO2=1.5×[HCO3−]+8±2=1.5(14)+8=29±2PaCO_2 = 1.5 \times [HCO_3^-] + 8 \pm 2 = 1.5(14) + 8 = 29 \pm 2 mm Hg (range 27-31).
The patient's actual PaCO2PaCO_2 (19 mm Hg) is significantly lower than the expected range (27-31 mm Hg), indicating an independent primary respiratory alkalosis.

Key Concept

A triple acid-base disorder (high anion gap metabolic acidosis, metabolic alkalosis, and respiratory alkalosis) requires systematic interpretation using the anion gap, delta ratio, and Winter's formula. It classically occurs in mixed clinical scenarios, such as salicylate toxicity complicated by severe vomiting.
Question 1545Question →

A 52-year-old man presents to the clinic for a follow-up evaluation of seropositive rheumatoid arthritis. Over the past 8 months, he has been treated with optimized doses of methotrexate, but he continues to experience significant morning stiffness and synovitis in his metacarpophalangeal and proximal interphalangeal joints. The physician decides to initiate targeted therapy with infliximab. Prior to starting the medication, an interferon-gamma release assay (IGRA) is performed and returns positive. A subsequent chest radiograph is clear, and the patient reports no cough, fever, or weight loss. Which of the following immunologic processes is most directly impaired by the planned biologic therapy, prompting the need for this screening?

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Answer: Macrophage activation and maintenance of caseating granulomas

Answer

Macrophage activation and maintenance of caseating granulomas
The correct answer identifies the fundamental role of TNF-alpha in the immune response to Mycobacterium tuberculosis. Alveolar macrophages and CD4+ Th1 cells interact closely to contain the pathogen. Th1 cells secrete interferon-gamma (IFN-gamma), which activates macrophages. These activated macrophages subsequently secrete TNF-alpha, a critical cytokine that drives the recruitment of additional immune cells and promotes the structural integrity of caseating granulomas. These granulomas wall off the mycobacteria, maintaining them in a dormant state. Biologic agents like infliximab, adalimumab, and etanercept neutralize TNF-alpha, which directly causes the dissolution of these granulomas. This leads to the rapid reactivation and dissemination of latent tuberculosis, which is why screening with an interferon-gamma release assay (IGRA) or tuberculin skin test is mandatory prior to initiating anti-TNF therapy.

Step-by-Step Solution

1
Identify the mechanism of action of the planned medication.
Infliximab is a monoclonal antibody that targets and neutralizes tumor necrosis factor-alpha (TNF-alpha).
Understanding the pharmacodynamics of the drug is essential to predict its immunologic side effects.
2
Interpret the pre-treatment screening test results.
A positive IGRA with a normal chest radiograph and no symptoms indicates latent tuberculosis infection (LTBI).
Differentiating latent infection from active disease dictates the need for prophylactic management versus active treatment before starting immunosuppression.
3
Correlate the drug's mechanism with the pathophysiology of latent tuberculosis.
TNF-alpha is critical for the maintenance of caseating granulomas that keep Mycobacterium tuberculosis in a dormant state. Inhibiting TNF-alpha leads to granuloma dissolution and tuberculosis reactivation.
Connecting the immunologic pathway to the infectious complication explains why screening is a mandatory guideline.

Key Concept

Tumor necrosis factor-alpha (TNF-alpha) is crucial for macrophage activation and the maintenance of granulomas; its inhibition by biologic agents like infliximab significantly increases the risk of latent tuberculosis reactivation.
Question 1546Question →

A 26-year-old man presents to the urgent care clinic with a 1-week history of profound fatigue, nausea, anorexia, and right upper quadrant abdominal pain. He recently noticed that his eyes appear yellowish and his urine has become dark. His medical history is unremarkable, and he takes no prescription medications, over-the-counter drugs, or herbal supplements. He does not consume alcohol. He reports having unprotected sexual intercourse with a new partner approximately three months ago. Vital signs are within normal limits. Physical examination reveals scleral icterus and a tender liver edge palpable 3 cm below the right costal margin.

Laboratory studies are obtained:

Laboratory TestResultReference Range
Alanine aminotransferase (ALT)1,850 U/L10-40 U/L
Aspartate aminotransferase (AST)1,620 U/L10-40 U/L
Alkaline phosphatase (ALP)185 U/L40-120 U/L
Total bilirubin4.8 mg/dL0.1-1.2 mg/dL
Direct bilirubin3.6 mg/dL0.0-0.3 mg/dL
Hepatitis A antibody, IgMNegativeNegative
Hepatitis B surface antigen (HBsAg)NegativeNegative
Hepatitis B surface antibody (Anti-HBs)NegativeNegative
Hepatitis B core antibody, IgM (Anti-HBc IgM)PositiveNegative
Hepatitis C virus antibodyNegativeNegative

Based on the provided clinical presentation and laboratory results, which of the following is the most likely diagnosis?

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Answer: Acute hepatitis B virus infection during the window period

Answer

Acute hepatitis B virus infection during the window period
The correct diagnosis is acute hepatitis B virus infection during the window period. This patient presents with classic signs and symptoms of acute hepatitis, supported by transaminases elevated well above 1,000 U/L. The hepatitis B serologic panel is the key to establishing the exact diagnosis. The patient has a negative hepatitis B surface antigen (HBsAg) and a negative hepatitis B surface antibody (Anti-HBs), but is positive for the IgM antibody to the hepatitis B core antigen (IgM Anti-HBc). This highly specific pattern occurs during the 'window period' of an acute hepatitis B infection. The window period is the time gap that occurs after HBsAg has declined below detectable levels as the body clears the antigen, but before Anti-HBs has been produced in high enough quantities to become detectable. During this interval, IgM Anti-HBc remains positive and serves as the primary and sometimes sole serologic marker indicating an acute or very recent hepatitis B infection.

Step-by-Step Solution

1
Analyze the clinical presentation and primary lab abnormalities.
The patient presents with symptoms and signs of acute hepatitis, including jaundice, right upper quadrant pain, and markedly elevated serum transaminases (>1,000 U/L).
This establishes an acute hepatic injury, likely viral given the timeline and sexual risk factors, narrowing the differential diagnosis to acute hepatitides.
2
Interpret the specific viral hepatitis serology panel.
Hepatitis A and C antibodies are negative. For Hepatitis B, HBsAg and Anti-HBs are both negative, but IgM Anti-HBc is explicitly positive.
The sole presence of an IgM core antibody is highly specific and is required to properly stage the timeline of the Hepatitis B infection.
3
Synthesize the findings into a definitive diagnosis based on established serological timelines.
The serologic profile identifies the 'window period', the phase where HBsAg has been cleared but Anti-HBs has not yet reached detectable levels. IgM Anti-HBc remains the only marker of recent, acute infection.
Correctly identifying this unique serological phase confirms the exact etiology of the patient's acute symptoms and prevents misdiagnosis.

Key Concept

During the 'window period' of acute hepatitis B infection, both the surface antigen (HBsAg) and the surface antibody (Anti-HBs) are negative, making the IgM core antibody (IgM Anti-HBc) the only detectable serological marker of the active/recent infection.
Question 1547Question →

A 27-year-old primigravida at 23 weeks of gestation is evaluated in the emergency department for right-sided abdominal pain that started yesterday. The pain was initially dull and located around the umbilicus but has progressively worsened and shifted to the right mid-abdomen over the last twelve hours. She reports severe nausea and has vomited twice. Her temperature is 38.0°C (100.4°F), blood pressure is 112/74 mmHg, and heart rate is 102/min. On physical examination, there is marked tenderness to palpation in the right mid-abdomen, superior to the typical location of McBurney's point. Rebound tenderness is absent. Fetal heart tones are normal. Laboratory analysis shows a leukocyte count of 14,500/mm³ with 82% neutrophils. A graded compression transabdominal ultrasound is performed by an experienced sonographer, but the appendix cannot be visualized due to displacement by the enlarged uterus and acoustic shadowing from overlying bowel gas. Which of the following is the most appropriate next diagnostic step?

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Answer: Magnetic resonance imaging (MRI) of the abdomen and pelvis without contrast

Answer

The most appropriate next diagnostic step is magnetic resonance imaging (MRI) of the abdomen and pelvis without contrast.
In pregnant patients presenting with signs and symptoms of acute appendicitis, the anatomical displacement of the appendix (often shifted superiorly and laterally) makes clinical diagnosis challenging. Graded compression ultrasound is the appropriate first-line imaging modality because it is safe and widely available. However, due to the gravid uterus and overlying bowel gas, the appendix often cannot be adequately visualized. When ultrasound is non-diagnostic, the standard of care is to proceed to magnetic resonance imaging (MRI) of the abdomen and pelvis without gadolinium contrast. MRI has excellent sensitivity and specificity for appendicitis in pregnancy and, importantly, avoids exposing the fetus to ionizing radiation.

Step-by-Step Solution

1
Identify the clinical presentation and context.
The patient is a pregnant woman in her second trimester presenting with classic signs of acute appendicitis, though the pain is displaced superiorly due to the gravid uterus.
Pregnancy alters anatomical landmarks and limits diagnostic testing options due to fetal safety concerns.
2
Evaluate the results of the initial diagnostic workup.
Graded compression ultrasound, the correct initial test, was properly performed but resulted in a non-diagnostic study (appendix not visualized).
Ultrasound is first-line in pregnancy, but it fails to visualize the appendix in a significant percentage of pregnant patients due to uterine size and bowel gas.
3
Determine the optimal secondary imaging modality.
MRI of the abdomen and pelvis without contrast is selected.
MRI provides definitive cross-sectional imaging without exposing the fetus to the ionizing radiation associated with CT scans.

Key Concept

In pregnant patients with suspected acute appendicitis, graded compression ultrasound is the initial imaging test of choice. If the ultrasound is non-diagnostic, magnetic resonance imaging (MRI) without contrast is the preferred next step to establish the diagnosis while avoiding ionizing radiation.
Question 1548Question →

Match each physical examination maneuver with the specific musculoskeletal or neurological pathology it is most commonly used to diagnose.

Click a left item, then click its matching right item

Items

Finkelstein test
Phalen maneuver
Empty can (Jobe) test
Lachman test

Matches

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Answer

Finkelstein test matches with stenosing tenosynovitis of the first dorsal compartment. Phalen maneuver matches with compression of the median nerve. Empty can test matches with supraspinatus tear or tendinopathy. Lachman test matches with anterior cruciate ligament rupture.
Each provocative physical examination maneuver is meticulously designed based on biomechanics to isolate and stress a single tendon, ligament, or nerve. Recognizing these specific clinical correlations allows for rapid bedside diagnosis before imaging is obtained.

Step-by-Step Solution

1
Analyze the anatomical target of the Finkelstein test.
Matches with stenosing tenosynovitis of the first dorsal compartment of the wrist.
The test stretches the tendons in the first dorsal extensor compartment (abductor pollicis longus and extensor pollicis brevis).
2
Analyze the anatomical target of the Phalen maneuver.
Matches with compression of the median nerve within the carpal tunnel.
The maneuver mechanically compresses the carpal tunnel space to elicit median nerve symptoms.
3
Analyze the anatomical target of the empty can (Jobe) test.
Matches with tear or tendinopathy of the supraspinatus muscle.
Internal rotation and elevation specifically isolate the supraspinatus tendon of the rotator cuff.
4
Analyze the anatomical target of the Lachman test.
Matches with rupture of the anterior cruciate ligament.
Anterior translation of the tibia specifically stresses the anterior cruciate ligament for integrity.

Key Concept

Clinical application and anatomical basis of provocative musculoskeletal and neurological physical examination maneuvers.
Estimated Time:1m 0s
Question 1549Question →

A 34-year-old woman is admitted to the intensive care unit with severe sepsis secondary to acute pyelonephritis. On her second day of admission, the nursing staff notes persistent bleeding from her intravenous catheter sites and new-onset ecchymoses over her extremities. Her temperature is 38.8°C (101.8°F), blood pressure is 90/60 mmHg, and pulse is 115/min. Laboratory studies are obtained and show the following:

Laboratory TestResultReference Range
Platelet count42,000/mm³150,000 - 400,000/mm³
Prothrombin time (PT)22 seconds11 - 15 seconds
Partial thromboplastin time (PTT)65 seconds25 - 40 seconds
Fibrinogen85 mg/dL150 - 400 mg/dL
D-dimer4,500 ng/mL FEU< 500 ng/mL FEU

Which of the following is the most likely diagnosis based on these laboratory findings?

Show answer & explanation

Answer: Disseminated intravascular coagulation

Answer

Disseminated intravascular coagulation
The correct answer is Disseminated intravascular coagulation (DIC). This patient's clinical presentation of sepsis with bleeding from intravenous sites, combined with a laboratory profile showing thrombocytopenia, prolonged PT, prolonged PTT, hypofibrinogenemia, and elevated D-dimer, is classic for DIC. In DIC, widespread systemic activation of the coagulation cascade leads to the rapid consumption of platelets and coagulation factors (which prolongs the PT and PTT and lowers fibrinogen). Concurrently, the fibrinolytic system is activated to break down the clots, resulting in significantly elevated fibrin degradation products, such as D-dimer.

Step-by-Step Solution

1
Analyze the platelet count and coagulation times.
The patient has severe thrombocytopenia, a prolonged PT, and a prolonged PTT.
This indicates a systemic issue affecting both primary hemostasis (platelets) and secondary hemostasis (coagulation factors).
2
Evaluate the fibrinogen and D-dimer levels.
Fibrinogen is abnormally low, and D-dimer is significantly elevated.
Low fibrinogen indicates widespread consumption of clotting factors. Elevated D-dimer indicates active fibrinolysis, which occurs as the body attempts to break down the numerous clots forming systemically.
3
Synthesize the laboratory data with the clinical context.
The clinical picture of sepsis with bleeding and a lab profile of consumptive coagulopathy perfectly matches disseminated intravascular coagulation (DIC).
Sepsis is a classic trigger for the widespread endothelial damage and tissue factor release that initiates the cascade of DIC.

Key Concept

Disseminated intravascular coagulation manifests with widespread consumption of platelets and coagulation factors, leading to prolonged PT/PTT, thrombocytopenia, decreased fibrinogen, and elevated D-dimer.
Question 1550Question →

During a routine preoperative evaluation for an elective total knee arthroplasty, an asymptomatic 79-year-old woman is noted to have a prominent cardiac murmur. She denies any recent syncope, angina, or dyspnea, although she admits her activity level is minimal due to severe osteoarthritis. Vital signs show a blood pressure of 124/76 mmHg and a regular pulse of 68/min. Cardiac auscultation at the right second intercostal space reveals a loud crescendo-decrescendo systolic ejection murmur that radiates to the carotid arteries. The anesthesiologist requests a cardiology consultation to determine if the valvular lesion is hemodynamically significant, which would increase her perioperative risk.

Which TWO of the following concurrent physical examination findings would most strongly indicate that this patient's aortic stenosis is hemodynamically severe? (Select exactly two options)

Select all that apply

Show answer & explanation

Answer: Pulsus parvus et tardus (diminished and delayed carotid upstroke); Soft, single second heart sound (S2)

Answer

The physical examination findings most indicative of severe aortic stenosis are a diminished and delayed carotid upstroke (pulsus parvus et tardus) and a soft, single second heart sound (S2).
In hemodynamically severe aortic stenosis, the heavily calcified and narrowed aortic valve fundamentally alters left ventricular outflow. Because it takes longer for the left ventricle to eject blood through the tight orifice, the carotid upstroke becomes notably weak and delayed (pulsus parvus et tardus). Furthermore, the rigid, immobile aortic leaflets fail to snap shut properly, leading to a diminished or completely absent aortic component (A2) of the second heart sound. This results in a soft, single S2, or occasionally paradoxical splitting.

Step-by-Step Solution

1
Analyze the clinical vignette and identify the primary structural lesion.
The patient has a loud crescendo-decrescendo systolic murmur at the right upper sternal border radiating to the carotids, which is classic for aortic stenosis.
Establishing the baseline valvular abnormality is required before assessing its severity.
2
Differentiate the physical examination findings of mild-to-moderate versus severe aortic stenosis.
Severe aortic stenosis presents with a late-peaking murmur, pulsus parvus et tardus, and a soft/single S2. Mild disease presents with an early-peaking murmur and a normally split S2.
The question specifically asks for markers of hemodynamically severe disease.
3
Evaluate the given options against the classic signs of severe aortic stenosis.
The options describing pulsus parvus et tardus and a soft, single S2 correctly identify severe disease. The other options describe mild disease or entirely different pathologies.
Systematic elimination ensures the selection of the precise constellation of findings for the requested severity.

Key Concept

The classic physical examination findings of hemodynamically severe aortic stenosis include pulsus parvus et tardus (delayed, weak carotid upstroke), a late-peaking systolic murmur, and a soft, single second heart sound (S2) due to immobility of the calcified leaflets.
Question 1551Question →

A 68-year-old woman with a history of stage 4 chronic kidney disease presents to the clinic for a routine follow-up. Laboratory evaluation reveals a serum calcium level of 7.8 mg/dL and an elevated intact parathyroid hormone level. The physician notes that her hypocalcemia is primarily driven by the loss of functional renal parenchyma, which impairs a critical step in a major endocrine pathway. To review the pathophysiology of her condition, arrange the following biochemical and cellular events involved in the synthesis and mechanism of action of the deficient hormone in the correct chronological sequence, beginning with the initial precursor event.

Drag items to arrange them in the correct order

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Answer

The correct sequence begins with the photochemical cleavage of 7-dehydrocholesterol in the skin, followed by hepatic 25-hydroxylation, then renal 1-alpha-hydroxylation, followed by intracellular heterodimerization with the retinoid X receptor, and finally the upregulation of calbindin-D9k transcription in enterocytes.
The correct sequence accurately reflects the biological pathway of vitamin D. It begins in the skin with the UV-mediated formation of cholecalciferol from 7-dehydrocholesterol. This is followed by hepatic 25-hydroxylation to calcidiol. The rate-limiting and strictly regulated step, 1-alpha-hydroxylation, occurs in the renal proximal tubule to form active calcitriol. Once secreted into the circulation, calcitriol enters target cells (such as enterocytes) to bind the intracellular Vitamin D Receptor (VDR). The VDR-ligand complex heterodimerizes with the Retinoid X Receptor (RXR), binds to DNA response elements, and upregulates the transcription of calcium-binding proteins such as calbindin, which are necessary for the intestinal absorption of calcium.

Step-by-Step Solution

1
Identify the deficient hormone based on the clinical presentation.
The patient has calcitriol (1,25-dihydroxycholecalciferol) deficiency due to advanced chronic kidney disease.
Loss of functioning nephrons reduces 1-alpha-hydroxylase activity, preventing the final activation step of vitamin D and leading to hypocalcemia and secondary hyperparathyroidism.
2
Trace the physiological synthesis of the hormone.
Synthesis begins in the skin with UV light, followed by liver 25-hydroxylation, and finishes with kidney 1-alpha-hydroxylation.
This establishes the first three steps in the systemic biochemical pathway of vitamin D.
3
Determine the cellular mechanism of action of the active hormone in target tissues.
Calcitriol binds to the intracellular VDR, heterodimerizes with RXR, and alters gene expression to produce proteins like calbindin.
This establishes the final two sequential cellular steps that result in the physiological effect (increased calcium absorption).

Key Concept

Vitamin D synthesis and intracellular mechanism of action
Question 1552Question →

A 27-year-old woman with a history of type 1 diabetes mellitus presents to the emergency department with abdominal pain, nausea, and severe, intractable vomiting for the past 48 hours. She stopped taking her insulin yesterday due to an inability to tolerate oral intake. On physical examination, her pulse is 118/min, blood pressure is 98/60 mm Hg, and respiratory rate is 18/min. Her mucous membranes are dry.

Arterial blood gas on room air reveals:
pH: 7.387.38
pCO2pCO_2: 42 mm Hg42 \text{ mm Hg}

Serum laboratory results are as follows:
Sodium: 140 mEq/L140 \text{ mEq/L}
Potassium: 3.1 mEq/L3.1 \text{ mEq/L}
Chloride: 88 mEq/L88 \text{ mEq/L}
Bicarbonate: 24 mEq/L24 \text{ mEq/L}
Glucose: 610 mg/dL610 \text{ mg/dL}
Blood urea nitrogen: 42 mg/dL42 \text{ mg/dL}
Creatinine: 1.8 mg/dL1.8 \text{ mg/dL}

To evaluate for the presence of a mixed acid-base disorder, the physician calculates the delta-adjusted bicarbonate (also known as the expected bicarbonate derived from the delta gap). Assuming a baseline normal anion gap of 12 mEq/L12 \text{ mEq/L}, what is this patient's delta-adjusted bicarbonate (in mEq/L)?

Show answer & explanation

Answer: 40

Answer

40
The delta-adjusted bicarbonate is calculated to uncover hidden metabolic disorders in the setting of a high anion gap metabolic acidosis (HAGMA). First, the anion gap (AG) is calculated as Na+−(Cl−+HCO3−)=140−(88+24)=28 mEq/LNa^+ - (Cl^- + HCO_3^-) = 140 - (88 + 24) = 28 \text{ mEq/L}. The excess anion gap (delta gap) is the measured AG minus the normal AG: 28−12=16 mEq/L28 - 12 = 16 \text{ mEq/L}. The delta-adjusted bicarbonate is the measured bicarbonate plus the delta gap: 24+16=40 mEq/L24 + 16 = 40 \text{ mEq/L}. A delta-adjusted bicarbonate > 26 mEq/L26 \text{ mEq/L} indicates a concurrent metabolic alkalosis, which in this patient is caused by severe vomiting (loss of H+H^+ and Cl−Cl^-), completely offsetting the acidemia from diabetic ketoacidosis and resulting in a falsely normal pH.

Step-by-Step Solution

1
Calculate the measured Anion Gap (AG).
AG = 28 mEq/L
AG is required to determine the presence of high anion gap metabolic acidosis (HAGMA) and to calculate the delta gap.
2
Calculate the Delta Gap.
Delta Gap = 16 mEq/L
The delta gap represents the amount of unmeasured anions (acid) consuming the bicarbonate.
3
Calculate the Delta-adjusted Bicarbonate.
Delta-adjusted Bicarbonate = 40 mEq/L
Adding the delta gap back to the measured bicarbonate reveals what the bicarbonate level would be if the HAGMA were not present, exposing concurrent acid-base disorders.

Key Concept

Delta-Delta Gap Calculation for Mixed Acid-Base Disorders
Estimated Time:2m 0s
Question 1553Question →

A 54-year-old man visits an urgent care clinic reporting four days of a progressively worsening cough, subjective fevers, and sharp pain on the right side of his chest that intensifies during inspiration. His temperature is 38.9∘C38.9^\circ\text{C} (102∘F102^\circ\text{F}), blood pressure is 118/76 mm Hg118/76\text{ mm Hg}, pulse is 102/min102\text{/min}, and respiratory rate is 22/min22\text{/min}. Physical examination of the posterior thorax reveals localized dullness to percussion over the right lower lung zone. While auscultating this specific area, the clinician asks the patient to continuously vocalize the vowel "E", which is heard through the stethoscope as a distinct, nasal "A" sound. Which of the following additional physical examination findings is most likely to be elicited over this precise anatomical area?

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Answer: Noticeably increased palpable vibrations when the patient speaks

Answer

Noticeably increased palpable vibrations when the patient speaks (increased tactile fremitus)
The patient's clinical presentation and the presence of egophony (an 'E' to 'A' transition on auscultation) alongside dullness to percussion are classic hallmarks of lobar lung consolidation, typical of bacterial pneumonia. When the normally air-filled alveolar spaces become engorged with fluid and inflammatory exudate, the density of the lung parenchyma increases. This solid medium acts as a superior conductor for specific sound frequencies and mechanical vibrations originating from the larynx. Consequently, vocal resonance signs like egophony and whispered pectoriloquy emerge. By this same acoustic principle, low-frequency vocal vibrations transmitted to the chest wall—tactile fremitus—are notably amplified over the consolidated lobe.

Step-by-Step Solution

1
Identify the primary clinical syndrome based on the patient's history and vital signs.
The patient has a 4-day history of fever, productive cough, and pleuritic chest pain, strongly suggesting an acute lower respiratory tract infection.
Recognizing the infectious and inflammatory nature of the presentation narrows the differential diagnosis to processes like pneumonia.
2
Interpret the focal physical examination findings of the chest.
Localized dullness to percussion and the presence of egophony ('E' to 'A' transition) specifically indicate lung consolidation, where the alveolar space is filled with fluid and cellular exudate.
Solid or fluid-filled lung tissue transmits high-frequency sounds better than air-filled tissue, leading to distinct acoustic signs like egophony and whispered pectoriloquy.
3
Deduce the corresponding physical examination finding that shares the same pathophysiological mechanism.
Because consolidated lung tissue efficiently conducts low-frequency vibrations as well, tactile fremitus (palpable vocal vibrations) will be noticeably increased over the affected area.
Matching the mechanism of enhanced sound/vibration transmission to the correct examination sign yields the final answer.

Key Concept

Physical signs of lung consolidation include dullness to percussion, bronchial breath sounds, egophony, whispered pectoriloquy, and increased tactile fremitus due to enhanced sound transmission through fluid-filled alveoli.
Question 1554Question →

A 6262-year-old woman comes to the clinic for a routine wellness examination. She reports feeling generally well, though she has experienced mild fatigue and occasional constipation over the past few months. She takes no medications and has no significant past medical history. Vital signs are within normal limits. Laboratory studies show:

Laboratory TestResultReference Range
Calcium, serum11.411.4 mg/dL8.4−10.28.4-10.2 mg/dL
Phosphorus, serum2.22.2 mg/dL2.7−4.52.7-4.5 mg/dL
Albumin, serum4.04.0 g/dL3.5−5.03.5-5.0 g/dL
Creatinine, serum0.90.9 mg/dL0.6−1.10.6-1.1 mg/dL
Intact parathyroid hormone8888 pg/mL10−6510-65 pg/mL

Which of the following is the most likely diagnosis based on these laboratory findings?

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Answer: Primary hyperparathyroidism

Answer

Primary hyperparathyroidism is the correct diagnosis.
The correct answer is primary hyperparathyroidism. The diagnostic algorithm for hypercalcemia begins with measuring intact parathyroid hormone (PTH). In a normal physiological state, high serum calcium strongly suppresses PTH secretion. Therefore, an elevated or even high-normal (inappropriately unsuppressed) PTH level in the presence of hypercalcemia defines PTH-dependent hypercalcemia. Given the patient's normal renal function (normal creatinine) and characteristic hypophosphatemia (PTH promotes renal phosphate excretion), primary hyperparathyroidism is the definitive diagnosis. Most cases are caused by a single benign parathyroid adenoma.

Step-by-Step Solution

1
Analyze the serum calcium and albumin levels.
Serum calcium is 11.411.4 mg/dL (elevated). Albumin is normal at 4.04.0 g/dL, meaning the total calcium does not need correction and true hypercalcemia is present.
Establishing the presence of true hypercalcemia is the first step in the diagnostic algorithm.
2
Evaluate the intact parathyroid hormone (PTH) level in the context of hypercalcemia.
Intact PTH is 8888 pg/mL (elevated).
PTH should normally be suppressed by hypercalcemia via negative feedback. An elevated or high-normal PTH in the setting of hypercalcemia indicates PTH-dependent hypercalcemia.
3
Evaluate the phosphorus and creatinine levels to differentiate causes of PTH-dependent hypercalcemia.
Phosphorus is 2.22.2 mg/dL (low) and creatinine is 0.90.9 mg/dL (normal).
Normal renal function and low phosphorus confirm primary autonomous secretion of PTH (Primary hyperparathyroidism), ruling out tertiary hyperparathyroidism which is associated with renal failure and high phosphorus.

Key Concept

The diagnosis of primary hyperparathyroidism is established by finding hypercalcemia with an inappropriately elevated or unsuppressed intact parathyroid hormone (PTH) level, typically accompanied by hypophosphatemia.
Estimated Time:45s
Question 1555Question →

A 32-year-old man presents to the primary care clinic requesting comprehensive sexually transmitted infection (STI) screening. He recently entered a new relationship and wants to ensure he is healthy. He has no current symptoms, and a detailed physical examination reveals no oral, genital, or anal lesions, nor any rashes. The clinic's laboratory employs the reverse sequence diagnostic algorithm for syphilis screening. For this patient, the initial screening test returns a reactive result, while the subsequent reflex test returns a nonreactive result, prompting a third laboratory test.

Arrange the following laboratory tests in the exact chronological sequence they would be performed for this patient according to the reverse sequence algorithm.

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Answer

The correct sequence of tests is: Treponemal-specific enzyme immunoassay (EIA), followed by Quantitative rapid plasma reagin (RPR) test, and finally Treponema pallidum particle agglutination (TP-PA) assay.
The reverse sequence algorithm for syphilis begins with an automated treponemal test (EIA or CIA). If this initial test is reactive, the sample must be reflexed to a nontreponemal test (RPR or VDRL) to evaluate for active disease and establish a baseline titer. If the results are discordant (i.e., reactive EIA but nonreactive RPR), a second, different treponemal test, most commonly the TP-PA assay, is required to determine whether the initial EIA was a false positive or if the patient has treated or late latent syphilis.

Step-by-Step Solution

1
Identify the initial screening test used in the reverse sequence algorithm.
The reverse sequence algorithm begins with an automated treponemal test, typically an enzyme immunoassay (EIA) or chemiluminescence immunoassay (CIA).
Laboratories increasingly favor this algorithm because treponemal immunoassays can be highly automated, saving labor and resources compared to manual nontreponemal testing.
2
Determine the reflex test ordered after a positive initial screen.
A quantitative nontreponemal test, such as the rapid plasma reagin (RPR) test, is ordered next.
While the EIA confirms treponemal exposure, the RPR assesses for active disease and provides a baseline titer to monitor the efficacy of future treatment.
3
Select the final confirmatory test based on the discordant results provided in the vignette.
Since the stem states the reflex test (RPR) was nonreactive, a second treponemal test, such as the Treponema pallidum particle agglutination (TP-PA) assay, must be performed.
A reactive EIA and a nonreactive RPR can represent either a false-positive EIA or a true prior/early infection. The TP-PA assay helps definitively distinguish between these possibilities.

Key Concept

The reverse sequence algorithm for syphilis testing begins with a treponemal immunoassay, reflexes to a nontreponemal test (such as RPR) if positive, and requires a second distinct treponemal test (such as TP-PA) if the first two tests yield discordant results.
Question 1556Question →

An attending physician is discussing the precise mechanisms of advanced immunomodulatory therapies with the medical team. Match each biological agent with its correct molecular target and primary immunopathologic mechanism of action.

Click a left item, then click its matching right item

Items

Abatacept
Belimumab
Tocilizumab
Secukinumab

Matches

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Answer

Abatacept matches with binding CD80/CD86; Belimumab matches with inhibiting BLyS; Tocilizumab matches with antagonizing IL-6 receptors; Secukinumab matches with neutralizing IL-17A.
Each biologic agent is correctly paired with its specific mechanism of action based on its engineered molecular target. Abatacept functions as a CTLA-4 decoy for CD80/86. Belimumab binds BLyS to inhibit B-cell survival. Tocilizumab blocks the IL-6 receptor. Secukinumab neutralizes the cytokine IL-17A.

Step-by-Step Solution

1
Identify the cellular target of Abatacept.
Abatacept is a CTLA-4 analog.
CTLA-4 naturally binds CD80/86 to downregulate T-cell activation, a pathway mimicking physiologic immune checkpoint regulation.
2
Identify the cellular target of Belimumab.
Belimumab targets B-cell activating factors.
It specifically inhibits BLyS (BAFF), leading to B-cell apoptosis, which is critical in autoantibody-driven diseases like SLE.
3
Identify the cytokine pathway blocked by Tocilizumab.
Tocilizumab blocks IL-6 signaling.
It is an anti-IL-6 receptor antibody, distinguished from anti-TNF agents, and is pivotal in reducing hepatic acute-phase reactant synthesis.
4
Identify the cytokine pathway blocked by Secukinumab.
Secukinumab targets the IL-17 pathway.
It binds directly to IL-17A, disrupting the Th17 inflammatory axis often implicated in spondyloarthropathies.

Key Concept

Biological immunomodulators have highly specific molecular targets that disrupt distinct pathways in the inflammatory cascade, ranging from T-cell costimulation (Abatacept) to specific interleukins (IL-6, IL-17) and B-cell survival factors (BLyS).
Estimated Time:1m 30s
Question 1557Question →

A 2222-year-old female college student is evaluated in the emergency department for severe, colicky abdominal pain, intractable nausea, and new-onset weakness in her bilateral upper extremities. She has a history of similar, albeit milder, abdominal pain episodes over the past 22 years. Her vital signs are notable for a heart rate of 122122/min and a blood pressure of 168/105168/105 mm Hg. Physical examination demonstrates generalized abdominal tenderness without rigidity or rebound. Initial laboratory workup reveals a serum sodium of 126126 mEq/L, with a normal lipase level, liver transaminases, and complete blood count. An abdominal ultrasound is unremarkable. Upon returning from the radiology suite, the nurse notes that the patient's urine in the bedside collection container has developed a deep red-purple hue after being exposed to ambient light. Arrange the following laboratory investigations in the most evidence-based sequential order for the diagnostic workup of this patient's suspected metabolic disorder.

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Answer

The correct sequence is to first obtain a spot urine test for PBG and ALA, followed by plasma and fecal porphyrin fractionation, then measure erythrocyte HMBS enzyme activity, and finally perform targeted molecular genetic sequencing.
The evidence-based sequence for diagnosing acute intermittent porphyria begins with a sensitive rapid screening test (spot urine PBG and ALA) to confirm an acute attack. Because elevated PBG is shared by multiple acute porphyrias, the next step is biochemical differentiation using plasma and fecal porphyrins. After the biochemical phenotype suggests a specific porphyria (AIP), the corresponding functional enzyme assay (erythrocyte HMBS) is checked. The final step is molecular genetic testing to pinpoint the exact mutation, primarily used to facilitate screening of family members.

Step-by-Step Solution

1
Identify the clinical presentation of an acute hepatic porphyria attack.
The triad of unexplained acute neurovisceral pain, dysautonomia (tachycardia, hypertension), hyponatremia, and light-sensitive dark urine points strongly to an acute porphyria.
Recognizing the toxidrome prevents unnecessary surgical exploration and dictates the initiation of a highly specialized biochemical laboratory workup.
2
Order a rapid initial biochemical screening test.
Spot urine PBG and ALA normalized to creatinine are ordered as the first-line test.
These porphyrin precursors are profoundly elevated during an acute attack. A spot test provides the most sensitive, rapid diagnostic confirmation needed to justify administering definitive therapy (e.g., intravenous hemin).
3
Differentiate the specific subtype of acute porphyria.
Plasma and fecal porphyrin fractionation is ordered as the second step.
Elevated PBG and ALA occur in Acute Intermittent Porphyria (AIP), Variegate Porphyria (VP), and Hereditary Coproporphyria (HCP). Fecal porphyrins effectively separate AIP (normal/low levels) from VP and HCP (highly elevated levels).
4
Confirm the functional enzymatic deficiency.
Erythrocyte HMBS (previously PBG deaminase) enzyme assay is performed.
Once the biochemical pattern suggests AIP, demonstrating the specific enzymatic block in the heme synthesis pathway confirms the functional defect.
5
Establish the definitive molecular diagnosis.
Targeted HMBS gene sequencing is ordered.
This definitively confirms the condition at the DNA level and is essential for enabling genetic counseling and cascade testing for asymptomatic relatives.

Key Concept

The diagnostic algorithm for acute hepatic porphyrias follows a strict sequence: initial rapid biochemical confirmation with spot urine porphobilinogen (PBG), followed by subtype differentiation with fecal/plasma porphyrins, enzyme activity confirmation, and finally, molecular genetic testing.
Estimated Time:2m 30s
Question 1558Question →

Match each laboratory profile with its most likely clinical diagnosis.

Click a left item, then click its matching right item

Items

Decreased serum iron, increased total iron-binding capacity (TIBC), decreased ferritin
Decreased serum iron, decreased total iron-binding capacity (TIBC), increased ferritin
Increased serum iron, decreased total iron-binding capacity (TIBC), increased transferrin saturation
Normal serum iron, normal total iron-binding capacity (TIBC), elevated indirect bilirubin, decreased haptoglobin

Matches

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Answer

Iron deficiency anemia matches with decreased iron/increased TIBC/decreased ferritin. Anemia of chronic inflammation matches with decreased iron/decreased TIBC/increased ferritin. Hereditary hemochromatosis matches with increased iron/decreased TIBC/increased saturation. Hemolytic anemia matches with normal iron studies/elevated bilirubin/decreased haptoglobin.
Each laboratory profile distinctly identifies a pathophysiologic state: iron deficiency features low stores (ferritin); chronic inflammation features iron trapping (high ferritin, low TIBC); hemochromatosis features overload (high iron/saturation); and hemolysis features RBC destruction markers (low haptoglobin, high indirect bilirubin).

Step-by-Step Solution

1
Analyze the ferritin and TIBC levels.
Low ferritin with high TIBC indicates an absolute iron deficit. High or normal ferritin with low TIBC indicates adequate stores but impaired utilization or iron overload.
Ferritin represents storage iron and TIBC reflects transferrin levels, differentiating absolute deficiency from other states.
2
Evaluate the serum iron and transferrin saturation in conjunction with ferritin.
Low serum iron with high ferritin suggests anemia of chronic inflammation (hepcidin effect), whereas high iron with high saturation suggests iron overload like hemochromatosis.
Serum iron levels help distinguish between functional trapping and true overload.
3
Assess for non-iron-related markers like haptoglobin and bilirubin.
Decreased haptoglobin and elevated indirect bilirubin without iron study derangements indicate hemolysis.
Hemolysis involves RBC breakdown, releasing hemoglobin and overwhelming haptoglobin capacity before significantly altering iron stores.

Key Concept

Interpretation of iron studies and hemolysis markers
Question 1559Question →

A 22-year-old female presents to the outpatient clinic reporting intermittent muscle cramping and tingling in her fingertips over the past several months. She has a history of mild intellectual disability but currently takes no medications. Vital signs are within normal limits. Physical examination reveals short stature, a round face, and shortened fourth and fifth metacarpals on both hands. Tapping the facial nerve anterior to the earlobe elicits twitching of the ipsilateral facial muscles. Laboratory studies show:

Laboratory TestResultReference Range
Serum calcium7.2 mg/dL8.4-10.2 mg/dL
Serum phosphorus5.6 mg/dL2.5-4.5 mg/dL
Intact parathyroid hormone350 pg/mL15-65 pg/mL
25-hydroxyvitamin D32 ng/mL20-50 ng/mL
Serum creatinine0.8 mg/dL0.6-1.1 mg/dL

Which of the following cellular mechanisms best explains this patient's clinical and laboratory findings?

Show answer & explanation

Answer: Impaired stimulatory G-protein subunit signaling

Answer

Impaired stimulatory G-protein subunit signaling
The correct answer accurately identifies the molecular pathophysiology of pseudohypoparathyroidism type 1a (PHP-1a). This patient's presentation of short stature, round facies, mild intellectual disability, and shortened 4th and 5th metacarpals is pathognomonic for Albright hereditary osteodystrophy. The laboratory findings of hypocalcemia, hyperphosphatemia, and a markedly elevated PTH level—in the presence of normal renal function and normal vitamin D stores—indicate target-organ resistance to parathyroid hormone. The PTH receptor is a G-protein coupled receptor that normally utilizes a stimulatory G-protein alpha subunit (GαsG\alpha_s) to activate adenylate cyclase. PHP-1a is caused by a maternally inherited inactivating mutation in the GNAS1 gene, which encodes this GαsG\alpha_s subunit, leading to impaired intracellular signaling.

Step-by-Step Solution

1
Identify the clinical syndrome based on the physical examination findings.
The patient has short stature, a round face, and shortened 4th and 5th metacarpals. These are the classic features of Albright hereditary osteodystrophy (AHO). The positive Chvostek sign indicates neuromuscular irritability due to hypocalcemia.
Recognizing the phenotypic presentation narrows the differential diagnosis for hypocalcemia and directs interpretation of the laboratory results.
2
Analyze the laboratory data to determine the functional endocrine state.
The patient has hypocalcemia and hyperphosphatemia despite a markedly elevated intact parathyroid hormone (PTH) level. Renal function and vitamin D stores are normal.
The combination of elevated PTH with hypocalcemia in the setting of normal renal function establishes the diagnosis of target-organ resistance to PTH (pseudohypoparathyroidism).
3
Correlate the clinical diagnosis with its underlying molecular mechanism.
The correct underlying mechanism is an inactivating mutation in the GNAS1 gene, which leads to a defective stimulatory G-protein alpha subunit (GαsG\alpha_s).
PTH acts on target tissues (kidney and bone) via a G-protein coupled receptor. The defective GαsG\alpha_s subunit prevents the generation of cAMP, causing end-organ resistance characteristic of pseudohypoparathyroidism type 1a.

Key Concept

Pseudohypoparathyroidism type 1a is characterized by end-organ resistance to PTH due to a defective stimulatory G-protein alpha subunit, presenting with hypocalcemia, hyperphosphatemia, elevated PTH, and the Albright hereditary osteodystrophy phenotype.
Question 1560Question →

A 42-year-old man comes to the clinic for a follow-up evaluation. Two weeks ago, he was noted to have an elevated serum calcium level on a routine comprehensive metabolic panel obtained for a life insurance policy. He feels well and has no fatigue, abdominal pain, bone pain, or changes in bowel habits. His only medical history is mild hypertension, for which he has been taking amlodipine for three years. He does not take any over-the-counter supplements. He is adopted and does not know his family medical history. Blood pressure is 128/82 mm Hg, and pulse is 72/min. Physical examination is unremarkable.

Laboratory results are as follows:

TestResultReference Range
Serum
Calcium11.0 mg/dL8.4-10.2 mg/dL
Albumin4.0 g/dL3.5-5.0 g/dL
Phosphorus2.3 mg/dL2.5-4.5 mg/dL
Creatinine1.0 mg/dL0.7-1.3 mg/dL
Intact parathyroid hormone68 pg/mL10-65 pg/mL
25-hydroxyvitamin D35 ng/mL20-50 ng/mL
Spot Urine
Calcium5 mg/dL-
Creatinine100 mg/dL-

Based on the laboratory results, which of the following is the most likely underlying mechanism for this patient's findings?

Show answer & explanation

Answer: Inactivating mutation in the calcium-sensing receptor

Answer

The most likely underlying mechanism is an inactivating mutation in the calcium-sensing receptor, resulting in Familial Hypocalciuric Hypercalcemia.
The patient has mild hypercalcemia with an inappropriately elevated intact parathyroid hormone (PTH) level, indicating PTH-dependent hypercalcemia. In an asymptomatic patient, the two primary considerations are primary hyperparathyroidism and familial hypocalciuric hypercalcemia (FHH). To differentiate these, the calcium-to-creatinine clearance ratio (CCCR) must be calculated using the formula: CCCR=UrineCa×SerumCrSerumCa×UrineCrCCCR = \frac{Urine_{Ca} \times Serum_{Cr}}{Serum_{Ca} \times Urine_{Cr}}. For this patient, CCCR=5×1.011.0×100=0.0045CCCR = \frac{5 \times 1.0}{11.0 \times 100} = 0.0045. A ratio less than 0.01 (1%) is highly suggestive of FHH, an autosomal dominant disorder caused by an inactivating mutation in the calcium-sensing receptor (CaSR) located in the parathyroid glands and renal tubules. This mutation alters the set-point for calcium homeostasis, requiring higher serum calcium levels to suppress PTH secretion, and simultaneously increases renal calcium reabsorption, leading to marked hypocalciuria.

Step-by-Step Solution

1
Evaluate the initial serum calcium and parathyroid hormone (PTH) levels.
The patient has hypercalcemia (11.0 mg/dL) with an inappropriately high-normal to mildly elevated PTH (68 pg/mL).
This establishes the presence of PTH-dependent hypercalcemia, immediately narrowing the primary differential diagnosis to primary hyperparathyroidism and familial hypocalciuric hypercalcemia (FHH).
2
Calculate the calcium-to-creatinine clearance ratio (CCCR) to differentiate the remaining etiologies.
CCCR = (Urine Calcium × Serum Creatinine) / (Serum Calcium × Urine Creatinine) = (5 × 1.0) / (11.0 × 100) = 5 / 1100 = 0.0045.
The CCCR is an essential diagnostic index for PTH-dependent hypercalcemia. A CCCR < 0.01 strongly suggests FHH, while a CCCR > 0.02 suggests primary hyperparathyroidism.
3
Correlate the calculated CCCR with the underlying pathophysiology.
A CCCR of 0.0045 (< 0.01) confirms the diagnosis of FHH, which is caused by an inactivating mutation in the calcium-sensing receptor (CaSR).
This mutation requires higher serum calcium levels to suppress PTH secretion and causes increased renal calcium reabsorption, directly resulting in the observed laboratory pattern.

Key Concept

Differentiating familial hypocalciuric hypercalcemia from primary hyperparathyroidism using the calculated calcium-to-creatinine clearance ratio.
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