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Zorluk: OrtaLaw of Sines and Law of Cosines

A telecommunications company connects two remote cell towers, Tower X and Tower Y, to a central relay station R. The cable path from Relay Station R to Tower X is 77 kilometers long, and the cable path from Relay Station R to Tower Y is 88 kilometers long. The angle formed between the two cables at Relay Station R, XRY\angle XRY, measures 120120^\circ. A straight wireless backup link is established directly between Tower X and Tower Y. What is the distance, in kilometers, of this direct wireless link?

Cevap: 13 km

Cevap

The distance of the direct wireless link between Tower X and Tower Y is 13 kilometers.
Using the Law of Cosines with two side lengths of 7 km and 8 km and an included angle of 120° gives XY2=72+822(7)(8)cos(120)=49+64112(0.5)=169XY^2 = 7^2 + 8^2 - 2(7)(8)\cos(120^\circ) = 49 + 64 - 112(-0.5) = 169. Taking the square root gives 13 km.

Adım Adım Çözüm

1
Identify known components of the triangle formed by the relay station and towers
Side RX=7 kmRX = 7\text{ km}, side RY=8 kmRY = 8\text{ km}, and included angle R=120\angle R = 120^\circ
Two sides and the included angle (SAS) are known, indicating that the Law of Cosines must be used to find the third side.
2
Apply the Law of Cosines formula for side XYXY
XY2=72+822(7)(8)cos(120)XY^2 = 7^2 + 8^2 - 2(7)(8)\cos(120^\circ)
The Law of Cosines relates three sides of a triangle to the cosine of one of its angles: c2=a2+b22abcos(C)c^2 = a^2 + b^2 - 2ab\cos(C).
3
Calculate the numeric value of XY2XY^2
XY2=49+64+56=169XY^2 = 49 + 64 + 56 = 169
Since cos(120)=0.5\cos(120^\circ) = -0.5, the term 2(56)(0.5)-2(56)(-0.5) evaluates to +56+56.
4
Take the principal square root of 169169
XY=13 kmXY = 13\text{ km}
Distance must be a positive length.

Anahtar Kavram

Law of Cosines (Side-Angle-Side configuration)
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