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Zorluk: OrtaCircle Geometry: Arc Length and Sector Area

A lighthouse beacon sweeps across a circular region of the ocean. The illuminated area forms a circular sector with a radius of 1515 nautical miles and an area of 75π75\pi square nautical miles. What is the total perimeter, in nautical miles, of this illuminated sector?

  1. A
    10π10\pi
  2. B
    10π+1510\pi + 15
  3. 10π+3010\pi + 30Cevap
  4. D
    20π+3020\pi + 30
  5. E
    5π+305\pi + 30

Cevap

10π+3010\pi + 30 nautical miles
The full circle has an area of π(15)2=225π\pi(15)^2 = 225\pi. The illuminated sector's area of 75π75\pi is 75π225π=13\frac{75\pi}{225\pi} = \frac{1}{3} of the total circle. Thus, its arc length is 13\frac{1}{3} of the total circumference 2π(15)=30π2\pi(15) = 30\pi, giving an arc length of 10π10\pi. Adding the two bounding radii of length 1515 each yields a total sector perimeter of 10π+3010\pi + 30 nautical miles.

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1
Calculate the total area of the full circle.
Total Area = πr2=π(15)2=225π\pi r^2 = \pi (15)^2 = 225\pi square nautical miles.
Knowing the full circle area allows us to find what fraction of the circle the sector occupies.
2
Determine the fractional proportion of the sector relative to the whole circle.
Fraction = Sector AreaTotal Area=75π225π=13\frac{\text{Sector Area}}{\text{Total Area}} = \frac{75\pi}{225\pi} = \frac{1}{3}.
The sector represents 13\frac{1}{3} of both the total area and the total circumference of the circle.
3
Calculate the arc length of the sector.
Arc length = 13×2πr=13×30π=10π\frac{1}{3} \times 2\pi r = \frac{1}{3} \times 30\pi = 10\pi nautical miles.
The curved boundary of the sector is 13\frac{1}{3} of the circle's full circumference.
4
Calculate the total perimeter of the sector by adding the arc length and the two straight radii.
Perimeter = Arc length +2r=10π+15+15=10π+30+ 2r = 10\pi + 15 + 15 = 10\pi + 30 nautical miles.
The perimeter of a circular sector consists of its curved outer arc plus its two straight bounding radii.

Anahtar Kavram

Perimeter of a Circular Sector
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