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Zorluk: ZorFractions, Decimals, and Percentages

A manufacturer of solar panels inspects their production in three stages. In the first stage, 112\frac{1}{12} of the total panels produced are identified as defective and recycled. In the second stage, 20%20\% of the remaining non-defective panels are found to have cosmetic flaws and are sold at a discount. In the third stage, 15\frac{1}{5} of the panels that passed the first two stages without any defects or flaws are selected for quality testing. If 1,7601,760 panels passed the first two stages but were NOT selected for quality testing, what was the total number of panels originally produced?

Cevap: 3000 panels

Cevap

The total number of panels originally produced was 3,0003,000.
The correct answer of 3,0003,000 is determined by calculating the cumulative fraction of panels that are not defective, do not have cosmetic flaws, and are not selected for testing. In Stage 1, subtracting 112\frac{1}{12} leaves 1112\frac{11}{12} of the original panels. In Stage 2, subtracting 20%20\% of those leaves 80%80\% (or 45\frac{4}{5}), resulting in 1115\frac{11}{15} of the original panels. In Stage 3, subtracting 15\frac{1}{5} of these leaves 45\frac{4}{5}, resulting in 4475\frac{44}{75} of the original panels. Setting 4475\frac{44}{75} of the original panels equal to 1,7601,760 and solving for the total original panels yields 3,0003,000.

Adım Adım Çözüm

1
Calculate the fraction of panels remaining after the first stage of inspection.
1112\frac{11}{12} of the original panels
Since 112\frac{1}{12} of the total panels are defective and recycled, the remaining portion is 1112=11121 - \frac{1}{12} = \frac{11}{12}.
2
Calculate the fraction of the original panels that pass the second stage without defects or flaws.
1115\frac{11}{15} of the original panels
Of the remaining 1112\frac{11}{12} of the panels, 20%20\% have cosmetic flaws, meaning 100%20%=80%100\% - 20\% = 80\% (or 45\frac{4}{5}) do not have flaws. Multiplying these fractions gives 45×1112=1115\frac{4}{5} \times \frac{11}{12} = \frac{11}{15}.
3
Calculate the fraction of original panels that pass the first two stages but are not selected for testing.
4475\frac{44}{75} of the original panels
Since 15\frac{1}{5} of the flawless panels are selected for testing, the remaining 115=451 - \frac{1}{5} = \frac{4}{5} are not selected. Multiplying this by the fraction from Step 2 gives 45×1115=4475\frac{4}{5} \times \frac{11}{15} = \frac{44}{75}.
4
Solve for the original number of panels, PP, using the given value of 1,7601,760.
P=3,000P = 3,000 panels
Set up the equation 4475P=1,760\frac{44}{75} P = 1,760. Solving for PP gives P=1,760×7544=40×75=3,000P = 1,760 \times \frac{75}{44} = 40 \times 75 = 3,000.

Anahtar Kavram

Applying successive fractions and percentages to resolve a multi-stage word problem by working backward to the initial value.
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