Fractions, Decimals, and Percentages

61 soru

Soru 1Soru

Four different saline solutions contain varying concentrations of dissolved salt: Solution P contains 720\frac{7}{20}, Solution Q contains 36.5%36.5\%, Solution R contains 38\frac{3}{8}, and Solution S contains 0.380.38 salt concentration. Place the four solutions in order from least concentration to greatest concentration.

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Cevap

The correct order from least to greatest concentration is Solution P (7/20), Solution Q (36.5%), Solution R (3/8), and Solution S (0.38).
Converting each quantity to a decimal gives Solution P = 0.350, Solution Q = 0.365, Solution R = 0.375, and Solution S = 0.380. Ordering these decimal values from smallest to largest yields Solution P, Solution Q, Solution R, and Solution S.

Adım Adım Çözüm

1
Convert all concentration values into equivalent decimal representations.
Solution P: 720=0.350\frac{7}{20} = 0.350; Solution Q: 36.5%=0.36536.5\% = 0.365; Solution R: 38=0.375\frac{3}{8} = 0.375; Solution S: 0.38=0.3800.38 = 0.380.
Converting all numbers to decimals allows for direct numerical comparison.
2
Compare the decimal values digit by digit from left to right.
0.350<0.365<0.375<0.3800.350 < 0.365 < 0.375 < 0.380
Comparing the hundredths and thousandths places establishes the precise order.
3
Map the ordered decimal values back to their corresponding original solutions.
Solution P (0.3500.350), Solution Q (0.3650.365), Solution R (0.3750.375), Solution S (0.3800.380).
To complete the sequence from least to greatest.

Anahtar Kavram

Converting fractions, decimals, and percentages to a common numerical form (decimals) to compare and order them.
Soru 2Soru

Four students are comparing the portion of their homework assignments they have completed:

* Jamie has completed 35%35\% of his assignment.
* Kayla has completed 38\frac{3}{8} of her assignment.
* Leo has completed 0.40.4 of his assignment.
* Mia has completed 12\frac{1}{2} of her assignment.

Arrange the students by the portion of their homework completed, from least to greatest.

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Cevap

Jamie (35%35\%), Kayla (38\frac{3}{8}), Leo (0.40.4), and Mia (12\frac{1}{2})
Converting all values to decimals yields 35%=0.3535\% = 0.35, 38=0.375\frac{3}{8} = 0.375, 0.4=0.400.4 = 0.40, and 12=0.50\frac{1}{2} = 0.50. Comparing these decimals gives 0.35<0.375<0.40<0.500.35 < 0.375 < 0.40 < 0.50, which corresponds to Jamie, Kayla, Leo, and Mia.

Adım Adım Çözüm

1
Convert each portion to a decimal value to make them easy to compare.
Jamie: 35%=0.3535\% = 0.35
Kayla: 38=0.375\frac{3}{8} = 0.375
Leo: 0.4=0.400.4 = 0.40
Mia: 12=0.50\frac{1}{2} = 0.50
Converting all values to a common format (decimals) allows for direct numerical comparison.
2
Compare the decimal values from least to greatest.
0.35<0.375<0.40<0.500.35 < 0.375 < 0.40 < 0.50
This establishes the relative sizes of the portions.
3
Match each decimal back to the student and order them.
Jamie (35%35\%), Kayla (38\frac{3}{8}), Leo (0.40.4), Mia (12\frac{1}{2})
This provides the final ordered sequence.

Anahtar Kavram

Converting fractions, decimals, and percents to a single format to compare their values.
Soru 3Soru

At Oakridge High School, 35\frac{3}{5} of the students participate in extracurricular sports. Of the students who participate in extracurricular sports, 25%25\% are members of the track and field team. What percent of the total students at Oakridge High School are on the track and field team?

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Cevap: 15

Cevap

The correct answer is 15.
To find the portion of the total students on the track team, convert the fraction of students in sports to a decimal, which is 0.60. Then, multiply this by the track team percentage expressed as a decimal, which is 0.25. The product is 0.15, which represents 15% of the total student body.

Adım Adım Çözüm

1
Convert the fraction of students playing sports to a decimal
0.60
To easily multiply the two portions, convert the fraction to a decimal: 35=0.60\frac{3}{5} = 0.60.
2
Multiply the sports-participating portion by the track team percentage
0.15
To find a percentage of a decimal, convert the percentage to a decimal (25%=0.2525\% = 0.25) and multiply: 0.60×0.25=0.150.60 \times 0.25 = 0.15.
3
Convert the final decimal back to a percentage
15\%
Multiply the decimal by 100 to express the final portion as a percentage: 0.15×100=15%0.15 \times 100 = 15\%.

Anahtar Kavram

Fractions, Decimals, and Percentages
Tahmini Süre:45s
Soru 4Soru

A chef uses 13\frac{1}{3} cup of milk and 14\frac{1}{4} cup of water for a recipe. What fraction of a cup is the total liquid used in the recipe?

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Cevap: 712\frac{7}{12}

Cevap

The correct fraction of a cup of liquid is 712\frac{7}{12}.
The correct answer is found by finding a common denominator for the two fractions. The least common multiple of 3 and 4 is 12. Converting the fractions gives 412\frac{4}{12} and 312\frac{3}{12}. Adding these fractions yields 712\frac{7}{12}.

Adım Adım Çözüm

1
Identify the mathematical operation needed to find the total liquid.
The total amount of liquid is the sum of the two fractions: 13+14\frac{1}{3} + \frac{1}{4}.
To find the combined total of two separate quantities, addition is required.
2
Find a common denominator for the two fractions.
The least common multiple of 3 and 4 is 12. Convert the fractions: 13=412\frac{1}{3} = \frac{4}{12} and 14=312\frac{1}{4} = \frac{3}{12}.
Fractions must have the same denominator before they can be added.
3
Add the converted fractions.
412+312=712\frac{4}{12} + \frac{3}{12} = \frac{7}{12}.
Add the numerators together and keep the common denominator.

Anahtar Kavram

Adding fractions with unlike denominators.
Tahmini Süre:45s
Soru 5Soru

A store sells a winter coat that is originally priced at $120. During a weekend clearance sale, the coat's price is reduced by 25%. What is the sale price of the coat, in dollars?

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Cevap: 90

Cevap

The sale price of the coat is $90.
The correct answer is 90.Tofindthesaleprice,wecomputethediscountbytaking2590. To find the sale price, we compute the discount by taking 25% of 120, which is 30,andthensubtractthatdiscountfromtheoriginalpriceof30, and then subtract that discount from the original price of 120.

Adım Adım Çözüm

1
Find 25% of $120 to determine the discount amount.
$30
A 25% reduction means we calculate 120multipliedby0.25,whichequals120 multiplied by 0.25, which equals 30.
2
Subtract the discount from the original price.
$90
The sale price is the original price minus the discount: 120120 - 30 = $90.

Anahtar Kavram

Calculating a percentage markdown to determine a final price
Tahmini Süre:45s
Soru 6Soru

In a local park, 25\frac{2}{5} of the trees are maple trees and 13\frac{1}{3} of the trees are oak trees. The remaining trees are pine trees. What fraction of the trees in the park are pine trees?

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Cevap: 415\frac{4}{15}

Cevap

415\frac{4}{15}
To find the fraction of pine trees, first calculate the total fraction occupied by maple and oak trees. Finding a common denominator of 1515 for 25\frac{2}{5} and 13\frac{1}{3} gives 615+515=1115\frac{6}{15} + \frac{5}{15} = \frac{11}{15}. Subtracting this combined fraction from 11 (represented as 1515\frac{15}{15}) yields the remaining fraction of pine trees, which is 415\frac{4}{15}.

Adım Adım Çözüm

1
Find the sum of the fractions representing maple and oak trees.
25+13=615+515=1115\frac{2}{5} + \frac{1}{3} = \frac{6}{15} + \frac{5}{15} = \frac{11}{15}
Before finding the remaining fraction, we need to know the combined fraction of the park occupied by maple and oak trees.
2
Subtract the combined fraction of maple and oak trees from the whole.
11115=15151115=4151 - \frac{11}{15} = \frac{15}{15} - \frac{11}{15} = \frac{4}{15}
Since the remaining trees are pine trees, subtracting the combined fraction of other trees from the total of 11 yields the fraction of pine trees.

Anahtar Kavram

To find a remaining fractional part of a whole, first sum the known fractional parts using a common denominator, and then subtract this sum from 1.
Soru 7Soru

At the start of the fiscal year, a city's municipal budget is divided among three departments: Education, Healthcare, and Infrastructure. Education receives 38\frac{3}{8} of the total budget, Healthcare receives 40%40\% of the total budget, and Infrastructure receives the remainder. Midyear, the total municipal budget is increased by 25%25\%. The budget allocated to Education is increased by 20%20\% of its original amount, and the budget allocated to Healthcare is increased by 15%15\% of its original amount. What percent of the new total municipal budget is allocated to Infrastructure?

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Cevap: 27.2

Cevap

27.2
The correct answer is 27.2%27.2\%. By representing the initial total budget as 11, we find the initial Infrastructure allocation is 1(0.375+0.40)=0.2251 - (0.375 + 0.40) = 0.225. After the budget increase of 25%25\%, the new total budget is 1.251.25. The new Education allocation is 0.375×1.20=0.450.375 \times 1.20 = 0.45, and the new Healthcare allocation is 0.40×1.15=0.460.40 \times 1.15 = 0.46. The remaining amount for Infrastructure is 1.250.450.46=0.341.25 - 0.45 - 0.46 = 0.34. Expressing 0.340.34 as a percentage of the new total budget 1.251.25 gives 0.341.25×100%=27.2%\frac{0.34}{1.25} \times 100\% = 27.2\%.

Adım Adım Çözüm

1
Convert the initial budget allocations to decimal shares of the original total budget.
Education share is 0.3750.375, Healthcare share is 0.400.40, and Infrastructure share is 0.2250.225.
Expressing all initial shares as decimals relative to a total budget of 1.01.0 makes successive calculations straightforward.
2
Calculate the updated budget amounts for the entire city, Education, and Healthcare.
The new total budget is 1.251.25, the new Education allocation is 0.375×1.20=0.450.375 \times 1.20 = 0.45, and the new Healthcare allocation is 0.40×1.15=0.460.40 \times 1.15 = 0.46.
Adjust each allocation by its respective percentage change to find its share relative to the initial total.
3
Compute the remaining budget share left for Infrastructure.
New Infrastructure share is 1.25(0.45+0.46)=0.341.25 - (0.45 + 0.46) = 0.34 of the initial budget.
The sum of the three department budgets must equal the new total budget of 1.251.25.
4
Find the percentage of the new total budget represented by the new Infrastructure allocation.
0.341.25×100%=27.2%\frac{0.34}{1.25} \times 100\% = 27.2\%
Divide the new Infrastructure share by the new total budget to find the new ratio, then convert to a percentage.

Anahtar Kavram

Converting between fractions, decimals, and percentages, and tracking changes across multiple base values.

Alternatif Yöntem

Instead of using 1.01.0 as the base, you can assume an initial total budget of 800800 dollars (since 800800 is a multiple of 88, which simplifies 38\frac{3}{8}). Initial Education = 300300, Healthcare = 320320, Infrastructure = 180180. The new total budget is 800×1.25=1000800 \times 1.25 = 1000. New Education = 300×1.20=360300 \times 1.20 = 360. New Healthcare = 320×1.15=368320 \times 1.15 = 368. New Infrastructure = 1000(360+368)=2721000 - (360 + 368) = 272. Percentage = 2721000×100%=27.2%\frac{272}{1000} \times 100\% = 27.2\%.
Tahmini Süre:3m 0s
Soru 8Soru

An investment fund allocates its capital into three portfolios: Real Estate, Technology, and Green Energy. Initially, 14\frac{1}{4} of the total capital is allocated to Real Estate, and 25\frac{2}{5} of the total capital is allocated to Technology. The remaining capital is allocated to Green Energy. During the first year, the Real Estate portfolio decreases in value by 16%16\%, the Technology portfolio increases in value by 15%15\%, and the Green Energy portfolio increases in value by p%p\%. If the total value of the entire investment fund at the end of the first year has increased by 9%9\% of its initial value, what is the value of pp?

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Cevap: 20.020.0

Cevap

The value of pp is 20.020.0.
The correct answer is 20.020.0. By assuming a total capital of 100100 units, we find that the Real Estate portfolio starts at 2525 units, the Technology portfolio at 4040 units, and the Green Energy portfolio at 3535 units. The change in Real Estate is 4-4 units, and the change in Technology is +6+6 units. To reach a total fund increase of 99 units, the change in the Green Energy portfolio must satisfy 4+6+Change in Green Energy=9-4 + 6 + \text{Change in Green Energy} = 9, which means the Green Energy portfolio must increase by 77 units. Finding what percent 77 is of 3535 yields 735=0.20\frac{7}{35} = 0.20, or 20%20\%.

Adım Adım Çözüm

1
Determine the initial allocation of capital for each portfolio by assuming a total initial capital of 100100 units.
Real Estate receives 14×100=25\frac{1}{4} \times 100 = 25 units. Technology receives 25×100=40\frac{2}{5} \times 100 = 40 units. The remaining capital allocated to Green Energy is 100(25+40)=35100 - (25 + 40) = 35 units.
This establishes the weighted share of each portfolio relative to the total capital.
2
Calculate the changes in value for the Real Estate and Technology portfolios based on their given percentage changes.
Real Estate change: 16% of 25=0.16×25=4-16\% \text{ of } 25 = -0.16 \times 25 = -4 units. Technology change: +15% of 40=0.15×40=+6+15\% \text{ of } 40 = 0.15 \times 40 = +6 units.
This determines the absolute change in value contributed by these two portfolios.
3
Calculate the total change in value for the entire fund.
Total fund change: +9% of 100=+9+9\% \text{ of } 100 = +9 units.
The total change in the fund is the sum of the individual changes in the portfolios.
4
Set up an equation representing the sum of the changes in all three portfolios and solve for pp.
4+6+(p100×35)=9    2+0.35p=9    0.35p=7    p=20-4 + 6 + \left(\frac{p}{100} \times 35\right) = 9 \implies 2 + 0.35p = 9 \implies 0.35p = 7 \implies p = 20.
This solves for the unknown percentage rate of increase required for the Green Energy portfolio.

Anahtar Kavram

Weighted average of percentage changes using fractional and decimal representations.

Alternatif Yöntem

Instead of choosing an arbitrary starting capital of 100100, you can use decimals directly. Let CC be the total capital. The weighted changes are 0.25C(0.16)+0.40C(0.15)+0.35C(p100)=0.09C0.25C(-0.16) + 0.40C(0.15) + 0.35C\left(\frac{p}{100}\right) = 0.09C. Dividing both sides by CC yields 0.04+0.06+0.0035p=0.09-0.04 + 0.06 + 0.0035p = 0.09. Simplifying gives 0.02+0.0035p=0.09    0.0035p=0.07    p=200.02 + 0.0035p = 0.09 \implies 0.0035p = 0.07 \implies p = 20.
Tahmini Süre:3m 0s
Soru 9Soru

A laboratory technician measured the concentration of active reagent in four different solutions and recorded the values in various numerical forms: Solution W contains 716\frac{7}{16} active reagent, Solution X contains 42.5%42.5\% active reagent, Solution Y contains 0.440.44 active reagent, and Solution Z contains 49\frac{4}{9} active reagent. What is the correct order of the four solutions from the least concentration of active reagent to the greatest concentration?

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Cevap

The correct order from least to greatest concentration is Solution X (42.5%42.5\%), Solution W (716\frac{7}{16}), Solution Y (0.440.44), and Solution Z (49\frac{4}{9}).
To arrange values given in different numerical formats, convert each to decimal form: Solution X equals 0.42500.4250, Solution W equals 0.43750.4375, Solution Y equals 0.44000.4400, and Solution Z equals 0.4444...0.4444.... Arranging these decimals from least to greatest yields Solution X, Solution W, Solution Y, then Solution Z.

Adım Adım Çözüm

1
Convert all values to decimal format for direct comparison.
Solution W: 716=0.4375\frac{7}{16} = 0.4375; Solution X: 42.5%=0.42542.5\% = 0.425; Solution Y: 0.44=0.44000.44 = 0.4400; Solution Z: 49=0.4444...\frac{4}{9} = 0.4444...
Converting fractions, decimals, and percentages to a single decimal format makes order comparisons straightforward.
2
Compare the resulting decimal values place by place.
0.4250<0.4375<0.4400<0.4444...0.4250 < 0.4375 < 0.4400 < 0.4444...
Comparing digits from left to right establishes the numerical sequence.
3
Match the ordered decimals back to their corresponding solution names.
Solution X (0.4250.425) < Solution W (0.43750.4375) < Solution Y (0.440.44) < Solution Z (49\frac{4}{9})
The question requires ranking the original solution labels.

Anahtar Kavram

Converting fractions, decimals, and percentages into a uniform decimal format to compare and order rational numbers
Soru 10Soru

A community library has a collection of 250 books. If 44%44\% of these books are classified as fiction, how many fiction books are in the library's collection?

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Cevap: 110

Cevap

There are 110 fiction books in the library's collection.
To find 44%44\% of 250 books, first convert 44%44\% to a decimal by dividing by 100, which is 0.440.44. Then, multiply the decimal by the total number of books: 0.44×250=1100.44 \times 250 = 110. This represents the number of fiction books in the library.

Adım Adım Çözüm

1
Convert the percentage of fiction books to a decimal.
0.440.44
To write a percent as a decimal, divide by 100 or move the decimal point two places to the left.
2
Multiply the decimal by the total number of books to find the number of fiction books.
110110
Multiplying the decimal representing the fraction of the total by the total number of items gives the portion representing fiction books.

Anahtar Kavram

Calculating a percentage of a total amount
Tahmini Süre:45s
Soru 11Soru

A certain metal alloy is made of copper, zinc, and nickel. By weight, 14\frac{1}{4} of the alloy is copper, and 30%30\% of the alloy is zinc. What fraction of the alloy is nickel?

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Cevap: 920\frac{9}{20}

Cevap

The fraction of the alloy that is nickel is 920\frac{9}{20}.
The correct answer is the fraction representing the remaining part of the alloy after accounting for copper and zinc. First, convert 30%30\% to the fraction 310\frac{3}{10}. The combined fraction of copper and zinc is 14+310=520+620=1120\frac{1}{4} + \frac{3}{10} = \frac{5}{20} + \frac{6}{20} = \frac{11}{20}. Subtracting this combined fraction from 11 yields the fraction of nickel: 11120=9201 - \frac{11}{20} = \frac{9}{20}.

Adım Adım Çözüm

1
Convert the percentage of zinc to a fraction.
Since 30%=3010030\% = \frac{30}{100}, this simplifies to 310\frac{3}{10}.
To add or subtract the proportions of the alloy, they must be expressed in the same form (fractions).
2
Calculate the combined fraction of copper and zinc.
14+310=520+620=1120\frac{1}{4} + \frac{3}{10} = \frac{5}{20} + \frac{6}{20} = \frac{11}{20}.
To find how much of the alloy is made of copper and zinc combined, we add their individual fractions using a common denominator of 20.
3
Subtract the combined fraction from the whole to find the fraction of nickel.
11120=20201120=9201 - \frac{11}{20} = \frac{20}{20} - \frac{11}{20} = \frac{9}{20}.
Since the entire alloy represents a whole (11), the remaining portion must be nickel.

Anahtar Kavram

Expressing percentages as fractions and performing operations with fractions to solve part-to-whole problems.
Soru 12Soru

A student took a history exam containing 8080 questions. If the student answered 15%15\% of the questions incorrectly, how many questions did the student answer correctly?

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Cevap: 68

Cevap

The student answered 6868 questions correctly.
First, find the percentage of correct answers by subtracting the percentage of incorrect answers (15%15\%) from 100%100\%, which gives 85%85\%. Convert 85%85\% to a decimal (0.850.85) and multiply it by the total number of questions (8080): 80×0.85=6880 \times 0.85 = 68.

Adım Adım Çözüm

1
Calculate the percentage of questions answered correctly.
85%85\%
Subtract the percentage of incorrect questions (15%15\%) from the total (100%100\%) to find the percentage of correct questions.
2
Convert the percentage of correct questions to a decimal.
0.850.85
Divide the percentage by 100100 to express it as a decimal.
3
Multiply the total questions by the decimal value.
6868
Multiplying the total number of questions by the proportion of correct answers gives the total number of correct questions: 80×0.85=6880 \times 0.85 = 68.

Anahtar Kavram

Calculating percentages of a whole number
Soru 13Soru

During a physical education class, a student ran 14\frac{1}{4} of a mile and walked 35\frac{3}{5} of a mile. What total distance, in miles, did the student cover by running and walking?

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Cevap: 1720\frac{17}{20}

Cevap

The correct answer is 1720\frac{17}{20} miles, which represents the sum of the distances covered by running and walking.
The correct answer is found by finding a common denominator for the two fractions representing the distances. The least common multiple of 44 and 55 is 2020. Converting the fractions gives 520\frac{5}{20} and 1220\frac{12}{20}. Adding these values yields a total of 1720\frac{17}{20} miles.

Adım Adım Çözüm

1
Set up the addition expression for the two distances.
14+35\frac{1}{4} + \frac{3}{5}
To find the total distance, the distance run and the distance walked must be added together.
2
Find the least common denominator (LCD) for the fractions.
The LCD for 44 and 55 is 2020.
Fractions can only be added when they share a common denominator.
3
Convert each fraction to an equivalent fraction with the denominator of 2020.
1×54×5=520\frac{1 \times 5}{4 \times 5} = \frac{5}{20} and 3×45×4=1220\frac{3 \times 4}{5 \times 4} = \frac{12}{20}
This scales the fractions correctly so they can be combined.
4
Add the numerators together while keeping the denominator the same.
5+1220=1720\frac{5 + 12}{20} = \frac{17}{20}
Adding the numerators of fractions with like denominators gives the total fractional quantity.

Anahtar Kavram

Adding fractions with unlike denominators by finding a common denominator.

Alternatif Yöntem

Convert the fractions to decimals before adding. 14\frac{1}{4} is equivalent to 0.250.25, and 35\frac{3}{5} is equivalent to 0.600.60. Adding these decimals yields 0.25+0.60=0.850.25 + 0.60 = 0.85. Converting the decimal back to a fraction results in 85100=1720\frac{85}{100} = \frac{17}{20}.
Tahmini Süre:45s
Soru 14Soru

A laboratory mixture is prepared by combining three liquid solutions: Solution X, Solution Y, and Solution Z. Initially, Solution X makes up 20%20\% of the total volume of the mixture. Solution Y's volume is 13\frac{1}{3} of the combined volume of Solution X and Solution Z, and Solution Z makes up the remaining portion of the mixture. If 3.03.0 liters of Solution Z are added to the mixture, Solution Z then constitutes exactly 58%58\% of the new total volume. What was the original total volume, in liters, of the mixture before Solution Z was added?

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Cevap: 42

Cevap

The original total volume of the mixture was 42 liters.
The correct option represents the original volume of 4242 liters. Setting the original total volume to VV, we find that Solution X is 0.20V0.20V. Since Solution Y is one-third of the combined volume of X and Z, we write Y=13(VY)Y = \frac{1}{3}(V - Y), which simplifies to Y=0.25VY = 0.25V. The remaining portion, Solution Z, must be V0.20V0.25V=0.55VV - 0.20V - 0.25V = 0.55V. Adding 3.03.0 liters of Solution Z increases both the volume of Solution Z and the total volume of the mixture, yielding the proportion (0.55V+3)/(V+3)=0.58(0.55V + 3) / (V + 3) = 0.58. Solving this linear equation results in 0.03V=1.260.03V = 1.26, which gives V=42V = 42.

Adım Adım Çözüm

1
Express the initial fraction of Solution X as a decimal.
Solution X makes up 0.200.20 of the total volume.
Converting 20%20\% to a decimal simplifies subsequent algebraic modeling.
2
Set up an equation for the fraction of Solution Y in terms of the total volume VV.
Solution Y makes up 0.250.25 of the total volume.
If Solution Y's volume is 13\frac{1}{3} of the combined volume of Solution X and Solution Z, then Y=13(VY)Y = \frac{1}{3}(V - Y). Multiplying by 33 gives 3Y=VY3Y = V - Y, which simplifies to 4Y=V4Y = V, or Y=0.25VY = 0.25V.
3
Determine the initial fraction of Solution Z in the mixture.
Solution Z initially makes up 0.550.55 of the total volume.
Subtracting the fractions of Solution X and Solution Y from the whole yields 10.200.25=0.551 - 0.20 - 0.25 = 0.55.
4
Set up and solve the equation representing the addition of Solution Z.
V=42V = 42 liters
Adding 3.03.0 liters of Solution Z increases the volume of Solution Z to 0.55V+30.55V + 3 and the total volume to V+3V + 3. The equation is 0.55V+3V+3=0.58\frac{0.55V + 3}{V + 3} = 0.58. Multiplying both sides by V+3V + 3 yields 0.55V+3=0.58(V+3)    0.55V+3=0.58V+1.740.55V + 3 = 0.58(V + 3) \implies 0.55V + 3 = 0.58V + 1.74. Rearranging terms gives 31.74=0.58V0.55V    1.26=0.03V    V=423 - 1.74 = 0.58V - 0.55V \implies 1.26 = 0.03V \implies V = 42.

Anahtar Kavram

Solving multi-step mixture word problems using equations involving fractions, decimals, and percentages.

Alternatif Yöntem

Instead of variables for the total volume, solve the problem by tracking parts. Initially, the mixture consists of 20%20\% Solution X, 25%25\% Solution Y, and 55%55\% Solution Z. The ratio of the volume of Solution Z to the combined volume of Solution X and Solution Y is 55:4555 : 45, which simplifies to 11:911 : 9. Let the volume of X and Y combined be 9x9x liters, and the initial volume of Z be 11x11x liters, making the initial total volume 20x20x liters. Adding 3.03.0 liters of Solution Z does not change the combined volume of X and Y (9x9x liters). In the new mixture, Solution Z constitutes 58%58\%, meaning the combined volume of X and Y must constitute 100%58%=42%100\% - 58\% = 42\% of the new mixture. Thus, the new total volume is 9x/0.42=150x/79x / 0.42 = 150x / 7 liters. The difference between the new and original total volumes is the 3.03.0 liters added: (150x/7)20x=3    10x/7=3    x=2.1(150x / 7) - 20x = 3 \implies 10x / 7 = 3 \implies x = 2.1. The original total volume was 20x=20(2.1)=4220x = 20(2.1) = 42 liters.
Tahmini Süre:3m 0s
Soru 15Soru

Arrange the following numbers in order from least to greatest: 25\frac{2}{5}, 0.380.38, 45%45\%, and 0.420.42.

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Cevap

The correct order of the values from least to greatest is 0.380.38, 25\frac{2}{5}, 0.420.42, and 45%45\%.
Converting all numbers to decimals allows for direct comparison: 0.380.38 remains 0.380.38; the fraction 25\frac{2}{5} equals 0.400.40; 0.420.42 remains 0.420.42; and 45%45\% equals 0.450.45. Comparing these decimal values, we get 0.38<0.40<0.42<0.450.38 < 0.40 < 0.42 < 0.45. Therefore, the correct order from least to greatest is 0.380.38, 25\frac{2}{5}, 0.420.42, and 45%45\%.

Adım Adım Çözüm

1
Convert the fraction to a decimal.
25=0.40\frac{2}{5} = 0.40
Converting all values to decimals makes them easier to compare.
2
Convert the percentage to a decimal.
45%=0.4545\% = 0.45
Percentages represent values out of 100, so 45%=45100=0.4545\% = \frac{45}{100} = 0.45.
3
Compare the four decimal numbers.
0.38<0.40<0.42<0.450.38 < 0.40 < 0.42 < 0.45
By comparing the tenths and hundredths place, we find the correct order from smallest to largest.

Anahtar Kavram

Comparing and ordering fractions, decimals, and percents by converting them to a common decimal format.
Soru 16Soru

A water purification plant processes raw water through three successive filtration stages: Stage A, Stage B, and Stage C. Stage A removes 38\frac{3}{8} of the impurities present in the raw water. Stage B removes 40%40\% of the remaining impurities. Stage C removes 0.750.75 of the impurities that remain after Stage B. If 4.54.5 kilograms of impurities are successfully removed in Stage C, how many kilograms of impurities were originally in the raw water?

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Cevap: 16

Cevap

The original amount of impurities in the raw water was 1616 kilograms.
The correct answer is 1616 kg. To find this, we express the remaining impurities at each stage as a fraction of the initial amount xx. After Stage A, 58x\frac{5}{8}x remains. In Stage B, 40%40\% is removed, meaning 60%60\% of 58x\frac{5}{8}x, or 38x\frac{3}{8}x, remains. In Stage C, 0.750.75 (or 34\frac{3}{4}) of this remainder is removed, which is 34×38x=932x\frac{3}{4} \times \frac{3}{8}x = \frac{9}{32}x. Setting 932x=4.5\frac{9}{32}x = 4.5 gives x=16x = 16.

Adım Adım Çözüm

1
Represent the initial mass of impurities in the raw water with a variable.
Let xx be the initial kilograms of impurities.
Establishing a variable allows setting up an equation to track the changes through each stage.
2
Calculate the remaining impurities after Stage A.
Impurities remaining = x38x=58xx - \frac{3}{8}x = \frac{5}{8}x kg.
Stage A removes 38\frac{3}{8} of the initial impurities, so 138=581 - \frac{3}{8} = \frac{5}{8} of the impurities remain.
3
Calculate the impurities removed and remaining after Stage B.
Impurities removed in Stage B = 0.40×58x=14x0.40 \times \frac{5}{8}x = \frac{1}{4}x kg. Impurities remaining after Stage B = \frac{5}{8}x - \frac{1}{4}x = \frac{3}{8}x$ kg.
Stage B removes 40%40\% of the impurities that remained after Stage A. Subtracting the removed portion from the starting amount for this stage yields the remaining fraction.
4
Express the impurities removed in Stage C.
Impurities removed in Stage C = 0.75×38x=932x0.75 \times \frac{3}{8}x = \frac{9}{32}x kg.
Stage C removes 0.750.75 (or 34\frac{3}{4}) of the impurities remaining after Stage B.
5
Equate the Stage C expression to the given value and solve for xx.
932x=4.5    x=4.5×329=16\frac{9}{32}x = 4.5 \implies x = 4.5 \times \frac{32}{9} = 16 kg.
The problem states that 4.54.5 kg of impurities are removed in Stage C, so solving this equation yields the initial value.

Anahtar Kavram

Solving multi-step word problems involving successive applications of fractions, decimals, and percentages.

Alternatif Yöntem

Working backwards from the final stage can simplify the calculations. Since Stage C removes 0.750.75 of the impurities remaining after Stage B, and this amount equals 4.54.5 kg, the amount remaining after Stage B is 4.50.75=6\frac{4.5}{0.75} = 6 kg. Since Stage B removes 40%40\% of the impurities remaining after Stage A, the 66 kg represents 100%40%=60%100\% - 40\% = 60\% of the impurities remaining after Stage A. Thus, the amount remaining after Stage A is 60.60=10\frac{6}{0.60} = 10 kg. Finally, since Stage A removes 38\frac{3}{8} of the original impurities, the 1010 kg represents 138=581 - \frac{3}{8} = \frac{5}{8} of the original impurities. The original amount is therefore 10×85=1610 \times \frac{8}{5} = 16 kg.
Tahmini Süre:3m 0s
Soru 17Soru

A baker is preparing a recipe that calls for 22 times the sum of 14\frac{1}{4} cup of milk and 25\frac{2}{5} cup of water. What is the total volume, in cups, of these two liquid ingredients combined?

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Cevap: 1310\frac{13}{10}

Cevap

The correct answer is 1310\frac{13}{10} cups.
To find the total volume, first determine the sum of the two fractions by finding a common denominator: 14+25=520+820=1320\frac{1}{4} + \frac{2}{5} = \frac{5}{20} + \frac{8}{20} = \frac{13}{20} cups. Then, multiply this sum by 22 as required by the recipe: 2×1320=2620=13102 \times \frac{13}{20} = \frac{26}{20} = \frac{13}{10} cups.

Adım Adım Çözüm

1
Find a common denominator for the two fractions to be added.
The common denominator for 4 and 5 is 20, converting the fractions to 520\frac{5}{20} and 820\frac{8}{20}.
Fractions must have the same denominator before they can be added.
2
Add the two converted fractions.
520+820=1320\frac{5}{20} + \frac{8}{20} = \frac{13}{20}.
To find the sum of the ingredients inside the parentheses.
3
Multiply the sum of the fractions by 2.
2×1320=2620=13102 \times \frac{13}{20} = \frac{26}{20} = \frac{13}{10}.
The recipe calls for 2 times the sum of the two liquid ingredients.

Anahtar Kavram

Adding fractions with unlike denominators and performing operations in the correct order.
Soru 18Soru

A company allocates its annual budget to three departments: Research, Marketing, and Operations. Initially, the Research department receives 14\frac{1}{4} of the total budget. Marketing receives 40%40\% of the remaining budget, and Operations receives the rest. Mid-year, the budget is adjusted: Research's budget is decreased by 16%16\% of its initial allocation, and Marketing's budget is increased by 112\frac{1}{12} of its initial allocation. If the total company budget remains unchanged, by what percentage must the Operations department's budget increase relative to its initial allocation?

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Cevap: 313%3\frac{1}{3}\%

Cevap

The Operations department's budget must increase by 313%3\frac{1}{3}\% relative to its initial allocation.
The correct answer is 313%3\frac{1}{3}\%. Under a total budget of 1,0001,000 units, Research initially receives 250250 units, Marketing receives 300300 units (40%40\% of the remaining 750750), and Operations receives the remaining 450450 units. The mid-year decrease for Research is 4040 units (16%16\% of 250250), and the increase for Marketing is 2525 units (112\frac{1}{12} of 300300). To keep the total budget constant, the Operations budget must increase by 1515 units (402540 - 25). Relative to its initial budget of 450450 units, this represents an increase of 15450×100%=313%\frac{15}{450} \times 100\% = 3\frac{1}{3}\%.

Adım Adım Çözüm

1
Set up a total initial budget and find initial allocations for each department.
Let the total initial budget be 1,0001,000 units. Research receives 14\frac{1}{4} of the budget, which is 250250 units. The remaining budget is 1,000250=7501,000 - 250 = 750 units. Marketing receives 40%40\% of this remaining budget, which is 0.40×750=3000.40 \times 750 = 300 units. Operations receives the rest, which is 1,000250300=4501,000 - 250 - 300 = 450 units.
Establishing the initial values of each department's budget provides a base to calculate subsequent changes.
2
Calculate the mid-year budget changes for Research and Marketing.
Research decreases by 16%16\%: 0.16×250=40-0.16 \times 250 = -40 units. Marketing increases by 112\frac{1}{12}: +112×300=+25+\frac{1}{12} \times 300 = +25 units.
Finding the individual change values shows the net budget surplus or deficit before adjusting Operations.
3
Determine the required budget change for the Operations department.
To keep the total budget unchanged, the net sum of changes must be zero: 40+25+ΔO=0ΔO=+15-40 + 25 + \Delta O = 0 \Rightarrow \Delta O = +15 units.
The change in the Operations budget must balance out the changes in the other two departments.
4
Calculate the percentage increase for the Operations department relative to its initial budget.
Percentage increase = 15450×100%=130×100%=103%=313%\frac{15}{450} \times 100\% = \frac{1}{30} \times 100\% = \frac{10}{3}\% = 3\frac{1}{3}\%.
Dividing the change in Operations by its initial budget yields the relative percentage increase.

Anahtar Kavram

Calculating percentage changes across weighted parts of a whole
Soru 19Soru

Four investment options, each with a different starting value (expressed as a fraction, decimal, or percentage of a standard initial budget BB) and a specified first-year growth rate, are described below. Arrange the options in order from the lowest final value to the highest final value after the first year.

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Cevap

Option Y, Option Z, Option X, Option W
The correct order is Option Y, Option Z, Option X, Option W. Converting each initial value to a decimal fraction of BB and applying the respective growth multipliers yields: Option Y is 0.90×1.15=1.035B0.90 \times 1.15 = 1.035B, Option Z is 0.875×1.184=1.036B0.875 \times 1.184 = 1.036B, Option X is 0.85×1.22=1.037B0.85 \times 1.22 = 1.037B, and Option W is 0.80×1.30=1.040B0.80 \times 1.30 = 1.040B. Comparing these decimal values gives 1.035<1.036<1.037<1.0401.035 < 1.036 < 1.037 < 1.040.

Adım Adım Çözüm

1
Calculate the final value of Option W relative to BB.
0.80×1.30×B=1.040B0.80 \times 1.30 \times B = 1.040B
Convert the starting fraction 45\frac{4}{5} to the decimal 0.800.80. A 30%30\% increase corresponds to a multiplier of 1+0.30=1.301 + 0.30 = 1.30. Multiply these values together: 0.80×1.30=1.0400.80 \times 1.30 = 1.040.
2
Calculate the final value of Option X relative to BB.
0.85×1.22×B=1.037B0.85 \times 1.22 \times B = 1.037B
The starting decimal is 0.850.85. A 22%22\% increase corresponds to a multiplier of 1+0.22=1.221 + 0.22 = 1.22. Multiply these values together: 0.85×1.22=1.0370.85 \times 1.22 = 1.037.
3
Calculate the final value of Option Y relative to BB.
0.90×1.15×B=1.035B0.90 \times 1.15 \times B = 1.035B
Convert the starting percentage 90%90\% to the decimal 0.900.90. A 15%15\% increase corresponds to a multiplier of 1+0.15=1.151 + 0.15 = 1.15. Multiply these values together: 0.90×1.15=1.0350.90 \times 1.15 = 1.035.
4
Calculate the final value of Option Z relative to BB.
0.875×1.184×B=1.036B0.875 \times 1.184 \times B = 1.036B
Convert the starting fraction 78\frac{7}{8} to the decimal 0.8750.875. An 18.4%18.4\% increase corresponds to a multiplier of 1+0.184=1.1841 + 0.184 = 1.184. Multiply these values together: 0.875×1.184=1.0360.875 \times 1.184 = 1.036.
5
Compare the resulting multipliers to order the final values from lowest to highest.
1.035<1.036<1.037<1.0401.035 < 1.036 < 1.037 < 1.040, which translates to Option Y < Option Z < Option X < Option W.
By arranging the computed multipliers in ascending order, we find the correct sequence.

Anahtar Kavram

Converting fractions, decimals, and percentages to common decimal representations to compute and compare multi-step percentage increases.
Soru 20Soru

A school garden has flowers of three colors: red, yellow, and white. Red flowers make up 25\frac{2}{5} of the garden, yellow flowers make up 14\frac{1}{4} of the garden, and the remaining flowers are white. What percentage of the flowers in the garden are white?

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Cevap: 35%

Cevap

The percentage of white flowers in the garden is 35%.
To find the percentage of white flowers, we convert the fractional parts of the other flowers to percentages: red flowers make up 25=40%\frac{2}{5} = 40\% of the garden, and yellow flowers make up 14=25%\frac{1}{4} = 25\% of the garden. Adding these together, red and yellow flowers account for 40%+25%=65%40\% + 25\% = 65\% of the garden. Subtracting this from the total garden (100%100\%) yields 100%65%=35%100\% - 65\% = 35\% for the white flowers.

Adım Adım Çözüm

1
Convert the fraction of red flowers to a percentage.
25=0.40=40%\frac{2}{5} = 0.40 = 40\%
Converting all components to percentages allows for direct addition and subtraction.
2
Convert the fraction of yellow flowers to a percentage.
14=0.25=25%\frac{1}{4} = 0.25 = 25\%
This puts the yellow flowers in the same percentage unit as the red flowers.
3
Add the percentages of red and yellow flowers to find their combined share of the garden.
40%+25%=65%40\% + 25\% = 65\%
This gives the total portion of the garden occupied by non-white flowers.
4
Subtract the combined share from the total garden percentage (100%) to find the percentage of white flowers.
100%65%=35%100\% - 65\% = 35\%
Since the entire garden represents 100%, subtracting the non-white portion yields the remaining white portion.

Anahtar Kavram

Converting fractions to percentages to solve part-to-whole word problems.
Tahmini Süre:45s
Sayfa 1 / 4Sonraki
Fractions, Decimals, and Percentages Alıştırma Soruları — ACT | Examkin