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Zorluk: KolayLogarithmic and Exponential Expressions and Equations

If log3(x+4)=4\log_3(x + 4) = 4, what is the value of xx?

Cevap: 77

Cevap

The value of xx is 77.
The correct answer is 77. To solve the equation log3(x+4)=4\log_3(x + 4) = 4, convert the equation from its logarithmic form to its exponential form. Since logb(a)=c\log_b(a) = c means bc=ab^c = a, the equation becomes 34=x+43^4 = x + 4. Calculating 343^4 yields 81. Thus, 81=x+481 = x + 4. Subtracting 4 from both sides gives x=77x = 77.

Adım Adım Çözüm

1
Rewrite the logarithmic equation in exponential form.
x+4=34x + 4 = 3^4
By definition, logb(a)=c\log_b(a) = c is equivalent to bc=ab^c = a.
2
Calculate the value of the exponential expression.
34=813^4 = 81
34=3×3×3×3=813^4 = 3 \times 3 \times 3 \times 3 = 81.
3
Solve for xx by isolating the variable.
x=77x = 77
Subtract 4 from both sides of the equation: 814=7781 - 4 = 77.

Anahtar Kavram

Converting logarithmic equations to exponential form
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