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Zorluk: ZorComplex Numbers and Operations

For the imaginary unit ii, where i2=1i^2 = -1, let zz be the complex number defined by z=10+ki2iz = \frac{10 + ki}{2 - i}, where kk is a real constant. If the imaginary part of zz is 44, what is the value of kk?

Cevap: 5

Cevap

The value of kk is 55.
Multiplying the numerator and denominator of z=10+ki2iz = \frac{10 + ki}{2 - i} by the complex conjugate 2+i2 + i gives z=(20k)+(10+2k)i5z = \frac{(20 - k) + (10 + 2k)i}{5}. The imaginary part is 10+2k5\frac{10 + 2k}{5}. Setting this expression equal to 44 and solving for kk yields k=5k = 5.

Adım Adım Çözüm

1
Multiply the numerator and denominator of the fraction by the complex conjugate of the denominator, which is 2+i2 + i.
z=(10+ki)(2+i)(2i)(2+i)z = \frac{(10 + ki)(2 + i)}{(2 - i)(2 + i)}
To eliminate the imaginary unit from the denominator and express the complex number in standard form.
2
Expand both the numerator and the denominator, using the property i2=1i^2 = -1.
z=20+10i+2ki+ki24i2=(20k)+(10+2k)i5z = \frac{20 + 10i + 2ki + ki^2}{4 - i^2} = \frac{(20 - k) + (10 + 2k)i}{5}
To separate the real terms and imaginary terms in the numerator and simplify the denominator to a real number.
3
Express the complex number in standard form a+bia + bi to identify the imaginary part.
z=20k5+(10+2k5)iz = \frac{20 - k}{5} + \left(\frac{10 + 2k}{5}\right)i
The imaginary part of a complex number is the coefficient of ii, which is 10+2k5\frac{10 + 2k}{5}.
4
Set the imaginary part equal to 44 and solve the linear equation for kk.
10+2k5=4    10+2k=20    2k=10    k=5\frac{10 + 2k}{5} = 4 \implies 10 + 2k = 20 \implies 2k = 10 \implies k = 5
To find the specific value of the constant kk that makes the imaginary part of zz equal to 44.

Anahtar Kavram

Rationalizing complex numbers and identifying real and imaginary components
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