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Zorluk: OrtaLaw of Sines and Law of Cosines

A park planner is designing a triangular walking trail connecting three landmarks: a fountain at point FF, a gazebo at point GG, and a bridge at point BB. The distance from the fountain to the gazebo is 800800 meters, and the distance from the gazebo to the bridge is 15001{}500 meters. If the angle formed at the gazebo (FGB\angle FGB) measures 6060^\circ, what is the direct distance, in meters, from the fountain at point FF to the bridge at point BB?

Cevap: 1300 meters

Cevap

1300 meters
Applying the Law of Cosines c2=a2+b22abcos(C)c^2 = a^2 + b^2 - 2ab\cos(C) with a=800a = 800, b=1500b = 1500, and C=60C = 60^\circ gives c2=8002+150022(800)(1500)(0.5)=1690000c^2 = 800^2 + 1500^2 - 2(800)(1500)(0.5) = 1{}690{}000. Taking the square root yields c=1300c = 1300 meters.

Adım Adım Çözüm

1
Identify given measurements and formula
FG=800FG = 800 m, GB=1500GB = 1500 m, FGB=60\angle FGB = 60^\circ, using Law of Cosines c2=a2+b22abcos(C)c^2 = a^2 + b^2 - 2ab\cos(C)
Two side lengths and the included angle (SAS) are known, requiring the Law of Cosines to solve for the opposite side.
2
Substitute values into the Law of Cosines equation
FB2=8002+150022(800)(1500)cos(60)FB^2 = 800^2 + 1500^2 - 2(800)(1500)\cos(60^\circ)
Direct replacement of known side lengths and angle measure into the formula.
3
Evaluate the arithmetic terms
FB2=640000+22500001200000=1690000FB^2 = 640{}000 + 2{}250{}000 - 1{}200{}000 = 1{}690{}000
Squaring the side lengths and calculating the product 2(800)(1500)(0.5)2(800)(1500)(0.5).
4
Take the square root to solve for FBFB
FB=1690000=1300FB = \sqrt{1{}690{}000} = 1300
Taking the principal square root yields the distance in meters.

Anahtar Kavram

Law of Cosines (SAS Triangle Solving)
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