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Zorluk: OrtaComplex Numbers and Operations

For the complex number z=4+2i3iz = \frac{4 + 2i}{3 - i}, where ii is the imaginary unit such that i2=1i^2 = -1, what is the imaginary part of zz?

  1. A
    54\frac{5}{4}
  2. B
    65\frac{6}{5}
  3. C
    15\frac{1}{5}
  4. 11Cevap
  5. E
    2-2

Cevap

The imaginary part of zz is 11.
To find the imaginary part of zz, multiply the numerator and denominator of 4+2i3i\frac{4 + 2i}{3 - i} by the complex conjugate of the denominator, which is 3+i3 + i. This simplifies the denominator to 9i2=109 - i^2 = 10 and the numerator to 12+10i+2i2=10+10i12 + 10i + 2i^2 = 10 + 10i. Dividing each term by 1010 yields 1+i1 + i, which has an imaginary part of 11.

Adım Adım Çözüm

1
Identify the complex conjugate of the denominator.
The complex conjugate of the denominator, 3i3 - i, is 3+i3 + i.
To divide complex numbers, we multiply both the numerator and denominator by the conjugate of the denominator to make the denominator a real number.
2
Multiply the numerator and denominator of the fraction by the complex conjugate.
z=(4+2i)(3+i)(3i)(3+i)z = \frac{(4 + 2i)(3 + i)}{(3 - i)(3 + i)}
Multiplying by 3+i3+i\frac{3 + i}{3 + i} is equivalent to multiplying by 11, which preserves the value of the complex number.
3
Expand and simplify the numerator and denominator.
Numerator: (4+2i)(3+i)=12+4i+6i+2i2=12+10i+2(1)=10+10i(4 + 2i)(3 + i) = 12 + 4i + 6i + 2i^2 = 12 + 10i + 2(-1) = 10 + 10i. Denominator: (3i)(3+i)=9i2=9(1)=10(3 - i)(3 + i) = 9 - i^2 = 9 - (-1) = 10.
Apply the distributive property (FOIL method) and substitute i2=1i^2 = -1 to simplify the expression.
4
Divide each term in the numerator by the denominator to find the imaginary part.
z=10+10i10=1+iz = \frac{10 + 10i}{10} = 1 + i, so the imaginary part is 11.
Rewrite the fraction in standard form a+bia + bi, where the imaginary part is bb (the coefficient of ii).

Anahtar Kavram

Simplifying a quotient of complex numbers by multiplying both the numerator and the denominator by the complex conjugate of the denominator.
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