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Zorluk: OrtaLogarithmic and Exponential Expressions and Equations

If bb is a positive real number unequal to 11 such that log⁡b3=x\log_b 3 = x and log⁡b5=y\log_b 5 = y, what is the value of log⁡b(45b2)\log_b \left( \frac{45}{b^2} \right) in terms of xx and yy?

  1. 2x+y−22x + y - 2Cevap
  2. B
    x2+y−2x^2 + y - 2
  3. C
    2x+y2\frac{2x + y}{2}
  4. D
    2x+y−2b2x + y - 2b
  5. E
    2x−y−22x - y - 2

Cevap

2x+y−22x + y - 2
The correct answer is 2x+y−22x + y - 2. By applying the quotient property of logarithms, log⁡b(45b2)\log_b \left( \frac{45}{b^2} \right) is rewritten as log⁡b45−log⁡b(b2)\log_b 45 - \log_b(b^2). Factoring 4545 as 32⋅53^2 \cdot 5 allows the first term to be expanded using the product and power properties into 2log⁡b3+log⁡b52\log_b 3 + \log_b 5. Simplifying log⁡b(b2)\log_b(b^2) to 22 and substituting xx and yy yields 2x+y−22x + y - 2.

Adım Adım Çözüm

1
Apply the quotient property of logarithms.
log⁡b(45b2)=log⁡b45−log⁡b(b2)\log_b \left( \frac{45}{b^2} \right) = \log_b 45 - \log_b(b^2)
The logarithm of a quotient is the difference of the logarithms of the numerator and the denominator: log⁡b(M/N)=log⁡bM−log⁡bN\log_b(M/N) = \log_b M - \log_b N.
2
Factor the number 45 and apply the product property of logarithms.
log⁡b(32⋅5)−log⁡b(b2)=log⁡b(32)+log⁡b5−log⁡b(b2)\log_b(3^2 \cdot 5) - \log_b(b^2) = \log_b(3^2) + \log_b 5 - \log_b(b^2)
Since 45=9⋅5=32⋅545 = 9 \cdot 5 = 3^2 \cdot 5, we can use the product property: log⁡b(M⋅N)=log⁡bM+log⁡bN\log_b(M \cdot N) = \log_b M + \log_b N.
3
Apply the power property to simplify the terms.
2log⁡b3+log⁡b5−22\log_b 3 + \log_b 5 - 2
The power property states that log⁡b(Mk)=klog⁡bM\log_b(M^k) = k\log_b M. Also, log⁡b(b2)=2\log_b(b^2) = 2 because the base bb raised to the second power is b2b^2.
4
Substitute the given values x=log⁡b3x = \log_b 3 and y=log⁡b5y = \log_b 5.
2x+y−22x + y - 2
Replacing the logarithmic expressions with xx and yy gives the final simplified expression.

Anahtar Kavram

Applying logarithmic properties (quotient, product, power) to simplify expressions
Tahmini Süre:1m 0s
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