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Zorluk: OrtaBasic Algebraic Expressions and One-Step Equations

A commercial bakery uses an automated dough divider that cuts a large batch of dough of mass mm kilograms into 4848 identical portioned rolls. If each portioned roll has a mass of 0.1250.125 kilograms, what was the total mass mm, in kilograms, of the original batch of dough?

  1. A
    0.00260.0026
  2. 6.006.00Cevap
  3. C
    47.87547.875
  4. D
    48.12548.125
  5. E
    384.00384.00

Cevap

The total mass of the original batch of dough is 6.006.00 kilograms.
The scenario describes dividing a total mass mm into 4848 equal parts, where each part equals 0.1250.125 kg. Setting up the one-step division equation m48=0.125\frac{m}{48} = 0.125 and multiplying both sides by 4848 gives m=6.00m = 6.00 kilograms.

Adım Adım Çözüm

1
Define the algebraic relationship based on the problem description.
m48=0.125\frac{m}{48} = 0.125
Dividing the total mass mm into 4848 equal pieces yields the mass of one individual roll.
2
Isolate the variable mm by performing the inverse operation.
m=48×0.125m = 48 \times 0.125
Multiply both sides of the equation by 4848 to cancel out the denominator.
3
Calculate the numerical product.
m=6.00m = 6.00
48×0.125=6.0048 \times 0.125 = 6.00 kilograms.

Anahtar Kavram

Basic Algebraic Expressions and One-Step Equations
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