A museum archivist digitizes a collection of historical glass-plate photographs at a const… — ACT

A museum archivist digitizes a collection of historical glass-plate photographs at a constant rate of $p$ photographs per hour. If the archivist digitizes a total of $336$ photographs over a continuous $14$ -hour shift, which of the following equations can be solved to find $p$ ?

A
$p + 14 = 336$
B
$\frac{p}{14} = 336$
$14p = 336$ Cevap
D
$p - 14 = 336$
E
$14 + 336 = p$

Cevap

The correct equation is

14p = 336

The total number of digitized photographs equals the rate per hour (

p

) multiplied by the number of hours (

14

). Setting this product equal to the total of

336

photographs yields

14p = 336

Adım Adım Çözüm

Identify the relationship between rate, time, and total quantity.

\text{Total Quantity} = \text{Rate} \times \text{Time}

The total work done at a constant rate is found by multiplying the rate per unit of time by total time.

Substitute the given values into the relationship.

336 = p \times 14

, which simplifies to

14p = 336

The rate is

p

photographs per hour, time is

14

hours, and total quantity is

336

photographs.

Anahtar Kavram

Writing one-step multiplication equations from rate and time word problems

Tahmini Süre:1m 0s

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Cevap

Adım Adım Çözüm

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