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Zorluk: OrtaFractions, Decimals, and Percentages

A solar power system generated a total of 450450 kilowatt-hours (kWh) of electricity during a 3-day period. On Day 1, the system generated 29\frac{2}{9} of the total 3-day electricity. On Day 2, it generated 40%40\% of the remaining electricity after Day 1. How many kilowatt-hours of electricity were generated on Day 3?

Cevap: 210 kWh

Cevap

210 kWh
To find the electricity generated on Day 3, first determine the Day 1 portion by multiplying 29\frac{2}{9} by 450450, which gives 100100 kWh. The amount remaining for Days 2 and 3 is 450100=350450 - 100 = 350 kWh. Day 2 accounts for 40%40\% of this remaining amount, which is 0.40×350=1400.40 \times 350 = 140 kWh. Finally, subtract Day 2's portion from the remaining amount: 350140=210350 - 140 = 210 kWh.

Adım Adım Çözüm

1
Calculate the amount of electricity generated on Day 1.
100100 kWh
Multiply the fraction 29\frac{2}{9} by the total electricity (450450 kWh).
2
Determine the remaining electricity after Day 1.
350350 kWh
Subtract Day 1's generation (100100 kWh) from the total amount (450450 kWh).
3
Calculate the amount of electricity generated on Day 2.
140140 kWh
Convert 40%40\% to a decimal (0.400.40) and multiply by the remaining 350350 kWh.
4
Calculate the amount of electricity generated on Day 3.
210210 kWh
Subtract Day 2's generation (140140 kWh) from the 350350 kWh remaining after Day 1.

Anahtar Kavram

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