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Zorluk: OrtaEvaluating Algebraic Expressions

If x=2x = -2, y=5y = 5, and z=12z = -\frac{1}{2}, what is the value of the algebraic expression x3y+z2y2x\frac{x^3 y + z^{-2}}{y - 2x}?

Cevap: -4

Cevap

The value of the expression is -4.
Substituting x=2x = -2, y=5y = 5, and z=12z = -\frac{1}{2} into the expression yields x3y=(2)3(5)=40x^3 y = (-2)^3(5) = -40 and z2=(12)2=4z^{-2} = \left(-\frac{1}{2}\right)^{-2} = 4, making the numerator 40+4=36-40 + 4 = -36. Evaluating the denominator gives y2x=52(2)=9y - 2x = 5 - 2(-2) = 9. Dividing 36-36 by 99 results in 4-4.

Adım Adım Çözüm

1
Evaluate the terms in the numerator individually.
x3y=(2)3(5)=40x^3 y = (-2)^3(5) = -40 and z2=(12)2=4z^{-2} = \left(-\frac{1}{2}\right)^{-2} = 4.
Negative bases raised to odd powers retain a negative sign, while negative exponents represent the reciprocal raised to a positive power.
2
Calculate the total numerator value.
40+4=36-40 + 4 = -36.
Summing the two evaluated terms gives the complete numerator.
3
Evaluate the denominator expression.
y2x=52(2)=5+4=9y - 2x = 5 - 2(-2) = 5 + 4 = 9.
Subtracting a negative quantity is equivalent to adding its positive counterpart.
4
Divide the numerator by the denominator.
369=4.\frac{-36}{9} = -4.
Dividing a negative integer by a positive integer yields a negative quotient.

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Evaluating Algebraic Expressions with Negative Integers and Negative Exponents
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