If a=−4a = -4a=−4 and b=7b = 7b=7, what is the value of the algebraic expression (a+b)2−3a(a + b)^2 - 3a(a+b)2−3a?A-3B1821CevapD45E77Cevap21Substituting a=−4a = -4a=−4 and b=7b = 7b=7 into (a+b)2−3a(a + b)^2 - 3a(a+b)2−3a gives ((−4)+7)2−3(−4)=(3)2+12=9+12=21((-4) + 7)^2 - 3(-4) = (3)^2 + 12 = 9 + 12 = 21((−4)+7)2−3(−4)=(3)2+12=9+12=21.Adım Adım Çözüm1Substitute the given values into the expression((−4)+7)2−3(−4)((-4) + 7)^2 - 3(-4)((−4)+7)2−3(−4)Replace aaa with −4-4−4 and bbb with 777.2Simplify inside the parentheses(3)2−3(−4)(3)^2 - 3(-4)(3)2−3(−4)Following order of operations (PEMDAS), simplify −4+7=3-4 + 7 = 3−4+7=3 first.3Evaluate the exponent and multiplication9+129 + 129+12Square 333 to get 999, and multiply −3-3−3 by −4-4−4 to get +12+12+12.4Add the terms together21Combine 999 and 121212.Anahtar KavramEvaluating Algebraic ExpressionsSık Yapılan Hatalar