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Zorluk: OrtaCircle Geometry: Arc Length and Sector Area

A garden bed is designed in the shape of a sector of a circle with a central angle measuring 120120^\circ. If the total perimeter of the sector-shaped garden bed is 24+8π24 + 8\pi feet, what is the area of the garden bed, in square feet?

  1. A
    8π8\pi
  2. B
    24π24\pi
  3. 48π48\piCevap
  4. D
    96π96\pi
  5. E
    144π144\pi

Cevap

The area of the garden bed is 48π48\pi square feet.
The perimeter of a sector is given by 2r+θ360(2πr)2r + \frac{\theta}{360^\circ}(2\pi r). Substituting θ=120\theta = 120^\circ gives 2r+2πr3=24+8π2r + \frac{2\pi r}{3} = 24 + 8\pi, which simplifies to r=12r = 12 feet. Using the sector area formula θ360πr2\frac{\theta}{360^\circ}\pi r^2 with r=12r = 12 yields 13π(144)=48π\frac{1}{3}\pi(144) = 48\pi square feet.

Adım Adım Çözüm

1
Set up the formula for the perimeter of a sector.
Perimeter =2r+Arc Length=2r+(θ360)(2πr)= 2r + \text{Arc Length} = 2r + \left(\frac{\theta}{360^\circ}\right)(2\pi r)
A sector's perimeter consists of two straight radii and the curved arc boundary.
2
Substitute θ=120\theta = 120^\circ into the perimeter expression and solve for the radius rr.
2r+(120360)(2πr)=24+8π    2r+2πr3=24+8π    r(2+2π3)=12(2+2π3)    r=122r + \left(\frac{120^\circ}{360^\circ}\right)(2\pi r) = 24 + 8\pi \implies 2r + \frac{2\pi r}{3} = 24 + 8\pi \implies r\left(2 + \frac{2\pi}{3}\right) = 12\left(2 + \frac{2\pi}{3}\right) \implies r = 12 feet
Equating the algebraic expression to the given perimeter allows finding the circle radius.
3
Calculate the sector area using r=12r = 12 feet and θ=120\theta = 120^\circ.
Area =(120360)πr2=13π(12)2=144π3=48π= \left(\frac{120^\circ}{360^\circ}\right) \pi r^2 = \frac{1}{3} \pi (12)^2 = \frac{144\pi}{3} = 48\pi square feet
The area of a sector is the fraction of the total circle's area defined by the ratio of central angle to 360360^\circ.

Anahtar Kavram

Perimeter and Area of a Circle Sector
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