Soru

Zorluk: OrtaEvaluating Algebraic Expressions

Evaluate the algebraic expression 3x2−2xy+y23x^2 - 2xy + y^2 for x=−3x = -3 and y=−2y = -2.

Cevap:The value of the expression 3x2−2xy+y23x^2 - 2xy + y^2 when x=−3x = -3 and y=−2y = -2 is 【19】.

Cevap

19
Substituting x=−3x = -3 and y=−2y = -2 into 3x2−2xy+y23x^2 - 2xy + y^2 yields 3(−3)2−2(−3)(−2)+(−2)2=3(9)−12+4=27−12+4=193(-3)^2 - 2(-3)(-2) + (-2)^2 = 3(9) - 12 + 4 = 27 - 12 + 4 = 19.

Adım Adım Çözüm

1
Substitute x=−3x = -3 and y=−2y = -2 into the expression
3(−3)2−2(−3)(−2)+(−2)23(-3)^2 - 2(-3)(-2) + (-2)^2
Replace each variable with its assigned value, using parentheses to properly preserve negative signs.
2
Evaluate the exponent terms
3(9)−2(−3)(−2)+43(9) - 2(-3)(-2) + 4
Follow the order of operations (PEMDAS) by evaluating powers first: (−3)2=9(-3)^2 = 9 and (−2)2=4(-2)^2 = 4.
3
Perform the multiplications
27−12+427 - 12 + 4
Multiply the numerical factors: 3×9=273 \times 9 = 27 and −2×(−3)×(−2)=−12-2 \times (-3) \times (-2) = -12.
4
Perform addition and subtraction from left to right
1919
Subtract 1212 from 2727 to get 1515, then add 44 to arrive at 1919.

Anahtar Kavram

Evaluating Algebraic Expressions with Negative Values
Bu soruyu puanla