Tüm alıştırma soruları

541 soru

Soru 341Soru

In the right trapezoid ABCDABCD below, ABAB is parallel to CDCD, and the measures of A\angle A and D\angle D are both 9090^\circ. The length of CDCD is 77, the length of BCBC is 88, and the measure of B\angle B is 6060^\circ. What is the length of the diagonal BDBD?

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Cevap: 13

Cevap

13
By drawing altitude CECE perpendicular to ABAB, we form rectangle AECDAECD and right triangle CEB\triangle CEB. Since B=60\angle B = 60^\circ, CEB\triangle CEB is a 3030^\circ-6060^\circ-9090^\circ triangle with hypotenuse BC=8BC = 8. The side opposite 3030^\circ is BE=8/2=4BE = 8/2 = 4, and the side opposite 6060^\circ is CE=43CE = 4\sqrt{3}. Since opposite sides of rectangle AECDAECD are equal, we find AD=CE=43AD = CE = 4\sqrt{3} and AE=CD=7AE = CD = 7. Thus, AB=AE+BE=7+4=11AB = AE + BE = 7 + 4 = 11. Finally, we apply the Pythagorean Theorem to right triangle DAB\triangle DAB: BD2=AD2+AB2=(43)2+112=48+121=169BD^2 = AD^2 + AB^2 = (4\sqrt{3})^2 + 11^2 = 48 + 121 = 169, yielding BD=13BD = 13.

Adım Adım Çözüm

1
Decompose the trapezoid by drawing an altitude from CC perpendicular to ABAB, meeting it at EE.
This forms a rectangle AECDAECD and a right triangle CEBCEB.
Decomposing the figure allows us to use right triangle trigonometry and parallel line relationships to determine missing side lengths.
2
Calculate the lengths of the legs of right triangle CEBCEB.
BE=4BE = 4 and CE=43CE = 4\sqrt{3}.
Since B=60\angle B = 60^\circ, CEB\triangle CEB is a 3030^\circ-6060^\circ-9090^\circ triangle. The shorter leg BEBE is half the hypotenuse BCBC, and the longer leg CECE is the shorter leg times 3\sqrt{3}.
3
Determine the lengths of ADAD and ABAB.
AD=43AD = 4\sqrt{3} and AB=11AB = 11.
In the rectangle AECDAECD, opposite sides are equal, so AD=CE=43AD = CE = 4\sqrt{3} and AE=CD=7AE = CD = 7. Thus, the base AB=AE+BE=7+4=11AB = AE + BE = 7 + 4 = 11.
4
Use the Pythagorean Theorem in right triangle DABDAB to solve for BDBD.
BD=13BD = 13.
In right triangle DABDAB, the legs are AD=43AD = 4\sqrt{3} and AB=11AB = 11. The hypotenuse BDBD satisfies BD2=AD2+AB2=(43)2+112=48+121=169BD^2 = AD^2 + AB^2 = (4\sqrt{3})^2 + 11^2 = 48 + 121 = 169, so BD=169=13BD = \sqrt{169} = 13.

Anahtar Kavram

Solving multi-step geometry problems by decomposing shapes into rectangles and special right triangles (3030^\circ-6060^\circ-9090^\circ), then applying the Pythagorean Theorem.
Soru 342Soru

A circle in the standard (x,y)(x, y) coordinate plane is described by the equation x2+y2=25x^2 + y^2 = 25. A line is described by the equation 3x4y=c3x - 4y = c, where cc is a positive constant. If the system of these two equations has exactly one real solution for (x,y)(x, y), what is the value of cc?

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Cevap: 25

Cevap

The value of cc is 2525.
The correct answer is 2525. The equation x2+y2=25x^2 + y^2 = 25 represents a circle centered at (0,0)(0, 0) with a radius of 55. For the system of equations to have exactly one real solution, the line 3x4y=c3x - 4y = c must be tangent to the circle. The perpendicular distance from the center (0,0)(0,0) to the line 3x4yc=03x - 4y - c = 0 is given by 3(0)4(0)c32+(4)2=c5\frac{|3(0) - 4(0) - c|}{\sqrt{3^2 + (-4)^2}} = \frac{|c|}{5}. Setting this distance equal to the radius of the circle yields c5=5\frac{|c|}{5} = 5, which gives c=25|c| = 25. Since cc is specified as a positive constant, cc must be 2525.

Adım Adım Çözüm

1
Find the center and radius of the circle.
Center is (0,0)(0, 0) and radius is r=5r = 5.
The circle equation x2+y2=25x^2 + y^2 = 25 is in the standard form x2+y2=r2x^2 + y^2 = r^2 centered at the origin with radius r=25=5r = \sqrt{25} = 5.
2
Set up the condition for tangency (exactly one real solution).
The perpendicular distance from the center (0,0)(0,0) to the line 3x4yc=03x - 4y - c = 0 must equal the radius 55.
A line intersects a circle at exactly one point if and only if the line is tangent to the circle.
3
Apply the point-to-line distance formula.
Distance d=3(0)4(0)c32+(4)2=c5d = \frac{|3(0) - 4(0) - c|}{\sqrt{3^2 + (-4)^2}} = \frac{|c|}{5}.
The formula for the distance from (x0,y0)(x_0, y_0) to the line Ax+By+C=0Ax + By + C = 0 is d=Ax0+By0+CA2+B2d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}}.
4
Solve for the positive constant cc.
c=25c = 25
Setting the distance c5\frac{|c|}{5} equal to the radius 55 gives c=25|c| = 25. Since cc is a positive constant, c=25c = 25.

Anahtar Kavram

Determining conditions for tangency in a system of linear and circular equations.

Alternatif Yöntem

Instead of using the geometric distance formula, the system can be solved algebraically by substitution. Express yy in terms of xx from the linear equation: y=3xc4y = \frac{3x - c}{4}. Substitute this expression into the circle's equation: x2+(3xc4)2=25x^2 + \left(\frac{3x - c}{4}\right)^2 = 25. Expand the terms and multiply by 1616 to clear the denominator: 16x2+9x26cx+c2=40016x^2 + 9x^2 - 6cx + c^2 = 400, which simplifies to the quadratic equation 25x26cx+(c2400)=025x^2 - 6cx + (c^2 - 400) = 0. For the system to have exactly one solution, this quadratic equation must have a discriminant equal to zero. Calculate the discriminant: D=(6c)24(25)(c2400)=36c2100c2+40000=64c2+40000=0D = (-6c)^2 - 4(25)(c^2 - 400) = 36c^2 - 100c^2 + 40000 = -64c^2 + 40000 = 0. Solving for cc yields 64c2=40000    c2=62564c^2 = 40000 \implies c^2 = 625. Since cc is a positive constant, c=25c = 25.
Tahmini Süre:1m 30s
Soru 343Soru

One of the solutions to the quadratic equation 0.5x2+bx6=00.5x^2 + bx - 6 = 0, where bb is a constant, is x=3x = 3. What is the value of the other solution?

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Cevap: -4

Cevap

The other solution to the quadratic equation is -4.
Substituting the given solution x=3x = 3 into the equation yields 0.5(3)2+3b6=00.5(3)^2 + 3b - 6 = 0. Simplifying this expression gives 4.5+3b6=04.5 + 3b - 6 = 0, which leads to 3b=1.53b = 1.5 and thus b=0.5b = 0.5. With b=0.5b = 0.5, the quadratic equation becomes 0.5x2+0.5x6=00.5x^2 + 0.5x - 6 = 0. Multiplying the entire equation by 2 to obtain integer coefficients results in x2+x12=0x^2 + x - 12 = 0. This quadratic factors into (x3)(x+4)=0(x - 3)(x + 4) = 0, which gives the solutions x=3x = 3 and x=4x = -4. Therefore, the other solution is 4-4. Alternatively, using Vieta's formulas, the product of the roots of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is equal to c/ac/a. Here, the product of the roots is 6/0.5=12-6 / 0.5 = -12. Since one root is 33, the other root must be 12/3=4-12 / 3 = -4.

Adım Adım Çözüm

1
Substitute the given solution x=3x = 3 into the quadratic equation to find the value of bb.
b=0.5b = 0.5
Since x=3x = 3 is a solution, it must satisfy the equation, allowing us to solve for the unknown coefficient bb.
2
Rewrite the equation using b=0.5b = 0.5 and simplify by multiplying all terms by 2.
x2+x12=0x^2 + x - 12 = 0
Multiplying the equation by 2 eliminates the decimal coefficients, making the quadratic expression easier to factor.
3
Factor the quadratic equation to determine the roots.
x=3x = 3 or x=4x = -4
The equation factors into (x3)(x+4)=0(x - 3)(x + 4) = 0. Solving for xx yields the given root of 3 and the second root of -4.

Anahtar Kavram

Solving quadratic equations by utilizing a known solution to determine unknown coefficients, and applying factoring techniques or root relationships to find the remaining solution.
Tahmini Süre:1m 30s
Soru 344Soru

In ABC\triangle ABC, the measure of exterior angle ACD\angle ACD is 135135^\circ, where DD lies on the extension of side BCBC past CC. If the measure of interior angle A\angle A is 2525^\circ greater than the measure of interior angle B\angle B, what is the measure, in degrees, of B\angle B?

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Cevap: 55

Cevap

55
According to the Exterior Angle Theorem, the measure of exterior angle ACD\angle ACD is equal to the sum of the measures of its remote interior angles, A\angle A and B\angle B. This gives the equation mA+mB=135\text{m}\angle A + \text{m}\angle B = 135^\circ. Using the information that mA=mB+25\text{m}\angle A = \text{m}\angle B + 25^\circ, we substitute this expression into the equation to get (mB+25)+mB=135(\text{m}\angle B + 25^\circ) + \text{m}\angle B = 135^\circ. Simplifying this equation gives 2mB+25=1352\text{m}\angle B + 25 = 135, which simplifies to 2mB=1102\text{m}\angle B = 110, and dividing by 2 yields mB=55\text{m}\angle B = 55^\circ.

Adım Adım Çözüm

1
Apply the Exterior Angle Theorem to express the relation between the exterior angle and the two remote interior angles.
mA+mB=135\text{m}\angle A + \text{m}\angle B = 135^\circ
The measure of an exterior angle of a triangle is equal to the sum of the measures of its two remote interior angles.
2
Substitute the relationship between the interior angles into the equation.
(mB+25)+mB=135(\text{m}\angle B + 25^\circ) + \text{m}\angle B = 135^\circ
The problem states that the measure of interior angle A\angle A is 2525^\circ greater than the measure of interior angle B\angle B.
3
Solve the algebraic equation for the measure of interior angle B\angle B.
mB=55\text{m}\angle B = 55^\circ
Combining like terms gives 2mB+25=1352\text{m}\angle B + 25 = 135. Subtracting 25 from both sides gives 2mB=1102\text{m}\angle B = 110. Dividing by 2 yields mB=55\text{m}\angle B = 55^\circ.

Anahtar Kavram

Exterior Angle Theorem and remote interior angles relation
Soru 345Soru

A convex polygon has nn sides. The sum of the measures of its interior angles is 33 times the sum of the measures of its exterior angles. What is the value of nn?

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Cevap: 8

Cevap

8
The sum of the interior angle measures of an nn-sided convex polygon is (n2)×180(n-2) \times 180^\circ. The sum of the exterior angle measures is always 360360^\circ. According to the problem, the sum of the interior angles is 33 times the sum of the exterior angles, which can be written as the equation (n2)×180=3×360(n-2) \times 180 = 3 \times 360. Simplifying the right side gives (n2)×180=1080(n-2) \times 180 = 1080. Dividing both sides by 180180 results in n2=6n - 2 = 6. Adding 22 to both sides yields n=8n = 8.

Adım Adım Çözüm

1
Use the formula for the sum of the interior angle measures of a convex polygon with nn sides.
The sum of the interior angles is (n2)×180(n-2) \times 180^\circ.
By the polygon interior angle sum theorem, the sum of the interior angles of any convex nn-gon is (n2)×180(n-2) \times 180^\circ.
2
Identify the sum of the exterior angle measures of a convex polygon.
The sum of the exterior angles is 360360^\circ.
The sum of the exterior angles of any convex polygon is always constant and equals 360360^\circ, regardless of the number of sides.
3
Set up the equation relating the two sums as given in the problem statement.
(n2)×180=3×360(n-2) \times 180^\circ = 3 \times 360^\circ
The problem states that the sum of the interior angles is 33 times the sum of the exterior angles.
4
Solve the equation for nn.
n=8n = 8
Divide both sides by 180180^\circ to get n2=6n - 2 = 6, then add 22 to both sides to find n=8n = 8.

Anahtar Kavram

The sum of the interior angles of a convex polygon with nn sides is (n2)×180(n-2) \times 180^\circ, and the sum of its exterior angles is 360360^\circ.
Soru 346Soru

What is the greatest integer value of kk that satisfies the inequality 83(2k5)4(k+6)8 - 3(2k - 5) \geq 4(k + 6)?

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Cevap: -1

Cevap

The greatest integer value of kk that satisfies the inequality is 1-1.
Solving the inequality step-by-step yields k0.1k \leq -0.1. The greatest integer less than or equal to 0.1-0.1 is 1-1.

Adım Adım Çözüm

1
Distribute the coefficients to remove parentheses
86k+154k+248 - 6k + 15 \geq 4k + 24
Expanding the terms makes it possible to combine like terms on each side of the inequality.
2
Combine like terms on the left side
236k4k+2423 - 6k \geq 4k + 24
Simplifying the constant values on the left side (8+15=238 + 15 = 23) simplifies the expression.
3
Subtract 4k4k from both sides
2310k2423 - 10k \geq 24
This groups all the variable terms on the left-hand side.
4
Subtract 2323 from both sides
10k1-10k \geq 1
This isolates the variable term on the left-hand side.
5
Divide by 10-10 and flip the inequality sign
k0.1k \leq -0.1
Dividing both sides by a negative number requires reversing the direction of the inequality sign.
6
Identify the greatest integer satisfying the inequality
k=1k = -1
The largest integer that is less than or equal to 0.1-0.1 is 1-1.

Anahtar Kavram

Solving linear inequalities and applying the sign-flip rule when dividing by a negative number.
Tahmini Süre:1m 30s
Soru 347Soru

A regular decagon has 1010 sides of equal length. What is the measure, in degrees, of one exterior angle of this decagon?

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Cevap: 36

Cevap

The correct answer is 36.
The sum of the exterior angles of any convex polygon is always 360360^\circ. A regular decagon has 1010 congruent sides and therefore 1010 congruent exterior angles. Dividing 360360^\circ by 1010 yields 3636^\circ for each exterior angle.

Adım Adım Çözüm

1
Determine the number of exterior angles in a regular decagon.
A decagon has 10 sides, so it has 10 exterior angles.
A polygon has the same number of exterior angles as its number of sides.
2
State the sum of the exterior angles for a convex polygon.
The sum of the exterior angles is 360 degrees.
The exterior angles of any convex polygon always sum to 360 degrees regardless of the number of sides.
3
Calculate the measure of one exterior angle.
360 / 10 = 36
Since the decagon is regular, all of its exterior angles are equal in measure, so we divide the total sum by the number of angles.

Anahtar Kavram

The sum of the exterior angles of any convex polygon is 360360^\circ. For a regular polygon with nn sides, the measure of each exterior angle is 360n\frac{360^\circ}{n}.
Soru 348Soru

A business analyst models a company's weekly net profit, N(x)N(x), in dollars, as the difference between its weekly revenue, R(x)=(2x+5)(30x)R(x) = (2x + 5)(30 - x), and its weekly production cost, C(x)=(x4)2+150C(x) = (x - 4)^2 + 150, where xx represents the number of items sold. When N(x)N(x) is simplified and written in standard form as ax2+bx+cax^2 + bx + c, where aa, bb, and cc are integers, what is the value of the coefficient bb?

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Cevap: 63

Cevap

The coefficient bb is 6363.
Expanding the revenue polynomial gives R(x)=2x2+55x+150R(x) = -2x^2 + 55x + 150 and the cost polynomial gives C(x)=x28x+166C(x) = x^2 - 8x + 166. Subtracting them gives N(x)=(2x2+55x+150)(x28x+166)=3x2+63x16N(x) = (-2x^2 + 55x + 150) - (x^2 - 8x + 166) = -3x^2 + 63x - 16. The coefficient of the xx term, which corresponds to bb, is 6363.

Adım Adım Çözüm

1
Expand the revenue expression R(x)=(2x+5)(30x)R(x) = (2x + 5)(30 - x) using polynomial multiplication.
R(x)=2x2+55x+150R(x) = -2x^2 + 55x + 150
To find the polynomial representing revenue in standard form.
2
Expand the cost expression C(x)=(x4)2+150C(x) = (x - 4)^2 + 150 using binomial squaring.
C(x)=x28x+166C(x) = x^2 - 8x + 166
To find the polynomial representing cost in standard form.
3
Subtract the cost polynomial from the revenue polynomial: N(x)=R(x)C(x)N(x) = R(x) - C(x), distributing the negative sign through all terms of the cost polynomial.
N(x)=3x2+63x16N(x) = -3x^2 + 63x - 16
To determine the net profit polynomial N(x)N(x) in standard form.
4
Identify the coefficient bb of the xx term in the standard form ax2+bx+cax^2 + bx + c.
b=63b = 63
To answer the specific question asking for the coefficient of the middle term.

Anahtar Kavram

Polynomial subtraction and expansion of algebraic expressions.
Soru 349Soru

An irregular convex polygon has nn sides. The measures of its interior angles, in degrees, are all distinct integers. If all of the interior angles are obtuse, what is the maximum possible value of nn?

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Cevap: 26

Cevap

The maximum possible value of nn is 26.
For a convex 2626-gon, the sum of the interior angles is 24×180=432024 \times 180^\circ = 4320^\circ. We can choose 2626 distinct integer angles from the range [91,179][91^\circ, 179^\circ] that sum to exactly 43204320^\circ because the maximum possible sum of 2626 distinct integers in this range is 43294329^\circ, which is greater than 43204320^\circ. For n=27n = 27, the sum of the interior angles must be 25×180=450025 \times 180^\circ = 4500^\circ, but the maximum possible sum of 2727 distinct integers in the range is only 44824482^\circ, which is less than 45004500^\circ. Therefore, 2626 is the maximum value of nn.

Adım Adım Çözüm

1
Determine the set of possible angle measures.
The angles must be integers in the range [91,179][91^\circ, 179^\circ].
Interior angles of a convex polygon must be less than 180180^\circ. Since they are obtuse and distinct integers, they must be strictly greater than 9090^\circ, giving the range [91,179][91, 179].
2
Write the sum of the interior angles of a convex nn-gon.
Sum =(n2)×180= (n - 2) \times 180^\circ.
This is the standard formula for the sum of the interior angles of any convex nn-gon.
3
Find the maximum possible sum of nn distinct angles in the range [91,179][91, 179].
Maximum Sum =179nn(n1)2= 179n - \frac{n(n - 1)}{2}.
The maximum sum is achieved by selecting the largest nn integers from the set: 179,178,,179(n1)179, 178, \dots, 179 - (n - 1).
4
Set up the inequality and simplify.
n2+n7200n^2 + n - 720 \le 0.
Since the sum of the angles must be less than or equal to the maximum possible sum, we have (n2)×180179nn(n1)2(n-2) \times 180 \le 179n - \frac{n(n-1)}{2}. Multiplying by 2 and simplifying yields the quadratic inequality.
5
Solve the quadratic inequality for the largest integer nn.
n=26n = 26.
Evaluating the quadratic expression for consecutive integers: for n=26n = 26, 262+26720=18026^2 + 26 - 720 = -18 \le 0; for n=27n = 27, 272+27720=36>027^2 + 27 - 720 = 36 > 0. Thus, 26 is the maximum possible integer value.

Anahtar Kavram

Sum of interior angles of a convex polygon combined with algebraic optimization.
Soru 350Soru

A convex polygon has nn sides. The sum of the measures of its interior angles is 66 times the sum of the measures of its exterior angles (one at each vertex). What is the value of nn?

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Cevap: 14

Cevap

The number of sides, nn, of the convex polygon is 14.
The sum of the interior angles of a convex polygon with nn sides is given by the formula (n2)×180(n-2) \times 180^\circ, and the sum of its exterior angles is always 360360^\circ. According to the problem, the sum of the interior angles is 66 times the sum of the exterior angles, yielding the equation (n2)×180=6×360(n - 2) \times 180 = 6 \times 360. Dividing both sides of the equation by 180180 gives n2=12n - 2 = 12. Adding 22 to both sides results in n=14n = 14.

Adım Adım Çözüm

1
State the sum of interior and exterior angles formulas.
Interior sum = (n2)×180(n-2) \times 180^\circ, Exterior sum = 360360^\circ.
To represent the geometric properties of the polygon algebraically.
2
Set up the equation based on the given ratio.
(n2)×180=6×360(n-2) \times 180 = 6 \times 360.
The problem states the interior sum is 6 times the exterior sum.
3
Solve the equation for nn.
n=14n = 14.
Divide by 180 to get n2=12n - 2 = 12, then add 2 to both sides.

Anahtar Kavram

The sum of the interior angles of an nn-sided convex polygon is (n2)×180(n-2) \times 180^\circ, and the sum of the exterior angles (one per vertex) is always 360360^\circ.
Soru 351Soru

In the quadratic equation 2x211x+c=02x^2 - 11x + c = 0, where cc is a constant, the ratio of the two real solutions is 3:83:8. What is the value of cc?

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Cevap: 12

Cevap

The value of the constant cc is 1212.
The correct answer is 1212. By representing the roots in the ratio of 3:83:8 as 3r3r and 8r8r, Vieta's formula for the sum of roots (ba-\frac{b}{a}) gives 3r+8r=112    11r=5.5    r=0.53r + 8r = -\frac{-11}{2} \implies 11r = 5.5 \implies r = 0.5. The actual roots are therefore 1.51.5 and 44. Using Vieta's formula for the product of roots (ca\frac{c}{a}) gives (1.5)(4)=c2    6=c2    c=12(1.5)(4) = \frac{c}{2} \implies 6 = \frac{c}{2} \implies c = 12.

Adım Adım Çözüm

1
Represent the roots using the given ratio.
Let the two roots of the quadratic equation be 3r3r and 8r8r.
The ratio of the two solutions is specified as 3:83:8.
2
Apply Vieta's formula for the sum of roots to find the ratio multiplier rr.
3r+8r=112    11r=5.5    r=0.53r + 8r = -\frac{-11}{2} \implies 11r = 5.5 \implies r = 0.5.
For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is given by ba-\frac{b}{a}.
3
Determine the numerical values of the two roots.
The roots are 3(0.5)=1.53(0.5) = 1.5 and 8(0.5)=48(0.5) = 4.
Substitute the value of r=0.5r = 0.5 back into the expressions for the roots.
4
Apply Vieta's formula for the product of roots to solve for the constant cc.
(1.5)(4)=c2    6=c2    c=12(1.5)(4) = \frac{c}{2} \implies 6 = \frac{c}{2} \implies c = 12.
For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the product of the roots is given by ca\frac{c}{a}.

Anahtar Kavram

Vieta's formulas and the relationship between the roots and coefficients of a quadratic equation

Alternatif Yöntem

Alternatively, you can express the roots using the quadratic formula: x=11±1218c4x = \frac{11 \pm \sqrt{121 - 8c}}{4}. Since the ratio of the smaller root to the larger root is 3:83:8, we set up the equation: 111218c11+1218c=38\frac{11 - \sqrt{121 - 8c}}{11 + \sqrt{121 - 8c}} = \frac{3}{8}. Cross-multiplying gives 8(111218c)=3(11+1218c)    8881218c=33+31218c    55=111218c    5=1218c    25=1218c    8c=96    c=128(11 - \sqrt{121 - 8c}) = 3(11 + \sqrt{121 - 8c}) \implies 88 - 8\sqrt{121 - 8c} = 33 + 3\sqrt{121 - 8c} \implies 55 = 11\sqrt{121 - 8c} \implies 5 = \sqrt{121 - 8c} \implies 25 = 121 - 8c \implies 8c = 96 \implies c = 12.
Tahmini Süre:1m 30s
Soru 352Soru

For all real values of xx that satisfy the inequality 53x24x+625 - \frac{3x - 2}{4} \ge \frac{x + 6}{2}, the solution set is represented by xbx \le b. What is the value of bb?

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Cevap: 2

Cevap

The value of bb is 2.
To solve 53x24x+625 - \frac{3x - 2}{4} \ge \frac{x + 6}{2}, multiply all terms by 4 to clear the denominators, resulting in 20(3x2)2(x+6)20 - (3x - 2) \ge 2(x + 6). Carefully distribute the negative sign to obtain 203x+22x+1220 - 3x + 2 \ge 2x + 12. Simplifying the left side gives 223x2x+1222 - 3x \ge 2x + 12. Moving the variable terms to one side yields 105x10 \ge 5x, which simplifies to x2x \le 2. Thus, the upper bound value bb is 2.

Adım Adım Çözüm

1
Multiply both sides of the inequality by the least common denominator, which is 4.
20(3x2)2(x+6)20 - (3x - 2) \ge 2(x + 6)
Multiplying all terms by the common denominator eliminates fractions and simplifies the inequality.
2
Distribute the negative sign to the numerator terms on the left and distribute the 2 on the right.
203x+22x+1220 - 3x + 2 \ge 2x + 12
Distributing the negative sign across (3x2)(3x - 2) changes it to 3x+2-3x + 2. Distributing 2 across (x+6)(x + 6) yields 2x+122x + 12.
3
Combine like terms on the left side of the inequality.
223x2x+1222 - 3x \ge 2x + 12
Combining the constant terms 2020 and 22 simplifies the expression to 2222.
4
Isolate the variable terms by adding 3x3x and subtracting 12 from both sides.
105x10 \ge 5x
Grouping variables on one side and constants on the other allows us to solve for xx.
5
Divide both sides by 5.
2x2 \ge x (or x2x \le 2)
Dividing by a positive number isolates the variable without changing the direction of the inequality sign.

Anahtar Kavram

Solving linear inequalities involving fractions and distributing negative coefficients.

Alternatif Yöntem

We can write the inequality by separating each fraction term first: 534x+2412x+625 - \frac{3}{4}x + \frac{2}{4} \ge \frac{1}{2}x + \frac{6}{2}. This simplifies to 5.50.75x0.5x+35.5 - 0.75x \ge 0.5x + 3. Subtracting 0.5x0.5x and 5.55.5 from both sides gives 1.25x2.5-1.25x \ge -2.5. Dividing by 1.25-1.25 and reversing the inequality sign gives x2x \le 2.
Tahmini Süre:1m 30s
Soru 353Soru

In the standard (x,y)(x, y) coordinate plane, a circle is defined by the equation x2+y2=25x^2 + y^2 = 25 and a line is defined by the equation 3x+4y=153x + 4y = 15. The line intersects the circle at two points, AA and BB. What is the distance between point AA and point BB?

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Cevap: 8

Cevap

The distance between the two intersection points is 8.
The correct answer is 8. We can find the intersection points by substituting y=153x4y = \frac{15 - 3x}{4} into the circle's equation x2+y2=25x^2 + y^2 = 25, yielding the quadratic equation 5x218x35=05x^2 - 18x - 35 = 0. Solving this gives x=5x = 5 and x=1.4x = -1.4, with corresponding yy-coordinates y=0y = 0 and y=4.8y = 4.8. The distance between (5,0)(5, 0) and (1.4,4.8)(-1.4, 4.8) is (1.45)2+(4.80)2=6.42+4.82=64=8\sqrt{(-1.4 - 5)^2 + (4.8 - 0)^2} = \sqrt{6.4^2 + 4.8^2} = \sqrt{64} = 8. Alternatively, we can use geometry: the distance from the center of the circle (0,0)(0,0) to the line 3x+4y15=03x + 4y - 15 = 0 is d=3(0)+4(0)1532+42=3d = \frac{|3(0) + 4(0) - 15|}{\sqrt{3^2 + 4^2}} = 3. Since the radius of the circle is r=5r = 5, the right triangle formed by the radius, the perpendicular segment, and half the chord has a half-chord length of 5232=4\sqrt{5^2 - 3^2} = 4. Thus, the total chord length is 2×4=82 \times 4 = 8.

Adım Adım Çözüm

1
Express the linear equation in terms of one variable
y=153x4y = \frac{15 - 3x}{4}
This allows for substitution into the equation of the circle.
2
Substitute the expression into the circle's equation and simplify
x2+(153x4)2=2516x2+(22590x+9x2)=40025x290x175=05x218x35=0x^2 + \left(\frac{15 - 3x}{4}\right)^2 = 25 \Rightarrow 16x^2 + (225 - 90x + 9x^2) = 400 \Rightarrow 25x^2 - 90x - 175 = 0 \Rightarrow 5x^2 - 18x - 35 = 0
To create a single quadratic equation in terms of xx representing the intersection points.
3
Solve the quadratic equation for xx
(5x+7)(x5)=0x=5(5x + 7)(x - 5) = 0 \Rightarrow x = 5 or x=1.4x = -1.4
To find the xx-coordinates of the intersection points.
4
Calculate the corresponding yy-coordinates
For x=5x = 5, y=0y = 0, giving point A(5,0)A(5, 0). For x=1.4x = -1.4, y=4.8y = 4.8, giving point B(1.4,4.8)B(-1.4, 4.8).
To determine the exact coordinates of both intersection points.
5
Apply the distance formula to find the length of the segment ABAB
d=(1.45)2+(4.80)2=(6.4)2+4.82=40.96+23.04=64=8d = \sqrt{(-1.4 - 5)^2 + (4.8 - 0)^2} = \sqrt{(-6.4)^2 + 4.8^2} = \sqrt{40.96 + 23.04} = \sqrt{64} = 8
To compute the final distance between the two intersection points.

Anahtar Kavram

Solving systems of linear and quadratic equations to determine intersection points and calculating the distance between coordinates.
Soru 354Soru

A regular hexagon ABCDEFABCDEF has a side length of 88 inches. Point MM lies on side CDCD such that the length of segment CMCM is 22 inches. What is the length, in inches, of segment AMAM?

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Cevap: 14

Cevap

14
The correct answer is 14 because ACM\triangle ACM is a right triangle with legs AC=83AC = 8\sqrt{3} and CM=2CM = 2. Applying the Pythagorean Theorem yields AM2=(83)2+22=192+4=196AM^2 = (8\sqrt{3})^2 + 2^2 = 192 + 4 = 196, so AM=196=14AM = \sqrt{196} = 14.

Adım Adım Çözüm

1
Find the properties of the regular hexagon and the diagonal ACAC.
The interior angle at vertex BB is 120120^\circ. Since AB=BC=8AB = BC = 8, the triangle ABC\triangle ABC is an isosceles triangle with angles BAC=BCA=30\angle BAC = \angle BCA = 30^\circ. Using the properties of 3030^\circ-6060^\circ-9090^\circ triangles, the diagonal length is AC=83AC = 8\sqrt{3}.
To find the length of the leg ACAC for the right triangle ACM\triangle ACM.
2
Determine the angle ACD\angle ACD to show ACM\triangle ACM is a right triangle.
Since the interior angle BCD=120\angle BCD = 120^\circ and BCA=30\angle BCA = 30^\circ, the remaining angle is ACD=12030=90\angle ACD = 120^\circ - 30^\circ = 90^\circ. Thus, ACM\triangle ACM is a right triangle with the right angle at vertex CC.
To establish the right-angle relationship between the legs ACAC and CMCM.
3
Apply the Pythagorean Theorem to calculate the hypotenuse AMAM.
AM2=AC2+CM2=(83)2+22=192+4=196AM^2 = AC^2 + CM^2 = (8\sqrt{3})^2 + 2^2 = 192 + 4 = 196. Taking the square root gives AM=14AM = 14.
To find the final length of segment AMAM.

Anahtar Kavram

Using properties of regular hexagons, special right triangles, and the Pythagorean Theorem to find lengths in multi-step plane geometry configurations.
Soru 355Soru

In the standard (x,y)(x, y) coordinate plane, line L1L_1 passes through the points (2,5)(2, 5) and (6,3)(6, -3). A second line, L2L_2, is perpendicular to L1L_1 and intersects L1L_1 at its yy-intercept. What is the xx-coordinate of the xx-intercept of L2L_2?

Cevabı ve açıklamayı göster

Cevap: -18

Cevap

The xx-coordinate of the xx-intercept of L2L_2 is 18-18.
First, the slope of L1L_1 is calculated as 2-2 using the slope formula. Substituting one of the points into the slope-intercept form gives the yy-intercept of L1L_1 as (0,9)(0, 9). Since L2L_2 is perpendicular to L1L_1, its slope is the negative reciprocal of 2-2, which is 12\frac{1}{2}. Since L2L_2 shares the yy-intercept (0,9)(0, 9), its equation is y=12x+9y = \frac{1}{2}x + 9. Setting y=0y = 0 to find the xx-intercept gives x=18x = -18.

Adım Adım Çözüm

1
Calculate the slope of line L1L_1.
The slope of L1L_1 is 2-2.
Using the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} with the given points (2,5)(2, 5) and (6,3)(6, -3) yields m1=3562=2m_1 = \frac{-3 - 5}{6 - 2} = -2.
2
Find the yy-intercept of L1L_1.
The yy-intercept is (0,9)(0, 9).
Substituting m=2m = -2 and the coordinates of (2,5)(2, 5) into the slope-intercept equation y=mx+by = mx + b gives 5=2(2)+b5 = -2(2) + b, which simplifies to b=9b = 9.
3
Find the slope of the perpendicular line, L2L_2.
The slope of L2L_2 is 12\frac{1}{2}.
Perpendicular lines have slopes that are negative reciprocals of each other. The negative reciprocal of 2-2 is 12\frac{1}{2}.
4
Determine the equation of L2L_2 and calculate its xx-intercept.
The xx-coordinate of the xx-intercept of L2L_2 is 18-18.
Since L2L_2 passes through the yy-intercept (0,9)(0, 9), its equation is y=12x+9y = \frac{1}{2}x + 9. Setting y=0y = 0 to find the xx-intercept yields 0=12x+90 = \frac{1}{2}x + 9, which solves to x=18x = -18.

Anahtar Kavram

Determining the equation and intercepts of a line perpendicular to a given line that passes through a specific shared point.
Tahmini Süre:1m 30s
Soru 356Soru

In the standard (x,y)(x, y) coordinate plane, a line segment has endpoints A(3,k)A(-3, k) and B(5,3)B(5, 3). If the midpoint of segment ABAB lies on the xx-axis, what is the length of segment ABAB?

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Cevap: 10

Cevap

The length of segment ABAB is 10.
The midpoint of segment ABAB with endpoints A(3,k)A(-3, k) and B(5,3)B(5, 3) is (1,k+32)\left(1, \frac{k + 3}{2}\right). Since the midpoint lies on the xx-axis, its yy-coordinate must be 00. Solving k+32=0\frac{k + 3}{2} = 0 gives k=3k = -3. This means the endpoints are A(3,3)A(-3, -3) and B(5,3)B(5, 3). The distance between these two points is (5(3))2+(3(3))2=82+62=100=10\sqrt{(5 - (-3))^2 + (3 - (-3))^2} = \sqrt{8^2 + 6^2} = \sqrt{100} = 10.

Adım Adım Çözüm

1
Set up the equation for the yy-coordinate of the midpoint.
k+32=0\frac{k + 3}{2} = 0
The midpoint of a segment with endpoints (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) has a yy-coordinate of y1+y22\frac{y_1 + y_2}{2}. Since the midpoint lies on the xx-axis, its yy-coordinate must be 00.
2
Solve the equation for kk.
k=3k = -3
Multiply both sides of the equation by 22 to get k+3=0k + 3 = 0, then subtract 33 from both sides.
3
Substitute k=3k = -3 to find the coordinates of point AA.
A(3,3)A(-3, -3)
This provides both complete endpoints, A(3,3)A(-3, -3) and B(5,3)B(5, 3), which are needed to find the distance.
4
Apply the distance formula to find the length of segment ABAB.
AB=10AB = 10
The distance formula is d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}. Substituting the coordinates gives AB=(5(3))2+(3(3))2=82+62=64+36=100=10AB = \sqrt{(5 - (-3))^2 + (3 - (-3))^2} = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10.

Anahtar Kavram

Distance and Midpoint Formulas
Soru 357Soru

In isosceles trapezoid ABCDABCD, the parallel bases are ABAB and CDCD. If the measure of interior angle AA is 7070^\circ, what is the measure, in degrees, of interior angle CC?

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Cevap: 110

Cevap

The measure of interior angle CC is 110110 degrees.
Since the trapezoid is isosceles with bases ABAB and CDCD, the base angles A\angle A and B\angle B are congruent, so B=70\angle B = 70^\circ. The consecutive interior angles along the leg BCBC are supplementary because ABCDAB \parallel CD, which means B+C=180\angle B + \angle C = 180^\circ. Solving for C\angle C gives 18070=110180^\circ - 70^\circ = 110^\circ.

Adım Adım Çözüm

1
Find the measure of angle BB using the properties of an isosceles trapezoid.
B=70\angle B = 70^\circ
In an isosceles trapezoid, the angles sharing a base are congruent. Since ABAB is a base, A=B=70\angle A = \angle B = 70^\circ.
2
Calculate the measure of angle CC using the parallel lines property.
C=110\angle C = 110^\circ
Because the bases ABAB and CDCD are parallel, the consecutive interior angles B\angle B and C\angle C must sum to 180180^\circ. Therefore, C=18070=110\angle C = 180^\circ - 70^\circ = 110^\circ.

Anahtar Kavram

Properties of an isosceles trapezoid

Alternatif Yöntem

Since the sum of interior angles in any quadrilateral is 360360^\circ, and in an isosceles trapezoid the base angles are equal (A=B=70\angle A = \angle B = 70^\circ and C=D\angle C = \angle D), we can write 70+70+C+D=36070^\circ + 70^\circ + \angle C + \angle D = 360^\circ. Since C=D\angle C = \angle D, this simplifies to 140+2C=360    2C=220    C=110140^\circ + 2\angle C = 360^\circ \implies 2\angle C = 220^\circ \implies \angle C = 110^\circ.
Tahmini Süre:45s
Soru 358Soru

The sum of the measures of all but one of the interior angles of a convex polygon is 20102010^\circ. What is the measure, in degrees, of the remaining interior angle?

Cevabı ve açıklamayı göster

Cevap: 150

Cevap

The measure of the remaining interior angle is 150 degrees.
The sum of the interior angles of any convex polygon with nn sides is a multiple of 180180^\circ given by (n2)×180(n-2) \times 180^\circ. Because the polygon is convex, the measure of the remaining angle must be strictly less than 180180^\circ. Thus, the total sum of all interior angles must be the smallest multiple of 180180^\circ that is strictly greater than the given sum of 20102010^\circ. Since 11×180=198011 \times 180^\circ = 1980^\circ (which is less than 20102010^\circ), the total sum must be at least 12×180=216012 \times 180^\circ = 2160^\circ. Subtracting the given sum of the other angles from this total gives 21602010=1502160^\circ - 2010^\circ = 150^\circ. Since 150150^\circ is less than 180180^\circ, this is a mathematically valid remaining angle for a convex polygon.

Adım Adım Çözüm

1
Set up the inequality for the sum of the interior angles.
The total sum S=(n2)×180S = (n-2) \times 180^\circ must satisfy 2010<S<2010+1802010^\circ < S < 2010^\circ + 180^\circ, which simplifies to 2010<S<21902010^\circ < S < 2190^\circ.
Since the polygon is convex, the remaining interior angle must have a measure strictly between 00^\circ and 180180^\circ.
2
Determine the value of n2n-2 by finding the unique integer multiple.
Dividing the inequality by 180180^\circ gives 11.17<n2<12.1711.17 < n-2 < 12.17. Since nn must be an integer, n2=12n-2 = 12, which means the polygon has n=14n = 14 sides.
The number of sides of a polygon must be a whole number, so n2n-2 must be an integer.
3
Calculate the measure of the remaining interior angle.
x=(12×180)2010=21602010=150x = (12 \times 180^\circ) - 2010^\circ = 2160^\circ - 2010^\circ = 150^\circ.
Subtract the sum of the other interior angles from the total sum of the interior angles of a 14-gon.

Anahtar Kavram

The sum of the interior angles of a convex polygon with nn sides is (n2)×180(n-2) \times 180^\circ, and each interior angle of a convex polygon must measure strictly less than 180180^\circ.
Soru 359Soru

A convex polygon has nn sides. The sum of the measures of all but one of its interior angles is 20202020^\circ. What is the measure, in degrees, of the remaining interior angle?

Cevabı ve açıklamayı göster

Cevap: 140

Cevap

The measure of the remaining interior angle is 140140^\circ.
For a convex polygon with nn sides, the sum of all interior angles is (n2)×180(n-2) \times 180^\circ. If we represent the remaining interior angle as xx, then the sum of all interior angles can be written as 2020+x2020^\circ + x. Because the polygon is convex, the measure of the remaining interior angle must satisfy the inequality 0<x<1800^\circ < x < 180^\circ. Substituting this into the sum expression gives the inequality 2020<(n2)×180<22002020^\circ < (n-2) \times 180^\circ < 2200^\circ. Dividing by 180180^\circ, we find 11.22<n2<12.2211.22 < n-2 < 12.22. Since n2n-2 must be an integer, n2n-2 must equal 1212, which means the total sum of the interior angles is 12×180=216012 \times 180^\circ = 2160^\circ. The remaining angle is found by subtracting 20202020^\circ from 21602160^\circ, resulting in 140140^\circ.

Adım Adım Çözüm

1
Use the polygon interior angle sum formula for an nn-sided polygon.
The sum of all interior angles is (n2)×180(n-2) \times 180^\circ.
This formula connects the number of sides of a convex polygon to the total sum of its interior angles.
2
Set up an equation containing the sum of all but one angle (20202020^\circ) and the remaining angle (xx).
(n2)×180=2020+x(n-2) \times 180^\circ = 2020^\circ + x
The total sum of all interior angles is equal to the sum of the n1n-1 known angles plus the remaining angle.
3
Apply the convexity constraint 0<x<1800^\circ < x < 180^\circ to construct an inequality for the total sum of the interior angles.
2020<(n2)×180<22002020^\circ < (n-2) \times 180^\circ < 2200^\circ
Since the remaining angle must be strictly between 00^\circ and 180180^\circ for a convex polygon, adding 20202020^\circ gives the boundaries for the total sum.
4
Divide the inequality by 180180^\circ to isolate the term n2n-2.
11.22<n2<12.2211.22 < n-2 < 12.22
This determines the numerical boundaries for the integer value of n2n-2.
5
Find the unique integer value for n2n-2 and calculate the exact total sum of the interior angles.
n2=12n-2 = 12, which gives a total sum of 12×180=216012 \times 180^\circ = 2160^\circ.
Because nn must be an integer, n2n-2 must be an integer. The only integer in the interval (11.22,12.22)(11.22, 12.22) is 1212.
6
Subtract the sum of the other angles from the total sum of the interior angles to solve for xx.
x=21602020=140x = 2160^\circ - 2020^\circ = 140^\circ.
This yields the exact value of the remaining interior angle.

Anahtar Kavram

The sum of the interior angles of an nn-sided convex polygon is (n2)×180(n-2) \times 180^\circ, where each interior angle is strictly between 00^\circ and 180180^\circ.
Soru 360Soru

In the standard (x,y)(x, y) coordinate plane, a rhombus ABCDABCD has vertices A(1,2)A(1, 2) and C(7,10)C(7, 10). The length of diagonal BDBD is half the length of diagonal ACAC. If the xx-coordinate of vertex BB is greater than the xx-coordinate of vertex DD, what is the yy-coordinate of vertex BB?

Cevabı ve açıklamayı göster

Cevap: 4.5

Cevap

The yy-coordinate of vertex BB is 4.54.5.
By using the geometric properties of a rhombus, we know that its diagonals bisect each other perpendicularly. The midpoint of diagonal ACAC is calculated as M(4,6)M(4, 6) and its length is 1010. Consequently, the perpendicular diagonal BDBD must pass through M(4,6)M(4, 6) with a slope of 34-\frac{3}{4} (the negative reciprocal of the slope of ACAC, which is 43\frac{4}{3}). Since the length of BDBD is half the length of ACAC, the length of BDBD is 55, meaning vertices BB and DD are each a distance of 2.52.5 units away from M(4,6)M(4, 6). Solving for points along the line y6=0.75(x4)y - 6 = -0.75(x - 4) at this distance gives (6,4.5)(6, 4.5) and (2,7.5)(2, 7.5). The condition that the xx-coordinate of BB is greater than the xx-coordinate of DD uniquely determines BB to be (6,4.5)(6, 4.5), yielding a yy-coordinate of 4.54.5.

Adım Adım Çözüm

1
Calculate the midpoint MM and the length of diagonal ACAC.
M=(4,6)M = (4, 6) and AC=10AC = 10.
The diagonals of a rhombus bisect each other at their midpoint and their lengths determine the proportions of the shape.
2
Find the slope and length of diagonal BDBD.
Slope of BDBD is 34-\frac{3}{4}, and length is 55.
Diagonals of a rhombus are perpendicular, meaning their slopes are negative reciprocals (m1m2=1m_1 \cdot m_2 = -1). The problem specifies that the length of BDBD is half of ACAC (10÷2=510 \div 2 = 5).
3
Set up equations to find coordinates of B(x,y)B(x, y) and D(x,y)D(x, y) that are at distance 2.52.5 from M(4,6)M(4, 6) along the line of diagonal BDBD.
(x4)2+(y6)2=6.25(x - 4)^2 + (y - 6)^2 = 6.25 and y6=0.75(x4)y - 6 = -0.75(x - 4).
Since the diagonals bisect each other, the distance from the midpoint MM to each of the remaining vertices BB and DD is half the length of diagonal BDBD (5÷2=2.55 \div 2 = 2.5).
4
Solve the system of equations for the coordinates.
P1(6,4.5)P_1(6, 4.5) and P2(2,7.5)P_2(2, 7.5).
Substituting y6y-6 into the distance equation yields (x4)2+0.5625(x4)2=6.25(x-4)^2 + 0.5625(x-4)^2 = 6.25, which simplifies to 1.5625(x4)2=6.25    (x4)2=4    x4=±21.5625(x-4)^2 = 6.25 \implies (x-4)^2 = 4 \implies x - 4 = \pm 2. Thus, x1=6x_1 = 6 (giving y1=4.5y_1 = 4.5) and x2=2x_2 = 2 (giving y2=7.5y_2 = 7.5).
5
Identify vertex BB using the given coordinate condition.
B=(6,4.5)B = (6, 4.5), so the yy-coordinate is 4.54.5.
The problem states that the xx-coordinate of BB is greater than the xx-coordinate of DD. Comparing the two solutions, the one with the larger xx-value (6>26 > 2) must belong to vertex BB.

Anahtar Kavram

Rhombus Diagonal Properties in the Coordinate Plane

Alternatif Yöntem

Alternatively, since the diagonals of a rhombus divide it into four congruent right triangles, we can determine the side length of the rhombus. The legs of these right triangles are half the diagonal lengths: 55 and 2.52.5. By the Pythagorean theorem, the square of the side length is 52+2.52=31.255^2 + 2.5^2 = 31.25. We can set up distance equations from B(x,y)B(x, y) to A(1,2)A(1, 2) and C(7,10)C(7, 10): (x1)2+(y2)2=31.25(x-1)^2 + (y-2)^2 = 31.25 and (x7)2+(y10)2=31.25(x-7)^2 + (y-10)^2 = 31.25. Subtracting the second equation from the first simplifies to the linear relation y=0.75x+9y = -0.75x + 9, which can then be substituted back into one of the quadratic equations to find x=6x = 6 or x=2x = 2, yielding y=4.5y = 4.5 or y=7.5y = 7.5.
Tahmini Süre:3m 0s
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