Tüm alıştırma soruları

541 soru

Soru 21Soru

On a standard number line, point AA is located at 7-7 and point BB is located at 55. What is the distance between point AA and point BB?

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Cevap: 12

Cevap

The distance between the two points is 12.
The distance between two points on a number line is the absolute value of their difference. Calculating 75|-7 - 5| yields 12|-12|, which is 1212. Alternatively, subtracting the lesser coordinate from the greater coordinate gives 5(7)=5+7=125 - (-7) = 5 + 7 = 12.

Adım Adım Çözüm

1
Identify the coordinates of the two points on the number line.
The coordinates are 7-7 for point AA and 55 for point BB.
These coordinates represent the positions from which we need to find the distance.
2
Apply the absolute value formula for the distance between two points, ab|a - b|.
The expression is 75|-7 - 5|.
Distance on a number line is always non-negative and is defined by the absolute value of the difference between the two coordinates.
3
Perform the subtraction and find the absolute value.
12=12|-12| = 12.
Subtracting 55 from 7-7 gives 12-12, and the absolute value of 12-12 is 1212.

Anahtar Kavram

The distance between two points aa and bb on a number line is given by ab|a - b|.
Tahmini Süre:45s
Soru 22Soru

An algebra student is simplifying the expression a(bc)d(ef)a(b - c) - d(e - f) by applying the distributive property. Instead of distributing correctly, the student incorrectly writes the expansion as a(bc)dedfa(b - c) - de - df. If a=2a = 2, b=3b = 3, c=5c = 5, d=3d = -3, e=4e = 4, and f=2f = -2, what is the absolute difference between the student's incorrect result and the correct value of the expression?

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Cevap: 12

Cevap

The correct answer is 12.
The correct expression evaluates to 14, and the incorrect expression evaluates to 2. The absolute difference between them is 142=12|14 - 2| = 12.

Adım Adım Çözüm

1
Evaluate the correct expression a(bc)d(ef)a(b - c) - d(e - f) using the given values.
14
To find the mathematically correct value of the expression.
2
Evaluate the incorrect expression a(bc)dedfa(b - c) - de - df using the same values.
2
To find the value resulting from the student's distribution error.
3
Find the absolute difference between the correct value and the incorrect value.
12
To determine the error magnitude as requested by the question.

Anahtar Kavram

Distributive Property and Order of Operations
Soru 23Soru

The prime factorization of a positive integer NN is 2a×3b×5c2^a \times 3^b \times 5^c, where aa, bb, and cc are positive integers. If NN has exactly 1212 distinct positive factors, what is the least possible value of NN?

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Cevap: 60

Cevap

60
The number of distinct positive factors of N=2a×3b×5cN = 2^a \times 3^b \times 5^c is given by the formula (a+1)(b+1)(c+1)(a+1)(b+1)(c+1). Given that NN has exactly 1212 positive factors and a,b,ca, b, c are positive integers (each at least 11), we must factor 1212 into three integers that are each at least 22. The only way to do this is 2×2×32 \times 2 \times 3. This means the set of exponents {a,b,c}\{a, b, c\} must be {1,1,2}\{1, 1, 2\}. To minimize the value of NN, we pair the largest exponent 22 with the smallest prime base 22, and the exponents of 11 with the prime bases 33 and 55. This yields the minimum value 22×31×51=602^2 \times 3^1 \times 5^1 = 60.

Adım Adım Çözüm

1
Determine the formula for the number of positive factors of NN.
The number of positive factors is (a+1)(b+1)(c+1)=12(a+1)(b+1)(c+1) = 12.
For any integer expressed as a product of prime powers, the number of positive factors is the product of each exponent increased by 1.
2
Find the possible values for the exponents aa, bb, and cc.
Since a,b,c1a, b, c \ge 1, we must have a+12a+1 \ge 2, b+12b+1 \ge 2, and c+12c+1 \ge 2. The only factorization of 1212 into three integers each at least 22 is 2×2×32 \times 2 \times 3. Thus, the exponents {a,b,c}\{a, b, c\} must be {1,1,2}\{1, 1, 2\} in some order.
We must find a set of integer values for the exponents that satisfy the factor count constraint.
3
Minimize the value of NN by assigning exponents to the prime bases.
Assign the largest exponent (22) to the smallest base (22), and the smaller exponents (11) to the larger bases (33 and 55). This gives a=2,b=1,c=1a=2, b=1, c=1, so N=22×31×51=60N = 2^2 \times 3^1 \times 5^1 = 60.
To minimize the total product, the largest power must be applied to the smallest base.

Anahtar Kavram

Finding the number of factors of a positive integer using its prime factorization.
Tahmini Süre:1m 15s
Soru 24Soru

What is the least common multiple of 1515 and 2020?

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Cevap: 60

Cevap

The least common multiple of 1515 and 2020 is 6060.
The correct answer is 6060. The least common multiple is the smallest positive integer that is divisible by both 1515 and 2020. By listing multiples or using prime factorization (22×3×52^2 \times 3 \times 5), we arrive at 6060.

Adım Adım Çözüm

1
Find the prime factorization of 1515 and 2020.
15=3×515 = 3 \times 5 and 20=22×520 = 2^2 \times 5.
Decomposing numbers into their prime factors makes it straightforward to compute their least common multiple.
2
Identify the highest exponent for each prime factor appearing in the prime factorizations.
The prime factors present are 22, 33, and 55. The highest powers are 222^2, 313^1, and 515^1.
The least common multiple must contain all prime factors of both numbers at their maximum frequency to be divisible by both.
3
Calculate the product of these highest powers of the prime factors.
22×3×5=4×3×5=602^2 \times 3 \times 5 = 4 \times 3 \times 5 = 60.
Multiplying these factors yields the smallest positive integer that is a multiple of both original numbers.

Anahtar Kavram

Least Common Multiple (LCM)
Tahmini Süre:45s
Soru 25Soru

What is the value of the mathematical expression below?

32+4×[183×(84)]÷2 -3^2 + 4 \times [18 - 3 \times (8 - 4)] \div 2
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Cevap: 3

Cevap

The correct value of the expression is 3.
Following the standard order of operations, we first simplify the nested parentheses (84)=4(8 - 4) = 4. Next, we evaluate the expression inside the brackets [183×4]=[1812]=6[18 - 3 \times 4] = [18 - 12] = 6. We then evaluate the exponent 32=9-3^2 = -9. We perform the multiplication and division from left to right: 4×6÷2=124 \times 6 \div 2 = 12. Finally, adding 9+12-9 + 12 yields the correct result of 3.

Adım Adım Çözüm

1
Simplify the innermost parentheses.
32+4×[183×4]÷2-3^2 + 4 \times [18 - 3 \times 4] \div 2
According to the order of operations (PEMDAS), operations inside parentheses or grouping symbols must be performed first.
2
Simplify the expression inside the square brackets by performing multiplication before subtraction.
32+4×6÷2-3^2 + 4 \times 6 \div 2
Multiplication has a higher precedence than subtraction.
3
Evaluate the exponent 32-3^2.
9+4×6÷2-9 + 4 \times 6 \div 2
The exponent applies only to the base 3, not to the negative sign, because there are no parentheses around 3-3.
4
Perform multiplication and division from left to right.
9+12-9 + 12
Multiplication and division have the same precedence and must be evaluated in order from left to right.
5
Add the remaining values.
33
Addition is the final operation to perform.

Anahtar Kavram

Order of operations (PEMDAS) dictates the sequence in which operations must be performed to evaluate an expression: Parentheses/Brackets, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).
Soru 26Soru

What is the value of the expression 12715|-12| - |7 - 15|?

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Cevap: 4

Cevap

The value of the expression is 4.
The absolute value of a number represents its distance from zero on a number line, so 12=12|-12| = 12. Simplifying inside the second term gives 715=87 - 15 = -8, and the absolute value 8=8|-8| = 8. Subtracting these two results yields 128=412 - 8 = 4.

Adım Adım Çözüm

1
Evaluate the first term
12=12|-12| = 12
The absolute value of a number is its distance from zero on the number line, which is always non-negative.
2
Simplify the expression inside the second absolute value
715=87 - 15 = -8
Subtracting 15 from 7 yields a negative difference of -8.
3
Evaluate the second absolute value term
8=8|-8| = 8
The absolute value of -8 is 8.
4
Subtract the two evaluated terms
128=412 - 8 = 4
Subtracting 8 from 12 gives the final simplified value of 4.

Anahtar Kavram

Evaluating expressions with absolute values requires simplifying the terms inside the absolute value grouping symbols first, taking the absolute value of the result, and then performing the subtraction.
Soru 27Soru

A positive integer NN has the prime factorization N=2a×3b×5cN = 2^a \times 3^b \times 5^c, where aa, bb, and cc are positive integers. The greatest common divisor of NN and 360360 has exactly 1212 positive factors, and the least common multiple of NN and 360360 has exactly 7272 positive factors. How many positive factors does NN have?

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Cevap: 36

Cevap

The positive integer NN has exactly 36 positive factors.
By writing the prime factorization of 360360 as 23×32×512^3 \times 3^2 \times 5^1 and expressing the GCD and LCM of NN and 360360 in terms of the minimum and maximum exponents of their prime factors, we establish a system of equations for the exponents. Solving this system yields two cases: either a=2a = 2, b=1b = 1, and c=5c = 5, or a=1a = 1 with (b+1)(c+1)=18(b + 1)(c + 1) = 18. In both cases, the formula for the number of positive factors of NN, which is (a+1)(b+1)(c+1)(a + 1)(b + 1)(c + 1), evaluates to exactly 36.

Adım Adım Çözüm

1
Find the prime factorization of 360360.
360=23×32×51360 = 2^3 \times 3^2 \times 5^1.
This allows us to write the greatest common divisor (GCD) and least common multiple (LCM) of NN and 360360 in terms of their prime factors.
2
Express the number of factors of GCD(N,360)\text{GCD}(N, 360) using the minimum exponents.
(min(a,3)+1)(min(b,2)+1)(min(c,1)+1)=12(\min(a, 3) + 1)(\min(b, 2) + 1)(\min(c, 1) + 1) = 12. Since c1c \ge 1, we have min(c,1)=1\min(c, 1) = 1, which simplifies the equation to (min(a,3)+1)(min(b,2)+1)=6(\min(a, 3) + 1)(\min(b, 2) + 1) = 6.
The GCD of two numbers is found by taking the minimum of their exponents for each prime factor.
3
Solve for the possible values of aa and bb from the GCD factor equation.
Since a,b1a, b \ge 1, the only integer pairs for the factors of 66 are: Case 1: a=2a = 2 and b=1b = 1, or Case 2: a=1a = 1 and b2b \ge 2.
We analyze the possible values of min(a,3)\min(a, 3) and min(b,2)\min(b, 2) that multiply to 66 under the constraints a,b1a, b \ge 1.
4
Apply the LCM condition to find the number of factors of NN for both cases.
For Case 1: LCM(N,360)\text{LCM}(N, 360) has factors count (3+1)(2+1)(c+1)=72    c=5(3+1)(2+1)(c+1) = 72 \implies c = 5, giving d(N)=(2+1)(1+1)(5+1)=36d(N) = (2+1)(1+1)(5+1) = 36. For Case 2: LCM(N,360)\text{LCM}(N, 360) has factors count (3+1)(b+1)(c+1)=72    (b+1)(c+1)=18(3+1)(b+1)(c+1) = 72 \implies (b+1)(c+1) = 18, giving d(N)=(1+1)(b+1)(c+1)=2×18=36d(N) = (1+1)(b+1)(c+1) = 2 \times 18 = 36.
The LCM uses the maximum of the exponents, which allows us to relate the remaining unknown exponents to the total factor count.

Anahtar Kavram

Factors, Multiples, and Prime Factorization
Soru 28Soru

A teacher has a bag of marbles to distribute to a class. If the marbles are divided equally among 88 students, there are 66 marbles left over. If the marbles are divided equally among 99 students, there are 77 marbles left over. What is the least possible number of marbles in the bag?

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Cevap: 70

Cevap

The least possible number of marbles in the bag is 70.
The correct answer is 70. The problem describes a situation where the number of marbles, NN, leaves a remainder of 66 when divided by 88, and a remainder of 77 when divided by 99. This means N+2N + 2 is a multiple of both 88 and 99. The smallest positive integer that is a multiple of both 88 and 99 is their least common multiple, which is 7272. Therefore, N+2=72N + 2 = 72, which gives N=70N = 70.

Adım Adım Çözüm

1
Analyze the relationship between the divisors and their respective remainders.
For divisor 88, the remainder is 66, which is 86=28 - 6 = 2 less than the divisor. For divisor 99, the remainder is 77, which is 97=29 - 7 = 2 less than the divisor. Therefore, adding 22 to the total number of marbles creates a number that is exactly divisible by both 88 and 99.
This establishes that the target number plus 22 must be a common multiple of the two divisors.
2
Calculate the least common multiple (LCM) of the divisors 88 and 99.
The prime factorization of 88 is 232^3 and of 99 is 323^2. The LCM is the product of the highest powers of all prime factors involved: 23×32=8×9=722^3 \times 3^2 = 8 \times 9 = 72.
To find the smallest positive common multiple of 88 and 99.
3
Subtract 22 from the LCM to find the least possible number of marbles.
722=7072 - 2 = 70.
Since the bag is 22 marbles short of having a multiple of both 88 and 99, we subtract 22 from the least common multiple.

Anahtar Kavram

Least Common Multiple (LCM) application with remainders
Soru 29Soru

Let f(n)f(n) represent the number of positive factors of a positive integer nn. If n=2x×3yn = 2^x \times 3^y, where xx and yy are positive integers such that x+y=7x + y = 7, what is the maximum possible value of f(n)f(n)?

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Cevap: 20

Cevap

The maximum possible value of f(n)f(n) is 2020.
The number of positive factors of n=2x×3yn = 2^x \times 3^y is (x+1)(y+1)(x + 1)(y + 1). Since xx and yy are positive integers that sum to 7, the possible pairs for (x,y)(x, y) are (1,6)(1, 6), (2,5)(2, 5), and (3,4)(3, 4) (and their reversals). The products (x+1)(y+1)(x+1)(y+1) for these pairs are 2×7=142 \times 7 = 14, 3×6=183 \times 6 = 18, and 4×5=204 \times 5 = 20. The maximum value is 20.

Adım Adım Çözüm

1
Determine the formula for the number of factors of nn.
f(n)=(x+1)(y+1)f(n) = (x + 1)(y + 1)
For any positive integer expressed in its prime factorization pa×qbp^a \times q^b, the total number of positive factors is (a+1)(b+1)(a + 1)(b + 1).
2
Identify the possible values for xx and yy given the constraints.
(x,y){(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}(x, y) \in \{(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)\}
The exponents xx and yy must be positive integers (x,y1x, y \geq 1) that sum to 7.
3
Calculate (x+1)(y+1)(x + 1)(y + 1) for each pair to find the maximum product.
The maximum product is 4×5=204 \times 5 = 20.
Evaluating the products: 2×7=142 \times 7 = 14, 3×6=183 \times 6 = 18, and 4×5=204 \times 5 = 20. The product of two integers with a fixed sum is maximized when the integers are as close as possible.

Anahtar Kavram

Calculating the number of positive factors of an integer from its prime factorization and maximizing the count under exponent constraints.
Tahmini Süre:1m 30s
Soru 30Soru

Four distinct integers, pp, qq, rr, and ss, are represented on a standard number line. The distance between pp and qq is 3, the distance between qq and rr is 4, and the distance between rr and ss is 5. What is the minimum possible distance between pp and ss?

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Cevap: 2

Cevap

The minimum possible distance between pp and ss is 2.
By setting p=0p = 0 as a reference point, the coordinate for qq must be either 33 or 3-3. Assuming q=3q = 3 by symmetry, rr must be either 1-1 or 77 because it is at a distance of 4 from qq. From r=7r = 7, a distance of 5 leads to ss being at 22 or 1212. From r=1r = -1, a distance of 5 leads to ss being at 44 or 6-6. All of these positions result in four distinct integers. The distances between pp and ss are the absolute values of their coordinates, which are 1212, 22, 66, and 44. The minimum of these distances is 22.

Adım Adım Çözüm

1
Establish a coordinate system on the number line.
Let pp be at position 0. Since the distance between pp and qq is 3, qq is at either 33 or 3-3. By symmetry, we assume q=3q = 3.
Setting one point at the origin simplifies the relative distance calculations for all other points.
2
Find the possible coordinates of rr.
Since the distance between qq and rr is 4, rr is at 34=13 - 4 = -1 or 3+4=73 + 4 = 7.
The absolute value equation qr=4|q - r| = 4 has two solutions for rr given q=3q = 3.
3
Find the possible coordinates of ss for each case of rr.
If r=7r = 7, then ss can be at 75=27 - 5 = 2 or 7+5=127 + 5 = 12. If r=1r = -1, then ss can be at 15=6-1 - 5 = -6 or 1+5=4-1 + 5 = 4. All generated sets contain distinct values, satisfying the requirement.
The absolute value equation rs=5|r - s| = 5 has two solutions for ss for each candidate coordinate of rr.
4
Determine the minimum distance between pp and ss.
The possible values for the distance ps|p - s| are 02=2|0 - 2| = 2, 012=12|0 - 12| = 12, 0(6)=6|0 - (-6)| = 6, and 04=4|0 - 4| = 4. The minimum value is 2.
Comparing all possible valid configurations ensures we find the true minimum distance.

Anahtar Kavram

Representing distances between points on a number line using absolute values and resolving configurations for distinct integers.
Soru 31Soru

If x=6x = -6, what is the value of the expression 12x312 - |x - 3|?

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Cevap: 3

Cevap

The value of the expression is 3.
Substituting x=6x = -6 into the expression 12x312 - |x - 3| gives 126312 - |-6 - 3|. Simplifying the subtraction inside the absolute value gives 12912 - |-9|. Since the absolute value of 9-9 is 99, the expression simplifies to 12912 - 9, which equals 33.

Adım Adım Çözüm

1
Substitute x=6x = -6 into the expression.
126312 - |-6 - 3|
Substitute the given value of the variable into the algebraic expression.
2
Simplify the expression inside the absolute value symbol.
12912 - |-9|
Subtracting 3 from 6-6 results in 9-9.
3
Calculate the absolute value.
12912 - 9
The absolute value represents the distance from zero on the number line, so 9=9|-9| = 9.
4
Subtract the numbers to find the final value.
33
129=312 - 9 = 3.

Anahtar Kavram

Evaluating algebraic expressions involving integers and absolute values.
Soru 32Soru

What is the value of the expression below?

[(3)242×5]×2318÷3×(2)3+1 -[(-3)^2 - |4 - 2 \times 5|] \times 2^3 - \frac{18 \div 3 \times (-2)}{-3 + 1}
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Cevap: -30

Cevap

The value of the expression is 30-30.
Applying the correct order of operations (PEMDAS) ensures the expression is evaluated systematically. Evaluating the first term gives [(3)242×5]×23=[96]×8=[96]×8=3×8=24-[(-3)^2 - |4 - 2 \times 5|] \times 2^3 = -[9 - |-6|] \times 8 = -[9 - 6] \times 8 = -3 \times 8 = -24. Evaluating the fraction term gives 18÷3×(2)3+1=6×(2)2=122=6\frac{18 \div 3 \times (-2)}{-3 + 1} = \frac{6 \times (-2)}{-2} = \frac{-12}{-2} = 6. Subtracting the fraction value from the first term results in 246=30-24 - 6 = -30.

Adım Adım Çözüm

1
Simplify the grouping symbols: the bracket and absolute value term.
3-3
First, evaluate the exponent (3)2=9(-3)^2 = 9. Inside the absolute value, multiplication takes precedence over subtraction: 42×5=410=64 - 2 \times 5 = 4 - 10 = -6. The absolute value is 6=6|-6| = 6. Subtracting this from 99 inside the brackets gives 33. Finally, apply the negative sign in front of the brackets to get 3-3.
2
Evaluate the exponent 232^3 and perform the multiplication.
24-24
Exponents are evaluated before multiplication. Since 23=82^3 = 8, the multiplication becomes 3×8=24-3 \times 8 = -24.
3
Evaluate the fraction term.
66
In the numerator, multiplication and division are performed from left to right: 18÷3=618 \div 3 = 6, then 6×(2)=126 \times (-2) = -12. The denominator evaluates to 3+1=2-3 + 1 = -2. Dividing the numerator by the denominator gives 122=6\frac{-12}{-2} = 6.
4
Perform the final subtraction.
30-30
Subtract the evaluated fraction value from the first term: 246=30-24 - 6 = -30.

Anahtar Kavram

Order of operations (PEMDAS), absolute value, and exponent rules with signed numbers.

Alternatif Yöntem

Evaluate each major term separately, paying close attention to grouping symbols, negative signs, and the left-to-right order for multiplication and division.
Tahmini Süre:2m 30s
Soru 33Soru

A positive integer is said to have exactly 88 positive factors. What is the fifth smallest positive integer that satisfies this condition?

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Cevap: 54

Cevap

The fifth smallest positive integer with exactly 8 positive factors is 54.
The fifth smallest positive integer with exactly 8 positive factors is 54. The number of factors of n=p1a1pkakn = p_1^{a_1} \cdots p_k^{a_k} is (a1+1)(ak+1)=8(a_1+1)\cdots(a_k+1) = 8. The possible factorization shapes are p7p^7 (smallest is 128), p3qp^3 q (smallest are 24, 40, 54, 56, 88), and pqrp q r (smallest are 30, 42, 66, 70). Sorting these gives 24, 30, 40, 42, 54, 56, 66, 70, 78, 88, where 54 is the fifth value.

Adım Adım Çözüm

1
Relate the number of positive factors to the prime factorization of a positive integer.
The number of positive factors is (a1+1)(a2+1)(ak+1)=8(a_1 + 1)(a_2 + 1) \cdots (a_k + 1) = 8.
This formula counts all possible combinations of prime factors that form divisors.
2
Determine the possible prime factorization structures that yield exactly 8 factors.
The possible prime factor structures are p7p^7, p3qp^3 q, and pqrp q r for distinct primes pp, qq, and rr.
These correspond to the integer factorizations of 8: 8, 4×24 \times 2, and 2×2×22 \times 2 \times 2.
3
List the smallest candidate values for each structure.
Candidates include 128 (for p7p^7); 24, 40, 54, 56, 88 (for p3qp^3 q); and 30, 42, 66, 70 (for pqrp q r).
Evaluating structures with the smallest available prime numbers (2, 3, 5, 7, etc.) yields the smallest positive integers.
4
Sort all the candidates in ascending order.
The sorted list of smallest values is 24, 30, 40, 42, 54, 56, 66, 70, 78, 88.
Sorting allows us to identify the fifth smallest value precisely.
5
Identify the fifth value in the sorted list.
The fifth element is 54.
Counting from the smallest value (24) to the fifth position yields 54.

Anahtar Kavram

Determining the number of factors of an integer from its prime factorization.
Soru 34Soru

Let xx and yy be integers such that x4|x| \leq 4 and y4|y| \leq 4. How many distinct pairs of integers (x,y)(x, y) satisfy the inequality xy2||x| - |y|| \geq 2?

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Cevap: 36

Cevap

There are 36 distinct pairs of integers (x,y)(x, y) that satisfy the inequality.
By analyzing the possible values for x|x| and y|y| within the set {0,1,2,3,4}\{0, 1, 2, 3, 4\}, we identify the 12 pairs that satisfy the inequality xy2||x| - |y|| \geq 2. When mapping these absolute values back to the actual integer coordinates, we account for the single option when a coordinate is 0 and the two positive/negative options when a coordinate is non-zero. Summing these possibilities yields exactly 36 distinct pairs.

Adım Adım Çözüm

1
Determine the range of absolute values for the integers.
The possible values for x|x| and y|y| are {0,1,2,3,4}\{0, 1, 2, 3, 4\}.
Since xx and yy are integers satisfying 4x,y4-4 \leq x, y \leq 4, their absolute values must be non-negative integers up to 4.
2
Find the pairs of absolute values (x,y)(|x|, |y|) that satisfy the inequality.
The valid pairs are: (0,2),(0,3),(0,4),(1,3),(1,4),(2,0),(2,4),(3,0),(3,1),(4,0),(4,1),(4,2)(0, 2), (0, 3), (0, 4), (1, 3), (1, 4), (2, 0), (2, 4), (3, 0), (3, 1), (4, 0), (4, 1), (4, 2).
We test all combinations of u,v{0,1,2,3,4}u, v \in \{0, 1, 2, 3, 4\} such that uv2|u - v| \geq 2.
3
Calculate the number of integer coordinate pairs (x,y)(x, y) corresponding to each absolute value pair.
Pairs with one zero value yield 2 integer solutions (e.g., u=0,v=2(0,2),(0,2)u=0, v=2 \Rightarrow (0, 2), (0, -2)). Pairs with both non-zero values yield 4 integer solutions (e.g., u=1,v=3(1,3),(1,3),(1,3),(1,3)u=1, v=3 \Rightarrow (1, 3), (1, -3), (-1, 3), (-1, -3)).
An absolute value of 0 corresponds to only 1 integer (00), whereas any positive absolute value kk corresponds to 2 integers (kk and k-k).
4
Sum the number of integer pairs for all valid cases.
Total pairs = (3×2)+(3×2)+(6×4)=6+6+24=36(3 \times 2) + (3 \times 2) + (6 \times 4) = 6 + 6 + 24 = 36.
There are 3 pairs with u=0u=0 (66 solutions), 3 pairs with v=0v=0 (66 solutions), and 6 pairs with both u,v>0u, v > 0 (2424 solutions).

Anahtar Kavram

Solving nested absolute value inequalities with integer constraints and counting solution pairs systematically.
Soru 35Soru

An artist has a rectangular sheet of stained glass that measures 8484 inches by 120120 inches. The artist wants to cut the sheet into congruent square tiles of the largest possible side length, such that there is no glass wasted. What is the total number of square tiles the artist will obtain?

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Cevap: 70

Cevap

The total number of square tiles the artist will obtain is 70.
To find the maximum side length of the square tiles without wasting any glass, we must find the greatest common factor (GCF) of the rectangular dimensions, 8484 and 120120. The prime factorizations are 84=22×3×784 = 2^2 \times 3 \times 7 and 120=23×3×5120 = 2^3 \times 3 \times 5, which gives a GCF of 22×3=122^2 \times 3 = 12 inches. The number of square tiles that fit along the length is 84÷12=784 \div 12 = 7 and along the width is 120÷12=10120 \div 12 = 10. Multiplying these dimensions gives a total of 7×10=707 \times 10 = 70 square tiles.

Adım Adım Çözüm

1
Determine the prime factorizations of the dimensions of the sheet.
84=22×3×784 = 2^2 \times 3 \times 7 and 120=23×3×5120 = 2^3 \times 3 \times 5
This allows finding the greatest common factor of the two side lengths.
2
Calculate the greatest common factor (GCF) of 8484 and 120120.
GCF(84,120)=22×3=12\text{GCF}(84, 120) = 2^2 \times 3 = 12
The largest congruent squares that can tile the sheet without waste must have a side length equal to this GCF.
3
Divide each dimension of the sheet by the tile side length to find the number of tiles along each side.
84÷12=784 \div 12 = 7 tiles along the width, and 120÷12=10120 \div 12 = 10 tiles along the length.
This determines the grid dimensions of the tiles.
4
Multiply the number of tiles along the width by the number of tiles along the length.
7×10=707 \times 10 = 70
The total number of square tiles is the product of the number of tiles along each dimension.

Anahtar Kavram

Greatest Common Factor (GCF) application to division of a two-dimensional grid
Soru 36Soru

Two positive integers, aa and bb, are such that a<ba < b. The greatest common divisor of aa and bb is 1212, and their least common multiple is 720720. If aa is a multiple of 55 but bb is not a multiple of 55, what is the value of aa?

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Cevap: 60

Cevap

60
By representing a=12xa = 12x and b=12yb = 12y with gcd(x,y)=1\gcd(x, y) = 1 and x<yx < y, the least common multiple constraint gives 12xy=72012xy = 720, which simplifies to xy=60xy = 60. Since aa is a multiple of 55 and bb is not, the factor of 55 in 6060 must belong to xx. Given that x<yx < y and gcd(x,y)=1\gcd(x, y) = 1, the only valid coprime factorization of 6060 where the factor 55 is in xx and x<yx < y is x=5x = 5 and y=12y = 12. This yields a=12×5=60a = 12 \times 5 = 60.

Adım Adım Çözüm

1
Express the two numbers in terms of their greatest common divisor (GCD).
a=12xa = 12x and b=12yb = 12y, where gcd(x,y)=1\gcd(x, y) = 1 and x<yx < y.
Since the greatest common divisor of aa and bb is 1212, both numbers must be multiples of 1212, and their remaining parts xx and yy must be coprime to ensure their GCD is exactly 1212.
2
Use the least common multiple (LCM) to find the product of xx and yy.
xy=60xy = 60.
The least common multiple of 12x12x and 12y12y when gcd(x,y)=1\gcd(x, y) = 1 is 12xy12xy. Setting 12xy=72012xy = 720 and dividing by 1212 gives xy=60xy = 60.
3
Identify the constraints on xx and yy based on the divisibility by 55.
55 must divide xx, and 55 must not divide yy.
We are given that a=12xa = 12x is a multiple of 55, which means 55 must be a factor of xx. Since b=12yb = 12y is not a multiple of 55, 55 cannot be a factor of yy.
4
Determine the unique pair (x,y)(x, y) that satisfies all constraints.
x=5x = 5 and y=12y = 12.
The product xy=60xy = 60 has prime factorization 22×3×52^2 \times 3 \times 5. Since gcd(x,y)=1\gcd(x, y) = 1, the factor 55 must belong to xx, and the other prime factors 222^2 and 33 can be distributed. To satisfy x<yx < y, the only possible assignment is x=5x = 5 and y=12y = 12 (since other assignments like x=15,y=4x = 15, y = 4 or x=20,y=3x = 20, y = 3 violate x<yx < y).
5
Calculate the value of aa.
a=60a = 60.
Since a=12xa = 12x and x=5x = 5, we find a=12×5=60a = 12 \times 5 = 60.

Anahtar Kavram

Using prime factorizations to analyze greatest common divisors and least common multiples under algebraic and inequality constraints.
Soru 37Soru

Point PP is located at 14-14 on a standard number line. Point QQ is located 88 units from point PP in the positive direction. Point RR is located 1111 units from point QQ in the negative direction. What integer represents the location of point RR?

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Cevap: -17

Cevap

The position of point RR is represented by the integer 17-17.
To find the location of point RR, we first determine the location of point QQ by moving 88 units in the positive direction (right) from point PP (at 14-14), which gives 14+8=6-14 + 8 = -6. Next, we find the location of point RR by moving 1111 units in the negative direction (left) from point QQ (at 6-6), which gives 611=17-6 - 11 = -17.

Adım Adım Çözüm

1
Calculate the position of point QQ.
6-6
Since point QQ is 88 units from point PP (which is at 14-14) in the positive direction, we add 88 to 14-14: 14+8=6-14 + 8 = -6.
2
Calculate the position of point RR.
17-17
Since point RR is 1111 units from point QQ (which is at 6-6) in the negative direction, we subtract 1111 from 6-6: 611=17-6 - 11 = -17.

Anahtar Kavram

Adding and subtracting integers on a number line to find positions relative to a starting point.
Tahmini Süre:45s
Soru 38Soru

What is the integer value of the expression 42+15÷3×2(3)3-4^2 + | -15 \div 3 \times 2 | - (-3)^3?

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Cevap: 21

Cevap

The correct answer is 21.
The correct answer is obtained by strictly following the order of operations (PEMDAS): first evaluating exponents (42=16-4^2 = -16 and (3)3=27(-3)^3 = -27), then performing the operations inside the absolute value from left to right (15÷3=5-15 \div 3 = -5 followed by 5×2=10-5 \times 2 = -10, which simplifies to 10=10|-10| = 10), and finally executing addition and subtraction from left to right (16+10(27)=21-16 + 10 - (-27) = 21).

Adım Adım Çözüm

1
Evaluate the exponent 42-4^2
16-16
According to the order of operations, the exponent is applied to the base 4 first, and then the negation is applied, yielding (42)=16-(4^2) = -16.
2
Evaluate the absolute value expression 15÷3×2|-15 \div 3 \times 2|
1010
Multiplication and division have the same precedence and must be performed from left to right: first 15÷3=5-15 \div 3 = -5, then 5×2=10-5 \times 2 = -10. Taking the absolute value of 10-10 yields 1010.
3
Evaluate the exponent (3)3(-3)^3
27-27
Since the negative sign is inside the parentheses, the base is 3-3, so (3)3=(3)×(3)×(3)=27(-3)^3 = (-3) \times (-3) \times (-3) = -27.
4
Combine the values and simplify
2121
Substitute the evaluated parts into the original expression: 16+10(27)-16 + 10 - (-27). Simplify by performing addition and subtraction from left to right: 16+10=6-16 + 10 = -6, and 6(27)=6+27=21-6 - (-27) = -6 + 27 = 21.

Anahtar Kavram

Order of operations (PEMDAS) and absolute value properties
Soru 39Soru

What is the value of the expression 53645^3 - \sqrt{64}?

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Cevap: 117

Cevap

The correct answer is 117117.
Evaluating 535^3 gives 125125 since 5×5×5=1255 \times 5 \times 5 = 125. The square root of 6464 is 88 because 82=648^2 = 64. Subtracting 88 from 125125 yields the correct result of 117117.

Adım Adım Çözüm

1
Evaluate the exponential term 535^3
125125
An exponent indicates how many times a base is multiplied by itself. Here, 53=5×5×5=1255^3 = 5 \times 5 \times 5 = 125.
2
Evaluate the radical term 64\sqrt{64}
88
The square root of a number is the non-negative value that, when multiplied by itself, equals the original number. Since 8×8=648 \times 8 = 64, 64=8\sqrt{64} = 8.
3
Subtract the evaluated terms
117117
Subtract the value of the radical from the value of the exponent to simplify the expression: 1258=117125 - 8 = 117.

Anahtar Kavram

Evaluating basic exponents and square roots
Soru 40Soru

If a=3a = 3 and b=2b = 2, what is the value of the expression a4b5\sqrt{a^4 - b^5}?

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Cevap: 7

Cevap

The value of the expression is 7.
Evaluating the exponents yields 34=813^4 = 81 and 25=322^5 = 32. Substituting these values under the radical gives 8132=49\sqrt{81 - 32} = \sqrt{49}. Evaluating the square root of 49 gives the correct value of 7.

Adım Adım Çözüm

1
Evaluate the terms with exponents using the given values a=3a = 3 and b=2b = 2.
a4=34=81a^4 = 3^4 = 81 and b5=25=32b^5 = 2^5 = 32
Exponent operations must be evaluated before performing subtraction or taking the root.
2
Substitute the evaluated terms back into the radical expression and subtract.
8132=49\sqrt{81 - 32} = \sqrt{49}
Simplifying the expression under the radical is necessary before taking the square root.
3
Find the square root of the simplified value.
49=7\sqrt{49} = 7
Evaluating the square root of 49 completes the simplification of the expression.

Anahtar Kavram

Evaluating expressions involving exponents, subtraction, and square roots
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