Tüm alıştırma soruları

5556 soru

Soru 1781Soru

If the expression x48x2+169y2x^4 - 8x^2 + 16 - 9y^2 is factored completely over the integers, the product of the factors can be written as (x2aby)(x2c+dy)(x^2 - a - by)(x^2 - c + dy), where aa, bb, cc, and dd are positive integers. What is the value of a+b+c+da + b + c + d?

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Cevap: 14

Cevap

14
By grouping the first three terms, the expression x48x2+16x^4 - 8x^2 + 16 is recognized as (x24)2(x^2 - 4)^2. Substituting this back into the original expression gives (x24)2(3y)2(x^2 - 4)^2 - (3y)^2. Applying the difference of squares identity, this factors into (x243y)(x24+3y)(x^2 - 4 - 3y)(x^2 - 4 + 3y). Comparing this result to (x2aby)(x2c+dy)(x^2 - a - by)(x^2 - c + dy) where a,b,c,da, b, c, d are positive integers yields a=4a = 4, b=3b = 3, c=4c = 4, and d=3d = 3. Summing these values gives 4+3+4+3=144 + 3 + 4 + 3 = 14.

Adım Adım Çözüm

1
Group the first three terms of the polynomial.
x48x2+16=(x24)2x^4 - 8x^2 + 16 = (x^2 - 4)^2
To recognize the perfect square trinomial structure in terms of x2x^2.
2
Rewrite the original expression using the grouped terms.
(x24)29y2=(x24)2(3y)2(x^2 - 4)^2 - 9y^2 = (x^2 - 4)^2 - (3y)^2
To express the polynomial as a difference of squares.
3
Factor the expression using the difference of squares formula A2B2=(AB)(A+B)A^2 - B^2 = (A - B)(A + B).
(x243y)(x24+3y)(x^2 - 4 - 3y)(x^2 - 4 + 3y)
To obtain the completely factored form over the integers.
4
Compare the factored expression to the given template (x2aby)(x2c+dy)(x^2 - a - by)(x^2 - c + dy) where a,b,c,da, b, c, d are positive integers.
a=4a = 4, b=3b = 3, c=4c = 4, d=3d = 3
To identify the values of the constants that satisfy the positivity constraint.
5
Calculate the sum of the identified values.
a+b+c+d=4+3+4+3=14a + b + c + d = 4 + 3 + 4 + 3 = 14
To answer the question.

Anahtar Kavram

Factoring by grouping and the difference of squares
Soru 1782Soru
What is the sum of all real values of xx that satisfy the equation x23xx23x+2+x23x1x23x3=113\frac{x^2 - 3x}{x^2 - 3x + 2} + \frac{x^2 - 3x - 1}{x^2 - 3x - 3} = \frac{11}{3}?
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Cevap: 3

Cevap

The sum of all real values of xx that satisfy the equation is 33.
Substituting y=x23xy = x^2 - 3x simplifies the original rational equation into the quadratic form y2y12=0y^2 - y - 12 = 0. Solving for yy yields the values 44 and 3-3. Substituting back x23xx^2 - 3x for yy produces two quadratic equations. The first, x23x4=0x^2 - 3x - 4 = 0, has real solutions of 44 and 1-1. The second, x23x+3=0x^2 - 3x + 3 = 0, has a negative discriminant and produces no real solutions. Summing the valid real solutions gives 4+(1)=34 + (-1) = 3.

Adım Adım Çözüm

1
Substitute y=x23xy = x^2 - 3x into the equation to simplify the rational terms.
yy+2+y1y3=113\frac{y}{y+2} + \frac{y-1}{y-3} = \frac{11}{3}
Using a temporary variable simplifies the algebraic manipulation of the rational expressions.
2
Multiply the entire equation by the least common denominator, 3(y+2)(y3)3(y+2)(y-3), to eliminate all fractions.
3y(y3)+3(y1)(y+2)=11(y+2)(y3)3y(y-3) + 3(y-1)(y+2) = 11(y+2)(y-3), where y2y \neq -2 and y3y \neq 3
This clears the denominators so the equation can be solved as a polynomial.
3
Expand the terms on both sides of the equation.
(3y29y)+(3y2+3y6)=11y211y66(3y^2 - 9y) + (3y^2 + 3y - 6) = 11y^2 - 11y - 66
Expanding allows for combining like terms.
4
Combine like terms and move all terms to one side of the equation to set it equal to zero.
5y25y60=05y^2 - 5y - 60 = 0
This sets up the expression in the standard quadratic form ay2+by+c=0ay^2 + by + c = 0.
5
Divide the entire quadratic equation by its greatest common factor, 55, and factor the resulting expression.
y2y12=0    (y4)(y+3)=0    y=4 or y=3y^2 - y - 12 = 0 \implies (y-4)(y+3) = 0 \implies y = 4 \text{ or } y = -3
Factoring solves for the possible values of the substituted variable yy.
6
Substitute back y=x23xy = x^2 - 3x for each case and solve the resulting quadratic equations for xx.
For y=4y = 4: x23x4=0    (x4)(x+1)=0    x=4 or x=1x^2 - 3x - 4 = 0 \implies (x-4)(x+1) = 0 \implies x = 4 \text{ or } x = -1.
For y=3y = -3: x23x+3=0x^2 - 3x + 3 = 0. The discriminant is (3)24(1)(3)=3<0(-3)^2 - 4(1)(3) = -3 < 0, which means there are no real solutions.
This determines the real values of xx that solve the original equation.
7
Verify that neither solution makes the original denominators zero, and add the valid real solutions.
4+(1)=34 + (-1) = 3
Since both x=4x = 4 and x=1x = -1 result in non-zero denominators, both are valid real solutions. Their sum is 33.

Anahtar Kavram

Solving rational equations by utilizing algebraic substitution to reduce complexity and analyzing quadratic equations for real solutions.
Soru 1783Soru

For the imaginary unit ii, where i2=1i^2 = -1, the complex number zz is defined by:

z=13i451+i95z = \frac{1 - 3i^{45}}{1 + i^{95}}

Which of the following is equivalent to z2z^2?

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Cevap: 3 - 4i

Cevap

3 - 4i
The correct answer is found by first simplifying the powers of ii in the expression for zz: i45=ii^{45} = i and i95=ii^{95} = -i, which yields z=13i1iz = \frac{1 - 3i}{1 - i}. Rationalizing the fraction by multiplying both the numerator and the denominator by the conjugate of the denominator (1+i1 + i) simplifies the expression to z=2iz = 2 - i. Finally, squaring this result using the binomial expansion formula gives (2i)2=44i+i2=34i(2 - i)^2 = 4 - 4i + i^2 = 3 - 4i.

Adım Adım Çözüm

1
Simplify the high integer powers of the imaginary unit ii by using the fact that powers of ii repeat in a cycle of four: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, and i4=1i^4 = 1.
i45=ii^{45} = i and i95=ii^{95} = -i
Since 45=4(11)+145 = 4(11) + 1, the remainder is 11, so i45=i1=ii^{45} = i^1 = i. Since 95=4(23)+395 = 4(23) + 3, the remainder is 33, so i95=i3=ii^{95} = i^3 = -i.
2
Substitute these simplified values back into the expression for zz.
z=13i1iz = \frac{1 - 3i}{1 - i}
This sets up the fraction with simplified imaginary terms in both the numerator and the denominator.
3
Rationalize the denominator by multiplying the numerator and denominator of the fraction by the complex conjugate of the denominator, which is 1+i1 + i.
z=2iz = 2 - i
Multiplying by the conjugate eliminates the imaginary unit from the denominator: (13i)(1+i)(1i)(1+i)=1+i3i3i21i2=42i2=2i\frac{(1 - 3i)(1 + i)}{(1 - i)(1 + i)} = \frac{1 + i - 3i - 3i^2}{1 - i^2} = \frac{4 - 2i}{2} = 2 - i.
4
Calculate the value of z2z^2 by squaring the simplified complex number 2i2 - i.
z2=34iz^2 = 3 - 4i
Using the binomial squaring formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2, we expand (2i)2(2 - i)^2 to get 222(2)(i)+i2=44i1=34i2^2 - 2(2)(i) + i^2 = 4 - 4i - 1 = 3 - 4i.

Anahtar Kavram

Simplifying complex numbers by evaluating powers of ii, rationalizing fractions with complex conjugates, and expanding complex binomials.
Tahmini Süre:1m 30s
Soru 1784Soru

When the expression (p2q)3p(p3q)(2p+q)+3q2(pq)-(p - 2q)^3 - p(p - 3q)(2p + q) + 3q^2(p - q) is completely simplified by combining like terms, what is the coefficient of p2qp^2q?

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Cevap: 11

Cevap

The coefficient of p2qp^2q in the fully simplified expression is 11.
Expanding the three components of the expression yields: (p2q)3=p3+6p2q12pq2+8q3-(p - 2q)^3 = -p^3 + 6p^2q - 12pq^2 + 8q^3; p(p3q)(2p+q)=2p3+5p2q+3pq2-p(p - 3q)(2p + q) = -2p^3 + 5p^2q + 3pq^2; and 3q2(pq)=3pq23q33q^2(p - q) = 3pq^2 - 3q^3. Combining these terms gives the simplified polynomial 3p3+11p2q6pq2+5q3-3p^3 + 11p^2q - 6pq^2 + 5q^3. The coefficient of p2qp^2q is 11.

Adım Adım Çözüm

1
Expand and negate the term (p2q)3-(p - 2q)^3
p3+6p2q12pq2+8q3-p^3 + 6p^2q - 12pq^2 + 8q^3
Using the binomial theorem expansion for (ab)3=a33a2b+3ab2b3(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3 and distributing the negative sign.
2
Multiply and distribute p(p3q)(2p+q)-p(p - 3q)(2p + q)
2p3+5p2q+3pq2-2p^3 + 5p^2q + 3pq^2
First multiply the binomials (p3q)(2p+q)=2p25pq3q2(p - 3q)(2p + q) = 2p^2 - 5pq - 3q^2, and then multiply each term by p-p.
3
Distribute 3q2(pq)3q^2(p - q)
3pq23q33pq^2 - 3q^3
Multiply 3q23q^2 by both terms inside the binomial.
4
Combine the like terms of p2qp^2q
1111
Identify and sum all terms containing p2qp^2q: 6p2q+5p2q=11p2q6p^2q + 5p^2q = 11p^2q.

Anahtar Kavram

Simplifying algebraic expressions by expanding polynomials, applying the distributive property with negative signs, and combining like terms.
Soru 1785Soru

Let ii be the imaginary unit such that i2=1i^2 = -1. What is the simplified form of the expression (1+2i)2(3i)(1 + 2i)^2(3 - i)?

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Cevap: 5+15i-5 + 15i

Cevap

5+15i-5 + 15i
The correct answer is 5+15i-5 + 15i. We first expand the squared binomial (1+2i)2(1 + 2i)^2, which results in 1+4i+4i21 + 4i + 4i^2. Substituting i2=1i^2 = -1 yields 3+4i-3 + 4i. We then multiply this by the second binomial (3i)(3 - i) to get 9+3i+12i4i2-9 + 3i + 12i - 4i^2. Substituting i2=1i^2 = -1 one more time and combining like terms leads to the final simplified result of 5+15i-5 + 15i.

Adım Adım Çözüm

1
Expand the squared binomial (1+2i)2(1 + 2i)^2
1+4i+4i21 + 4i + 4i^2
Before multiplying by the second binomial, we must apply the exponent to the first binomial according to the order of operations.
2
Substitute i2=1i^2 = -1 to simplify the expression from Step 1
3+4i-3 + 4i
Since i2=1i^2 = -1, the term 4i24i^2 becomes 4(1)=44(-1) = -4, and combining the real parts gives 14=31 - 4 = -3.
3
Multiply the simplified term by (3i)(3 - i) using the FOIL method
9+3i+12i4i2-9 + 3i + 12i - 4i^2
We distribute each term of the first binomial into the second binomial: (3)(3)=9(-3)(3) = -9, (3)(i)=3i(-3)(-i) = 3i, (4i)(3)=12i(4i)(3) = 12i, and (4i)(i)=4i2(4i)(-i) = -4i^2.
4
Simplify the resulting expression by combining like terms and substituting i2=1i^2 = -1
5+15i-5 + 15i
Combining the imaginary parts gives 3i+12i=15i3i + 12i = 15i. Substituting i2=1i^2 = -1 into 4i2-4i^2 gives 4(1)=+4-4(-1) = +4. Finally, combining the real parts yields 9+4=5-9 + 4 = -5.

Anahtar Kavram

Simplification of complex expressions involving binomial squaring and multiplication under the definition i2=1i^2 = -1.
Tahmini Süre:1m 30s
Soru 1786Soru

If kk is a positive real number such that k+4k=15\sqrt{k} + \sqrt{4k} = 15, what is the value of kk?

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Cevap: 25

Cevap

25
The correct answer is 2525. To find this, we simplify 4k\sqrt{4k} to 2k2\sqrt{k}. Substituting this into the equation gives k+2k=15\sqrt{k} + 2\sqrt{k} = 15. Combining like terms yields 3k=153\sqrt{k} = 15. Dividing both sides by 33 gives k=5\sqrt{k} = 5. Squaring both sides of the equation results in k=25k = 25. Checking the solution: 25+4(25)=5+10=15\sqrt{25} + \sqrt{4(25)} = 5 + 10 = 15, which is true.

Adım Adım Çözüm

1
Simplify the radical term 4k\sqrt{4k} using the product property of radicals.
4k=4k=2k\sqrt{4k} = \sqrt{4} \cdot \sqrt{k} = 2\sqrt{k}
This allows us to express both terms in the equation using the same radical base, k\sqrt{k}.
2
Substitute the simplified term back into the equation and combine like terms.
k+2k=15    3k=15\sqrt{k} + 2\sqrt{k} = 15 \implies 3\sqrt{k} = 15
Combining like radical terms simplifies the equation to a single radical term.
3
Isolate the radical by dividing both sides of the equation by 33.
k=5\sqrt{k} = 5
Isolating the radical term is necessary before squaring both sides to solve for the variable.
4
Square both sides of the equation to solve for kk.
k=25k = 25
Squaring is the inverse operation of taking the square root, which isolates kk.

Anahtar Kavram

Solving radical equations by simplifying and combining like radical terms
Soru 1787Soru

For the imaginary unit ii, where i2=1i^2 = -1, what is the real part of the complex number z=(2i)3+9iz = (2 - i)^3 + 9i?

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Cevap: 2

Cevap

The real part of the complex number is 2.
Expanding the expression (2i)3(2 - i)^3 yields 211i2 - 11i. Adding 9i9i gives 22i2 - 2i. The real part of this complex number is the term without ii, which is 2.

Adım Adım Çözüm

1
Expand the squared binomial (2i)2(2 - i)^2.
34i3 - 4i
Apply the identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 and substitute i2=1i^2 = -1.
2
Multiply the result of the square by (2i)(2 - i) to calculate (2i)3(2 - i)^3.
211i2 - 11i
Distribute the terms (34i)(2i)=63i8i+4i2(3 - 4i)(2 - i) = 6 - 3i - 8i + 4i^2 and substitute i2=1i^2 = -1.
3
Add 9i9i to the simplified cube to find the complex number zz.
22i2 - 2i
Combine the imaginary components: 11i+9i=2i-11i + 9i = -2i.
4
Identify the real part of zz.
2
The real part of a complex number a+bia + bi is aa.

Anahtar Kavram

Expanding complex binomials and simplifying powers of the imaginary unit
Soru 1788Soru

For all real numbers yy that satisfy the inequality y362||y - 3| - 6| \leq 2, what is the sum of all possible integer values of yy?

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Cevap: 3030

Cevap

The sum of all possible integer values of yy is 3030.
The compound inequality 4y384 \leq |y - 3| \leq 8 splits into two parts: y38|y - 3| \leq 8 (which gives 5y11-5 \leq y \leq 11) and y34|y - 3| \geq 4 (which gives y1y \leq -1 or y7y \geq 7). The intersection of these intervals is [5,1][7,11][-5, -1] \cup [7, 11]. Summing all the integers in these intervals gives (5+4+3+2+1)+(7+8+9+10+11)=15+45=30(-5 + -4 + -3 + -2 + -1) + (7 + 8 + 9 + 10 + 11) = -15 + 45 = 30.

Adım Adım Çözüm

1
Set up the compound inequality representing the outer absolute value.
2y362-2 \leq |y - 3| - 6 \leq 2
By definition, ua|u| \leq a is equivalent to aua-a \leq u \leq a for a0a \geq 0.
2
Isolate the inner absolute value term by adding 66 to all parts of the inequality.
4y384 \leq |y - 3| \leq 8
Isolating the absolute value allows us to split the compound inequality into two separate cases.
3
Split the compound inequality into two separate inequalities and solve each one.
y38|y - 3| \leq 8 and y34|y - 3| \geq 4
The expression y3|y - 3| must be simultaneously less than or equal to 88 and greater than or equal to 44.
4
Solve the first inequality, y38|y - 3| \leq 8.
5y11-5 \leq y \leq 11
Rewriting the inequality gives 8y38-8 \leq y - 3 \leq 8, and adding 33 to all parts yields the interval [5,11][-5, 11].
5
Solve the second inequality, y34|y - 3| \geq 4.
y1y \leq -1 or y7y \geq 7
By definition, ua|u| \geq a is equivalent to uau \geq a or uau \leq -a. Thus, y34    y7y - 3 \geq 4 \implies y \geq 7, and y34    y1y - 3 \leq -4 \implies y \leq -1.
6
Determine the intersection of the two solution sets.
y[5,1][7,11]y \in [-5, -1] \cup [7, 11]
The values of yy must lie within [5,11][-5, 11] and also satisfy y1y \leq -1 or y7y \geq 7.
7
Identify the integers within the final intervals and calculate their sum.
Sum = 3030
The integers in [5,1][-5, -1] are 5,4,3,2,1-5, -4, -3, -2, -1 (sum = 15-15). The integers in [7,11][7, 11] are 7,8,9,10,117, 8, 9, 10, 11 (sum = 4545). The total sum is 15+45=30-15 + 45 = 30.

Anahtar Kavram

Solving compound and nested absolute value inequalities

Alternatif Yöntem

Instead of solving the inequality algebraically, one can test the integer values around the critical points. Since yy must satisfy 4y384 \leq |y - 3| \leq 8, we can see that the distance of yy from 33 must be between 44 and 88 units. The integers at distance 4,5,6,7,84, 5, 6, 7, 8 to the right of 33 are 7,8,9,10,117, 8, 9, 10, 11. The integers at distance 4,5,6,7,84, 5, 6, 7, 8 to the left of 33 are 1,2,3,4,5-1, -2, -3, -4, -5. Summing these ten integers yields 3030.
Tahmini Süre:3m 0s
Soru 1789Soru

When solving the radical equation 2x24x6=x3\sqrt{2x^2 - 4x - 6} = x - 3 for all real values of xx, one of the solutions obtained from the squared equation is extraneous. What is the value of this extraneous solution?

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Cevap: -5

Cevap

The value of the extraneous solution is 5-5.
The correct answer is 5-5. Squaring both sides of the equation 2x24x6=x3\sqrt{2x^2 - 4x - 6} = x - 3 yields 2x24x6=x26x+92x^2 - 4x - 6 = x^2 - 6x + 9, which simplifies to x2+2x15=0x^2 + 2x - 15 = 0. Factoring this quadratic gives (x+5)(x3)=0(x + 5)(x - 3) = 0, leading to potential solutions of 33 and 5-5. Substituting 5-5 back into the original equation results in the left side simplifying to 88 and the right side simplifying to 8-8. Since 888 \neq -8, the value 5-5 is an extraneous solution.

Adım Adım Çözüm

1
Square both sides of the original radical equation to eliminate the square root.
2x24x6=(x3)22x^2 - 4x - 6 = (x - 3)^2
Squaring both sides removes the radical on the left side.
2
Expand the right side and move all terms to the left side to set the quadratic equation to zero.
x2+2x15=0x^2 + 2x - 15 = 0
Expanding (x3)2(x - 3)^2 gives x26x+9x^2 - 6x + 9. Subtracting this expression from both sides yields the simplified quadratic equation.
3
Factor the quadratic equation to find the potential solutions.
(x+5)(x3)=0(x + 5)(x - 3) = 0, which gives x=5x = -5 and x=3x = 3.
The factors of 15-15 that add up to 22 are 55 and 3-3.
4
Substitute each potential solution back into the original equation to check for extraneous roots.
For x=3x = 3, 2(3)24(3)6=33\sqrt{2(3)^2 - 4(3) - 6} = 3 - 3 simplifies to 0=00 = 0 (valid). For x=5x = -5, 2(5)24(5)6=53\sqrt{2(-5)^2 - 4(-5) - 6} = -5 - 3 simplifies to 8=88 = -8 (invalid).
Extraneous solutions satisfy the squared equation but do not satisfy the original radical equation due to the sign difference introduced by squaring.

Anahtar Kavram

Solving radical equations and identifying extraneous solutions
Tahmini Süre:2m 0s
Soru 1790Soru

A dataset consists of 77 positive integers sorted in non-decreasing order. The mean of the dataset is 2020, the median is 1818, and the unique mode is 1515. If the range of the dataset is 2222, what is the minimum possible value of the largest number in the dataset?

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Cevap: 30

Cevap

30
The correct answer is 30 because minimizing the largest value requires minimizing the smallest value under the sum and uniqueness constraints. When the smallest value is 8, the largest value is 30, which allows for a valid, sorted sequence of positive integers where 15 is the unique mode: {8, 15, 15, 18, 26, 28, 30}.

Adım Adım Çözüm

1
Set up the variables for the sorted dataset.
Let the seven positive integers in non-decreasing order be x1,x2,x3,x4,x5,x6,x7x_1, x_2, x_3, x_4, x_5, x_6, x_7. Since the median is the 4th value, x4=18x_4 = 18. The mean is 2020, so the sum of all elements is 7×20=1407 \times 20 = 140.
Establishing standard notation and utilizing the definitions of median and mean.
2
Incorporate the range into the sum equation.
x1+x2+x3+18+x5+x6+x7=140x_1 + x_2 + x_3 + 18 + x_5 + x_6 + x_7 = 140. Since the range is 2222, the largest number is x7=x1+22x_7 = x_1 + 22. Substituting this into the sum gives 2x1+x2+x3+x5+x6=1002x_1 + x_2 + x_3 + x_5 + x_6 = 100.
Simplifying the system of equations by expressing the largest element in terms of the smallest element.
3
Apply the mode constraint.
The unique mode is 1515. Since x4=18x_4 = 18 and the dataset is sorted, 1515 must be in the lower half of the dataset and must repeat. Thus, x2=x3=15x_2 = x_3 = 15. The equation simplifies to 2x1+30+x5+x6=100    2x1+x5+x6=702x_1 + 30 + x_5 + x_6 = 100 \implies 2x_1 + x_5 + x_6 = 70.
Using the properties of the mode and sorted list to lock the values of the second and third elements.
4
Set up inequalities to minimize the largest value.
To minimize x7=x1+22x_7 = x_1 + 22, we must minimize x1x_1, which is equivalent to maximizing x5x_5 and x6x_6. Since 1515 is the unique mode with a frequency of 22, no other value can repeat. Thus, x5,x6,x_5, x_6, and x7x_7 must be distinct from each other and larger than the median 1818. This means x519x_5 \ge 19. The upper bounds are x6x71=x1+21x_6 \le x_7 - 1 = x_1 + 21 and x5x72=x1+20x_5 \le x_7 - 2 = x_1 + 20.
Applying the uniqueness constraint of the mode to restrict the values of the upper half of the dataset.
5
Solve for the minimum integer value of the smallest element.
Substitute the maximum bounds of x5x_5 and x6x_6 into the equation: 2x1+(x1+20)+(x1+21)70    4x1+4170    4x129    x17.252x_1 + (x_1 + 20) + (x_1 + 21) \ge 70 \implies 4x_1 + 41 \ge 70 \implies 4x_1 \ge 29 \implies x_1 \ge 7.25. Since x1x_1 must be an integer, the minimum possible value is x1=8x_1 = 8. This yields a minimum largest value of x7=8+22=30x_7 = 8 + 22 = 30.
Solving the inequality system to find the smallest valid integer boundaries.

Anahtar Kavram

Descriptive Statistics and Optimization
Soru 1791Soru

For all real values of xx and yy, the expression 4x29y212y44x^2 - 9y^2 - 12y - 4 can be factored into the form (2x+ay+b)(2xcyd)(2x + ay + b)(2x - cy - d), where a,b,ca, b, c, and dd are positive integers. What is the value of a+b+c+da + b + c + d?

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Cevap: 10

Cevap

The value of a+b+c+da + b + c + d is 10.
Grouping the yy terms gives 4x2(9y2+12y+4)4x^2 - (9y^2 + 12y + 4). Factoring the quadratic within the parentheses gives 4x2(3y+2)24x^2 - (3y + 2)^2. Applying the difference of squares identity (u2v2)=(u+v)(uv)(u^2 - v^2) = (u + v)(u - v) leads to (2x+(3y+2))(2x(3y+2))=(2x+3y+2)(2x3y2)(2x + (3y + 2))(2x - (3y + 2)) = (2x + 3y + 2)(2x - 3y - 2). Matching this expression to the template (2x+ay+b)(2xcyd)(2x + ay + b)(2x - cy - d) reveals that a=3a = 3, b=2b = 2, c=3c = 3, and d=2d = 2, all of which are positive integers. The sum of these values is 3+2+3+2=103 + 2 + 3 + 2 = 10.

Adım Adım Çözüm

1
Group the terms containing yy
4x2(9y2+12y+4)4x^2 - (9y^2 + 12y + 4)
Grouping the terms allows us to identify a perfect square trinomial pattern.
2
Factor the trinomial inside the parentheses
4x2(3y+2)24x^2 - (3y + 2)^2
The expression 9y2+12y+49y^2 + 12y + 4 is a perfect square trinomial of the form (3y)2+2(3y)(2)+22(3y)^2 + 2(3y)(2) + 2^2.
3
Apply the difference of squares identity
(2x+(3y+2))(2x(3y+2))(2x + (3y + 2))(2x - (3y + 2))
The expression is in the form u2v2u^2 - v^2, where u=2xu = 2x and v=3y+2v = 3y + 2. Using u2v2=(u+v)(uv)u^2 - v^2 = (u + v)(u - v) factors the expression.
4
Simplify the factored binomials by distributing signs
(2x+3y+2)(2x3y2)(2x + 3y + 2)(2x - 3y - 2)
Simplifying the expressions removes inner parentheses, allowing comparison with the target template.
5
Compare with the template (2x+ay+b)(2xcyd)(2x + ay + b)(2x - cy - d) to find the constants
a=3a = 3, b=2b = 2, c=3c = 3, d=2d = 2
Matching the terms directly gives ay=3ya=3ay = 3y \Rightarrow a = 3, b=2b = 2, cy=3yc=3-cy = -3y \Rightarrow c = 3, and d=2d=2-d = -2 \Rightarrow d = 2.
6
Calculate the sum of the positive integers
10
The question asks for the value of a+b+c+da + b + c + d, which is 3+2+3+2=103 + 2 + 3 + 2 = 10.

Anahtar Kavram

Factoring polynomials using grouping, perfect square trinomials, and the difference of squares identity
Tahmini Süre:2m 0s
Soru 1792Soru

When the expression 2x(x23xy+2y2)(x2y)3y(x25xy+4y2)2x(x^2 - 3xy + 2y^2) - (x - 2y)^3 - y(x^2 - 5xy + 4y^2) is fully simplified by combining like terms, what is the coefficient of the xy2xy^2 term?

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Cevap: -3

Cevap

The coefficient of the xy2xy^2 term is 3-3.
Expanding the terms of the expression yields 2x36x2y+4xy22x^3 - 6x^2y + 4xy^2, x3+6x2y12xy2+8y3-x^3 + 6x^2y - 12xy^2 + 8y^3, and x2y+5xy24y3-x^2y + 5xy^2 - 4y^3. Summing the coefficients of the xy2xy^2 terms gives 412+5=34 - 12 + 5 = -3. Thus, the coefficient of xy2xy^2 is 3-3.

Adım Adım Çözüm

1
Expand the first term of the expression: 2x(x23xy+2y2)2x(x^2 - 3xy + 2y^2)
2x36x2y+4xy22x^3 - 6x^2y + 4xy^2
Distribute the monomial 2x2x to each term inside the parentheses: 2xx2=2x32x \cdot x^2 = 2x^3, 2x(3xy)=6x2y2x \cdot (-3xy) = -6x^2y, and 2x2y2=4xy22x \cdot 2y^2 = 4xy^2.
2
Expand the cubed binomial (x2y)3(x - 2y)^3 and distribute the negative sign
x3+6x2y12xy2+8y3-x^3 + 6x^2y - 12xy^2 + 8y^3
First, expand the binomial (x2y)3=x33(x2)(2y)+3(x)(2y)2(2y)3=x36x2y+12xy28y3(x - 2y)^3 = x^3 - 3(x^2)(2y) + 3(x)(2y)^2 - (2y)^3 = x^3 - 6x^2y + 12xy^2 - 8y^3. Then, distribute the negative sign to all terms inside the parentheses.
3
Expand the third term: y(x25xy+4y2)-y(x^2 - 5xy + 4y^2)
x2y+5xy24y3-x^2y + 5xy^2 - 4y^3
Distribute the negative monomial y-y to each term inside the parentheses: yx2=x2y-y \cdot x^2 = -x^2y, y(5xy)=5xy2-y \cdot (-5xy) = 5xy^2, and y4y2=4y3-y \cdot 4y^2 = -4y^3.
4
Group and combine all like terms
x3x2y3xy2+4y3x^3 - x^2y - 3xy^2 + 4y^3
Combine the coefficients of the corresponding terms: (2x3x3)+(6x2y+6x2yx2y)+(4xy212xy2+5xy2)+(8y34y3)=x3x2y3xy2+4y3(2x^3 - x^3) + (-6x^2y + 6x^2y - x^2y) + (4xy^2 - 12xy^2 + 5xy^2) + (8y^3 - 4y^3) = x^3 - x^2y - 3xy^2 + 4y^3.

Anahtar Kavram

Simplifying Expressions and Combining Like Terms
Tahmini Süre:3m 0s
Soru 1793Soru

For a certain positive number yy, the product of yy and the quantity 2y+52y + 5 is equal to 1212. What is the value of yy?

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Cevap: 1.5

Cevap

The positive value of yy is 1.51.5.
The correct answer is 1.51.5. By translating the word problem, we obtain y(2y+5)=12y(2y + 5) = 12. Expanding this gives 2y2+5y=122y^2 + 5y = 12, and subtracting 1212 from both sides yields the standard quadratic equation 2y2+5y12=02y^2 + 5y - 12 = 0. Factoring this expression gives (2y3)(y+4)=0(2y - 3)(y + 4) = 0. Setting the first factor to zero yields y=1.5y = 1.5, which is positive and therefore satisfies the given condition.

Adım Adım Çözüm

1
Write the equation representing the relationship.
y(2y+5)=12y(2y + 5) = 12
To translate the verbal description into an algebraic equation.
2
Distribute yy and set the equation equal to zero.
2y2+5y12=02y^2 + 5y - 12 = 0
To put the quadratic equation into standard form ay2+by+c=0ay^2 + by + c = 0 so it can be factored.
3
Factor the quadratic equation.
(2y3)(y+4)=0(2y - 3)(y + 4) = 0
To find the factors that multiply to give the quadratic expression.
4
Solve for yy and apply the constraint.
y=1.5y = 1.5
Setting the factors to zero gives y=1.5y = 1.5 and y=4y = -4. Since the problem states yy is positive, we select the positive root.

Anahtar Kavram

Solving a non-monic quadratic equation by factoring after translating a verbal description into algebra.
Soru 1794Soru

A list of 1515 positive integers is sorted in non-decreasing order. The minimum value in the list is 1010, the maximum value is 5050, and the median is 3030. If the unique mode of the list is 2020, what is the maximum possible sum of the 1515 integers in the list?

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Cevap: 508

Cevap

508
The maximum sum is achieved by setting the frequency of the unique mode 2020 to its maximum limit of 66, occupying positions 22 through 77 (since the first element is 1010 and the median at position 88 is 3030). This allows any other value to appear at most 55 times. To maximize the sum, we assign the maximum value 5050 to 55 positions (positions 1111 to 1515), and the next highest value 4949 to the remaining 22 positions in the upper half (positions 99 and 1010). Summing these values gives 10+6(20)+30+2(49)+5(50)=50810 + 6(20) + 30 + 2(49) + 5(50) = 508.

Adım Adım Çözüm

1
Identify fixed elements based on the median, minimum, and maximum constraints.
For 1515 sorted integers, the median is the 8th term: x8=30x_8 = 30. The minimum is x1=10x_1 = 10, and the maximum is x15=50x_{15} = 50.
Establishing these boundary points helps constrain the values of the other elements in the sorted list.
2
Determine the maximum possible frequency of the unique mode 2020.
Since x8=30x_8 = 30 and the list is sorted, 2020 can only occupy positions 22 through 77 (a maximum of 66 occurrences).
To maximize the overall sum, we want to maximize the frequency of the mode so that other large values (like 5050) can also appear as many times as possible.
3
Determine the maximum allowed frequency of other values under the unique mode constraint.
With the frequency of 2020 set to 66, any other number can appear at most 55 times.
Since 2020 is the unique mode, no other value in the list can have a frequency equal to or greater than 66.
4
Assign the largest possible values to the remaining positions in the upper half (x9x_9 to x14x_{14}).
Set x11=x12=x13=x14=x15=50x_{11} = x_{12} = x_{13} = x_{14} = x_{15} = 50 (frequency of 55). The remaining two positions, x9x_9 and x10x_{10}, are set to the next largest integer, 4949.
This maximizes the sum of the upper half of the list without violating the maximum frequency limit of 55 for any non-mode value.
5
Sum the elements of the optimal list.
Sum = 10+6(20)+30+2(49)+5(50)=10+120+30+98+250=50810 + 6(20) + 30 + 2(49) + 5(50) = 10 + 120 + 30 + 98 + 250 = 508.
Adding all fifteen optimal values together gives the absolute maximum possible sum.

Anahtar Kavram

Using central tendency constraints (median, mode) and range limits to optimize a dataset sum.
Soru 1795Soru

When the polynomial 4x437x2+94x^4 - 37x^2 + 9 is factored completely into linear factors of the form ax+bax + b, where aa and bb are integers and a>0a > 0, which of the following expressions represents the sum of these linear factors?

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Cevap: 6x6x

Cevap

The sum of the linear factors is 6x6x.
Factoring the polynomial 4x437x2+94x^4 - 37x^2 + 9 by substituting u=x2u = x^2 yields (4u1)(u9)(4u - 1)(u - 9), which becomes (4x21)(x29)(4x^2 - 1)(x^2 - 9). Applying the difference of squares identity to both terms results in the four linear factors (2x1)(2x - 1), (2x+1)(2x + 1), (x3)(x - 3), and (x+3)(x + 3). The sum of these factors is 6x6x.

Adım Adım Çözüm

1
Substitute u=x2u = x^2 to rewrite the quartic polynomial as a quadratic expression.
4u237u+94u^2 - 37u + 9
This simplifies the polynomial from degree 4 to degree 2, making it easier to factor.
2
Factor the quadratic expression by grouping or finding two numbers that multiply to 3636 and add to 37-37.
(4u1)(u9)(4u - 1)(u - 9)
The numbers are 36-36 and 1-1. Rewriting and grouping gives 4u(u9)1(u9)=(4u1)(u9)4u(u - 9) - 1(u - 9) = (4u - 1)(u - 9).
3
Substitute x2x^2 back in place of uu and factor the resulting difference of squares binomials.
(2x1)(2x+1)(x3)(x+3)(2x - 1)(2x + 1)(x - 3)(x + 3)
Since 4x21=(2x)2124x^2 - 1 = (2x)^2 - 1^2 and x29=x232x^2 - 9 = x^2 - 3^2, both binomials can be factored completely using the difference of squares identity.
4
Sum the four linear factors.
6x6x
Combining the like terms gives (2x1)+(2x+1)+(x3)+(x+3)=(2x+2x+x+x)+(1+13+3)=6x+0=6x(2x - 1) + (2x + 1) + (x - 3) + (x + 3) = (2x + 2x + x + x) + (-1 + 1 - 3 + 3) = 6x + 0 = 6x.

Anahtar Kavram

Factoring quartic polynomials using quadratic substitution and the difference of squares identity.
Soru 1796Soru

When the expression 2x2(3xy)3y(x22y)(x33xy2)2x^2(3x - y) - 3y(x^2 - 2y) - (x^3 - 3xy^2) is fully simplified by combining like terms, which of the following represents the resulting expression?

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Cevap: 5x35x2y+3xy2+6y25x^3 - 5x^2y + 3xy^2 + 6y^2

Cevap

5x35x2y+3xy2+6y25x^3 - 5x^2y + 3xy^2 + 6y^2
The correct expression is obtained by systematically distributing the coefficients outside the parentheses and then grouping and combining the coefficients of the like terms: (6x3x3)+(2x2y3x2y)+3xy2+6y2=5x35x2y+3xy2+6y2(6x^3 - x^3) + (-2x^2y - 3x^2y) + 3xy^2 + 6y^2 = 5x^3 - 5x^2y + 3xy^2 + 6y^2.

Adım Adım Çözüm

1
Distribute 2x22x^2 to each term in the first parenthetical expression: (3xy)(3x - y)
6x32x2y6x^3 - 2x^2y
Applying the distributive property of multiplication over subtraction.
2
Distribute 3y-3y to each term in the second parenthetical expression: (x22y)(x^2 - 2y)
3x2y+6y2-3x^2y + 6y^2
Applying the distributive property and multiplying negative coefficients (3×2=6-3 \times -2 = 6).
3
Distribute the negative sign to each term in the third parenthetical expression: (x33xy2)(x^3 - 3xy^2)
x3+3xy2-x^3 + 3xy^2
Distributing 1-1 across the parentheses to remove them.
4
Combine the expanded expressions and group the like terms
(6x3x3)+(2x2y3x2y)+3xy2+6y2(6x^3 - x^3) + (-2x^2y - 3x^2y) + 3xy^2 + 6y^2
Grouping together terms that have the same variables raised to the same powers.
5
Simplify by performing the operations on the coefficients of the like terms
5x35x2y+3xy2+6y25x^3 - 5x^2y + 3xy^2 + 6y^2
Combining coefficients: 61=56 - 1 = 5 for the x3x^3 terms, and 23=5-2 - 3 = -5 for the x2yx^2y terms.

Anahtar Kavram

Simplifying algebraic expressions by distributing coefficients and combining like terms.

Alternatif Yöntem

To check your work, substitute simple values for xx and yy, such as x=1x = 1 and y=1y = 1, into the original expression and the simplified expression. Evaluating the original expression: 2(1)2(3(1)1)3(1)(122(1))(133(1)(1)2)=2(2)3(1)(13)=4+3(2)=92(1)^2(3(1) - 1) - 3(1)(1^2 - 2(1)) - (1^3 - 3(1)(1)^2) = 2(2) - 3(-1) - (1 - 3) = 4 + 3 - (-2) = 9. Evaluating the correct simplified expression: 5(1)35(1)2(1)+3(1)(1)2+6(1)2=55+3+6=95(1)^3 - 5(1)^2(1) + 3(1)(1)^2 + 6(1)^2 = 5 - 5 + 3 + 6 = 9. Since both evaluations yield 9, this confirms the simplification.
Tahmini Süre:1m 0s
Soru 1797Soru

Given that i=1i = \sqrt{-1}, what is the value of the expression i83i^{83}?

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Cevap: i-i

Cevap

The value of the expression is i-i.
The expression i83i^{83} can be simplified by dividing the exponent 83 by 4. Because the remainder is 3, the expression is equivalent to i3i^3. Since i3=i2i=(1)i=ii^3 = i^2 \cdot i = (-1) \cdot i = -i, the correct value is i-i.

Adım Adım Çözüm

1
Divide the exponent 83 by 4 to determine the remainder.
The quotient is 20 with a remainder of 3, which means 83=4×20+383 = 4 \times 20 + 3.
Powers of the imaginary unit ii repeat in a cycle of four: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, and i4=1i^4 = 1.
2
Rewrite the expression using the rules of exponents and substitute the values of i4i^4 and i3i^3.
i83=i4(20)+3=(i4)20i3=(1)20(i)=ii^{83} = i^{4(20) + 3} = (i^4)^{20} \cdot i^3 = (1)^{20} \cdot (-i) = -i.
Since i4=1i^4 = 1, any power of ii that is a multiple of 4 simplifies to 1, leaving only the remainder power to determine the final value.

Anahtar Kavram

Simplifying powers of the imaginary unit ii
Soru 1798Soru

A business analyst models the daily cost, CC, and daily revenue, RR, of a manufacturing process using the following expressions:

C=2x2(x3y)y(x22y2)C = 2x^2(x - 3y) - y(x^2 - 2y^2)
R=5x3x(y2x)2+3y3R = 5x^3 - x(y - 2x)^2 + 3y^3

where xx represents the number of units of product X sold, and yy represents the number of units of product Y sold. The daily profit, PP, is defined as P=RCP = R - C. When the profit expression is fully simplified by combining like terms, which of the following expressions represents the daily profit PP?

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Cevap: $-x^3 + 11x^2y - xy^2 + y^3

Cevap

x3+11x2yxy2+y3-x^3 + 11x^2y - xy^2 + y^3
The expression x3+11x2yxy2+y3-x^3 + 11x^2y - xy^2 + y^3 is correct. Calculating profit requires subtracting the fully simplified cost from the fully simplified revenue. Simplifying CC yields 2x37x2y+2y32x^3 - 7x^2y + 2y^3. Expanding and simplifying RR yields x3+4x2yxy2+3y3x^3 + 4x^2y - xy^2 + 3y^3. Subtracting these two expressions and correctly distributing the negative sign gives x3+11x2yxy2+y3-x^3 + 11x^2y - xy^2 + y^3.

Adım Adım Çözüm

1
Expand and simplify the cost expression C=2x2(x3y)y(x22y2)C = 2x^2(x - 3y) - y(x^2 - 2y^2).
C=2x36x2yx2y+2y3=2x37x2y+2y3C = 2x^3 - 6x^2y - x^2y + 2y^3 = 2x^3 - 7x^2y + 2y^3
Distribute the terms outside the parentheses and combine the like terms 6x2y-6x^2y and x2y-x^2y.
2
Expand and simplify the revenue expression R=5x3x(y2x)2+3y3R = 5x^3 - x(y - 2x)^2 + 3y^3.
R=5x3x(y24xy+4x2)+3y3=5x3xy2+4x2y4x3+3y3=x3+4x2yxy2+3y3R = 5x^3 - x(y^2 - 4xy + 4x^2) + 3y^3 = 5x^3 - xy^2 + 4x^2y - 4x^3 + 3y^3 = x^3 + 4x^2y - xy^2 + 3y^3
Square the binomial (y2x)2=y24xy+4x2(y - 2x)^2 = y^2 - 4xy + 4x^2, distribute the x-x, and combine the like terms 5x35x^3 and 4x3-4x^3.
3
Subtract the cost expression from the revenue expression to find P=RCP = R - C.
P=(x3+4x2yxy2+3y3)(2x37x2y+2y3)=x3+4x2yxy2+3y32x3+7x2y2y3=x3+11x2yxy2+y3P = (x^3 + 4x^2y - xy^2 + 3y^3) - (2x^3 - 7x^2y + 2y^3) = x^3 + 4x^2y - xy^2 + 3y^3 - 2x^3 + 7x^2y - 2y^3 = -x^3 + 11x^2y - xy^2 + y^3
Distribute the subtraction negative sign to all terms in the cost expression and group like terms together to obtain the final simplified expression.

Anahtar Kavram

Simplifying multi-variable algebraic expressions by distributing coefficients and combining like terms.
Soru 1799Soru

Match each algebraic expression on the left with its fully simplified equivalent expression on the right. All variables represent real numbers.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

3a(a22ab)(a35a2b)3a(a^2 - 2ab) - (a^3 - 5a^2b)
a2(2ab)2a(a2ab)a^2(2a - b) - 2a(a^2 - ab)
(a3+3a2b)+3a2(a+b)-(a^3 + 3a^2b) + 3a^2(a + b)

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

The first expression 3a(a22ab)(a35a2b)3a(a^2 - 2ab) - (a^3 - 5a^2b) matches 2a3a2b2a^3 - a^2b. The second expression a2(2ab)2a(a2ab)a^2(2a - b) - 2a(a^2 - ab) matches a2ba^2b. The third expression (a3+3a2b)+3a2(a+b)-(a^3 + 3a^2b) + 3a^2(a + b) matches 2a32a^3.
Each expression on the left is simplified by distributing the coefficients and combining the like terms. The first expression simplifies to 2a3a2b2a^3 - a^2b. The second expression simplifies to a2ba^2b. The third expression simplifies to 2a32a^3. These match the corresponding simplified expressions on the right.

Adım Adım Çözüm

1
Simplify the first expression 3a(a22ab)(a35a2b)3a(a^2 - 2ab) - (a^3 - 5a^2b)
2a3a2b2a^3 - a^2b
Multiply 3a3a by both terms in the first parentheses to get 3a36a2b3a^3 - 6a^2b. Distribute the negative sign to both terms in the second parentheses to get a3+5a2b-a^3 + 5a^2b. Combine the a3a^3 terms to get 2a32a^3 and the a2ba^2b terms to get a2b-a^2b.
2
Simplify the second expression a2(2ab)2a(a2ab)a^2(2a - b) - 2a(a^2 - ab)
a2ba^2b
Multiply a2a^2 by both terms in the first parentheses to get 2a3a2b2a^3 - a^2b. Multiply 2a-2a by both terms in the second parentheses to get 2a3+2a2b-2a^3 + 2a^2b. Combine the a3a^3 terms to get 00 and the a2ba^2b terms to get a2ba^2b.
3
Simplify the third expression (a3+3a2b)+3a2(a+b)-(a^3 + 3a^2b) + 3a^2(a + b)
2a32a^3
Distribute the negative sign to get a33a2b-a^3 - 3a^2b. Multiply 3a23a^2 by both terms in the second parentheses to get 3a3+3a2b3a^3 + 3a^2b. Combine the a3a^3 terms to get 2a32a^3 and the a2ba^2b terms to get 00.

Anahtar Kavram

Simplifying Expressions and Combining Like Terms
Tahmini Süre:1m 30s
Soru 1800Soru

Determine the value of xx for which the given rational expression is undefined.

Aşağıdaki boşlukları doldurun

The rational expression x+72x10\frac{x + 7}{2x - 10} is undefined when x=x = .
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Cevap

5
The rational expression is undefined when the denominator, 2x102x - 10, equals 00. Solving 2x10=02x - 10 = 0 gives 2x=102x = 10, which simplifies to x=5x = 5.

Adım Adım Çözüm

1
Identify the denominator of the rational expression and set it equal to zero.
2x10=02x - 10 = 0
A rational expression is undefined when its denominator is equal to zero, as division by zero is not defined in the real number system.
2
Solve the linear equation for xx by adding 10 to both sides and then dividing by 2.
2x=10x=52x = 10 \Rightarrow x = 5
Isolating xx yields the value that makes the denominator zero.

Anahtar Kavram

Rational expressions are undefined when the denominator is equal to zero.
Tahmini Süre:45s
ÖncekiSayfa 90 / 278Sonraki
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