Tüm alıştırma soruları

5556 soru

Soru 1881Soru

For the function h(x)=53xh(x) = 5 - 3x, what is the value of h(h(2))h(h(2))?

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Cevap: 8

Cevap

8
To find h(h(2))h(h(2)), we first calculate the value of the inner function, h(2)=53(2)=56=1h(2) = 5 - 3(2) = 5 - 6 = -1. We then substitute this result back into the function to evaluate the outer function: h(1)=53(1)=5+3=8h(-1) = 5 - 3(-1) = 5 + 3 = 8. Therefore, the correct value is 8.

Adım Adım Çözüm

1
Evaluate the inner function h(2)h(2)
h(2)=1h(2) = -1
To evaluate a nested function composition of the form h(h(x))h(h(x)), first calculate the value of the inner function at the given input.
2
Evaluate the outer function h(1)h(-1) using the result from Step 1
h(h(2))=h(1)=8h(h(2)) = h(-1) = 8
Substitute the output of the inner function, 1-1, as the new input for the outer function h(x)h(x).

Anahtar Kavram

Evaluating the composition of a function with itself
Soru 1882Soru

A security passcode consists of a sequence of 4 digits chosen from the digits 0 through 9. To be valid, a passcode must contain at least one repeated digit, but no digit can appear more than twice. Additionally, the passcode cannot end with an odd digit. How many different valid security passcodes can be created?

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Cevap: 2295

Cevap

There are 2,295 different valid security passcodes.
The correct answer of 2,295 is found by subtracting all invalid passcodes from the total possible passcodes. The total number of 4-digit passcodes ending in an even digit is 5,000. The invalid passcodes are those with all distinct digits (2,520), those with a digit repeated three times (180), and those with all four digits identical (5). Subtracting these gives 5,000 - 2,520 - 180 - 5 = 2,295.

Adım Adım Çözüm

1
Calculate the total number of 4-digit passcodes ending in an even digit.
5,000
The last digit must be even (0, 2, 4, 6, or 8) to not be odd, giving 5 choices. The first three digits can be any of the 10 digits from 0 through 9. By the Fundamental Counting Principle, the total number of passcodes is 10 * 10 * 10 * 5 = 5,000.
2
Calculate the number of invalid passcodes where all 4 digits are distinct.
2,520
For all 4 digits to be distinct, the last digit must be chosen from the 5 even digits. The remaining 3 positions must be filled with 3 distinct digits chosen from the remaining 9 digits. There are 9 * 8 * 7 = 504 ways to choose these. This gives 504 * 5 = 2,520 passcodes.
3
Calculate the number of invalid passcodes where a single digit is repeated three times.
180
If the repeated digit is the last digit, there are 5 choices for that digit, and the single distinct digit (9 choices) can be placed in any of the 3 remaining positions, giving 5 * 9 * 3 = 135 passcodes. If the repeated digit is not the last digit, the three identical digits occupy the first three positions, and the last digit (5 choices) is distinct from them (9 choices), giving 5 * 9 = 45 passcodes. In total, 135 + 45 = 180 passcodes.
4
Calculate the number of invalid passcodes where all four digits are identical.
5
Since the last digit must be even, all four digits must be the same even digit (0000, 2222, 4444, 6666, or 8888), which gives 5 passcodes.
5
Subtract the invalid passcodes from the total number of passcodes.
2,295
Subtracting the passcodes with all distinct digits (2,520) and those with a digit repeated three or four times (180 + 5 = 185) from the total of 5,000 gives 5,000 - 2,520 - 185 = 2,295.

Anahtar Kavram

Complementary counting using permutations and partition analysis

Alternatif Yöntem

Instead of complementary counting, count the valid cases directly: Case A where the digit frequencies are [2, 1, 1] (which yields 2,160 codes) and Case B where the digit frequencies are [2, 2] (which yields 135 codes). Adding these yields 2,160 + 135 = 2,295 codes.
Tahmini Süre:3m 0s
Soru 1883Soru

In the standard (x,y)(x, y) coordinate plane, a circle is defined by the equation x2+y212y+27=0x^2 + y^2 - 12y + 27 = 0. A parabola that opens downward has its vertex at (0,k)(0, k) and is defined by the equation y=x2+ky = -x^2 + k. If the system of equations consisting of this circle and parabola has exactly three distinct real solution points, what is the value of kk?

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Cevap: 9

Cevap

The value of kk is 9.
The correct value of kk is 9 because when k=9k=9, the system of equations reduces to a quadratic in yy with roots y=9y=9 and y=4y=4. Both roots satisfy the real-number constraint y9y \leq 9 for the parabola x2=9yx^2 = 9-y, producing three distinct real solutions: (0,9)(0, 9), (5,4)(\sqrt{5}, 4), and (5,4)(-\sqrt{5}, 4).

Adım Adım Çözüm

1
Complete the square for the circle's equation.
x2+(y6)2=9x^2 + (y-6)^2 = 9
To identify the circle's center at (0,6)(0, 6) and radius R=3R=3 for geometric interpretation.
2
Express x2x^2 in terms of yy using the parabola's equation.
x2=kyx^2 = k - y
To substitute into the circle's equation and eliminate the xx variable.
3
Substitute x2x^2 into the circle's equation and simplify.
y213y+(k+27)=0y^2 - 13y + (k+27) = 0
To create a quadratic equation in yy representing the y-coordinates of the intersection points.
4
Set y=ky = k in the quadratic equation.
k212k+27=0k^2 - 12k + 27 = 0, which factors as (k3)(k9)=0(k-3)(k-9) = 0
An intersection must lie on the y-axis (x=0x=0, which means y=ky=k) to yield an odd number of intersection points.
5
Verify which candidate value of kk yields exactly three real solutions.
For k=3k=3, the solutions are restricted because y=10y=10 gives no real xx value, resulting in only 1 solution. For k=9k=9, the roots y=9y=9 and y=4y=4 both yield real xx values, resulting in exactly 3 solutions: (0,9)(0, 9), (5,4)(\sqrt{5}, 4), and (5,4)(-\sqrt{5}, 4).
The algebraic condition for real xx coordinates is x2=ky0x^2 = k - y \geq 0, so we must verify that the roots yy satisfy yky \leq k.

Anahtar Kavram

Solving systems of non-linear equations algebraically and analyzing the number of real intersection points under coordinate constraints.

Alternatif Yöntem

Geometrically, a parabola opening downward with its vertex on the y-axis will intersect a circle centered on the y-axis in exactly three points if and only if its vertex is at the top of the circle and its curvature is less than that of the circle at that point. Completing the square for the circle x2+y212y+27=0x^2 + y^2 - 12y + 27 = 0 gives x2+(y6)2=9x^2 + (y-6)^2 = 9, which shows the top point of the circle is (0,9)(0, 9). Thus, the vertex of the downward-opening parabola must be at (0,9)(0, 9), meaning k=9k = 9. We then algebraically verify that this curvature indeed allows two other real intersections.
Tahmini Süre:3m 0s
Soru 1884Soru

For all real values of xx, what is the real solution to the equation x+131=x\sqrt{x+13} - 1 = x?

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Cevap: 3

Cevap

The only real solution to the equation is 3.
Isolating the radical term gives x+13=x+1\sqrt{x+13} = x+1. Squaring both sides yields x+13=x2+2x+1x+13 = x^2 + 2x + 1. Rearranging into standard quadratic form gives x2+x12=0x^2 + x - 12 = 0, which factors as (x+4)(x3)=0(x+4)(x-3) = 0. This yields candidate solutions x=3x = 3 and x=4x = -4. Checking these values in the original equation shows that x=3x = 3 is a valid solution because 3+131=3\sqrt{3+13} - 1 = 3, whereas x=4x = -4 is extraneous because 4+131=24\sqrt{-4+13} - 1 = 2 \neq -4.

Adım Adım Çözüm

1
Isolate the radical expression on one side of the equation.
x+13=x+1\sqrt{x+13} = x+1
This prepares the equation for squaring both sides to eliminate the radical.
2
Square both sides of the equation.
x+13=(x+1)2    x+13=x2+2x+1x+13 = (x+1)^2 \implies x+13 = x^2 + 2x + 1
Squaring both sides eliminates the radical and yields a polynomial equation.
3
Move all terms to one side to set the quadratic equation equal to zero.
x2+x12=0x^2 + x - 12 = 0
This puts the equation in the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0 so it can be solved by factoring.
4
Factor the quadratic equation.
(x+4)(x3)=0    x=3(x+4)(x-3) = 0 \implies x = 3 or x=4x = -4
Factoring allows us to find the potential roots of the quadratic equation.
5
Check both candidate solutions in the original equation to identify any extraneous solutions.
For x=3x = 3: 3+131=41=3\sqrt{3+13} - 1 = 4 - 1 = 3 (valid). For x=4x = -4: 4+131=31=24\sqrt{-4+13} - 1 = 3 - 1 = 2 \neq -4 (extraneous).
Squaring both sides of an equation can introduce extraneous roots that must be checked and discarded.

Anahtar Kavram

Solving radical equations and checking for extraneous solutions
Tahmini Süre:1m 30s
Soru 1885Soru

If f(x)=3x5f(x) = 3x - 5 and g(x)=(x1)2g(x) = (x - 1)^2, what is the value of f(g(4))f(g(4))?

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Cevap: 22

Cevap

22
To find f(g(4))f(g(4)), we evaluate the inner function first: g(4)=(41)2=32=9g(4) = (4 - 1)^2 = 3^2 = 9. We then evaluate the outer function at this result: f(9)=3(9)5=275=22f(9) = 3(9) - 5 = 27 - 5 = 22.

Adım Adım Çözüm

1
Evaluate the inner function g(x)g(x) at x=4x = 4
g(4)=(41)2=32=9g(4) = (4 - 1)^2 = 3^2 = 9
In function composition f(g(x))f(g(x)), the inner function must be evaluated first.
2
Substitute the result from the first step into the outer function f(x)f(x)
f(9)=3(9)5f(9) = 3(9) - 5
The output of the inner function becomes the input of the outer function.
3
Calculate the final value of f(9)f(9) following the order of operations
f(9)=275=22f(9) = 27 - 5 = 22
Multiplication must be performed before subtraction.

Anahtar Kavram

Function Evaluation and Composition
Soru 1886Soru

A food truck charges a flat fee of 6foracustomlunchboxcontainer,plus6 for a custom lunch box container, plus 8 for each scoop of specialty salad added to the box. If a customer paid a total of $38 for one custom lunch box filled with specialty salad, how many scoops of specialty salad did they receive?

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Cevap: 4

Cevap

4 scoops of specialty salad
The correct answer is 4. The total cost is represented by the equation 6+8s=386 + 8s = 38, where ss represents the number of scoops. Subtracting the flat container fee of 6fromthetotalof6 from the total of 38 leaves 32.Dividing32. Dividing 32 by the per-scoop cost of $8 yields 4 scoops.

Adım Adım Çözüm

1
Set up the linear equation representing the total cost.
6+8s=386 + 8s = 38, where ss is the number of scoops of specialty salad.
The total cost consists of a one-time flat fee of 6plus6 plus 8 per scoop of salad.
2
Subtract the flat fee from both sides of the equation.
8s=328s = 32
To isolate the variable term, we subtract the constant cost of the container from the total cost.
3
Divide both sides of the equation by the cost per scoop.
s=4s = 4
Dividing the remaining cost by the price per scoop yields the number of scoops purchased.

Anahtar Kavram

Translating a verbal description of a linear cost scenario into a one-variable linear equation and solving it.
Soru 1887Soru

If 35x7=8\frac{3}{5}x - 7 = 8, what is the value of 2x32x - 3?

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Cevap: 47

Cevap

47
To find the value of 2x32x - 3, first solve the equation 35x7=8\frac{3}{5}x - 7 = 8 for xx. Adding 7 to both sides of the equation gives 35x=15\frac{3}{5}x = 15. Multiplying both sides by the reciprocal 53\frac{5}{3} yields x=25x = 25. Finally, substitute 2525 for xx in the expression 2x32x - 3 to get 2(25)3=503=472(25) - 3 = 50 - 3 = 47.

Adım Adım Çözüm

1
Add 7 to both sides of the equation 35x7=8\frac{3}{5}x - 7 = 8 to isolate the variable term.
35x=15\frac{3}{5}x = 15
Adding 7 to both sides eliminates the constant on the left side of the equation.
2
Multiply both sides of the equation by 53\frac{5}{3} to solve for xx.
x=25x = 25
Multiplying by the reciprocal of 35\frac{3}{5} isolates xx on the left side of the equation.
3
Substitute x=25x = 25 into the expression 2x32x - 3.
2(25)3=503=472(25) - 3 = 50 - 3 = 47
The question asks for the value of the expression 2x32x - 3 rather than just the variable xx.

Anahtar Kavram

Solving two-step linear equations involving fractions, and evaluating algebraic expressions.

Alternatif Yöntem

Instead of solving for xx first, you can express the target expression in terms of 35x\frac{3}{5}x. Specifically, note that 2x3=103(35x)32x - 3 = \frac{10}{3}(\frac{3}{5}x) - 3. Since 35x=15\frac{3}{5}x = 15, substituting this directly gives 103(15)3=503=47\frac{10}{3}(15) - 3 = 50 - 3 = 47.
Tahmini Süre:45s
Soru 1888Soru
Which of the following expressions is equivalent to the expression below?
(3x32y2)22(x34y2)(4x35y2)(3x^3 - 2y^2)^2 - 2(x^3 - 4y^2)(4x^3 - 5y^2)
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Cevap: x6+30x3y236y4x^6 + 30x^3y^2 - 36y^4

Cevap

The expression x6+30x3y236y4x^6 + 30x^3y^2 - 36y^4.
To find the correct expression, we first square the binomial to obtain 9x612x3y2+4y49x^6 - 12x^3y^2 + 4y^4. Next, we multiply the two binomials (x34y2)(4x35y2)(x^3 - 4y^2)(4x^3 - 5y^2) to get 4x621x3y2+20y44x^6 - 21x^3y^2 + 20y^4, and distribute the factor of 2 to obtain 8x642x3y2+40y48x^6 - 42x^3y^2 + 40y^4. Finally, we subtract this from the squared binomial by distributing the negative sign to all terms: 9x612x3y2+4y48x6+42x3y240y49x^6 - 12x^3y^2 + 4y^4 - 8x^6 + 42x^3y^2 - 40y^4. Combining like terms yields x6+30x3y236y4x^6 + 30x^3y^2 - 36y^4.

Adım Adım Çözüm

1
Expand the squared binomial (3x32y2)2(3x^3 - 2y^2)^2.
9x612x3y2+4y49x^6 - 12x^3y^2 + 4y^4
Use the binomial squaring formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2, where a=3x3a = 3x^3 and b=2y2b = 2y^2.
2
Multiply the two binomials (x34y2)(4x35y2)(x^3 - 4y^2)(4x^3 - 5y^2).
4x621x3y2+20y44x^6 - 21x^3y^2 + 20y^4
Apply the FOIL method to expand the product: 4x65x3y216x3y2+20y44x^6 - 5x^3y^2 - 16x^3y^2 + 20y^4, and combine the like middle terms.
3
Multiply the resulting trinomial from Step 2 by the constant factor of 2.
8x642x3y2+40y48x^6 - 42x^3y^2 + 40y^4
Distribute the factor of 2 to each term of the simplified trinomial expression.
4
Subtract the expression in Step 3 from the expression in Step 1.
x6+30x3y236y4x^6 + 30x^3y^2 - 36y^4
Distribute the negative sign to all terms of the subtracted polynomial: 9x612x3y2+4y48x6+42x3y240y49x^6 - 12x^3y^2 + 4y^4 - 8x^6 + 42x^3y^2 - 40y^4, and combine the remaining like terms.

Anahtar Kavram

Operations on Polynomials
Soru 1889Soru

Which of the following is the completely factored form of the expression 3x312x2+12x3x^3 - 12x^2 + 12x?

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Cevap: 3x(x2)23x(x - 2)^2

Cevap

The completely factored form of the expression is 3x(x2)23x(x - 2)^2.
To factor the expression 3x312x2+12x3x^3 - 12x^2 + 12x completely, we first look for the greatest common factor (GCF) of the three terms. The GCF of 3x33x^3, 12x2-12x^2, and 12x12x is 3x3x. Factoring out 3x3x yields 3x(x24x+4)3x(x^2 - 4x + 4). Next, we factor the quadratic trinomial inside the parentheses. The expression x24x+4x^2 - 4x + 4 is a perfect square trinomial that factors into (x2)2(x - 2)^2. Putting it all together, the completely factored form is 3x(x2)23x(x - 2)^2.

Adım Adım Çözüm

1
Identify and factor out the Greatest Common Factor (GCF) from all three terms of the polynomial 3x312x2+12x3x^3 - 12x^2 + 12x.
3x(x24x+4)3x(x^2 - 4x + 4)
Each term in the polynomial is divisible by 33, and the lowest power of xx common to all terms is x1x^1. Thus, the GCF is 3x3x.
2
Factor the remaining quadratic trinomial x24x+4x^2 - 4x + 4 inside the parentheses.
(x2)2(x - 2)^2
The trinomial x24x+4x^2 - 4x + 4 is a perfect square trinomial matching the form a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2, where a=xa = x and b=2b = 2.
3
Combine the factored parts to write the final completely factored expression.
3x(x2)23x(x - 2)^2
Bringing together the GCF and the factored trinomial yields the simplest, fully factored form.

Anahtar Kavram

Factoring a polynomial completely by first extracting the greatest common factor (GCF) and then factoring the remaining perfect square trinomial.

Alternatif Yöntem

Instead of factoring directly, you can expand the answer choices to see which one is equivalent to the original polynomial. For example, expanding the correct option: 3x(x2)2=3x(x24x+4)=3x312x2+12x3x(x-2)^2 = 3x(x^2 - 4x + 4) = 3x^3 - 12x^2 + 12x. This matches the original expression.
Tahmini Süre:1m 0s
Soru 1890Soru

Let the complex number zz be defined as z=(43i)(1+2i)+5i14z = (4 - 3i)(1 + 2i) + 5i^{14}, where i=1i = \sqrt{-1}. What is the real part of zz?

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Cevap: 5

Cevap

The real part of the complex number zz is 55.
First, expand the product (43i)(1+2i)(4 - 3i)(1 + 2i) to get 4+8i3i6i24 + 8i - 3i - 6i^2. Replacing i2i^2 with 1-1 gives 10+5i10 + 5i. Next, simplify 5i145i^{14}. Since i14=(i4)3i2=13(1)=1i^{14} = (i^4)^3 \cdot i^2 = 1^3 \cdot (-1) = -1, the term becomes 5-5. Adding the components together gives z=(10+5i)5=5+5iz = (10 + 5i) - 5 = 5 + 5i. The real part of this complex number is 55.

Adım Adım Çözüm

1
Expand the product of the complex binomials (43i)(1+2i)(4 - 3i)(1 + 2i)
10 + 5i
Applying the distributive property gives 4+8i3i6i24 + 8i - 3i - 6i^2. Substituting i2=1i^2 = -1 simplifies the expression to 4+5i+6=10+5i4 + 5i + 6 = 10 + 5i.
2
Simplify the power of the imaginary unit in 5i145i^{14}
-5
Since the powers of ii cycle every 4 terms, i14=i12i2=1(1)=1i^{14} = i^{12} \cdot i^2 = 1 \cdot (-1) = -1. Therefore, 5i14=5(1)=55i^{14} = 5(-1) = -5.
3
Add the simplified terms together to find zz
5 + 5i
Adding the real and imaginary parts of the terms yields z=(10+5i)+(5)=5+5iz = (10 + 5i) + (-5) = 5 + 5i.
4
Determine the real part of zz
5
A complex number is written in the form a+bia + bi, where aa represents the real part. For 5+5i5 + 5i, the real part is 55.

Anahtar Kavram

Complex multiplication and simplification of powers of the imaginary unit
Soru 1891Soru

A certain value xx satisfies the relationship where the square of the difference between xx and 44 is equal to 1616 decreased by 33 times xx. If x1x_1 and x2x_2 are the two real solutions to this relationship, with x1>x2x_1 > x_2, what is the value of 3x12x23x_1 - 2x_2?

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Cevap: 15

Cevap

The value of the expression is 15.
The value 15 is correct. First, translate the relationship into the algebraic equation (x4)2=163x(x-4)^2 = 16 - 3x. Expanding the left side yields x28x+16=163xx^2 - 8x + 16 = 16 - 3x. To solve the quadratic equation by factoring, rearrange the terms to set one side to zero: subtract 16 and add 3x3x to both sides, which simplifies to x25x=0x^2 - 5x = 0. Factoring the left-hand side gives x(x5)=0x(x - 5) = 0. The solutions are x=5x = 5 and x=0x = 0. Since the problem defines x1>x2x_1 > x_2, the larger solution is x1=5x_1 = 5 and the smaller solution is x2=0x_2 = 0. Substituting these values into the expression 3x12x23x_1 - 2x_2 yields 3(5)2(0)=153(5) - 2(0) = 15.

Adım Adım Çözüm

1
Translate the verbal description into a mathematical equation.
(x4)2=163x(x - 4)^2 = 16 - 3x
The 'square of the difference between xx and 44' is represented as (x4)2(x-4)^2, and '16 decreased by 3 times xx' is represented as 163x16 - 3x.
2
Expand the squared binomial on the left side of the equation.
x28x+16=163xx^2 - 8x + 16 = 16 - 3x
Using the binomial expansion formula (ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2, expand (x4)2(x-4)^2 to x22(4)(x)+42=x28x+16x^2 - 2(4)(x) + 4^2 = x^2 - 8x + 16.
3
Rearrange the equation to set one side to zero.
x25x=0x^2 - 5x = 0
Add 3x3x and subtract 1616 from both sides of the equation to gather all terms on one side: x28x+3x+1616=0x^2 - 8x + 3x + 16 - 16 = 0, which simplifies to x25x=0x^2 - 5x = 0.
4
Factor the quadratic equation.
x(x5)=0x(x - 5) = 0
Factor out the greatest common factor, which is xx.
5
Solve for the roots of the equation.
x=0x = 0 or x=5x = 5
Set each factor to zero: x=0x = 0 or x5=0x - 5 = 0.
6
Identify the values of x1x_1 and x2x_2 and calculate the required expression.
x1=5x_1 = 5, x2=0x_2 = 0, so 3x12x2=153x_1 - 2x_2 = 15
Since x1>x2x_1 > x_2, assign x1=5x_1 = 5 and x2=0x_2 = 0. Calculate 3(5)2(0)=153(5) - 2(0) = 15.

Anahtar Kavram

Solving quadratic equations by rearranging terms, expanding binomials, factoring out the greatest common factor, and solving for roots.
Soru 1892Soru

When the polynomial 12x2+11x1512x^2 + 11x - 15 is factored completely into the form (ax+b)(cx+d)(ax + b)(cx + d), where aa, bb, cc, and dd are integers such that a>c>0a > c > 0, what is the value of the constant term dd?

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Cevap: 5

Cevap

The value of the constant term dd is 55.
Factoring the trinomial 12x2+11x1512x^2 + 11x - 15 completely gives (4x3)(3x+5)(4x - 3)(3x + 5). Applying the constraint a>c>0a > c > 0 means the factor with the larger xx-coefficient must be written first in the template (ax+b)(cx+d)(ax + b)(cx + d). This yields a=4a = 4, b=3b = -3, c=3c = 3, and d=5d = 5. Thus, the constant term dd is 55.

Adım Adım Çözüm

1
Find the factor pair for the AC method.
We need two numbers that multiply to 12×(15)=18012 \times (-15) = -180 and add up to 1111. The numbers are 2020 and 9-9.
This allows us to split the linear middle term to factor by grouping.
2
Rewrite the polynomial and factor by grouping.
12x2+20x9x15=4x(3x+5)3(3x+5)=(4x3)(3x+5)12x^2 + 20x - 9x - 15 = 4x(3x + 5) - 3(3x + 5) = (4x - 3)(3x + 5).
Grouping the first two terms and the last two terms reveals a common binomial factor of (3x+5)(3x + 5).
3
Apply the given inequality constraints to match the template.
Comparing (4x3)(3x+5)(4x - 3)(3x + 5) to (ax+b)(cx+d)(ax + b)(cx + d) with a>c>0a > c > 0 yields a=4a = 4, b=3b = -3, c=3c = 3, and d=5d = 5.
Since the lead coefficient 44 is greater than 33, the factor (4x3)(4x - 3) must correspond to (ax+b)(ax + b).

Anahtar Kavram

Factoring quadratic trinomials of the form Ax2+Bx+CAx^2 + Bx + C using the grouping (AC) method.
Soru 1893Soru

A chemist wants to create 100100 milliliters of a 42.5%42.5\% acid solution by mixing three different acid solutions: a 10%10\% acid solution, a 20%20\% acid solution, and an 80%80\% acid solution. She decides that the volume of the 20%20\% acid solution used must be exactly 33 times the volume of the 10%10\% acid solution used. What is the difference, in milliliters, between the volume of the 80%80\% acid solution and the volume of the 10%10\% acid solution used in the final mixture?

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Cevap: 25

Cevap

The difference between the volume of the 80%80\% acid solution and the volume of the 10%10\% acid solution is 2525 milliliters.
Solving the system of equations yields that 1515 milliliters of the 10%10\% solution, 4545 milliliters of the 20%20\% solution, and 4040 milliliters of the 80%80\% solution are needed. The difference between the volume of the 80%80\% solution and the 10%10\% solution is 4015=2540 - 15 = 25 milliliters.

Adım Adım Çözüm

1
Define variables for the volume of each acid solution.
Let xx be the volume of the 10%10\% solution, yy be the volume of the 20%20\% solution, and zz be the volume of the 80%80\% solution.
This establishes algebraic representations for the unknowns.
2
Set up a system of linear equations based on the relationships given in the problem statement.
x+y+z=100x + y + z = 100 (total volume)
y=3xy = 3x (relationship between the 20%20\% and 10%10\% solutions)
0.10x+0.20y+0.80z=42.50.10x + 0.20y + 0.80z = 42.5 (total acid content)
Translating word problems to mathematical equations allows us to solve for the variables systematically.
3
Reduce the system to a single equation in terms of xx by substituting y=3xy = 3x and expressing zz in terms of xx.
4x+z=100    z=1004x4x + z = 100 \implies z = 100 - 4x
Substitute both into the acid equation:
0.10x+0.20(3x)+0.80(1004x)=42.50.10x + 0.20(3x) + 0.80(100 - 4x) = 42.5
Substitution simplifies the system of equations to a single linear equation with one variable.
4
Solve the simplified linear equation for xx.
0.70x+803.20x=42.5    2.50x=37.5    x=150.70x + 80 - 3.20x = 42.5 \implies -2.50x = -37.5 \implies x = 15
This determines the volume of the 10%10\% acid solution.
5
Calculate the volume of the 80%80\% solution, zz.
z=1004(15)=40z = 100 - 4(15) = 40
This determines the volume of the 80%80\% acid solution.
6
Find the difference between zz and xx.
zx=4015=25z - x = 40 - 15 = 25
The question asks for the difference between these two volumes.

Anahtar Kavram

Translating and solving systems of linear equations from verbal descriptions (mixture problems).
Tahmini Süre:2m 30s
Soru 1894Soru

Which of the following is a factor of the polynomial 4x212xy+9y2254x^2 - 12xy + 9y^2 - 25?

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Cevap: 2x3y52x - 3y - 5

Cevap

The expression 2x3y52x - 3y - 5 is a factor of the polynomial.
The polynomial can be factored by first grouping the first three terms as a perfect square trinomial: 4x212xy+9y2=(2x3y)24x^2 - 12xy + 9y^2 = (2x - 3y)^2. This simplifies the expression to (2x3y)225(2x - 3y)^2 - 25. Since 25=5225 = 5^2, this is a difference of squares of the form A2B2A^2 - B^2, which factors into (AB)(A+B)(A - B)(A + B). Substituting A=2x3yA = 2x - 3y and B=5B = 5 gives the factored form (2x3y5)(2x3y+5)(2x - 3y - 5)(2x - 3y + 5). Thus, the option representing 2x3y52x - 3y - 5 is a factor.

Adım Adım Çözüm

1
Group the first three terms of the polynomial and recognize the perfect square trinomial pattern.
4x212xy+9y2=(2x3y)24x^2 - 12xy + 9y^2 = (2x - 3y)^2
The term 4x24x^2 is (2x)2(2x)^2, 9y29y^2 is (3y)2(3y)^2, and the middle term 12xy-12xy is 2(2x)(3y)-2(2x)(3y), which matches the perfect square trinomial identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
2
Rewrite the original expression using the factored trinomial and write 25 as a perfect square.
(2x3y)252(2x - 3y)^2 - 5^2
Substituting the factored trinomial and expressing 25 as 525^2 sets up the expression as a difference of squares in the form A2B2A^2 - B^2.
3
Apply the difference of squares factoring formula A2B2=(AB)(A+B)A^2 - B^2 = (A - B)(A + B).
(2x3y5)(2x3y+5)(2x - 3y - 5)(2x - 3y + 5)
Substituting A=2x3yA = 2x - 3y and B=5B = 5 into the formula yields the completely factored polynomial.

Anahtar Kavram

Factoring by grouping using perfect square trinomials and difference of squares
Tahmini Süre:1m 0s
Soru 1895Soru

For all real numbers uu and vv, which of the following is equivalent to the expression 12(2u3v)223u(3u9v)23v2\frac{1}{2}(2u - 3v)^2 - \frac{2}{3}u(3u - 9v) - \frac{2}{3}v^2?

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Cevap: 236v2\frac{23}{6}v^2

Cevap

The simplified equivalent expression is 236v2\frac{23}{6}v^2.
The correct answer is obtained by expanding (2u3v)2(2u - 3v)^2 to 4u212uv+9v24u^2 - 12uv + 9v^2, multiplying it by 12\frac{1}{2} to get 2u26uv+92v22u^2 - 6uv + \frac{9}{2}v^2, distributing 23u-\frac{2}{3}u to get 2u2+6uv-2u^2 + 6uv, and combining the terms: (2u22u2)+(6uv+6uv)+(9223)v2=236v2(2u^2 - 2u^2) + (-6uv + 6uv) + (\frac{9}{2} - \frac{2}{3})v^2 = \frac{23}{6}v^2.

Adım Adım Çözüm

1
Expand the squared binomial (2u3v)2(2u - 3v)^2.
4u212uv+9v24u^2 - 12uv + 9v^2
Using the binomial square formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 allows us to expand the expression before applying the outer coefficient.
2
Multiply the expanded binomial by the coefficient 12\frac{1}{2}.
2u26uv+92v22u^2 - 6uv + \frac{9}{2}v^2
Distributing the constant factor of 12\frac{1}{2} to each term of the expanded binomial.
3
Distribute the term 23u-\frac{2}{3}u across the parenthetical expression (3u9v)(3u - 9v).
2u2+6uv-2u^2 + 6uv
Multiplying each term inside the parentheses by 23u-\frac{2}{3}u, making sure to distribute the negative sign properly: 23u3u=2u2-\frac{2}{3}u \cdot 3u = -2u^2 and 23u(9v)=6uv-\frac{2}{3}u \cdot (-9v) = 6uv.
4
Combine all terms and group like terms.
2u26uv+92v22u2+6uv23v22u^2 - 6uv + \frac{9}{2}v^2 - 2u^2 + 6uv - \frac{2}{3}v^2
Write the full expression with all distributed terms to identify and combine like terms.
5
Combine the u2u^2, uvuv, and v2v^2 terms.
236v2\frac{23}{6}v^2
Combining the coefficients: 2u22u2=02u^2 - 2u^2 = 0, 6uv+6uv=0-6uv + 6uv = 0, and 92v223v2=(27646)v2=236v2\frac{9}{2}v^2 - \frac{2}{3}v^2 = (\frac{27}{6} - \frac{4}{6})v^2 = \frac{23}{6}v^2.

Anahtar Kavram

Simplifying expressions by expanding binomials, distributing negative signs, and combining like terms with fractional coefficients.

Alternatif Yöntem

Instead of algebraic expansion, you can substitute simple non-zero values for uu and vv (e.g., u=3u = 3 and v=2v = 2) into the original expression and evaluate it. Then, substitute the same values into the answer choices to find which one yields the same result.
Tahmini Süre:1m 30s
Soru 1896Soru

For what values of the real number pp is the inequality 2p410-2|p - 4| \geq -10 true?

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Cevap: 1p9-1 \leq p \leq 9

Cevap

1p9-1 \leq p \leq 9
The correct answer is the inequality showing that pp is between 1-1 and 99, inclusive. First, divide both sides of the inequality 2p410-2|p - 4| \geq -10 by 2-2 and reverse the inequality sign to obtain p45|p - 4| \leq 5. Next, set up the compound inequality 5p45-5 \leq p - 4 \leq 5. Finally, add 44 to all parts of the inequality to isolate pp, which yields 1p9-1 \leq p \leq 9.

Adım Adım Çözüm

1
Divide both sides of the inequality 2p410-2|p - 4| \geq -10 by 2-2.
p45|p - 4| \leq 5
Dividing by a negative number reverses the direction of the inequality sign.
2
Rewrite the absolute value inequality p45|p - 4| \leq 5 as a compound inequality.
5p45-5 \leq p - 4 \leq 5
An inequality of the form xa|x| \leq a for a0a \geq 0 is equivalent to axa-a \leq x \leq a.
3
Add 44 to all parts of the compound inequality to isolate pp.
1p9-1 \leq p \leq 9
Adding a constant to all parts of an inequality preserves the inequality relationships and isolates the variable.

Anahtar Kavram

Solving absolute value inequalities involving multiplication or division by a negative number.
Soru 1897Soru

A newly designed temperature scale, Scale X, is related to the Celsius scale (C^{\circ}\text{C}) by a linear equation. Water freezes at 0C0^{\circ}\text{C}, which corresponds to 15X-15^{\circ}\text{X}, and water boils at 100C100^{\circ}\text{C}, which corresponds to 135X135^{\circ}\text{X}. If a chemical reaction must be maintained at a temperature where the reading on Scale X is exactly 2.52.5 times the reading on the Celsius scale, what is this temperature in degrees Celsius?

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Cevap: 15.0-15.0

Cevap

15.0-15.0 degrees Celsius
By writing the linear relationship between Scale X (XX) and Celsius (CC) as X=mC+kX = mC + k, we determine the constants using the given coordinates: (0,15)(0, -15) yields k=15k = -15, and (100,135)(100, 135) yields m=1.5m = 1.5. The resulting equation is X=1.5C15X = 1.5C - 15. We then substitute the given condition X=2.5CX = 2.5C, resulting in 2.5C=1.5C152.5C = 1.5C - 15. Subtracting 1.5C1.5C from both sides gives C=15C = -15.

Adım Adım Çözüm

1
Set up the general linear equation relating Scale X (XX) and Celsius (CC).
X=mC+kX = mC + k
Since the relationship is linear, it can be represented by a slope-intercept linear model.
2
Use the freezing point of water to find the y-intercept kk.
When C=0C = 0, X=15X = -15, so 15=m(0)+k    k=15-15 = m(0) + k \implies k = -15.
The freezing point of water provides the point (0,15)(0, -15) on the linear graph.
3
Use the boiling point of water to find the slope mm.
When C=100C = 100, X=135X = 135, so 135=m(100)15    150=100m    m=1.5135 = m(100) - 15 \implies 150 = 100m \implies m = 1.5.
The boiling point of water provides the second point (100,135)(100, 135) to determine the rate of change.
4
Substitute the condition X=2.5CX = 2.5C into the linear equation and solve for CC.
2.5C=1.5C15    1.0C=15    C=152.5C = 1.5C - 15 \implies 1.0C = -15 \implies C = -15.
This isolates the Celsius variable to find the temperature where the Scale X value is exactly 2.52.5 times the Celsius value.

Anahtar Kavram

Formulating and solving a linear equation from word-problem constraints and coordinate pairs.

Alternatif Yöntem

Instead of deriving the full equation, you can test the options directly. For example, check 15C-15^{\circ}\text{C}. The distance from freezing (0C0^{\circ}\text{C}) to 15C-15^{\circ}\text{C} is 15-15 units. Since Scale X changes by 1.51.5 units for every 11 unit of Celsius (calculated from a change of 150150 on Scale X for 100100 on Celsius), Scale X will change by 1.5×(15)=22.51.5 \times (-15) = -22.5 units from its freezing point value of 15-15. This yields 1522.5=37.5X-15 - 22.5 = -37.5^{\circ}\text{X}. Checking the ratio: 37.515=2.5\frac{-37.5}{-15} = 2.5, which matches the given condition.
Tahmini Süre:2m 0s
Soru 1898Soru

The rational expression x242x2+5x3\frac{x^2 - 4}{2x^2 + 5x - 3} is undefined for two real values of xx. If the smaller value is aa and the larger value is bb, what are the values of aa and bb?

Aşağıdaki boşlukları doldurun

a=a =
b=b =
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Cevap

The smaller value is 3-3 and the larger value is 1/21/2 (or 0.50.5).
A rational expression is undefined when the denominator is equal to zero. To find these values, set the denominator 2x2+5x32x^2 + 5x - 3 equal to 00 and solve for xx. Factoring the quadratic yields (2x1)(x+3)=0(2x - 1)(x + 3) = 0. Setting each factor to zero gives x=1/2x = 1/2 and x=3x = -3. Since 3-3 is less than 1/21/2, the smaller value is 3-3 and the larger value is 1/21/2 (or 0.50.5).

Adım Adım Çözüm

1
Identify the condition that makes a rational expression undefined.
The rational expression is undefined when its denominator is equal to zero: 2x2+5x3=02x^2 + 5x - 3 = 0.
Division by zero is undefined in the set of real numbers.
2
Factor the quadratic expression in the denominator.
2x2+5x3=(2x1)(x+3)=02x^2 + 5x - 3 = (2x - 1)(x + 3) = 0.
Factoring allows us to find the roots of the quadratic equation using the zero product property.
3
Solve for the roots of the factored equation.
2x1=0x=1/22x - 1 = 0 \Rightarrow x = 1/2, and x+3=0x=3x + 3 = 0 \Rightarrow x = -3.
Setting each linear factor to zero determines the values of xx that make the denominator zero.
4
Assign the values to the variables based on the inequality constraint.
Since 3<1/2-3 < 1/2, the smaller value is a=3a = -3 and the larger value is b=1/2b = 1/2 (or 0.50.5).
The question specifies that aa is the smaller value and bb is the larger value.

Anahtar Kavram

Identifying domain restrictions of rational expressions by finding where the denominator is equal to zero.
Tahmini Süre:1m 30s
Soru 1899Soru

A craft shop sells handmade candles. The price of a large candle is 33 dollars more than twice the price of a small candle. If a large candle costs 1515 dollars, what is the price, in dollars, of a small candle?

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Cevap: 6

Cevap

The price of a small candle is 66 dollars.
By letting ss represent the price of a small candle, the price of a large candle is 2s+32s + 3. Since the large candle costs 1515 dollars, we write the equation 2s+3=152s + 3 = 15. Subtracting 33 from both sides gives 2s=122s = 12, and dividing by 22 yields s=6s = 6. Therefore, the price of a small candle is 66 dollars.

Adım Adım Çözüm

1
Define the variable and translate the verbal description into an algebraic expression.
Let ss be the price of a small candle. The price of a large candle is expressed as 2s+32s + 3.
Translating 'twice the price of a small candle' to 2s2s and '3 more than' to +3+ 3 allows us to represent the large candle's cost algebraically.
2
Formulate an equation by setting the expression equal to the known cost of the large candle.
2s+3=152s + 3 = 15
The problem states that the large candle costs 1515 dollars.
3
Solve the equation for the variable ss.
s=6s = 6
Subtracting 33 from both sides gives 2s=122s = 12. Dividing both sides by 22 isolates ss, resulting in 66.

Anahtar Kavram

Translating verbal statements into linear equations and solving for a single variable.

Alternatif Yöntem

We can solve the problem by working backward from the price of the large candle. Since the large candle (1515 dollars) is 33 dollars more than twice the small candle's price, we subtract 33 dollars to find twice the price of the small candle: 153=1215 - 3 = 12 dollars. Then, since 1212 dollars is twice the price of the small candle, we divide by 22 to find the price of a single small candle: 12÷2=612 \div 2 = 6 dollars.
Tahmini Süre:45s
Soru 1900Soru

A quadratic equation of the form ax2+bx+c=0a x^2 + b x + c = 0, where aa, bb, and cc are real constants and a>0a > 0, has a discriminant of 3737. If the sum of the roots of this equation is 5.55.5 and the product of the roots is 5.255.25, what is the value of the coefficient aa?

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Cevap: 2

Cevap

The value of the coefficient aa is 22.
By applying Vieta's formulas, we can write b=5.5ab = -5.5a and c=5.25ac = 5.25a. Plugging these into the discriminant formula gives D=(5.5a)24a(5.25a)=30.25a221a2=9.25a2D = (-5.5a)^2 - 4a(5.25a) = 30.25a^2 - 21a^2 = 9.25a^2. Setting the discriminant to 3737 results in 9.25a2=37    a2=49.25a^2 = 37 \implies a^2 = 4. Since the problem specifies a>0a > 0, taking the positive square root gives a=2a = 2.

Adım Adım Çözüm

1
Express the coefficients bb and cc in terms of aa using Vieta's formulas.
b=5.5ab = -5.5a and c=5.25ac = 5.25a
The sum of the roots is ba-\frac{b}{a} and the product is ca\frac{c}{a}.
2
Substitute the expressions for bb and cc into the discriminant formula D=b24acD = b^2 - 4ac.
D=9.25a2D = 9.25a^2
Substituting the terms yields D=(5.5a)24a(5.25a)=30.25a221a2=9.25a2D = (-5.5a)^2 - 4a(5.25a) = 30.25a^2 - 21a^2 = 9.25a^2.
3
Equate the discriminant expression to 3737 and solve for aa.
a=2a = 2
Since D=37D = 37, we write 9.25a2=37    a2=49.25a^2 = 37 \implies a^2 = 4. Because aa must be positive, we find a=2a = 2.

Anahtar Kavram

Using the properties of quadratic roots (Vieta's formulas) and the definition of the discriminant to solve for coefficients.
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