Elementary Algebra

302 soru

Soru 181Soru
For all non-zero real numbers aa, bb, and cc, the expression below is simplified:
(2a2b1c3)34a5(b2c2)2\frac{(2a^2 b^{-1} c^3)^3}{4a^5 (b^2 c^{-2})^{-2}}
Which of the following is equivalent to this expression?
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Cevap: 2abc52abc^5

Cevap

The expression is equivalent to 2abc52abc^5.
The correct answer is obtained by first simplifying the numerator and denominator using the power of a product and power of a power rules, then dividing the coefficients and subtracting the exponents of like bases. This yields the simplified expression 2abc52abc^5.

Adım Adım Çözüm

1
Apply the power of a product rule to the numerator.
(2a2b1c3)3=23(a2)3(b1)3(c3)3=8a6b3c9(2a^2 b^{-1} c^3)^3 = 2^3 \cdot (a^2)^3 \cdot (b^{-1})^3 \cdot (c^3)^3 = 8 a^6 b^{-3} c^9
Each factor inside the parentheses must be raised to the power of 3, multiplying the exponents of the variables.
2
Apply the power of a product rule to the denominator's parentheses.
4a5(b2c2)2=4a5(b2)2(c2)2=4a5b4c44a^5 (b^2 c^{-2})^{-2} = 4a^5 \cdot (b^2)^{-2} \cdot (c^{-2})^{-2} = 4a^5 b^{-4} c^4
The terms inside the parentheses are raised to the power of -2, multiplying their exponents.
3
Divide the simplified numerator by the simplified denominator.
2a1b1c52a^1 b^1 c^5, which is 2abc52abc^5
Divide the coefficients (8 / 4 = 2) and subtract the exponents of the same bases: a65=a1a^{6-5} = a^1, b3(4)=b1b^{-3 - (-4)} = b^1, and c94=c5c^{9-4} = c^5.

Anahtar Kavram

Properties of Exponents in Algebraic Expressions

Alternatif Yöntem

Alternatively, you can rewrite the expression by eliminating negative exponents first. Convert b1b^{-1} to 1b\frac{1}{b}, b2b^2 to itself, and c2c^{-2} to 1c2\frac{1}{c^2} within the parentheses, apply the outer exponents, and then simplify the resulting complex fraction.
Tahmini Süre:1m 30s
Soru 182Soru

Two polynomial expressions are defined as P(x)=(2x4)(x25x+c)P(x) = (2x - 4)(x^2 - 5x + c) and Q(x)=(x2+3x4)(2x+a)Q(x) = (x^2 + 3x - 4)(2x + a), where aa and cc are constants. When P(x)P(x) is expanded and simplified, it has no xx term. If the coefficient of the x2x^2 term in the expanded and simplified form of Q(x)Q(x) is equal to the coefficient of the x2x^2 term in the expanded and simplified form of P(x)P(x), what is the value of aa?

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Cevap: -20

Cevap

The value of aa is 20-20.
Expanding P(x)=(2x4)(x25x+c)P(x) = (2x - 4)(x^2 - 5x + c) yields 2x314x2+(2c+20)x4c2x^3 - 14x^2 + (2c + 20)x - 4c. Since there is no xx term, 2c+20=02c + 20 = 0, which means c=10c = -10. This leaves the coefficient of the x2x^2 term in P(x)P(x) as 14-14. Expanding Q(x)=(x2+3x4)(2x+a)Q(x) = (x^2 + 3x - 4)(2x + a) yields 2x3+(a+6)x2+(3a8)x4a2x^3 + (a + 6)x^2 + (3a - 8)x - 4a, so the coefficient of its x2x^2 term is a+6a + 6. Setting a+6=14a + 6 = -14 and solving for aa gives a=20a = -20.

Adım Adım Çözüm

1
Expand the polynomial P(x)=(2x4)(x25x+c)P(x) = (2x - 4)(x^2 - 5x + c) using the distributive property.
P(x)=2x314x2+(2c+20)x4cP(x) = 2x^3 - 14x^2 + (2c + 20)x - 4c
To identify the coefficients of each term in P(x)P(x).
2
Set the coefficient of the xx term, 2c+202c + 20, to 00 and solve for cc.
c=10c = -10
The problem states that P(x)P(x) has no xx term when simplified, which means its coefficient must be zero.
3
Determine the coefficient of the x2x^2 term in P(x)P(x).
The coefficient of x2x^2 is 14-14.
This coefficient will be equated to the x2x^2 coefficient of Q(x)Q(x) as per the problem constraints.
4
Expand the polynomial Q(x)=(x2+3x4)(2x+a)Q(x) = (x^2 + 3x - 4)(2x + a) using the distributive property.
Q(x)=2x3+(a+6)x2+(3a8)x4aQ(x) = 2x^3 + (a + 6)x^2 + (3a - 8)x - 4a
To identify the coefficient of the x2x^2 term in Q(x)Q(x).
5
Set the coefficient of the x2x^2 term in Q(x)Q(x), which is a+6a + 6, equal to the coefficient of the x2x^2 term in P(x)P(x), which is 14-14, and solve for aa.
a=20a = -20
The problem states that these two coefficients are equal.

Anahtar Kavram

Operations on Polynomials
Tahmini Süre:2m 30s
Soru 183Soru

A rectangle has a length of y+7y + 7 inches and a width of y3y - 3 inches. Which of the following expressions represents the area, in square inches, of the rectangle?

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Cevap: y^2 + 4y - 21

Cevap

The expression y2+4y21y^2 + 4y - 21
The area of a rectangle is found by multiplying its length by its width. The product of the dimensions is represented by the expression (y+7)(y3)(y + 7)(y - 3). Applying the distributive property gives y23y+7y21y^2 - 3y + 7y - 21. Combining the like terms 3y-3y and 7y7y results in +4y+4y. Therefore, the simplified expression for the area is y2+4y21y^2 + 4y - 21.

Adım Adım Çözüm

1
Set up the area formula for the rectangle by multiplying its length and width.
Area =(y+7)(y3)= (y + 7)(y - 3)
The area of a rectangle is calculated by multiplying its length by its width.
2
Use the distributive property to expand the product of the two binomials.
Area =y(y)+y(3)+7(y)+7(3)=y23y+7y21= y(y) + y(-3) + 7(y) + 7(-3) = y^2 - 3y + 7y - 21
Each term in the first binomial must be multiplied by each term in the second binomial.
3
Combine the like terms to simplify the expression into standard form.
Area =y2+4y21= y^2 + 4y - 21
Combining 3y-3y and +7y+7y yields +4y+4y.

Anahtar Kavram

Finding the area of a rectangle by multiplying binomial expressions using the distributive property.
Tahmini Süre:45s
Soru 184Soru

If xx is a real number such that (3x)492x27x1=81\frac{(3^x)^4 \cdot 9^{2-x}}{27^{x-1}} = 81, what is the value of xx?

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Cevap: 3

Cevap

The value of xx is 3.
Rewriting the bases in terms of 3, the expression becomes 34x342x33x3=34\frac{3^{4x} \cdot 3^{4-2x}}{3^{3x-3}} = 3^4. Combining the numerator using the product rule gives 32x+43^{2x+4} in the numerator. Dividing by the denominator using the quotient rule gives 3(2x+4)(3x3)=3x+73^{(2x+4)-(3x-3)} = 3^{-x+7}. Equating this to 343^4 gives x+7=4-x + 7 = 4, which yields x=3x = 3.

Adım Adım Çözüm

1
Express each base in terms of the common base 3
9=329 = 3^2, 27=3327 = 3^3, and 81=3481 = 3^4
Converting all terms to a common base allows the use of exponent rules to combine them.
2
Apply the power of a power rule (bm)n=bmn(b^m)^n = b^{mn} to rewrite each exponent
(3x)4=34x(3^x)^4 = 3^{4x}, (32)2x=342x(3^2)^{2-x} = 3^{4-2x}, and (33)x1=33x3(3^3)^{x-1} = 3^{3x-3}
This simplifies individual terms by multiplying their exponents.
3
Apply the product rule of exponents bmbn=bm+nb^m \cdot b^n = b^{m+n} to combine the terms in the numerator
34x342x=34x+42x=32x+43^{4x} \cdot 3^{4-2x} = 3^{4x + 4 - 2x} = 3^{2x + 4}
Multiplying exponential terms with the same base is simplified by adding their exponents.
4
Apply the quotient rule of exponents bmbn=bmn\frac{b^m}{b^n} = b^{m-n} to simplify the fraction
3(2x+4)(3x3)=3x+73^{(2x+4) - (3x-3)} = 3^{-x+7}
Dividing exponential terms with the same base is simplified by subtracting the exponent in the denominator from the exponent in the numerator.
5
Equate the exponents of the simplified base 3 expression and base 3 representation of 81
x+7=4-x + 7 = 4, which solves to x=3x = 3
Since the bases are equal, the powers must be equal for the equation to hold true.

Anahtar Kavram

Properties of Exponents in Algebraic Expressions
Soru 185Soru

What is the greatest integer value of xx that satisfies the inequality 25x3x423\frac{2 - 5x}{3} - \frac{x - 4}{2} \geq 3?

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Cevap: -1

Cevap

The greatest integer value of xx that satisfies the inequality is -1.
The correct answer is -1 because solving the inequality leads to x213x \leq -\frac{2}{13}. Since 213-\frac{2}{13} is approximately 0.154-0.154, the set of integers satisfying the inequality is {1,2,3,}\{-1, -2, -3, \dots\}. The greatest integer in this set is -1.

Adım Adım Çözüm

1
Multiply the entire inequality by the least common multiple of the denominators (6) to eliminate the fractions.
2(25x)3(x4)182(2 - 5x) - 3(x - 4) \geq 18
Multiplying by a positive number clears the fractions without changing the direction of the inequality.
2
Distribute the coefficients and combine like terms on the left side of the inequality.
1613x1816 - 13x \geq 18
Simplifying the expressions on each side makes it easier to isolate the variable.
3
Subtract 16 from both sides to isolate the term with the variable xx.
13x2-13x \geq 2
Moving the constant terms to one side prepares the inequality for division.
4
Divide both sides by -13 and reverse the direction of the inequality sign.
x213x \leq -\frac{2}{13}
Dividing by a negative number requires flipping the inequality sign to maintain a true statement.
5
Determine the greatest integer that is less than or equal to 213-\frac{2}{13}.
-1
Since 2130.154-\frac{2}{13} \approx -0.154, the largest integer that is less than or equal to this value is -1.

Anahtar Kavram

Solving multi-step linear inequalities, including clearing fractional coefficients and reversing the inequality sign when multiplying or dividing by a negative number.
Soru 186Soru

What is the maximum integer value of kk that satisfies the inequality 85k>288 - 5k > 28?

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Cevap: -5

Cevap

The maximum integer value that satisfies the inequality is 5-5.
Subtracting 8 from both sides of the inequality 85k>288 - 5k > 28 yields 5k>20-5k > 20. Dividing both sides of the inequality by 5-5 and reversing the inequality sign results in k<4k < -4. The largest integer strictly less than 4-4 is 5-5.

Adım Adım Çözüm

1
Subtract 8 from both sides of the inequality.
5k>20-5k > 20
To isolate the term with the variable on the left side of the inequality.
2
Divide both sides by 5-5 and reverse the inequality sign.
k<4k < -4
Dividing both sides of an inequality by a negative number requires reversing the direction of the inequality symbol.
3
Determine the largest integer strictly less than 4-4.
5-5
Because the inequality is strict (<<), the value of kk cannot be equal to 4-4. The greatest integer less than 4-4 is 5-5.

Anahtar Kavram

Solving linear inequalities and reversing the inequality sign when dividing by a negative number.
Soru 187Soru

For the opening night of a school play, a total of 320320 tickets were sold, raising a total of $2140\$2{}140 in ticket sales. Student tickets were sold for $5\$5 each, and adult tickets were sold for $8\$8 each. How many adult tickets were sold?

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Cevap: 180

Cevap

180
The correct answer is 180180. By setting up a single-variable linear equation where aa represents the number of adult tickets, the problem translates to 8a+5(320a)=21408a + 5(320 - a) = 2140. Simplifying this yields 3a+1600=21403a + 1600 = 2140, which simplifies to 3a=5403a = 540 and results in a=180a = 180.

Adım Adım Çözüm

1
Define variables for the unknown quantities based on the given total.
Let aa represent the number of adult tickets sold. The number of student tickets sold is represented as 320a320 - a.
Since the total number of tickets is 320320, subtracting the number of adult tickets from the total yields the number of student tickets.
2
Construct a linear equation using the ticket prices and the total revenue.
8a+5(320a)=21408a + 5(320 - a) = 2140
Multiplying the quantity of each ticket type by its respective price (88 dollars for adult and 55 dollars for student) yields the total ticket sales revenue of 2,1402,140 dollars.
3
Solve the equation for the variable aa.
8a+16005a=2140    3a+1600=2140    3a=540    a=1808a + 1600 - 5a = 2140 \implies 3a + 1600 = 2140 \implies 3a = 540 \implies a = 180
Apply the distributive property, group like terms, isolate the variable term, and divide to solve for the number of adult tickets.

Anahtar Kavram

Translating word problems into a single-variable linear equation and solving for the unknown quantity.
Soru 188Soru

If 23(3x4)14(x+2)=223\frac{2}{3}(3x - 4) - \frac{1}{4}(x + 2) = \frac{22}{3}, what is the value of 3x+23x + 2?

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Cevap: 20

Cevap

The correct answer is 20, which is the value of the expression 3x+23x + 2 when x=6x = 6.
The value of the expression 3x+23x + 2 is 20. Solving the linear equation 23(3x4)14(x+2)=223\frac{2}{3}(3x - 4) - \frac{1}{4}(x + 2) = \frac{22}{3} yields x=6x = 6. Substituting x=6x = 6 into 3x+23x + 2 gives 3(6)+2=203(6) + 2 = 20.

Adım Adım Çözüm

1
Multiply the entire equation by the least common multiple of the denominators (12).
8(3x4)3(x+2)=888(3x - 4) - 3(x + 2) = 88
This clears the fractions to make solving the equation simpler.
2
Distribute the coefficients to remove parentheses.
24x323x6=8824x - 32 - 3x - 6 = 88
This allows like terms to be grouped together.
3
Combine like terms on the left side of the equation.
21x38=8821x - 38 = 88
Simplifies the equation to prepare for isolating the variable.
4
Add 38 to both sides of the equation.
21x=12621x = 126
Isolates the variable term on one side of the equation.
5
Divide both sides by 21 to solve for xx.
x=6x = 6
Finds the value of the variable xx.
6
Substitute x=6x = 6 into the target expression 3x+23x + 2.
3(6)+2=203(6) + 2 = 20
Calculates the final requested value.

Anahtar Kavram

Solving multi-step linear equations with fractions and evaluating algebraic expressions.
Soru 189Soru

For a certain real number xx, the equation 34(x3)13(2x+5)=2\frac{3}{4}(x - 3) - \frac{1}{3}(2x + 5) = -2 is true. What is the value of 2x52x - 5?

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Cevap: 41

Cevap

The value of the expression 2x52x - 5 is 41.
Solving the linear equation by multiplying both sides by the least common denominator of 12 yields the simplified equation 9(x3)4(2x+5)=249(x - 3) - 4(2x + 5) = -24. Expanding the terms gives 9x278x20=249x - 27 - 8x - 20 = -24, which simplifies to x47=24x - 47 = -24. Adding 47 to both sides gives x=23x = 23. Finally, evaluating the expression 2x52x - 5 for x=23x = 23 results in 2(23)5=412(23) - 5 = 41.

Adım Adım Çözüm

1
Multiply both sides of the equation by the least common denominator of 12 to eliminate fractions.
9(x3)4(2x+5)=249(x - 3) - 4(2x + 5) = -24
Multiplying by the LCD clears all fractional coefficients, making the equation easier to solve.
2
Distribute the constants and expand the terms on the left side of the equation.
9x278x20=249x - 27 - 8x - 20 = -24
Applying the distributive property removes the parentheses.
3
Combine like terms on the left side of the equation.
x47=24x - 47 = -24
Simplifying the equation makes it easier to isolate the variable xx.
4
Isolate the variable xx by adding 47 to both sides of the equation.
x=23x = 23
This determines the value of the unknown variable xx.
5
Substitute x=23x = 23 into the target expression 2x52x - 5.
4141
The question asks for the value of the expression 2x52x - 5, not just the value of xx.

Anahtar Kavram

Solving multi-step linear equations with fractional coefficients by clearing the denominators and then evaluating algebraic expressions.

Alternatif Yöntem

Instead of multiplying by the LCD first, distribute the fractions directly: 34x9423x53=2\frac{3}{4}x - \frac{9}{4} - \frac{2}{3}x - \frac{5}{3} = -2. Combine the xx terms: (3423)x=112x(\frac{3}{4} - \frac{2}{3})x = \frac{1}{12}x. Combine the constant terms: 9453=27122012=4712-\frac{9}{4} - \frac{5}{3} = -\frac{27}{12} - \frac{20}{12} = -\frac{47}{12}. This gives the equation 112x4712=2\frac{1}{12}x - \frac{47}{12} = -2. Add 4712\frac{47}{12} to both sides: 112x=2+4712=2412+4712=2312\frac{1}{12}x = -2 + \frac{47}{12} = -\frac{24}{12} + \frac{47}{12} = \frac{23}{12}. Multiply by 12 to get x=23x = 23, then evaluate 2x5=412x - 5 = 41.
Tahmini Süre:1m 30s
Soru 190Soru

Which of the following inequalities represents the complete set of real values of xx that satisfy the inequality 1534x15 \leq 3 - 4x?

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Cevap: x3x \leq -3

Cevap

The inequality x3x \leq -3
Subtracting 3 from both sides of the inequality 1534x15 \leq 3 - 4x yields 124x12 \leq -4x. Dividing both sides by 4-4 and reversing the inequality sign results in 3x-3 \geq x, which is equivalent to x3x \leq -3.

Adım Adım Çözüm

1
Subtract 3 from both sides of the inequality.
124x12 \leq -4x
This isolates the variable term on the right side of the inequality.
2
Divide both sides of the inequality by 4-4 and reverse the inequality sign.
3x-3 \geq x
Reversing the inequality sign is required whenever both sides of an inequality are multiplied or divided by a negative number.
3
Rewrite the inequality to place the variable on the left side.
x3x \leq -3
Reorganizing the inequality with xx on the left side is the standard format for representing the solution set.

Anahtar Kavram

Solving linear inequalities by isolating the variable and reversing the inequality sign when dividing by a negative number.
Soru 191Soru

A local library has two types of books: fiction and non-fiction. The number of fiction books is 120120 more than twice the number of non-fiction books. If the library has a total of 18601\text{}860 books, how many more fiction books than non-fiction books does the library have?

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Cevap: 700700

Cevap

The library has 700700 more fiction books than non-fiction books.
The correct answer is 700700 because defining the non-fiction books as nn gives 2n+1202n + 120 fiction books. Summing these to equal 18601860 yields 3n+120=18603n + 120 = 1860, which solves to n=580n = 580. The number of fiction books is therefore 2(580)+120=12802(580) + 120 = 1280. The difference between the two quantities is 1280580=7001280 - 580 = 700.

Adım Adım Çözüm

1
Define variables for the two categories of books.
Let nn be the number of non-fiction books. Then the number of fiction books, ff, can be written as f=2n+120f = 2n + 120.
This translates the statement 'the number of fiction books is 120120 more than twice the number of non-fiction books' into an algebraic expression.
2
Set up an equation representing the total number of books.
n+f=1860    n+(2n+120)=1860    3n+120=1860n + f = 1860 \implies n + (2n + 120) = 1860 \implies 3n + 120 = 1860.
The sum of the fiction and non-fiction books must equal the total library inventory of 18601860 books.
3
Solve the equation for the number of non-fiction books, nn.
3n=1740    n=5803n = 1740 \implies n = 580.
Subtracting 120120 from both sides and then dividing by 33 isolates the variable nn.
4
Calculate the number of fiction books and find the difference.
Fiction books: f=2(580)+120=1280f = 2(580) + 120 = 1280. Difference: fn=1280580=700f - n = 1280 - 580 = 700.
The question asks for the difference between the number of fiction and non-fiction books.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Tahmini Süre:1m 30s
Soru 192Soru

A certain relationship between a number xx and other values is described as follows: one-fourth of the difference when 3x3x is subtracted from 22, decreased by one-third of the sum of xx and 33, is strictly greater than the difference when xx is subtracted from 11. Which of the following inequalities represents the complete set of all possible values of xx?

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Cevap: x<18x < -18

Cevap

x<18x < -18
To find the correct solution set, translate the word problem into the inequality 23x4x+33>1x\frac{2 - 3x}{4} - \frac{x + 3}{3} > 1 - x. First, multiply all terms by the least common denominator, 1212, to clear the fractions, giving 3(23x)4(x+3)>12(1x)3(2 - 3x) - 4(x + 3) > 12(1 - x). Distributing the constants yields 69x4x12>1212x6 - 9x - 4x - 12 > 12 - 12x. Combining like terms on the left side simplifies the expression to 13x6>1212x-13x - 6 > 12 - 12x. Adding 12x12x to both sides results in x6>12-x - 6 > 12. Adding 66 to both sides gives x>18-x > 18. Finally, dividing by 1-1 and reversing the inequality sign results in the solution set x<18x < -18.

Adım Adım Çözüm

1
Translate the verbal description into an algebraic inequality.
23x4x+33>1x\frac{2 - 3x}{4} - \frac{x + 3}{3} > 1 - x
To represent the relationships described in the word problem mathematically.
2
Multiply the entire inequality by the least common denominator, 12, to clear the fractions.
3(23x)4(x+3)>12(1x)3(2 - 3x) - 4(x + 3) > 12(1 - x)
Clearing denominators makes it easier to combine like terms and solve for xx.
3
Distribute the constants on both sides.
69x4x12>1212x6 - 9x - 4x - 12 > 12 - 12x
To remove parentheses and separate individual terms for simplification.
4
Combine like terms on the left side of the inequality.
13x6>1212x-13x - 6 > 12 - 12x
Simplifying the expressions on each side makes the inequality easier to solve.
5
Add 12x12x and 66 to both sides of the inequality to isolate variables on one side.
x>18-x > 18
To group variable terms on the left and constant terms on the right.
6
Divide both sides by 1-1 and reverse the inequality sign.
x<18x < -18
Dividing or multiplying an inequality by a negative number requires reversing the inequality sign to maintain a true statement.

Anahtar Kavram

Solving multi-step linear inequalities with rational terms and variable terms on both sides, including reversing the inequality sign when dividing by a negative number.

Alternatif Yöntem

Instead of clearing fractions first, you can distribute the division to each term (e.g., 243x4x333>1x\frac{2}{4} - \frac{3x}{4} - \frac{x}{3} - \frac{3}{3} > 1 - x), group the xx terms on one side and constants on the other using fraction arithmetic, and then solve for xx. However, clearing fractions with the LCD is generally faster and less prone to arithmetic errors.
Tahmini Süre:2m 0s
Soru 193Soru

A manufacturing company produces sheet metal. The area of a large rectangular sheet is represented by the expression 2x2(3x34x+5)2x^2(3x^3 - 4x + 5) square inches. A square piece with a side length of 3x43x - 4 inches is cut out from the sheet. Which of the following expressions represents the area of the remaining metal sheet, in square inches, for all x>2x > 2?

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Cevap: 6x58x3+x2+24x166x^5 - 8x^3 + x^2 + 24x - 16

Cevap

The remaining area of the metal sheet is represented by 6x58x3+x2+24x166x^5 - 8x^3 + x^2 + 24x - 16.
To find the remaining area, the area of the square piece must be subtracted from the area of the large rectangular sheet. Expanding the large rectangular sheet's area yields 2x2(3x34x+5)=6x58x3+10x22x^2(3x^3 - 4x + 5) = 6x^5 - 8x^3 + 10x^2. Expanding the area of the square piece yields (3x4)2=9x224x+16(3x - 4)^2 = 9x^2 - 24x + 16. Subtracting the second polynomial from the first requires distributing the negative sign to all terms: (6x58x3+10x2)(9x224x+16)=6x58x3+10x29x2+24x16(6x^5 - 8x^3 + 10x^2) - (9x^2 - 24x + 16) = 6x^5 - 8x^3 + 10x^2 - 9x^2 + 24x - 16. Combining the quadratic terms 10x29x2=x210x^2 - 9x^2 = x^2 yields the correct simplified expression 6x58x3+x2+24x166x^5 - 8x^3 + x^2 + 24x - 16.

Adım Adım Çözüm

1
Expand the expression for the area of the large rectangular sheet.
2x2(3x34x+5)=6x58x3+10x22x^2(3x^3 - 4x + 5) = 6x^5 - 8x^3 + 10x^2
Distribute the term 2x22x^2 to each term in the trinomial, using the exponent rule xaxb=xa+bx^a \cdot x^b = x^{a+b} to combine the variable factors.
2
Expand the expression for the area of the square piece.
(3x4)2=9x224x+16(3x - 4)^2 = 9x^2 - 24x + 16
Apply the binomial squaring formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2, where a=3xa = 3x and b=4b = 4.
3
Subtract the area of the square piece from the area of the large rectangular sheet.
(6x58x3+10x2)(9x224x+16)=6x58x3+10x29x2+24x16(6x^5 - 8x^3 + 10x^2) - (9x^2 - 24x + 16) = 6x^5 - 8x^3 + 10x^2 - 9x^2 + 24x - 16
Distribute the negative sign to each term of the subtracted polynomial, changing the sign of each term inside the second parenthesis.
4
Combine like terms and write the final expression in descending order.
6x58x3+x2+24x166x^5 - 8x^3 + x^2 + 24x - 16
Combine the quadratic terms: 10x29x2=x210x^2 - 9x^2 = x^2. Arrange the remaining terms in descending order of their exponents.

Anahtar Kavram

Polynomial operations involving monomial distribution with exponent rules, binomial squaring, and polynomial subtraction with sign distribution.
Tahmini Süre:2m 0s
Soru 194Soru

A smart home heating system has two operating modes: Eco mode and Comfort mode. In a certain week, the system was active in one of these two modes for a total of 168168 hours. The number of hours the system was in Eco mode was 2424 hours less than three times the number of hours it was in Comfort mode. For how many hours was the heating system in Comfort mode during that week?

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Cevap: 48

Cevap

The heating system was in Comfort mode for 48 hours.
The correct answer is obtained by representing the hours in Comfort mode as cc and Eco mode as 3c243c - 24. Since their sum is 168168, we write the equation c+3c24=168c + 3c - 24 = 168. Solving this linear equation gives 4c=1924c = 192, which yields c=48c = 48.

Adım Adım Çözüm

1
Define variables for the Comfort and Eco modes.
Let cc represent the hours in Comfort mode and ee represent the hours in Eco mode.
To represent the unknown quantities algebraically.
2
Translate the given information into a system of equations.
c+e=168c + e = 168 and e=3c24e = 3c - 24
The sum of the hours in both modes is 168168, and the relationship between Eco and Comfort hours is described.
3
Substitute the expression for ee into the total hours equation.
c+(3c24)=168c + (3c - 24) = 168
To create a single linear equation with one variable.
4
Solve for the variable cc.
4c24=1684c=192c=484c - 24 = 168 \Rightarrow 4c = 192 \Rightarrow c = 48
Simplifying the equation gives the value of cc, which is the hours spent in Comfort mode.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Soru 195Soru

In a chemistry laboratory, a beaker contains a mixture of water and acid. The volume of water in the beaker is 33 liters more than twice the volume of acid. After 55 liters of water are added to the beaker, the ratio of the volume of water to the volume of acid is 55 to 22. If no acid was added or removed, what was the initial volume of water, in liters, in the beaker?

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Cevap: 35

Cevap

35
The correct answer of 35 liters is found by setting up the linear equation where the initial volume of acid is aa and the initial volume of water is 2a+32a + 3. Adding 5 liters of water gives 2a+82a + 8 liters of water. Setting the ratio of water to acid to 52\frac{5}{2} and solving gives a=16a = 16. Finally, substituting a=16a = 16 into the expression for the initial volume of water (2a+32a + 3) yields 35 liters.

Adım Adım Çözüm

1
Define variables for the initial volumes of acid and water based on the given relationships.
Let aa be the initial volume of acid in liters. The initial volume of water is 2a+32a + 3 liters.
This translates the statement 'the volume of water is 3 liters more than twice the volume of acid' into algebraic expressions.
2
Set up a linear equation representing the ratio after adding 5 liters of water.
The new volume of water is (2a+3)+5=2a+8(2a + 3) + 5 = 2a + 8 liters. The ratio of water to acid is 2a+8a=52\frac{2a + 8}{a} = \frac{5}{2}.
This uses the new state of the mixture to form an equation that can be solved for aa.
3
Solve the linear equation for aa by cross-multiplying and isolating the variable.
2(2a+8)=5a    4a+16=5a    a=162(2a + 8) = 5a \implies 4a + 16 = 5a \implies a = 16.
Cross-multiplication removes the fractions and allows for standard term isolation.
4
Calculate the initial volume of water.
Initial water volume = 2a+3=2(16)+3=352a + 3 = 2(16) + 3 = 35 liters.
The question asks for the initial volume of water, which is represented by 2a+32a + 3, not the volume of acid aa.

Anahtar Kavram

Solving linear equations in one variable derived from word problems.

Alternatif Yöntem

Instead of solving algebraically, one could test the answer choices. For example, testing 35 liters of water means the initial acid is (353)/2=16(35 - 3) / 2 = 16 liters. Adding 5 liters of water gives 40 liters of water. The ratio of water to acid is 40:1640 : 16, which simplifies to 5:25 : 2. This confirms 35 is correct.
Tahmini Süre:1m 30s
Soru 196Soru

A manufacturing company produces two types of metal alloys. The production cost, in dollars per ton, of Alloy A is modeled by the expression 80015(x5)800 - 15(x - 5), where xx is the amount of stabilizer added in kilograms. The production cost of Alloy B, in dollars per ton, is modeled by the expression 520+5(x+3)520 + 5(x + 3). If the company requires the production cost of Alloy A to be strictly less than the production cost of Alloy B, what is the minimum integer amount of stabilizer xx, in kilograms, that must be added?

Cevabı ve açıklamayı göster

Cevap: 18

Cevap

The minimum integer amount of stabilizer that must be added is 1818 kg.
The inequality representing the condition is 80015(x5)<520+5(x+3)800 - 15(x - 5) < 520 + 5(x + 3). Expanding both sides gives 87515x<535+5x875 - 15x < 535 + 5x. Isolating xx yields 20x<340-20x < -340. Dividing by 20-20 and flipping the inequality sign results in x>17x > 17. The minimum integer value that is strictly greater than 1717 is 1818.

Adım Adım Çözüm

1
Set up the linear inequality using the cost expressions for Alloy A and Alloy B.
80015(x5)<520+5(x+3)800 - 15(x - 5) < 520 + 5(x + 3)
The cost of Alloy A must be strictly less than the cost of Alloy B.
2
Distribute and combine like terms to simplify both sides of the inequality.
87515x<535+5x875 - 15x < 535 + 5x
Simplifying the expressions makes it easier to isolate the variable.
3
Isolate the variable term on one side of the inequality.
20x<340-20x < -340
Subtracting 5x5x and 875875 from both sides moves all variable terms to the left and constant terms to the right.
4
Divide both sides by the negative coefficient 20-20 and reverse the inequality sign.
x>17x > 17
Dividing an inequality by a negative number requires reversing the direction of the inequality sign.
5
Identify the smallest integer that satisfies the inequality.
1818
The solution requires a strict inequality x>17x > 17, so the smallest integer value that is strictly greater than 1717 is 1818.

Anahtar Kavram

Solving multi-step linear inequalities with variables on both sides, including reversing the inequality sign when dividing by a negative number.
Soru 197Soru

If the equation 25(x4)+13(2x+k)=7\frac{2}{5}(x - 4) + \frac{1}{3}(2x + k) = 7 is true when x=9x = 9, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 3-3

Cevap

3-3
Substituting x=9x = 9 into the equation gives 25(94)+13(2(9)+k)=7\frac{2}{5}(9 - 4) + \frac{1}{3}(2(9) + k) = 7. Simplifying the terms yields 2+18+k3=72 + \frac{18 + k}{3} = 7. Subtracting 2 from both sides results in 18+k3=5\frac{18 + k}{3} = 5. Multiplying by 3 gives 18+k=1518 + k = 15. Subtracting 18 from both sides gives k=3k = -3.

Adım Adım Çözüm

1
Substitute x=9x = 9 into the given equation.
25(94)+13(2(9)+k)=7\frac{2}{5}(9 - 4) + \frac{1}{3}(2(9) + k) = 7
We are given that the equation is true when x=9x = 9.
2
Simplify the operations inside the parentheses.
2+18+k3=72 + \frac{18 + k}{3} = 7
Simplifying 25(5)\frac{2}{5}(5) gives 2, and 2(9)2(9) gives 18.
3
Subtract 2 from both sides of the equation.
18+k3=5\frac{18 + k}{3} = 5
Isolating the fraction term simplifies the equation.
4
Multiply both sides by 3.
18+k=1518 + k = 15
Clearing the denominator allows us to isolate the variable kk.
5
Subtract 18 from both sides of the equation.
k=3k = -3
This isolates kk to find its value.

Anahtar Kavram

Solving linear equations in one variable by substitution and simplification
Soru 198Soru

Let P(x)=(3x22x+4)(2x5)(4x37x2+x3)P(x) = (3x^2 - 2x + 4)(2x - 5) - (4x^3 - 7x^2 + x - 3). When P(x)P(x) is simplified and written in standard form, what is the coefficient of the x2x^2 term?

Cevabı ve açıklamayı göster

Cevap: -12

Cevap

The coefficient of the x2x^2 term is -12.
Expanding (3x22x+4)(2x5)(3x^2 - 2x + 4)(2x - 5) yields 6x319x2+18x206x^3 - 19x^2 + 18x - 20. Distributing the negative sign across the second polynomial yields 4x3+7x2x+3-4x^3 + 7x^2 - x + 3. Combining the x2x^2 terms gives 19x2+7x2=12x2-19x^2 + 7x^2 = -12x^2, so the coefficient of the x2x^2 term is -12.

Adım Adım Çözüm

1
Expand the product of the trinomial and the binomial: (3x22x+4)(2x5)(3x^2 - 2x + 4)(2x - 5)
6x319x2+18x206x^3 - 19x^2 + 18x - 20
To find the expanded form of the first polynomial component before subtraction
2
Distribute the negative sign across the second polynomial: (4x37x2+x3)-(4x^3 - 7x^2 + x - 3)
4x3+7x2x+3-4x^3 + 7x^2 - x + 3
To prepare the second polynomial for combination of like terms
3
Combine the like terms from the two expanded components
2x312x2+17x172x^3 - 12x^2 + 17x - 17
To write the entire polynomial in standard form and identify the coefficient of x2x^2

Anahtar Kavram

Operations on Polynomials
Soru 199Soru
For all non-zero real numbers pp and qq, which of the following expressions is equivalent to
(p2+q1)2p4q2?\frac{(p^2 + q^{-1})^2 - p^4}{q^{-2}}?
Cevabı ve açıklamayı göster

Cevap: 2p2q+12p^2 q + 1

Cevap

2p2q+12p^2 q + 1
Expanding the binomial in the numerator yields p4+2p2q1+q2p^4 + 2p^2 q^{-1} + q^{-2}. After subtracting p4p^4, the numerator is left as 2p2q1+q22p^2 q^{-1} + q^{-2}. Dividing this numerator term-by-term by the denominator q2q^{-2} gives 2p2q1q2+q2q2\frac{2p^2 q^{-1}}{q^{-2}} + \frac{q^{-2}}{q^{-2}}. Applying the quotient property of exponents to each term yields 2p2q(1)(2)+1=2p2q1+1=2p2q+12p^2 q^{(-1) - (-2)} + 1 = 2p^2 q^1 + 1 = 2p^2 q + 1.

Adım Adım Çözüm

1
Expand the binomial in the numerator using the perfect square identity: (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2.
(p2+q1)2=(p2)2+2(p2)(q1)+(q1)2=p4+2p2q1+q2(p^2 + q^{-1})^2 = (p^2)^2 + 2(p^2)(q^{-1}) + (q^{-1})^2 = p^4 + 2p^2 q^{-1} + q^{-2}
To begin simplifying the numerator, we must resolve the exponent outside the parentheses.
2
Subtract p4p^4 from the expanded numerator expression.
(p4+2p2q1+q2)p4=2p2q1+q2(p^4 + 2p^2 q^{-1} + q^{-2}) - p^4 = 2p^2 q^{-1} + q^{-2}
This simplifies the numerator by combining the p4p^4 terms.
3
Divide each term in the simplified numerator by the denominator q2q^{-2}.
2p2q1q2+q2q2=2p2q1(2)+q2(2)\frac{2p^2 q^{-1}}{q^{-2}} + \frac{q^{-2}}{q^{-2}} = 2p^2 q^{-1 - (-2)} + q^{-2 - (-2)}
To divide a polynomial by a monomial, we distribute the division to each term of the polynomial.
4
Apply the quotient rule of exponents, xaxb=xab\frac{x^a}{x^b} = x^{a-b}, and simplify the terms.
2p2q1+q0=2p2q+12p^2 q^1 + q^0 = 2p^2 q + 1
Subtracting the exponents of qq in each term simplifies the division to its final form.

Anahtar Kavram

Properties of Exponents in Algebraic Expressions
Soru 200Soru

A commercial printing press charges a business a setup fee of 100100 plus 0.150.15 per brochure printed. To encourage green practices, the press offers a recycling discount equal to 3030 less than 0.050.05 per brochure printed. If the business has a budget of at most 380380 for their brochure order, what is the maximum number of brochures they can print?

Cevabı ve açıklamayı göster

Cevap: 2,500

Cevap

2,500
The correct answer is 2,500 brochures. The total cost is the setup fee of 100plustheprintingcostof100 plus the printing cost of 0.15 per brochure, minus the discount of 30lessthan30 less than 0.05 per brochure. Setting bb as the number of brochures, the discount is 0.05b300.05b - 30. The total cost equation is 100+0.15b(0.05b30)=130+0.10b100 + 0.15b - (0.05b - 30) = 130 + 0.10b. Setting this less than or equal to 380380 yields 130+0.10b3800.10b250b2,500130 + 0.10b \leq 380 \Rightarrow 0.10b \leq 250 \Rightarrow b \leq 2,500.

Adım Adım Çözüm

1
Define the variable and write the algebraic expressions for the cost components.
Let bb be the number of brochures printed. The total cost before the discount is 100+0.15b100 + 0.15b. The recycling discount is represented as 0.05b300.05b - 30.
Establishing clear variables and translating the textual relationships into mathematical expressions is the first step in solving word problems.
2
Set up the inequality representing the budget constraint.
100+0.15b(0.05b30)380100 + 0.15b - (0.05b - 30) \leq 380
The total cost (original cost minus the discount) must be at most the budget of 380380.
3
Simplify the left side of the inequality.
100+0.15b0.05b+30380130+0.10b380100 + 0.15b - 0.05b + 30 \leq 380 \Rightarrow 130 + 0.10b \leq 380
Distributing the subtraction sign across the discount expression and combining like terms simplifies the inequality.
4
Solve for the variable bb.
0.10b250b25000.10b \leq 250 \Rightarrow b \leq 2500
Isolating bb gives the maximum number of brochures that can be printed.

Anahtar Kavram

Translating and Solving Algebraic Word Problems
Tahmini Süre:1m 30s
ÖncekiSayfa 10 / 16Sonraki
Elementary Algebra Alıştırma Soruları — ACT — Sayfa 10 | Examkin