Pre-Algebra

419 soru

Soru 181Soru

A video streaming service has three subscription tiers: Basic, Standard, and Premium. Originally, 25\frac{2}{5} of the subscribers are on the Basic tier and 45%45\% are on the Standard tier. During a promotional campaign, 14\frac{1}{4} of the Basic subscribers upgrade to the Standard tier, and 20%20\% of the original Standard subscribers upgrade to the Premium tier. If no other subscription changes occur, what percent of the total subscribers are now on the Premium tier?

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Cevap: 24%24\%

Cevap

The correct answer is 24%24\% of the total subscribers.
To find the new Premium subscriber percentage, we first convert the basic tier fraction to a percent: 25=40%\frac{2}{5} = 40\%. Since the Standard tier is 45%45\%, the original Premium tier must contain the remaining subscribers, which is 100%40%45%=15%100\% - 40\% - 45\% = 15\% of the total. The upgrade represents 20%20\% of the original 45%45\% Standard subscribers, which is 0.20×45%=9%0.20 \times 45\% = 9\% of the total subscribers. Adding this 9%9\% upgrade to the original 15%15\% Premium percentage results in a final percentage of 24%24\%.

Adım Adım Çözüm

1
Determine the original subscriber percentages for all three tiers.
Basic: 25=40%\frac{2}{5} = 40\%. Standard: 45%45\%. Premium: 100%(40%+45%)=15%100\% - (40\% + 45\%) = 15\%.
Establishing the starting percentages allows us to track changes relative to the total subscriber population.
2
Calculate the percentage of total subscribers upgrading from Standard to Premium.
20%20\% of the original 45%45\% Standard subscribers = 0.20×45%=9%0.20 \times 45\% = 9\% of the total subscribers.
Since the upgrade rate is relative to the Standard tier, we multiply the rate by the Standard tier's share of the total population.
3
Calculate the final Premium percentage by adding the upgrade percentage to the original Premium percentage.
15%+9%=24%15\% + 9\% = 24\%.
The final Premium percentage is the sum of the original Premium percentage and the percentage of subscribers who upgraded from Standard.

Anahtar Kavram

Calculating percentages of subpopulations and translating them to percentages of the entire population.
Soru 182Soru

An astronomical unit (AU) is a unit of length equal to the average distance from the Earth to the Sun, approximately 1.5×1081.5 \times 10^8 kilometers. A scientific probe travels through space at a constant speed of 2.5×1042.5 \times 10^4 meters per second. How many hours would it take the probe to travel a distance of 3.6×1023.6 \times 10^2 AU?

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Cevap: 6.0×1056.0 \times 10^5

Cevap

6.0×1056.0 \times 10^5 hours
To find the travel time, we first determine the total distance in meters. Since 1 AU=1.5×108 km1\text{ AU} = 1.5 \times 10^8\text{ km} and 1 km=103 m1\text{ km} = 10^3\text{ m}, 1 AU=1.5×1011 m1\text{ AU} = 1.5 \times 10^{11}\text{ m}. Thus, a distance of 3.6×102 AU3.6 \times 10^2\text{ AU} equals (3.6×102)×(1.5×1011)=5.4×1013 m(3.6 \times 10^2) \times (1.5 \times 10^{11}) = 5.4 \times 10^{13}\text{ m}. Dividing this distance by the speed of 2.5×104 m/s2.5 \times 10^4\text{ m/s} yields the travel time in seconds: 5.4×10132.5×104=2.16×109 s\frac{5.4 \times 10^{13}}{2.5 \times 10^4} = 2.16 \times 10^9\text{ s}. Finally, converting seconds to hours by dividing by 3.6×103 s/h3.6 \times 10^3\text{ s/h} gives 2.16×1093.6×103=0.6×106=6.0×105 hours\frac{2.16 \times 10^9}{3.6 \times 10^3} = 0.6 \times 10^6 = 6.0 \times 10^5\text{ hours}.

Adım Adım Çözüm

1
Convert the total distance from astronomical units (AU) to kilometers, and then to meters.
Distance = 3.6×102 AU×1.5×108 km/AU=5.4×1010 km=5.4×1013 m3.6 \times 10^2 \text{ AU} \times 1.5 \times 10^8 \text{ km/AU} = 5.4 \times 10^{10} \text{ km} = 5.4 \times 10^{13} \text{ m}.
Since the speed is given in meters per second, the total distance must be in meters to keep units consistent.
2
Calculate the travel time in seconds by dividing the distance in meters by the speed in meters per second.
Time in seconds = 5.4×1013 m2.5×104 m/s=2.16×109 s\frac{5.4 \times 10^{13} \text{ m}}{2.5 \times 10^4 \text{ m/s}} = 2.16 \times 10^9 \text{ s}.
Time is equal to distance divided by speed (t=dst = \frac{d}{s}).
3
Convert the travel time from seconds to hours by dividing by 3.6×1033.6 \times 10^3 (the number of seconds in one hour).
Time in hours = 2.16×1093.6×103=6.0×105 hours\frac{2.16 \times 10^9}{3.6 \times 10^3} = 6.0 \times 10^5 \text{ hours}.
Dividing the total seconds by 3,6003,600 yields the time in hours.

Anahtar Kavram

Operations with scientific notation and dimensional analysis involving distance, rate, and time.

Alternatif Yöntem

Convert the speed to astronomical units per hour first, then divide the distance in astronomical units by this speed.
Tahmini Süre:2m 0s
Soru 183Soru

Arrange the following four mathematical expressions in order from least to greatest value:

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Cevap

The correct order from least to greatest is SS, PP, RR, and QQ, which correspond to the decimal values 0.16<0.25<0.28<0.30.16 < 0.25 < 0.28 < 0.3.
Evaluating each term yields decimal values: S=0.16S = 0.16, P=0.25P = 0.25, R=0.28R = 0.28, and Q=0.3Q = 0.3. Ordering these from least to greatest gives 0.16<0.25<0.28<0.30.16 < 0.25 < 0.28 < 0.3, which corresponds to the sequence S,P,R,QS, P, R, Q.

Adım Adım Çözüm

1
Convert the fractional squared expression SS to a decimal.
S=(25)2=425=0.16S = \left(\frac{2}{5}\right)^2 = \frac{4}{25} = 0.16
Squaring a fraction involves squaring both the numerator and denominator, then converting the resulting fraction to decimal form.
2
Convert the negative exponent expression PP to a decimal.
P=41=14=0.25P = 4^{-1} = \frac{1}{4} = 0.25
A negative exponent represents the reciprocal of the base raised to the positive power.
3
Convert the scientific notation expression RR to a decimal.
R=2.8×101=0.28R = 2.8 \times 10^{-1} = 0.28
Multiplying by 10110^{-1} shifts the decimal point one position to the left.
4
Convert the square root expression QQ to a decimal.
Q=0.09=0.3Q = \sqrt{0.09} = 0.3
Finding the square root of a decimal less than 11 results in a value larger than the original decimal, since 0.3×0.3=0.090.3 \times 0.3 = 0.09.
5
Compare the resulting decimal values to order them from least to greatest.
0.16<0.25<0.28<0.30.16 < 0.25 < 0.28 < 0.3, so the order is S<P<R<QS < P < R < Q.
Ordering the converted decimal values yields the correct final arrangement.

Anahtar Kavram

Converting exponential, radical, and scientific notation expressions to decimals to compare and order their values.
Soru 184Soru

A bookstore has a sale where the price of any paperback book is reduced by 44 dollars. If the sale price of a paperback book is 1212 dollars, and its original price is pp dollars, which of the following equations can be used to find pp?

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Cevap: p4=12p - 4 = 12

Cevap

The equation p4=12p - 4 = 12
The original price of the book is pp dollars. Since the price is reduced by 44 dollars, we subtract 44 from pp, which is written as p4p - 4. Since this resulting sale price is equal to 1212 dollars, the correct equation representing the relationship is p4=12p - 4 = 12.

Adım Adım Çözüm

1
Identify the variable and the mathematical values given in the scenario.
The original price is represented by the variable pp. The price reduction is 44 dollars, and the final sale price is 1212 dollars.
This sets up the translation of the word problem into algebraic terms.
2
Translate the phrase 'reduced by 44 dollars' into an algebraic expression.
A reduction of 44 dollars from the original price pp is written as p4p - 4.
A reduction or discount represents subtraction from the starting amount.
3
Equate the expression representing the sale price to the given sale price value.
The equation is p4=12p - 4 = 12.
Since the sale price is given as 1212 dollars, the expression for the reduced price must equal 1212.

Anahtar Kavram

Translating real-world discount scenarios into one-step linear equations.
Tahmini Süre:45s
Soru 185Soru

A manufacturing plant operates two types of machines, Type A and Type B. The ratio of the number of Type A machines to Type B machines is 3:53:5. Each Type A machine produces widgets at a constant rate that is 60%60\% faster than the constant rate of a Type B machine. When all machines of both types are operating simultaneously, they produce a total of 9898 widgets per hour. If the plant increases the number of Type A machines by 50%50\% and decreases the number of Type B machines by 20%20\%, what is the total number of widgets the new setup will produce in 33 hours?

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Cevap: 336

Cevap

336
The correct answer is 336 because setting up the initial production equation based on the ratios gives a compound constant of xr=10xr = 10. Applying the percentage adjustments yields a new hourly production rate of 112 widgets. Multiplying this hourly rate by the specified 3 hours gives a total of 336 widgets.

Adım Adım Çözüm

1
Represent the machine counts and rates using variables based on the given ratios.
Let the number of Type A machines be 3x3x and the number of Type B machines be 5x5x. Let the rate of a Type B machine be rr widgets/hour. The rate of a Type A machine is 1.6r1.6r widgets/hour.
This establishes algebraic expressions for the quantities in terms of common multipliers xx and rr.
2
Set up an equation for the initial total hourly production and solve for xrxr.
(3x)(1.6r)+(5x)(r)=98    4.8xr+5xr=98    9.8xr=98    xr=10(3x)(1.6r) + (5x)(r) = 98 \implies 4.8xr + 5xr = 98 \implies 9.8xr = 98 \implies xr = 10.
This allows us to find the value of the joint constant factor xrxr needed for subsequent calculations.
3
Determine the new machine counts after the percentage changes.
New Type A count: 3x×1.50=4.5x3x \times 1.50 = 4.5x. New Type B count: 5x×0.80=4x5x \times 0.80 = 4x.
This applies the 50% increase to Type A and the 20% decrease to Type B machine counts.
4
Calculate the new total hourly production rate using the value of xrxr.
New hourly rate: (4.5x)(1.6r)+(4x)(r)=7.2xr+4xr=11.2xr(4.5x)(1.6r) + (4x)(r) = 7.2xr + 4xr = 11.2xr. Substituting xr=10xr = 10 yields 11.2×10=11211.2 \times 10 = 112 widgets/hour.
This finds the rate at which widgets are produced in the new configuration.
5
Multiply the new hourly rate by the specified time of 3 hours.
Total production: 112 widgets/hour×3 hours=336112 \text{ widgets/hour} \times 3 \text{ hours} = 336 widgets.
This yields the final total quantity of widgets produced over the 3-hour duration.

Anahtar Kavram

Solving compound ratio and rate problems with percentage changes

Alternatif Yöntem

Instead of variables, you can plug in convenient numbers that satisfy the ratios. Suppose there are initially 3030 machines of Type A and 5050 machines of Type B. Let a Type B machine produce at a rate of 11 widget/hour, so a Type A machine produces 1.61.6 widgets/hour. The total initial hourly rate is 30(1.6)+50(1)=48+50=9830(1.6) + 50(1) = 48 + 50 = 98 widgets/hour, which matches the prompt. Increasing Type A by 50% gives 4545 machines, and decreasing Type B by 20% gives 4040 machines. The new hourly rate is 45(1.6)+40(1)=72+40=11245(1.6) + 40(1) = 72 + 40 = 112 widgets/hour. For 3 hours, this gives 112×3=336112 \times 3 = 336 widgets.
Tahmini Süre:3m 0s
Soru 186Soru

Arrange the following mathematical expressions in order from least to greatest value:

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Cevap

The correct order from least to greatest value is (2.5×101)2(2.5 \times 10^1)^2, followed by 3.43×1083\sqrt[3]{3.43 \times 10^8}, then 6.4×105\sqrt{6.4 \times 10^5}, and finally 5.4×1066×103\frac{5.4 \times 10^6}{6 \times 10^3}.
Each expression is simplified to a standard integer representation: (2.5×101)2=625(2.5 \times 10^1)^2 = 625, 3.43×1083=700\sqrt[3]{3.43 \times 10^8} = 700, 6.4×105=800\sqrt{6.4 \times 10^5} = 800, and 5.4×1066×103=900\frac{5.4 \times 10^6}{6 \times 10^3} = 900. Comparing these integers from smallest to largest yields the correct sequence.

Adım Adım Çözüm

1
Evaluate the expression 6.4×105\sqrt{6.4 \times 10^5} by converting the radicand to a standard square value.
64×104=8×102=800\sqrt{64 \times 10^4} = 8 \times 10^2 = 800
Converting the base to 64 and reducing the exponent of 10 to an even number allows easy extraction of the square root.
2
Evaluate the expression (2.5×101)2(2.5 \times 10^1)^2 by simplifying the terms inside the parentheses first.
(25)2=625(25)^2 = 625
Multiplying 2.5 by 10 simplifies the base to 25 before applying the exponent.
3
Evaluate the expression 5.4×1066×103\frac{5.4 \times 10^6}{6 \times 10^3} using rules of scientific division.
0.9×103=9000.9 \times 10^3 = 900
Dividing the coefficients (5.4÷6=0.95.4 \div 6 = 0.9) and subtracting the exponent in the denominator from the numerator (1063=10310^{6-3} = 10^3) yields the result.
4
Evaluate the expression 3.43×1083\sqrt[3]{3.43 \times 10^8} by converting the radicand to a standard cube value.
343×1063=7×102=700\sqrt[3]{343 \times 10^6} = 7 \times 10^2 = 700
Converting the base to 343 and adjusting the exponent to 6 (a multiple of 3) allows easy extraction of the cube root.
5
Compare the evaluated integers to determine the correct order from least to greatest.
625<700<800<900625 < 700 < 800 < 900
Comparing the simplified values reveals that the correct sequence is (2.5×101)2(2.5 \times 10^1)^2, 3.43×1083\sqrt[3]{3.43 \times 10^8}, 6.4×105\sqrt{6.4 \times 10^5}, and 5.4×1066×103\frac{5.4 \times 10^6}{6 \times 10^3}.

Anahtar Kavram

Simplification of exponential, radical, and scientific notation expressions to comparable decimal values.

Alternatif Yöntem

Instead of converting all expressions to standard numbers, convert them all to scientific notation with a base power of 10210^2 (i.e., 6.25×1026.25 \times 10^2, 7.0×1027.0 \times 10^2, 8.0×1028.0 \times 10^2, and 9.0×1029.0 \times 10^2) to compare their coefficients directly.
Tahmini Süre:2m 0s
Soru 187Soru

Four different brands of a sports drink contain different proportions of electrolytes by weight. The proportions for each brand are listed below:

* Brand P: 512\frac{5}{12} of its weight is electrolytes
* Brand Q: 41.8%41.8\% of its weight is electrolytes
* Brand R: 0.4160.416 of its weight is electrolytes
* Brand S: 1330\frac{13}{30} of its weight is electrolytes

Arrange the brands in order from the least proportion of electrolytes to the greatest proportion of electrolytes.

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Cevap

The correct order from least to greatest proportion of electrolytes is Brand R, Brand P, Brand Q, and Brand S.
To compare the values, converting each to a decimal is the most reliable strategy. Brand R is already a decimal (0.4160.416). Converting Brand P yields 5120.4167\frac{5}{12} \approx 0.4167. Converting Brand Q yields 41.8%=0.41841.8\% = 0.418. Converting Brand S yields 13300.4333\frac{13}{30} \approx 0.4333. Comparing these decimals reveals that 0.416<0.4167<0.418<0.43330.416 < 0.4167 < 0.418 < 0.4333, corresponding to the sequence: Brand R, Brand P, Brand Q, Brand S.

Adım Adım Çözüm

1
Identify and list all values given for each brand.
Brand P: 512\frac{5}{12}, Brand Q: 41.8%41.8\%, Brand R: 0.4160.416, Brand S: 1330\frac{13}{30}.
This establishes the raw numbers that need comparison.
2
Convert each value into a decimal format to allow direct comparison, rounding to four decimal places where necessary.
Brand R: 0.41600.4160; Brand P: 5÷120.41675 \div 12 \approx 0.4167; Brand Q: 41.8%=0.418041.8\% = 0.4180; Brand S: 13÷300.433313 \div 30 \approx 0.4333.
Converting to decimals standardizes the formats and makes close comparisons straightforward.
3
Compare the standardized decimal values from smallest to largest.
0.4160<0.4167<0.4180<0.43330.4160 < 0.4167 < 0.4180 < 0.4333, which corresponds to the order: Brand R, Brand P, Brand Q, Brand S.
Ordering the values correctly identifies the brands from the least proportion of electrolytes to the greatest.

Anahtar Kavram

Comparing and ordering rational numbers by converting fractions, decimals, and percents into a single consistent format.

Alternatif Yöntem

Instead of converting to decimals, all values can be converted to percentages: Brand R is 41.6%41.6\%, Brand P is 512×100%41.67%\frac{5}{12} \times 100\% \approx 41.67\%, Brand Q is 41.8%41.8\%, and Brand S is 1330×100%43.33%\frac{13}{30} \times 100\% \approx 43.33\%. Comparing these values gives 41.6%<41.67%<41.8%<43.33%41.6\% < 41.67\% < 41.8\% < 43.33\%.
Tahmini Süre:1m 30s
Soru 188Soru

A set of cards is numbered consecutively from 11 to NN. If exactly 1212 of these cards have a number that is a multiple of both 66 and 88, what is the greatest possible value of NN?

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Cevap: 311

Cevap

The greatest possible value of NN is 311311.
The correct value is 311. Since the numbers must be multiples of both 6 and 8, they must be multiples of their least common multiple, which is 24. The twelfth multiple of 24 is 288, and the thirteenth multiple is 312. To have exactly 12 such multiples, the maximum number N must be at least 288 but strictly less than 312, meaning the largest integer value is 311.

Adım Adım Çözüm

1
Find the least common multiple (LCM) of 6 and 8.
The LCM of 6 and 8 is 24.
Any number that is a multiple of both 6 and 8 must be a multiple of their least common multiple.
2
Calculate the 12th and 13th multiples of 24.
The 12th multiple is 12×24=28812 \times 24 = 288 and the 13th multiple is 13×24=31213 \times 24 = 312.
To have exactly 12 multiples in the set, the set must include the 12th multiple but exclude the 13th multiple.
3
Determine the maximum value of NN such that 312 is not included.
N=311N = 311.
The largest integer less than 312 is 311. If NN were 312 or greater, the set would contain 13 or more multiples.

Anahtar Kavram

Least Common Multiple and Divisibility Properties
Soru 189Soru

A runner completed a race in 4545 minutes. If this time is 1212 minutes faster than their previous race time, tt, which of the following equations can be used to find the previous race time?

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Cevap: t12=45t - 12 = 45

Cevap

The equation t12=45t - 12 = 45 correctly models the relationship between the previous and current race times.
The equation t12=45t - 12 = 45 is correct because 'faster than' in running means a shorter duration of time. Thus, the previous time tt must be 1212 minutes greater than 4545 minutes, which is algebraically expressed as t12=45t - 12 = 45 (or t=45+12t = 45 + 12).

Adım Adım Çözüm

1
Identify the relationship between the current time and the previous time tt.
The current time is 4545 minutes, which is 1212 minutes faster than tt.
This establishes that the previous time tt is larger than the current time of 4545 minutes.
2
Set up the algebraic equation based on the time difference.
t12=45t - 12 = 45
Subtracting the difference of 1212 minutes from the slower previous time tt yields the faster current time of 4545 minutes.

Anahtar Kavram

Translating verbal descriptions of differences into one-step subtraction equations
Tahmini Süre:45s
Soru 190Soru

Simplify the four mathematical expressions below. How should these expressions be ordered from least to greatest based on their simplified values?

* Expression A: 2.25×104×(2.0×101)2\sqrt{2.25 \times 10^4} \times \left(2.0 \times 10^{-1}\right)^{-2}
* Expression B: (3.0×102)36.0×103\frac{\left(3.0 \times 10^2\right)^3}{6.0 \times 10^3}
* Expression C: 2.7×1073×(4.0×102)1/2\sqrt[3]{2.7 \times 10^7} \times \left(4.0 \times 10^{-2}\right)^{-1/2}
* Expression D: (6.4×105)1/2×5.0×100\left(6.4 \times 10^5\right)^{1/2} \times 5.0 \times 10^0

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Cevap

Expression C, Expression A, Expression D, Expression B
The correct order is determined by fully simplifying each expression: Expression C simplifies to 1,5001,500, Expression A simplifies to 3,7503,750, Expression D simplifies to 4,0004,000, and Expression B simplifies to 4,5004,500. Arranging these values in ascending order gives the correct sequence starting with Expression C, followed by Expression A, then Expression D, and ending with Expression B.

Adım Adım Çözüm

1
Simplify Expression C: 2.7×1073×(4.0×102)1/2\sqrt[3]{2.7 \times 10^7} \times \left(4.0 \times 10^{-2}\right)^{-1/2}
C=1,500C = 1,500
First, rewrite 2.7×1072.7 \times 10^7 as 27×10627 \times 10^6 to compute the cube root easily: 27×1063=3×102=300\sqrt[3]{27 \times 10^6} = 3 \times 10^2 = 300. Second, evaluate the term with the rational exponent: (4.0×102)1/2=14.0×102=12.0×101=10.2=5\left(4.0 \times 10^{-2}\right)^{-1/2} = \frac{1}{\sqrt{4.0 \times 10^{-2}}} = \frac{1}{2.0 \times 10^{-1}} = \frac{1}{0.2} = 5. Finally, multiply the two parts: 300×5=1,500300 \times 5 = 1,500.
2
Simplify Expression A: 2.25×104×(2.0×101)2\sqrt{2.25 \times 10^4} \times \left(2.0 \times 10^{-1}\right)^{-2}
A=3,750A = 3,750
First, calculate the square root: 2.25×104=2.25×104=1.5×102=150\sqrt{2.25 \times 10^4} = \sqrt{2.25} \times \sqrt{10^4} = 1.5 \times 10^2 = 150. Second, evaluate the term with the negative exponent: (2.0×101)2=(0.2)2=10.04=25\left(2.0 \times 10^{-1}\right)^{-2} = (0.2)^{-2} = \frac{1}{0.04} = 25. Finally, multiply the two simplified values: 150×25=3,750150 \times 25 = 3,750.
3
Simplify Expression D: (6.4×105)1/2×5.0×100\left(6.4 \times 10^5\right)^{1/2} \times 5.0 \times 10^0
D=4,000D = 4,000
First, simplify the square root by rewriting the radicand: (6.4×105)1/2=64×104=8×102=800\left(6.4 \times 10^5\right)^{1/2} = \sqrt{64 \times 10^4} = 8 \times 10^2 = 800. Second, evaluate 5.0×100=5.0×1=55.0 \times 10^0 = 5.0 \times 1 = 5. Finally, multiply the results: 800×5=4,000800 \times 5 = 4,000.
4
Simplify Expression B: (3.0×102)36.0×103\frac{\left(3.0 \times 10^2\right)^3}{6.0 \times 10^3}
B=4,500B = 4,500
First, raise the numerator to the power of three: (3.0×102)3=33×(102)3=27×106\left(3.0 \times 10^2\right)^3 = 3^3 \times \left(10^2\right)^3 = 27 \times 10^6. Next, divide by the denominator: 27×1066.0×103=276.0×103=4.5×103=4,500\frac{27 \times 10^6}{6.0 \times 10^3} = \frac{27}{6.0} \times 10^3 = 4.5 \times 10^3 = 4,500.
5
Compare the simplified values of the four expressions.
1,500<3,750<4,000<4,5001,500 < 3,750 < 4,000 < 4,500, which corresponds to Expression C, Expression A, Expression D, then Expression B.
Sorting the values in ascending numerical order reveals the correct order from least to greatest.

Anahtar Kavram

Simplifying complex numeric expressions containing combinations of square roots, cube roots, negative exponents, fractional exponents, and scientific notation.
Tahmini Süre:3m 0s
Soru 191Soru

A construction crew of 1212 workers can build 22 identical storage sheds in 88 days, working 66 hours per day. To complete a new project of building 33 of these same storage sheds in 66 days, how many additional workers, working at the same rate, must be hired if they will work 44 hours per day?

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Cevap: 24

Cevap

The correct answer is 24 additional workers.
The correct answer is 24 additional workers. First, calculate the rate of work: 1212 workers working 66 hours per day for 88 days is 12×8×6=57612 \times 8 \times 6 = 576 total worker-hours to complete 22 sheds, which equals 288288 worker-hours per shed. For the new project of 33 sheds, the total worker-hours needed is 3×288=8643 \times 288 = 864 hours. Under the new schedule of 66 days at 44 hours per day, each worker will work 6×4=246 \times 4 = 24 hours. Thus, the total number of workers required is 864/24=36864 / 24 = 36 workers. Subtracting the original crew of 1212 workers, the crew needs to hire 3612=2436 - 12 = 24 additional workers.

Adım Adım Çözüm

1
Calculate the total worker-hours required to build one storage shed.
288 worker-hours per shed
A crew of 1212 workers working for 88 days at 66 hours per day contributes a total of 12×8×6=57612 \times 8 \times 6 = 576 worker-hours to build 22 sheds. Dividing 576576 by 22 gives 288288 worker-hours per shed.
2
Determine the total worker-hours required for the new project of building 3 sheds.
864 worker-hours
Since each shed requires 288288 worker-hours, building 33 sheds will require 3×288=8643 \times 288 = 864 worker-hours.
3
Calculate the number of hours each worker will contribute under the new schedule.
24 hours per worker
On the new schedule, workers work for 66 days at 44 hours per day, which equals 6×4=246 \times 4 = 24 hours per worker.
4
Calculate the total number of workers required and the number of additional workers to hire.
36 total workers, which means 24 additional workers
Dividing the total required hours (864864) by the hours per worker (2424) gives 3636 total workers. Subtracting the initial crew of 1212 workers yields 3612=2436 - 12 = 24 additional workers.

Anahtar Kavram

Compound rates and proportional relationships

Alternatif Yöntem

We can set up a compound proportion equation where W1D1H1S1=W2D2H2S2\frac{W_1 \cdot D_1 \cdot H_1}{S_1} = \frac{W_2 \cdot D_2 \cdot H_2}{S_2}. Substituting the known values: 12862=W2643\frac{12 \cdot 8 \cdot 6}{2} = \frac{W_2 \cdot 6 \cdot 4}{3}. Simplifying both sides gives 288=8W2288 = 8 W_2, which yields W2=36W_2 = 36. The number of additional workers is 3612=2436 - 12 = 24.
Tahmini Süre:1m 30s
Soru 192Soru

Four prototype solar cells are tested for their efficiency in converting solar energy into electricity. The efficiency of each solar cell is recorded as follows:

* Cell W: 425\frac{4}{25} of the incoming energy is converted.
* Cell X: 16.5%16.5\% of the incoming energy is converted.
* Cell Y: 0.16050.1605 of the incoming energy is converted.
* Cell Z: 1380\frac{13}{80} of the incoming energy is converted.

Based on this data, how should these solar cells be ordered from least efficient to most efficient?

Öğeleri doğru sıraya koymak için sürükleyin

Cevabı ve açıklamayı göster

Cevap

The correct ordering from least efficient to most efficient is Cell W, Cell Y, Cell Z, and Cell X.
Converting all efficiency values to decimals facilitates comparison. Cell W is 425=0.1600\frac{4}{25} = 0.1600. Cell Y is 0.16050.1605. Cell Z is 1380=0.1625\frac{13}{80} = 0.1625. Cell X is 16.5%=0.165016.5\% = 0.1650. Comparing these decimals shows that 0.1600<0.1605<0.1625<0.16500.1600 < 0.1605 < 0.1625 < 0.1650, which matches the order: Cell W, Cell Y, Cell Z, Cell X.

Adım Adım Çözüm

1
Convert the efficiency of Cell W to a decimal.
425=0.16=0.1600\frac{4}{25} = 0.16 = 0.1600
To easily compare the values, convert the fraction to a decimal by dividing the numerator by the denominator.
2
Convert the efficiency of Cell X to a decimal.
16.5%=0.165=0.165016.5\% = 0.165 = 0.1650
Convert the percentage to a decimal by dividing by 100.
3
Convert the efficiency of Cell Z to a decimal.
1380=0.1625\frac{13}{80} = 0.1625
Divide 13 by 80 to obtain its decimal representation.
4
Compare all four decimal values: 0.16000.1600 (Cell W), 0.16500.1650 (Cell X), 0.16050.1605 (Cell Y), and 0.16250.1625 (Cell Z).
0.1600<0.1605<0.1625<0.16500.1600 < 0.1605 < 0.1625 < 0.1650
Align the decimals by place value to determine their correct ascending order.

Anahtar Kavram

Comparing and ordering fractions, decimals, and percentages by converting them to a common format (decimals).
Tahmini Süre:1m 30s
Soru 193Soru

On a standard number line, point AA has coordinate 15-15 and point BB has coordinate 1717. Point CC is located to the right of point BB such that the distance between AA and CC is exactly 33 times the distance between BB and CC. What is the coordinate of point CC?

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Cevap: 33

Cevap

The coordinate of point CC is 33.
The correct coordinate is found by setting up the distance equation for point CC (with coordinate c>17c > 17) relative to A(15)A(-15) and B(17)B(17). The distance ACAC is c(15)=c+15c - (-15) = c + 15, and the distance BCBC is c17c - 17. Setting c+15=3(c17)c + 15 = 3(c - 17) and solving yields c=33c = 33, which is to the right of BB.

Adım Adım Çözüm

1
Define the variable for the coordinate of point C and write the expressions for distances.
Let cc be the coordinate of point CC. The distance between AA and CC is c(15)=c+15|c - (-15)| = |c + 15|, and the distance between BB and CC is c17|c - 17|. Since point CC is to the right of point BB (which is at 1717), we know c>17c > 17, so c+15=c+15|c + 15| = c + 15 and c17=c17|c - 17| = c - 17.
To set up an algebraic equation representing the physical distance relations on the number line.
2
Set up the equation using the given relationship.
The equation is c+15=3(c17)c + 15 = 3(c - 17).
The problem states the distance between AA and CC is 33 times the distance between BB and CC.
3
Solve the equation for cc.
c+15=3c51    15+51=3cc    66=2c    c=33c + 15 = 3c - 51 \implies 15 + 51 = 3c - c \implies 66 = 2c \implies c = 33.
To find the coordinate of point CC.

Anahtar Kavram

Calculating distances between points on a number line using absolute value and solving the resulting equations.

Alternatif Yöntem

Use geometric visualization: The distance from A(15)A(-15) to B(17)B(17) is 17(15)=3217 - (-15) = 32 units. Since point CC lies to the right of BB, the distance ACAC is the sum of ABAB and BCBC. Therefore, AC=32+BCAC = 32 + BC. We are given that AC=3×BCAC = 3 \times BC. Substituting this gives 32+BC=3×BC    2×BC=32    BC=1632 + BC = 3 \times BC \implies 2 \times BC = 32 \implies BC = 16. Since CC is 16 units to the right of B(17)B(17), its coordinate is 17+16=3317 + 16 = 33.
Tahmini Süre:1m 30s
Soru 194Soru

A laboratory sample contains 1.6×10171.6 \times 10^{17} atoms of a radioactive isotope. The sample decays such that at the end of each 6-hour interval, the number of remaining atoms is equal to the square root of the number of atoms that were present at the beginning of that interval. Which of the following is the number of atoms remaining in the sample at the end of 12 hours?

Cevabı ve açıklamayı göster

Cevap: 2×1042 \times 10^4

Cevap

2×1042 \times 10^4
The correct option is 2×1042 \times 10^4. To find the number of remaining atoms after 12 hours, we must apply the square root operation twice, since 12 hours consists of two 6-hour intervals. First, rewrite the initial number of atoms as 16×101616 \times 10^{16} to make the exponent even. After 6 hours, the number of atoms is 16×1016=4×108\sqrt{16 \times 10^{16}} = 4 \times 10^8. After another 6 hours, we take the square root again: 4×108=2×104\sqrt{4 \times 10^8} = 2 \times 10^4.

Adım Adım Çözüm

1
Determine the number of 6-hour intervals in a 12-hour period.
There are 12÷6=212 \div 6 = 2 intervals.
Since the population is reduced to its square root every 6 hours, we must apply the square root operation twice over a 12-hour period.
2
Rewrite the initial number of atoms in a form that simplifies taking the square root.
1.6×1017=16×10161.6 \times 10^{17} = 16 \times 10^{16}
Converting the coefficient to a perfect square and the exponent to an even number allows us to easily compute the square root without a calculator.
3
Calculate the number of atoms remaining after the first 6-hour interval by taking the square root of the initial value.
16×1016=16×1016=4×108\sqrt{16 \times 10^{16}} = \sqrt{16} \times \sqrt{10^{16}} = 4 \times 10^8
The square root of a product is the product of the square roots, and the square root of 101610^{16} is 10160.5=10810^{16 \cdot 0.5} = 10^8.
4
Calculate the number of atoms remaining after the second 6-hour interval (12 hours total) by taking the square root of the value at the end of the first interval.
4×108=4×108=2×104\sqrt{4 \times 10^8} = \sqrt{4} \times \sqrt{10^8} = 2 \times 10^4
Applying the square root operation to the intermediate quantity of 4×1084 \times 10^8 yields the final remaining atoms after the full 12 hours.

Anahtar Kavram

Applying square root operations to expressions written in scientific notation.

Alternatif Yöntem

We can compute the overall decay multiplier first. Taking the square root twice is equivalent to raising the initial quantity to the power of 14\frac{1}{4}. Thus, the final quantity is (1.6×1017)1/4=(16×1016)1/4=161/4×(1016)1/4=2×104(1.6 \times 10^{17})^{1/4} = (16 \times 10^{16})^{1/4} = 16^{1/4} \times (10^{16})^{1/4} = 2 \times 10^4.
Tahmini Süre:2m 0s
Soru 195Soru

A youth soccer league has a group of players. The players can be divided into equal-sized teams of either 12 or 18, with no players left over. However, if they are divided into teams of 15, there are exactly 3 players left over. What is the least possible number of players in the league?

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Cevap: 108

Cevap

The least possible number of players in the league is 108.
To satisfy the condition that players can be divided into teams of 12 or 18 with no remainders, the total number of players must be a multiple of their least common multiple (LCM). The prime factorization of 12 is 22×32^2 \times 3, and for 18 it is 2×322 \times 3^2, so their LCM is 22×32=362^2 \times 3^2 = 36. Next, we evaluate the positive multiples of 36 to find the smallest one that leaves a remainder of 3 when divided by 15. Testing 36: 36=15(2)+636 = 15(2) + 6 (remainder 6). Testing 72: 72=15(4)+1272 = 15(4) + 12 (remainder 12). Testing 108: 108=15(7)+3108 = 15(7) + 3 (remainder 3). Thus, 108 satisfies all conditions.

Adım Adım Çözüm

1
Find the least common multiple (LCM) of 12 and 18.
The LCM of 12 and 18 is 36.
Since the players can be divided into teams of 12 or 18 without remainders, the total number of players must be a multiple of both 12 and 18, which means it must be a multiple of their LCM.
2
List the positive multiples of 36.
The multiples are 36, 72, 108, 144, 180, and so on.
To find the least possible number of players, we need to test the multiples of 36 in increasing order.
3
Test the multiples of 36 to find which one leaves a remainder of 3 when divided by 15.
Testing 36 gives a remainder of 6; testing 72 gives a remainder of 12; testing 108 gives a remainder of 3.
Dividing 108 by 15 yields 7 with a remainder of 3, satisfying all the conditions of the problem.

Anahtar Kavram

Using the least common multiple (LCM) to satisfy multiple divisibility and remainder constraints.
Tahmini Süre:1m 30s
Soru 196Soru

An art teacher divides a container of clay equally among 66 students. If each student receives 1515 ounces of clay, and cc represents the total number of ounces of clay in the container, which of the following equations can be used to find cc?

Cevabı ve açıklamayı göster

Cevap: c6=15\frac{c}{6} = 15

Cevap

c6=15\frac{c}{6} = 15
The equation representing the total amount of clay divided by the number of students equals the amount of clay per student is correct. Since the teacher divides the clay cc equally among 66 students, the expression c6\frac{c}{6} represents the amount each student gets, which is given as 1515 ounces. Therefore, the correct equation is c6=15\frac{c}{6} = 15.

Adım Adım Çözüm

1
Identify the relationship between the total amount of clay, the number of students, and the amount per student.
The total amount of clay, cc, divided by the number of students, 66, must equal the amount of clay each student receives.
Dividing a total quantity equally among a set number of groups is represented by division.
2
Write the relationship as an algebraic equation.
c6=15\frac{c}{6} = 15
Substitute the given values and variables into the division relationship.

Anahtar Kavram

Translating word problems into one-step algebraic division equations
Tahmini Süre:45s
Soru 197Soru

The volume of a spherical cell is given by the formula V=43πr3V = \frac{4}{3}\pi r^3, where rr is the radius of the cell. If a certain spherical cell has a radius of r=3.0×106r = 3.0 \times 10^{-6} meters, what is its volume in cubic meters, written in scientific notation?

Cevabı ve açıklamayı göster

Cevap: 3.6π×10173.6\pi \times 10^{-17}

Cevap

3.6π×10173.6\pi \times 10^{-17}
To find the volume, substitute the radius r=3.0×106r = 3.0 \times 10^{-6} into the formula V=43πr3V = \frac{4}{3}\pi r^3. First, cube the radius: (3.0×106)3=27×1018(3.0 \times 10^{-6})^3 = 27 \times 10^{-18}. Next, multiply this value by 43π\frac{4}{3}\pi to get 36π×101836\pi \times 10^{-18}. Finally, convert this value to standard scientific notation by rewriting it as 3.6π×10173.6\pi \times 10^{-17}.

Adım Adım Çözüm

1
Substitute the radius r=3.0×106r = 3.0 \times 10^{-6} meters into the sphere volume formula V=43πr3V = \frac{4}{3}\pi r^3.
V=43π(3.0×106)3V = \frac{4}{3}\pi (3.0 \times 10^{-6})^3
This sets up the expression for calculating the volume.
2
Cube the term inside the parentheses using the power of a product and power of a power rules.
(3.0×106)3=3.03×(106)3=27×1018(3.0 \times 10^{-6})^3 = 3.0^3 \times (10^{-6})^3 = 27 \times 10^{-18}
This simplifies the radius term before performing the remaining operations.
3
Multiply the simplified term by 43π\frac{4}{3}\pi.
V=43π×27×1018=36π×1018V = \frac{4}{3}\pi \times 27 \times 10^{-18} = 36\pi \times 10^{-18}
This performs the fractional multiplication to find the volume.
4
Convert the volume into standard scientific notation by rewriting 3636 as 3.6×1013.6 \times 10^1 and combining the exponents.
36π×1018=3.6π×101736\pi \times 10^{-18} = 3.6\pi \times 10^{-17}
Standard scientific notation requires the coefficient to be between 1 and 10.

Anahtar Kavram

Applying laws of exponents and scientific notation rules to evaluate formulas.
Soru 198Soru

A car travels at a constant speed of rr miles per hour. If the car travels 240240 miles in 44 hours, which of the following equations can be used to determine the value of rr?

Cevabı ve açıklamayı göster

Cevap: 4r=2404r = 240

Cevap

The equation 4r=2404r = 240 represents the relationship because distance equals rate multiplied by time.
The relationship between distance, rate, and time is given by the formula Distance=Rate×Time\text{Distance} = \text{Rate} \times \text{Time}. Substituting the distance of 240240 miles and the time of 44 hours into this formula yields 240=r×4240 = r \times 4, which is equivalent to 4r=2404r = 240.

Adım Adım Çözüm

1
Identify the formula relating distance, rate, and time.
Distance=Rate×Time\text{Distance} = \text{Rate} \times \text{Time} (or d=rtd = r \cdot t)
This is the standard physical relationship governing constant speed motion.
2
Substitute the given values into the formula.
240=r4240 = r \cdot 4
The total distance dd is given as 240240 miles, the time tt is 44 hours, and the speed is the variable rr.
3
Rewrite the equation in standard algebraic format.
4r=2404r = 240
Multiplying the variable rr by the coefficient 44 is conventionally written with the number first.

Anahtar Kavram

Translating a constant rate word problem into a one-step linear equation.
Tahmini Süre:45s
Soru 199Soru

If xx is a real number such that 4x+2+4x+2+4x+2+4x+28x3=64\sqrt{\frac{4^{x+2} + 4^{x+2} + 4^{x+2} + 4^{x+2}}{8^{x-3}}} = 64, what is the value of xx?

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Cevap: 3

Cevap

The value of xx is 33.
By rewriting the repeated addition in the numerator as 4×4x+2=4x+34 \times 4^{x+2} = 4^{x+3} and converting all bases to 2, the expression inside the square root simplifies to 215x2^{15-x}. Taking the square root gives 215x22^{\frac{15-x}{2}}. Setting this equal to 6464 (which is 262^6) and equating the exponents yields x=3x = 3.

Adım Adım Çözüm

1
Rewrite the sum in the numerator 4x+2+4x+2+4x+2+4x+24^{x+2} + 4^{x+2} + 4^{x+2} + 4^{x+2} as a product.
4×4x+2=4x+34 \times 4^{x+2} = 4^{x+3}
Adding a term to itself four times is equivalent to multiplying that term by 4.
2
Convert the base 4 numerator and base 8 denominator to base 2.
Numerator: (22)x+3=22x+6(2^2)^{x+3} = 2^{2x+6}; Denominator: (23)x3=23x9(2^3)^{x-3} = 2^{3x-9}
Expressing terms with the same base allows the use of exponent laws to simplify the fraction.
3
Simplify the fraction by subtracting the denominator's exponent from the numerator's exponent.
22x+623x9=2(2x+6)(3x9)=215x\frac{2^{2x+6}}{2^{3x-9}} = 2^{(2x+6)-(3x-9)} = 2^{15-x}
The quotient rule for exponents states that aman=amn\frac{a^m}{a^n} = a^{m-n}.
4
Apply the square root to the simplified fraction, set it equal to 6464, and express both sides as powers of 2.
215x=215x2=64=26\sqrt{2^{15-x}} = 2^{\frac{15-x}{2}} = 64 = 2^6
The square root of a term is equivalent to raising that term to the power of 12\frac{1}{2}.
5
Equate the exponents and solve for xx.
15x2=6    15x=12    x=3\frac{15-x}{2} = 6 \implies 15-x = 12 \implies x = 3
If two exponential expressions with the same positive base are equal, their exponents must be equal.

Anahtar Kavram

Simplifying expressions using the laws of exponents and properties of roots
Soru 200Soru

A container holds a mixture of sand, gravel, and cement. By weight, the mixture is 30%30\% sand, 25\frac{2}{5} gravel, and the remaining portion is cement. To adjust the mixture's properties, the amount of sand is doubled, the amount of gravel is increased by 25%25\%, and the amount of cement is decreased by 50%50\%. What percentage of the new mixture, by weight, is cement?

Cevabı ve açıklamayı göster

Cevap: 12%12\%

Cevap

12%
To find the correct percentage, we establish that out of an initial 100 g100\text{ g} of the mixture, there are 30 g30\text{ g} of sand, 40 g40\text{ g} of gravel, and 30 g30\text{ g} of cement. After the changes, the new weights are 60 g60\text{ g} of sand, 50 g50\text{ g} of gravel, and 15 g15\text{ g} of cement. The new total weight is 125 g125\text{ g}. Thus, cement constitutes 15125=12%\frac{15}{125} = 12\% of the new mixture.

Adım Adım Çözüm

1
Determine the initial proportions and assign a hypothetical total weight of 100 g100\text{ g} to simplify the calculations.
Sand is 30 g30\text{ g}. Gravel is 25×100 g=40 g\frac{2}{5} \times 100\text{ g} = 40\text{ g}. Cement is the remaining weight: 100 g(30 g+40 g)=30 g100\text{ g} - (30\text{ g} + 40\text{ g}) = 30\text{ g}.
Establishing concrete weights makes applying percentage changes straightforward.
2
Apply the specified weight changes to each component to find their new weights.
New sand weight: 30 g×2=60 g30\text{ g} \times 2 = 60\text{ g}. New gravel weight: 40 g×1.25=50 g40\text{ g} \times 1.25 = 50\text{ g}. New cement weight: 30 g×0.50=15 g30\text{ g} \times 0.50 = 15\text{ g}.
This calculates the individual component weights after the adjustments.
3
Calculate the new total weight of the mixture and the new percentage of cement.
New total weight: 60 g+50 g+15 g=125 g60\text{ g} + 50\text{ g} + 15\text{ g} = 125\text{ g}. Cement percentage: 15 g125 g×100%=12%\frac{15\text{ g}}{125\text{ g}} \times 100\% = 12\%.
The percentage of a component in a mixture is its weight divided by the new total weight of the mixture.

Anahtar Kavram

Calculating new percentage concentrations after changes in individual component weights within a mixture.
Tahmini Süre:2m 0s
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