Pre-Algebra

419 soru

Soru 321Soru

A high school student council must select a 3-member executive committee consisting of a President, a Vice President, and a Treasurer from a group of 6 juniors and 4 seniors. If the positions are filled sequentially at random and no student can hold more than one position, what is the probability that the President is a senior, the Vice President is a junior, and the Treasurer is a senior?

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Cevap: 110\frac{1}{10}

Cevap

The probability that the President is a senior, the Vice President is a junior, and the Treasurer is a senior is 110\frac{1}{10}.
To find the probability of dependent sequential events, multiply the probability of each event given that the preceding events have occurred. First, selecting a senior President has a probability of 410\frac{4}{10}. Next, selecting a junior Vice President from the remaining 9 students has a probability of 69\frac{6}{9}. Finally, selecting another senior as Treasurer from the remaining 8 students (which now contains 3 seniors) has a probability of 38\frac{3}{8}. Multiplying these probabilities yields 410×69×38=72720=110\frac{4}{10} \times \frac{6}{9} \times \frac{3}{8} = \frac{72}{720} = \frac{1}{10}.

Adım Adım Çözüm

1
Determine the probability of choosing a senior as President.
There are 4 seniors out of 10 total students, so P(President is Senior)=410P(\text{President is Senior}) = \frac{4}{10}.
The first selection is made from the full group of 10 students.
2
Determine the probability of choosing a junior as Vice President given the first event.
There are 6 juniors remaining out of 9 total remaining students, so P(VP is JuniorPresident is Senior)=69P(\text{VP is Junior} \mid \text{President is Senior}) = \frac{6}{9}.
One student (a senior) has already been selected, reducing the total count to 9.
3
Determine the probability of choosing a senior as Treasurer given the first two events.
There are 3 seniors remaining out of 8 total remaining students, so P(Treasurer is Seniorfirst two selections)=38P(\text{Treasurer is Senior} \mid \text{first two selections}) = \frac{3}{8}.
Two students have now been selected, leaving 8 total students and 3 remaining seniors.
4
Multiply the sequential conditional probabilities together.
410×69×38=72720=110\frac{4}{10} \times \frac{6}{9} \times \frac{3}{8} = \frac{72}{720} = \frac{1}{10}.
According to the Multiplication Rule for Dependent Events, the joint probability is the product of the sequential probabilities.

Anahtar Kavram

Probability of Dependent Compound Events
Tahmini Süre:1m 30s
Soru 322Soru

A municipal transit system tracks its monthly revenue from three fare categories: Single-Ride passes, Weekly passes, and Monthly subscriptions. Single-Ride passes account for 920\frac{9}{20} of the total monthly revenue, and Weekly passes account for 30%30\% of the total monthly revenue. If the remaining revenue from Monthly subscriptions is $21,000\$21,000, what was the total monthly revenue, in dollars, for the transit system?

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Cevap: $84,000

Cevap

The total monthly revenue for the transit system is $84,000.
Single-Ride passes account for 920=45%\frac{9}{20} = 45\% of revenue, and Weekly passes account for 30%30\%. Together, they account for 45%+30%=75%45\% + 30\% = 75\% of total revenue. The remaining 25%25\% (100%75%100\% - 75\%) corresponds to Monthly subscriptions, which equals $21,000\$21,000. Dividing $21,000\$21,000 by 0.250.25 gives the total monthly revenue of $84,000\$84,000.

Adım Adım Çözüm

1
Convert the fraction portion into a percentage.
920=45100=45%\frac{9}{20} = \frac{45}{100} = 45\%
Converting all proportions to percentages allows for direct comparison and addition.
2
Calculate the combined percentage accounted for by Single-Ride and Weekly passes.
45%+30%=75%45\% + 30\% = 75\%
Summing the two given parts determines the total portion of revenue accounted for so far.
3
Find the percentage corresponding to Monthly subscriptions.
100%75%=25%100\% - 75\% = 25\%
The three fare categories make up 100%100\% of the total monthly revenue.
4
Set up an equation to solve for the total revenue TT.
0.25T=21,000    T=21,0000.25=84,0000.25 T = 21,000 \implies T = \frac{21,000}{0.25} = 84,000
Dividing the dollar amount of the remaining category by its percentage equivalent yields the total revenue.

Anahtar Kavram

Combining fractions and percentages to solve for an unknown total value.
Tahmini Süre:1m 30s
Soru 323Soru

A community orchard initially planted apple, peach, and plum trees in the ratio 4:3:54 : 3 : 5, respectively. After a severe frost, 1212 plum trees died and were removed from the orchard, while all apple and peach trees survived. If the new ratio of apple trees to remaining plum trees became 2:12 : 1, how many total trees were originally in the orchard?

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Cevap: 4848

Cevap

The total number of trees originally in the orchard was 48.
By representing the initial tree counts with the multiplier xx as 4x4x (apple), 3x3x (peach), and 5x5x (plum), the total original tree count is 12x12x. Setting up the proportion 4x5x12=21\frac{4x}{5x - 12} = \frac{2}{1} gives 4x=10x244x = 10x - 24, which simplifies to 6x=246x = 24, or x=4x = 4. Multiplying x=4x = 4 by the total ratio units (1212) yields 4848 original trees.

Adım Adım Çözüm

1
Define variables using the initial ratio.
Let the original number of apple, peach, and plum trees be 4x4x, 3x3x, and 5x5x, respectively. The original total number of trees is 4x+3x+5x=12x4x + 3x + 5x = 12x.
Ratios allow quantities to be represented in terms of a common multiplier xx.
2
Set up an equation based on the updated number of plum trees and the new ratio.
After removing 1212 plum trees, the number of plum trees is 5x125x - 12. The ratio of apple trees to remaining plum trees is 4x5x12=21\frac{4x}{5x - 12} = \frac{2}{1}.
The number of apple trees remains 4x4x, and the problem states the new apple-to-plum ratio is 2:12 : 1.
3
Solve the proportion for xx.
4x=2(5x12)    4x=10x24    6x=24    x=44x = 2(5x - 12) \implies 4x = 10x - 24 \implies 6x = 24 \implies x = 4.
Cross-multiplying eliminates fractions and isolates the variable xx.
4
Calculate the original total number of trees.
Original total trees =12x=12(4)=48= 12x = 12(4) = 48.
Substituting x=4x = 4 back into the original total expression yields the requested answer.

Anahtar Kavram

Solving multi-part ratio problems with altered quantities by establishing algebraic proportions.
Tahmini Süre:1m 15s
Soru 324Soru

A software development team consists of 44 front-end developers, 55 back-end developers, and 33 quality assurance (QA) engineers. The project manager needs to select a 33-member subcommittee to present a new product feature. If the subcommittee must contain at least 11 front-end developer and at least 11 back-end developer, how many different 33-member subcommittees can be formed?

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Cevap: 130

Cevap

The total number of valid 3-member subcommittees that can be formed is 130.
To form a 3-member committee with at least 1 front-end developer and at least 1 back-end developer from 4 front-end, 5 back-end, and 3 QA engineers, we break the problem into three mutually exclusive valid scenarios: selecting 1 member from each role gives 4×5×3=604 \times 5 \times 3 = 60 ways; selecting 2 front-end and 1 back-end developer gives C(4,2)×C(5,1)=6×5=30C(4,2) \times C(5,1) = 6 \times 5 = 30 ways; and selecting 1 front-end and 2 back-end developers gives C(4,1)×C(5,2)=4×10=40C(4,1) \times C(5,2) = 4 \times 10 = 40 ways. Summing these possibilities gives 60+30+40=13060 + 30 + 40 = 130. Alternatively, subtracting invalid committees (those with no front-end developers: C(8,3)=56C(8,3) = 56, no back-end developers: C(7,3)=35C(7,3) = 35, minus double-counted 3 QA engineers: 11) from total 3-member committees (C(12,3)=220C(12,3) = 220) yields 220(56+351)=130220 - (56 + 35 - 1) = 130.

Adım Adım Çözüm

1
Determine the required subcommittee size and role counts
The team has 4 front-end developers, 5 back-end developers, and 3 QA engineers (12 members total). A subcommittee of size 3 is required.
Establishing the total population and category counts is necessary before computing combination constraints.
2
Enumerate the mutually exclusive cases that satisfy all constraints
Case 1: (1 front-end, 1 back-end, 1 QA)
Case 2: (2 front-end, 1 back-end, 0 QA)
Case 3: (1 front-end, 2 back-end, 0 QA)
The committee requires at least 1 front-end and at least 1 back-end member in a 3-person group.
3
Compute combinations for each valid case using the combination formula C(n,k)=n!k!(nk)!C(n, k) = \frac{n!}{k!(n-k)!}
Case 1: C(4,1)×C(5,1)×C(3,1)=4×5×3=60C(4,1) \times C(5,1) \times C(3,1) = 4 \times 5 \times 3 = 60
Case 2: C(4,2)×C(5,1)×C(3,0)=6×5×1=30C(4,2) \times C(5,1) \times C(3,0) = 6 \times 5 \times 1 = 30
Case 3: C(4,1)×C(5,2)×C(3,0)=4×10×1=40C(4,1) \times C(5,2) \times C(3,0) = 4 \times 10 \times 1 = 40
Order of selection does not matter when forming a committee, so combinations are used.
4
Add the counts from all mutually exclusive cases
Total valid subcommittees = 60+30+40=13060 + 30 + 40 = 130
According to the addition rule of counting, the total number of outcomes across disjoint cases is the sum of their individual counts.

Anahtar Kavram

Counting combinations across multiple groups with specific distribution constraints
Soru 325Soru

A municipal recycling center processes pp tons of plastic waste per hour. During a standard 14-hour operation cycle, the center processes a total of 119 tons of plastic waste. Which of the following equations represents this scenario, and what is the value of pp?

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Cevap: 14p=11914p = 119; p=8.5p = 8.5

Cevap

The equation representing the situation is 14p=11914p = 119, which solves to p=8.5p = 8.5 tons per hour.
The total amount of plastic waste processed is determined by multiplying the rate per hour (pp) by the total number of hours (14), yielding the equation 14p=11914p = 119. Dividing both sides of this equation by 14 isolates pp, giving p=8.5p = 8.5 tons of plastic processed per hour.

Adım Adım Çözüm

1
Set up the algebraic equation for total processing amount
14p=11914p = 119
Total plastic processed equals the hourly processing rate (pp) multiplied by the total hours of operation (14).
2
Solve the one-step linear equation for pp
p=11914=8.5p = \frac{119}{14} = 8.5
Divide both sides of the equation by 14 to isolate the variable pp.

Anahtar Kavram

Formulating and solving one-step linear equations from real-world rate scenarios
Tahmini Süre:1m 0s
Soru 326Soru

A local fitness center recorded the number of weekly workout sessions attended by a sample of 2020 members over the past month. The results are summarized in the frequency table below:

Sessions per WeekNumber of Members
1144
2266
3355
4433
5522

What is the positive difference between the mean and the median number of weekly workout sessions for these 2020 members?

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Cevap: 0.150.15

Cevap

The positive difference between the mean and median number of weekly workout sessions is 0.150.15.
To find the mean, multiply each number of sessions by its frequency, sum the products, and divide by the total number of members (2020): (4+12+15+12+10)/20=53/20=2.65(4 + 12 + 15 + 12 + 10) / 20 = 53 / 20 = 2.65. To find the median for 2020 members, take the average of the 10th and 11th values in order. Looking at cumulative frequencies, the 5th through 10th entries are 22 and the 11th through 15th entries are 33. The median is (2+3)/2=2.5(2 + 3)/2 = 2.5. The positive difference is 2.652.5=0.152.65 - 2.5 = 0.15.

Adım Adım Çözüm

1
Calculate the total number of sessions.
(1×4)+(2×6)+(3×5)+(4×3)+(5×2)=4+12+15+12+10=53(1 \times 4) + (2 \times 6) + (3 \times 5) + (4 \times 3) + (5 \times 2) = 4 + 12 + 15 + 12 + 10 = 53
Multiply each session value by its corresponding frequency to find the total sum of sessions.
2
Calculate the mean number of sessions.
Mean=5320=2.65\text{Mean} = \frac{53}{20} = 2.65
Divide the total number of sessions by the total number of members (2020).
3
Find the median number of sessions.
\text{Median} = \frac{2 + 3}{2} = 2.5
With 2020 total data points, the median is the average of the 10th and 11th ordered values. The cumulative frequencies show that the first 44 values are 11, the next 66 values (5th through 10th) are 22, and the next 55 values (11th through 15th) are 33. The 10th value is 22 and the 11th value is 33.
4
Calculate the positive difference between the mean and median.
|2.65 - 2.5| = 0.15
Subtract the median from the mean to find the difference.

Anahtar Kavram

Calculating mean and median from a frequency table
Tahmini Süre:1m 30s
Soru 327Soru

A wildlife conservation team tags and monitors sea turtle nests along a coastal beach. The team divides a total of nn nesting data loggers equally among 66 field researchers. If each researcher receives 1414 data loggers, which of the following equations correctly models this situation to find nn?

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Cevap: n6=14\frac{n}{6} = 14

Cevap

The correct equation is n6=14\frac{n}{6} = 14.
Dividing the total quantity nn equally among 66 researchers is algebraically expressed as n6\frac{n}{6}. Setting this equal to the 1414 loggers each researcher receives yields n6=14\frac{n}{6} = 14.

Adım Adım Çözüm

1
Identify the total quantity and how it is divided.
The total number of loggers is nn, and it is split equally among 66 researchers.
Dividing a total quantity into equal groups corresponds to the division operation n6\frac{n}{6}.
2
Equate the algebraic expression to the given result per group.
n6=14\frac{n}{6} = 14
Each researcher receives 1414 loggers, so the share per researcher, n6\frac{n}{6}, must equal 1414.

Anahtar Kavram

Translating verbal descriptions of equal sharing into one-step division equations.
Tahmini Süre:1m 0s
Soru 328Soru

An art gallery features a collection of 6060 paintings, each categorized by its medium (oil or watercolor) and its historical period (19th19\text{th}-century or 20th20\text{th}-century). Among the collection, 3535 paintings are 19th19\text{th}-century works, 4040 paintings are oil paintings, and 1010 paintings are 20th20\text{th}-century watercolor works. If a single painting is selected at random from the collection, what is the probability that the selected painting is a 19th19\text{th}-century oil painting?

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Cevap: 512\frac{5}{12}

Cevap

512\frac{5}{12}
To find the probability of choosing a 19th19\text{th}-century oil painting, determine the number of paintings that fit both criteria. Out of 6060 paintings, 4040 are oil, meaning 2020 are watercolors. Given that 1010 watercolors are 20th20\text{th}-century, the remaining 1010 watercolors must be 19th19\text{th}-century. Since there are 3535 total 19th19\text{th}-century paintings, subtracting the 1010 19th19\text{th}-century watercolors yields 2525 19th19\text{th}-century oil paintings. The probability is therefore 2560\frac{25}{60}, which simplifies to 512\frac{5}{12}.

Adım Adım Çözüm

1
Find the total number of watercolor paintings in the collection.
Since there are 6060 total paintings and 4040 oil paintings, the number of watercolor paintings is 6040=2060 - 40 = 20.
Paintings are categorized into oil or watercolor, so the remaining paintings must be watercolors.
2
Find the number of 19th19\text{th}-century watercolor paintings.
There are 2020 total watercolor paintings and 1010 are from the 20th20\text{th} century, so the number of 19th19\text{th}-century watercolors is 2010=1020 - 10 = 10.
Subtracting the 20th20\text{th}-century watercolors from the total watercolors gives the 19th19\text{th}-century watercolors.
3
Calculate the number of 19th19\text{th}-century oil paintings.
There are 3535 total 19th19\text{th}-century paintings. Subtracting the 1010 19th19\text{th}-century watercolors leaves 3510=2535 - 10 = 25 19th19\text{th}-century oil paintings.
All 19th19\text{th}-century paintings are either oil or watercolor.
4
Compute the probability of picking a 19th19\text{th}-century oil painting.
The probability is 2560=512\frac{25}{60} = \frac{5}{12}.
Divide the number of favorable outcomes (2525) by the total number of paintings in the sample space (6060).

Anahtar Kavram

Two-way categorization and conditional counting for compound probabilities
Tahmini Süre:2m 0s
Soru 329Soru

A software development company allocated its annual operating budget across three departments: Engineering, Marketing, and Customer Support. Exactly 25\frac{2}{5} of the total budget was allocated to Engineering, and 35%35\% of the total budget was allocated to Marketing. If the remaining budget of $45,000\$45,000 was allocated to Customer Support, what was the company's total annual operating budget?

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Cevap: $180,000\$180,000

Cevap

The total annual operating budget of the company was $180,000\$180,000.
To find the total budget, first convert 25\frac{2}{5} to a percentage, which is 40%40\%. Adding Engineering's 40%40\% and Marketing's 35%35\% gives 75%75\% of the total budget. This leaves 100%75%=25%100\% - 75\% = 25\% for Customer Support. Since Customer Support received $45,000\$45,000, setting 0.25T=45,0000.25 T = 45,000 yields T=45,0000.25=$180,000T = \frac{45,000}{0.25} = \$180,000.

Adım Adım Çözüm

1
Convert the fraction allocated to Engineering into a percentage.
25=40100=40%\frac{2}{5} = \frac{40}{100} = 40\%
Converting all departmental allocations to percentages allows for direct comparison and summation.
2
Calculate the combined percentage allocated to Engineering and Marketing.
40%+35%=75%40\% + 35\% = 75\%
Adding the two known departmental shares determines the total fraction of the budget accounted for.
3
Find the percentage allocated to Customer Support.
100%75%=25%100\% - 75\% = 25\%
The remaining portion of the 100%100\% total budget belongs to Customer Support.
4
Set up an equation relating Customer Support's dollar allocation to the total budget TT and solve for TT.
0.25T=45,000    T=45,0000.25=180,0000.25 T = 45,000 \implies T = \frac{45,000}{0.25} = 180,000
Dividing the dollar amount by its corresponding decimal percentage yields the original total budget.

Anahtar Kavram

Solving word problems involving mixed representations of fractions, decimals, and percentages to find an unknown initial total.
Tahmini Süre:1m 30s
Soru 330Soru

In a wildlife sanctuary habitat, the ratio of finches to sparrows is 3:53 : 5, and the ratio of sparrows to thrushes is 2:32 : 3. If there are 4545 thrushes in the habitat, what is the total number of finches, sparrows, and thrushes?

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Cevap: 93

Cevap

The total number of birds in the habitat is 93.
To find the total number of birds, first combine the finch-to-sparrow ratio (3:53 : 5) and the sparrow-to-thrush ratio (2:32 : 3) into a single three-part ratio. Since sparrows are common to both, scale the ratios so that sparrows have the same number of parts: 3:5=6:103 : 5 = 6 : 10 and 2:3=10:152 : 3 = 10 : 15. The combined ratio of finches to sparrows to thrushes is 6:10:156 : 10 : 15. Since there are 4545 thrushes corresponding to 1515 parts, 11 part represents 45÷15=345 \div 15 = 3 birds. The total number of parts is 6+10+15=316 + 10 + 15 = 31, so the total number of birds is 31×3=9331 \times 3 = 93.

Adım Adım Çözüm

1
Unify the two given ratios using a common term for sparrows.
The ratio of finches to sparrows is 3:5=6:103 : 5 = 6 : 10. The ratio of sparrows to thrushes is 2:3=10:152 : 3 = 10 : 15. Combined ratio of finches to sparrows to thrushes is 6:10:156 : 10 : 15.
Since sparrows appear in both ratios with values 55 and 22, finding the least common multiple (1010) allows all three quantities to be expressed in a single triple ratio.
2
Determine the value of one ratio unit using the known quantity of thrushes.
Thrushes correspond to 1515 ratio parts. Value per unit =4515=3= \frac{45}{15} = 3 birds.
Given that there are 4545 thrushes and they represent 1515 units in the combined ratio, dividing the total thrushes by 1515 gives the multiplier for each unit.
3
Calculate the total number of birds across all three species.
Total ratio units =6+10+15=31= 6 + 10 + 15 = 31 units. Total birds =31×3=93= 31 \times 3 = 93.
Multiplying the total number of ratio units by the value of a single unit yields the overall population of birds in the habitat.

Anahtar Kavram

Combining Compound Ratios and Scaling Proportions
Tahmini Süre:1m 30s
Soru 331Soru

A customer satisfaction survey asked 2525 patrons at a local restaurant to rate their dining experience on a scale from 11 (poor) to 55 (excellent). The frequency table below summarizes the ratings collected:

RatingNumber of Patrons
13
25
38
46
53

What is the positive difference between the mean rating and the median rating of these 2525 patrons?

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Cevap: 0.040.04

Cevap

The positive difference between the mean rating and the median rating is 0.040.04.
To find the positive difference, first compute the mean by calculating the sum of products of each rating and its frequency: (1×3)+(2×5)+(3×8)+(4×6)+(5×3)=76(1 \times 3) + (2 \times 5) + (3 \times 8) + (4 \times 6) + (5 \times 3) = 76. Dividing 7676 by the total number of patrons (2525) yields a mean of 3.043.04. Next, find the median by identifying the 13th13\text{th} ordered rating out of 2525. The cumulative frequency reaches 88 after rating 2 and 1616 after rating 3, so the 13th13\text{th} entry is 33. The positive difference between the mean (3.043.04) and median (3.003.00) is 0.040.04.

Adım Adım Çözüm

1
Calculate the total sum of all ratings.
Sum =(1×3)+(2×5)+(3×8)+(4×6)+(5×3)=3+10+24+24+15=76= (1 \times 3) + (2 \times 5) + (3 \times 8) + (4 \times 6) + (5 \times 3) = 3 + 10 + 24 + 24 + 15 = 76.
Each rating value must be multiplied by its frequency to find the total value of all responses.
2
Calculate the mean rating.
Mean =7625=3.04= \frac{76}{25} = 3.04.
Divide the total sum of all ratings by the total number of patrons (2525).
3
Determine the median rating.
Median =3= 3.
With 2525 data points arranged in ascending order, the median is the 25+12=13th\frac{25 + 1}{2} = 13\text{th} score. Accumulating frequencies: Ratings 1 and 2 cover the first 3+5=83 + 5 = 8 scores, while Rating 3 covers the 9th9\text{th} through 16th16\text{th} scores. Thus, the 13th13\text{th} score is 33.
4
Find the positive difference between the mean and median.
Difference =3.043.00=0.04= 3.04 - 3.00 = 0.04.
Subtract the median rating (33) from the mean rating (3.043.04).

Anahtar Kavram

Calculating Mean and Median from a Frequency Table
Tahmini Süre:1m 30s
Soru 332Soru

A solar-powered charging station operates using two types of solar panels, Type A and Type B. The ratio of Type A panels to Type B panels installed at the station is 5:35 : 3. Each Type A panel generates 2424 watt-hours of energy per hour, and each Type B panel generates 4040 watt-hours of energy per hour. If there are a total of 4848 solar panels installed at the station, how many total watt-hours of energy do all the panels generate combined in one hour?

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Cevap: 1,4401,440

Cevap

The total energy generated by all panels in one hour is 1,4401,440 watt-hours.
The correct answer is 1,4401,440 watt-hours. The ratio 5:35 : 3 indicates that out of every 8 panels (5+35 + 3), 5 are Type A and 3 are Type B. Converting these to fractions of the total 4848 panels gives 48×58=3048 \times \frac{5}{8} = 30 Type A panels and 48×38=1848 \times \frac{3}{8} = 18 Type B panels. Multiplying each quantity by its respective hourly output yields 30×24=72030 \times 24 = 720 watt-hours for Type A panels and 18×40=72018 \times 40 = 720 watt-hours for Type B panels. Combining these gives 720+720=1,440720 + 720 = 1,440 watt-hours.

Adım Adım Çözüm

1
Calculate the total number of ratio parts
The total ratio parts equal 5+3=85 + 3 = 8.
To divide the total number of panels into proportional parts, add the terms of the ratio together.
2
Find the quantity of each type of panel installed
Type A panels = 48×58=3048 \times \frac{5}{8} = 30; Type B panels = 48×38=1848 \times \frac{3}{8} = 18.
Multiply the total number of panels (4848) by each panel type's fraction of the total ratio.
3
Calculate the energy generated by each panel type in one hour
Type A energy = 30×24=72030 \times 24 = 720 watt-hours; Type B energy = 18×40=72018 \times 40 = 720 watt-hours.
Multiply the count of each panel type by its specific hourly generation rate.
4
Sum the energy outputs to find the combined total
Total combined energy = 720+720=1,440720 + 720 = 1,440 watt-hours.
Add the hourly energy outputs of Type A and Type B panels together.

Anahtar Kavram

Solving multi-step word problems involving part-to-whole ratios and rate calculations
Tahmini Süre:1m 30s
Soru 333Soru

A container holds 4040 marbles, each of which is red, blue, or green. The probability of randomly drawing a red marble from the container is 25\frac{2}{5}. Among the remaining marbles, the ratio of blue marbles to green marbles is 1:31:3. If one marble is selected at random from the container, what is the probability that it is green?

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Cevap: 920\frac{9}{20}

Cevap

The probability that the randomly selected marble is green is 920\frac{9}{20}.
The correct answer is 920\frac{9}{20}. The probability of drawing a non-red marble is 125=351 - \frac{2}{5} = \frac{3}{5}. Given that the non-red marbles are split in a 1:31:3 ratio between blue and green, green marbles represent 31+3=34\frac{3}{1+3} = \frac{3}{4} of the non-red group. Multiplying the probability of drawing a non-red marble by the proportion of green marbles within that group gives 35×34=920\frac{3}{5} \times \frac{3}{4} = \frac{9}{20}.

Adım Adım Çözüm

1
Find the total number of red marbles and the number of remaining marbles.
Since the probability of drawing a red marble is 25\frac{2}{5}, the number of red marbles is 25×40=16\frac{2}{5} \times 40 = 16. The remaining number of marbles (blue and green) is 4016=2440 - 16 = 24.
Determining the count of non-red marbles isolates the sample space for blue and green marbles.
2
Use the ratio of blue to green marbles to find the number of green marbles.
The ratio of blue to green is 1:31:3, meaning there are 1+3=41 + 3 = 4 equal parts. Each part contains 244=6\frac{24}{4} = 6 marbles. Therefore, there are 3×6=183 \times 6 = 18 green marbles.
Converting a part-to-part ratio into actual counts allows calculation of the favorable outcome.
3
Calculate the probability of randomly drawing a green marble.
The probability is the number of green marbles divided by the total number of marbles: 1840=920\frac{18}{40} = \frac{9}{20}.
Basic probability is defined as the number of favorable outcomes divided by the total number of possible outcomes.

Anahtar Kavram

Combining complement probability rules with part-to-whole ratio conversions to compute event probabilities.
Tahmini Süre:1m 30s
Soru 334Soru

A solar power plant generated a total of 480 megawatt-hours (MWh)480\text{ megawatt-hours (MWh)} of energy in one month. Of this total, 25\frac{2}{5} was stored in battery banks, 0.350.35 was supplied directly to an industrial facility, and the remaining portion was delivered to residential homes. How many megawatt-hours of energy were delivered to residential homes?

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Cevap: 120 MWh

Cevap

120 MWh
Converting 25\frac{2}{5} to 0.400.40 allows us to sum the battery and industrial portions (0.40+0.35=0.750.40 + 0.35 = 0.75). The remaining residential portion is 10.75=0.251 - 0.75 = 0.25, or 25%25\%. Taking 25%25\% of 480 MWh480\text{ MWh} gives 120 MWh120\text{ MWh}.

Adım Adım Çözüm

1
Convert the fraction to a decimal
25=0.40\frac{2}{5} = 0.40
Converting all given values to a common format (decimals) simplifies addition.
2
Sum the non-residential portions of energy
0.40 + 0.35 = 0.75
Combining the battery storage fraction and industrial supply fraction determines the total non-residential portion.
3
Find the remaining fraction for residential homes
1.00 - 0.75 = 0.25
Subtracting the combined non-residential portion from the whole (1.00) gives the residential fraction.
4
Calculate the megawatt-hours delivered to residential homes
0.25 \times 480 = 120\text{ MWh}
Multiplying the residential fraction by the total energy generated gives the target quantity.

Anahtar Kavram

Combining fractions and decimals to determine a remaining percentage of a whole quantity
Tahmini Süre:1m 0s
Soru 335Soru

A community garden supervisor distributes a total of dd pounds of organic compost equally among 88 raised garden beds. If each bed receives exactly 14.514.5 pounds of compost, which of the following equations can be solved to find dd?

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Cevap: d8=14.5\frac{d}{8} = 14.5

Cevap

The equation representing the relationship is d8=14.5\frac{d}{8} = 14.5.
The correct equation represents taking the total weight of compost, dd, and dividing it equally into 88 parts to get 14.514.5 pounds per bed, which yields d8=14.5\frac{d}{8} = 14.5.

Adım Adım Çözüm

1
Identify the total quantity and how it is divided.
Total compost = dd pounds, divided equally among 88 beds.
Equal sharing corresponds to division of the total quantity by the number of shares.
2
Set up the algebraic expression for the amount per bed.
Amount per bed = d8\frac{d}{8}.
Dividing total pounds dd by 88 gives the weight allocated to each individual bed.
3
Equate the expression to the given quantity per bed.
d8=14.5\frac{d}{8} = 14.5.
The problem states that each bed receives 14.514.5 pounds of compost.

Anahtar Kavram

Translating equal division word problems into one-step algebraic equations
Tahmini Süre:1m 0s
Soru 336Soru

A commercial diver descends at a constant rate of 2.52.5 meters per second. If the diver's total change in depth after tt seconds is 85-85 meters, which of the following equations can be solved to find tt?

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Cevap: 2.5t=85-2.5t = -85

Cevap

2.5t=85-2.5t = -85
The rate of depth change is 2.5-2.5 meters per second. Over tt seconds, the total distance descended is given by the product of the unit rate and time, 2.5t-2.5t. Equating this to the given total change in depth of 85-85 meters gives 2.5t=85-2.5t = -85.

Adım Adım Çözüm

1
Identify the given rate, total quantity, and variable.
Rate of change = 2.5-2.5 m/s, time = tt seconds, total depth change = 85-85 m.
Establishing knowns and unknown variables is the first step in setting up a one-step algebraic equation.
2
Formulate the relationship using the rate formula (Rate)×(Time)=Total Change(\text{Rate}) \times (\text{Time}) = \text{Total Change}.
2.5×t=85-2.5 \times t = -85, which simplifies to 2.5t=85-2.5t = -85.
Since the descent occurs at a constant rate per second, total change is the product of the rate per second and total seconds.

Anahtar Kavram

Formulating one-step linear equations from rate word problems
Soru 337Soru

A solar power system generated a total of 450450 kilowatt-hours (kWh) of electricity during a 3-day period. On Day 1, the system generated 29\frac{2}{9} of the total 3-day electricity. On Day 2, it generated 40%40\% of the remaining electricity after Day 1. How many kilowatt-hours of electricity were generated on Day 3?

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Cevap: 210

Cevap

210 kWh
To find the electricity generated on Day 3, first determine the Day 1 portion by multiplying 29\frac{2}{9} by 450450, which gives 100100 kWh. The amount remaining for Days 2 and 3 is 450100=350450 - 100 = 350 kWh. Day 2 accounts for 40%40\% of this remaining amount, which is 0.40×350=1400.40 \times 350 = 140 kWh. Finally, subtract Day 2's portion from the remaining amount: 350140=210350 - 140 = 210 kWh.

Adım Adım Çözüm

1
Calculate the amount of electricity generated on Day 1.
100100 kWh
Multiply the fraction 29\frac{2}{9} by the total electricity (450450 kWh).
2
Determine the remaining electricity after Day 1.
350350 kWh
Subtract Day 1's generation (100100 kWh) from the total amount (450450 kWh).
3
Calculate the amount of electricity generated on Day 2.
140140 kWh
Convert 40%40\% to a decimal (0.400.40) and multiply by the remaining 350350 kWh.
4
Calculate the amount of electricity generated on Day 3.
210210 kWh
Subtract Day 2's generation (140140 kWh) from the 350350 kWh remaining after Day 1.

Anahtar Kavram

Multi-step word problems involving fractions, percentage calculations, and remaining quantities.
Tahmini Süre:1m 15s
Soru 338Soru

A community library's summer program requires participants to create a 3-book reading list consisting of exactly 11 biography, 11 science fiction novel, and 11 history book selected from a featured list. The featured list contains 55 biographies (2 of which have over 400400 pages), 66 science fiction novels (3 of which have over 400400 pages), and 44 history books (1 of which has over 400400 pages). If a participant selects 11 book of each genre at random from the featured list, what is the probability that at least 11 of the selected books has over 400400 pages? Express your answer as a decimal.

Cevabı ve açıklamayı göster

Cevap: 0.775

Cevap

0.775
To find the probability of selecting at least one book over 400400 pages, it is most efficient to use the complement rule: P(at least one)=1P(none)P(\text{at least one}) = 1 - P(\text{none}). There are 5×6×4=1205 \times 6 \times 4 = 120 total 3-book combinations. The number of books with 400400 pages or fewer in each category are 33 biographies, 33 sci-fi novels, and 33 history books. Thus, there are 3×3×3=273 \times 3 \times 3 = 27 combinations with no books over 400400 pages. The probability of choosing no books over 400400 pages is 27120=0.225\frac{27}{120} = 0.225. Subtracting this from 11 gives 10.225=0.7751 - 0.225 = 0.775.

Adım Adım Çözüm

1
Calculate the total number of possible combinations of selecting 1 book from each genre
Total combinations = 5×6×4=1205 \times 6 \times 4 = 120
By the Fundamental Counting Principle, multiplying the number of choices in each independent category yields the total outcomes.
2
Determine the complement event: selecting a reading list where NO book has over 400 pages
Available books of 400 pages or fewer: 3 biographies, 3 sci-fi novels, and 3 history books
Subtracting the number of books over 400 pages from the total in each category gives the count of books with 400 pages or fewer.
3
Calculate the number of combinations consisting entirely of books with 400 pages or fewer
Complement combinations = 3×3×3=273 \times 3 \times 3 = 27
Applying the Fundamental Counting Principle to the non-qualifying choices gives the total outcomes for the complement event.
4
Find the probability of the complement event and subtract from 1 to find the target probability
P(at least one over 400)=127120=10.225=0.775P(\text{at least one over } 400) = 1 - \frac{27}{120} = 1 - 0.225 = 0.775
The complement rule states that P(A)=1P(A)P(A) = 1 - P(A'), which is much more efficient than calculating probabilities for 1, 2, or 3 long books separately.

Anahtar Kavram

Complementary Probability and Fundamental Counting Principle
Tahmini Süre:1m 30s
Soru 339Soru

A high school science club organized a daily recycling drive over a 10-day period. The frequency table below summarizes the number of aluminum cans collected per day:

Cans Collected Per DayNumber of Days
102
203
303
401
501

What is the positive difference between the mean number of cans collected per day and the median number of cans collected per day?

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Cevap: 1

Cevap

The positive difference between the mean and median is 1.
To find the mean, calculate the weighted sum of the products of each daily quantity and its frequency: (10 × 2 + 20 × 3 + 30 × 3 + 40 × 1 + 50 × 1) = 260. Dividing 260 by the total 10 days gives a mean of 26. To find the median, list the 10 data points in order: 10, 10, 20, 20, 20, 30, 30, 30, 40, 50. The middle two numbers are the 5th and 6th terms (20 and 30), so the median is (20 + 30) / 2 = 25. Subtracting 25 from 26 yields a positive difference of 1.

Adım Adım Çözüm

1
Calculate the total number of cans collected and the total number of days.
Total days = 2 + 3 + 3 + 1 + 1 = 10. Total cans = (10 × 2) + (20 × 3) + (30 × 3) + (40 × 1) + (50 × 1) = 20 + 60 + 90 + 40 + 50 = 260.
To find the mean from a frequency table, multiply each data value by its frequency and sum the results, then divide by the total frequency.
2
Calculate the mean number of cans collected per day.
Mean = 260 / 10 = 26.
Divide the total sum of collected cans by the total number of days.
3
Find the median of the data set.
The 10 ordered data points are: 10, 10, 20, 20, 20, 30, 30, 30, 40, 50. The 5th value is 20 and the 6th value is 30. Median = (20 + 30) / 2 = 25.
For an even number of data points (N=10N = 10), the median is the arithmetic mean of the two middle values (N/2N/2 th and (N/2+1)(N/2 + 1) th terms).
4
Compute the positive difference between the mean and median.
Difference = 26 - 25 = 1.
Subtract the median from the mean to find the requested difference.

Anahtar Kavram

Weighted Mean and Median from Frequency Tables
Tahmini Süre:1m 15s
Soru 340Soru

A community theater group allocated a total budget of $1,500\$1,500 to create costumes for an upcoming production. Exactly 14\frac{1}{4} of the budget was spent on fabric, 0.300.30 of the budget was spent on specialized footwear, and 15\frac{1}{5} of the budget was spent on sewing accessories. The remaining amount of the budget was spent on theatrical wigs. What amount, in dollars, did the theater group spend on theatrical wigs?

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Cevap: $375\$375

Cevap

The theater group spent $375\$375 on theatrical wigs.
The correct answer of $375\$375 is found by determining each individual expense and subtracting their sum from the total budget. Fabric accounts for 14\frac{1}{4} of $1,500\$1,500, which is $375\$375. Footwear accounts for 0.300.30 of $1,500\$1,500, which is $450\$450. Sewing accessories account for 15\frac{1}{5} of $1,500\$1,500, which is $300\$300. Combined, these three categories equal $375+$450+$300=$1,125\$375 + \$450 + \$300 = \$1,125. Subtracting $1,125\$1,125 from the total budget of $1,500\$1,500 leaves $375\$375 for theatrical wigs.

Adım Adım Çözüm

1
Calculate the dollar amount spent on fabric
14×$1,500=$375\frac{1}{4} \times \$1,500 = \$375
Multiply the fraction representing fabric by the total budget.
2
Calculate the dollar amount spent on footwear
0.30×$1,500=$4500.30 \times \$1,500 = \$450
Multiply the decimal representing footwear by the total budget.
3
Calculate the dollar amount spent on sewing accessories
15×$1,500=$300\frac{1}{5} \times \$1,500 = \$300
Multiply the fraction representing accessories by the total budget.
4
Sum the three known category expenses
\$375 + \$450 + \$300 = \$1,125
Add the expenses together to determine the total spent before wigs.
5
Subtract the sum of known expenses from the total budget
\$1,500 - \$1,125 = \$375
The remaining portion of the budget is allocated to theatrical wigs.

Anahtar Kavram

Converting fractions and decimals to quantities of a total amount and calculating remaining portions.
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