Pre-Algebra

419 soru

Soru 21Soru

For all real numbers aa, bb, and cc, let the operation \oplus be defined by ab=ab+1a \oplus b = ab + 1. Which of the following statements must be true?

I. ab=baa \oplus b = b \oplus a
II. a(bc)=(ab)ca \oplus (b \oplus c) = (a \oplus b) \oplus c
III. a(b+c)=(ab)+(ac)a \oplus (b + c) = (a \oplus b) + (a \oplus c)

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Cevap: I only

Cevap

The correct option is the one stating that only Statement I must be true.
The correct option is the one stating that only Statement I must be true. This is because multiplication of real numbers is commutative, making the custom operation commutative. Statement II is false because the operation is not associative, and Statement III is false because the operation does not distribute over addition.

Adım Adım Çözüm

1
Evaluate Statement I (ab=baa \oplus b = b \oplus a) by substituting the definition of the operation.
ab=ab+1a \oplus b = ab + 1 and ba=ba+1b \oplus a = ba + 1. Since multiplication of real numbers is commutative, ab=baab = ba, which means ab+1=ba+1ab + 1 = ba + 1. Thus, Statement I is true for all real numbers.
To test the commutative property of the defined operation.
2
Evaluate Statement II (a(bc)=(ab)ca \oplus (b \oplus c) = (a \oplus b) \oplus c) by applying the operation's definition to both sides.
Left side: a(bc)=a(bc+1)=a(bc+1)+1=abc+a+1a \oplus (b \oplus c) = a \oplus (bc + 1) = a(bc + 1) + 1 = abc + a + 1. Right side: (ab)c=(ab+1)c=(ab+1)c+1=abc+c+1(a \oplus b) \oplus c = (ab + 1) \oplus c = (ab + 1)c + 1 = abc + c + 1. Since abc+a+1abc + a + 1 is not equal to abc+c+1abc + c + 1 for all real numbers (for example, if a=1a = 1, b=1b = 1, and c=2c = 2, then 454 \neq 5), Statement II is not always true.
To test the associative property of the defined operation.
3
Evaluate Statement III (a(b+c)=(ab)+(ac)a \oplus (b + c) = (a \oplus b) + (a \oplus c)) using the operation's definition.
Left side: a(b+c)=a(b+c)+1=ab+ac+1a \oplus (b + c) = a(b + c) + 1 = ab + ac + 1. Right side: (ab)+(ac)=(ab+1)+(ac+1)=ab+ac+2(a \oplus b) + (a \oplus c) = (ab + 1) + (ac + 1) = ab + ac + 2. Since ab+ac+1ab+ac+2ab + ac + 1 \neq ab + ac + 2 for all real numbers, Statement III is false.
To test whether the operation distributes over addition.

Anahtar Kavram

Identifying properties of operations (commutativity, associativity, and distributivity) on real numbers.

Alternatif Yöntem

To quickly disprove Statements II and III, you can substitute simple counterexamples. For Statement II, let a=1,b=1,c=2a=1, b=1, c=2: 1(12)=13=41 \oplus (1 \oplus 2) = 1 \oplus 3 = 4, while (11)2=22=5(1 \oplus 1) \oplus 2 = 2 \oplus 2 = 5. Since 454 \neq 5, Statement II is false. For Statement III, let a=1,b=1,c=1a=1, b=1, c=1: 1(1+1)=12=31 \oplus (1+1) = 1 \oplus 2 = 3, while (11)+(11)=2+2=4(1 \oplus 1) + (1 \oplus 1) = 2 + 2 = 4. Since 343 \neq 4, Statement III is false.
Tahmini Süre:2m 0s
Soru 22Soru

Evaluate the four mathematical expressions below and arrange them in order from least to greatest value.

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Cevap

Expression X, Expression W, Expression Z, Expression Y
Evaluating all four expressions using the proper order of operations (PEMDAS) yields the values: Expression X is 16-16, Expression W is 10-10, Expression Z is 66, and Expression Y is 77. Ordering these values from least to greatest results in the sequence Expression X, Expression W, Expression Z, Expression Y.

Adım Adım Çözüm

1
Evaluate Expression X: (3)26×2+5-(-3)^2 - | -6 \times 2 + 5 |
16-16
First, evaluate the exponent: (3)2=9(-3)^2 = 9, which makes the first term 9-9. Next, calculate the expression inside the absolute value bars: 6×2+5=12+5=7-6 \times 2 + 5 = -12 + 5 = -7. The absolute value of 7-7 is 77. Subtracting this value gives 97=16-9 - 7 = -16.
2
Evaluate Expression W: 243(57)2÷(2)-2^4 - 3(5 - 7)^2 \div (-2)
10-10
First, evaluate the exponent: 24=(24)=16-2^4 = -(2^4) = -16. Then, evaluate inside the parentheses: 57=25 - 7 = -2, and square it: (2)2=4(-2)^2 = 4. Next, perform multiplication and division from left to right: 3(4)÷(2)=12÷(2)=6-3(4) \div (-2) = -12 \div (-2) = 6. Adding this to 16-16 gives 16+6=10-16 + 6 = -10.
3
Evaluate Expression Z: 18÷(3)×(2)4+23÷4\frac{-18 \div (-3) \times (-2)}{-4 + 2^3 \div 4}
66
In the numerator, perform multiplication and division from left to right: 18÷(3)=6-18 \div (-3) = 6, and then 6×(2)=126 \times (-2) = -12. In the denominator, evaluate the exponent: 23=82^3 = 8, divide: 8÷4=28 \div 4 = 2, and add: 4+2=2-4 + 2 = -2. Finally, divide the numerator by the denominator: 122=6\frac{-12}{-2} = 6.
4
Evaluate Expression Y: 43×[8(25)2]4 - 3 \times [8 - (2 - 5)^2]
77
Evaluate the innermost parentheses first: 25=32 - 5 = -3, and square it: (3)2=9(-3)^2 = 9. Simplify inside the brackets: 89=18 - 9 = -1. Multiply: 3×(1)=3-3 \times (-1) = 3. Add to the remaining term: 4+3=74 + 3 = 7.
5
Compare the evaluated values to find the correct ordering.
Expression X (16-16) < Expression W (10-10) < Expression Z (66) < Expression Y (77)
Comparing the values 16-16, 10-10, 66, and 77 from least to greatest establishes the correct sequence.

Anahtar Kavram

Order of operations dictates evaluating parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right). Negation outside exponents and absolute values must be treated with care.
Soru 23Soru

What is the value of the expression 153×23+1015 - 3 \times 2^3 + 10?

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Cevap: 11

Cevap

The value of the expression is 11.
Evaluating the exponent first gives 23=82^3 = 8. Next, multiplying 3 by 8 yields 24, resulting in the expression 1524+1015 - 24 + 10. Finally, performing addition and subtraction from left to right gives 1524=915 - 24 = -9, and 9+10=1-9 + 10 = 1. Therefore, the value of the expression is 11.

Adım Adım Çözüm

1
Evaluate the exponential expression.
23=82^3 = 8
According to the order of operations, exponents must be evaluated before multiplication, division, addition, and subtraction.
2
Perform the multiplication.
3×8=243 \times 8 = 24
Multiplication has higher priority than addition and subtraction.
3
Perform addition and subtraction from left to right.
1524+10=9+10=115 - 24 + 10 = -9 + 10 = 1
Addition and subtraction have equal priority and must be performed in the order they appear from left to right.

Anahtar Kavram

Order of Operations (PEMDAS)
Soru 24Soru

What is the greatest common factor of 3636 and 5454?

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Cevap: 18

Cevap

The greatest common factor of 3636 and 5454 is 1818.
The greatest common factor of 3636 and 5454 is 1818 because it is the largest integer that divides both numbers evenly (36÷18=236 \div 18 = 2 and 54÷18=354 \div 18 = 3).

Adım Adım Çözüm

1
Find the prime factorization of 3636 and 5454.
36=22×3236 = 2^2 \times 3^2 and 54=2×3354 = 2 \times 3^3
Prime factorization decomposes each number into its basic prime building blocks.
2
Identify the common prime factors with their lowest exponents.
The common prime factors are 22 with an exponent of 11 (212^1) and 33 with an exponent of 22 (323^2).
The greatest common factor consists of the product of the lowest powers of the shared prime factors.
3
Multiply the common factors raised to their lowest exponents.
21×32=2×9=182^1 \times 3^2 = 2 \times 9 = 18
Calculating this product gives the greatest common factor.

Anahtar Kavram

The greatest common factor (GCF) of two integers is the largest integer that divides both numbers without leaving a remainder. It is calculated by taking the product of the lowest powers of all common prime factors.

Alternatif Yöntem

List all factors of both numbers: Factors of 3636 are 1,2,3,4,6,9,12,18,361, 2, 3, 4, 6, 9, 12, 18, 36. Factors of 5454 are 1,2,3,6,9,18,27,541, 2, 3, 6, 9, 18, 27, 54. The largest number present in both lists is 1818.
Tahmini Süre:45s
Soru 25Soru

A red light flashes every 8 seconds, and a blue light flashes every 12 seconds. If they both flash at the same instant, how many seconds will pass before they next flash at the same instant?

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Cevap: 24

Cevap

24 seconds
The correct answer is 24 seconds. To find when both lights will flash at the same time again, we need to find the least common multiple (LCM) of their individual flashing intervals, 8 seconds and 12 seconds. Listing the multiples of each number:
Multiples of 8: 8, 16, 24, 32, 40, 48...
Multiples of 12: 12, 24, 36, 48...
The smallest number that appears in both lists is 24. Thus, the lights will flash together next after 24 seconds.

Adım Adım Çözüm

1
Identify the mathematical concept needed to solve the problem.
The problem requires finding the least common multiple (LCM) of the two flashing intervals, 8 and 12.
The lights will next flash together at the smallest positive integer that is a multiple of both 8 and 12.
2
Find the prime factorization of each number.
8=238 = 2^3 and 12=22×312 = 2^2 \times 3.
Prime factorization allows us to construct the LCM by taking the highest power of each prime factor present in either number.
3
Calculate the LCM from the prime factors.
LCM(8,12)=23×3=8×3=24\text{LCM}(8, 12) = 2^3 \times 3 = 8 \times 3 = 24.
We take the highest power of 2, which is 232^3, and the highest power of 3, which is 313^1.

Anahtar Kavram

Least Common Multiple
Tahmini Süre:45s
Soru 26Soru

For all non-zero real numbers xx and yy, let the operation \star be defined by xy=xyyxx \star y = \frac{x}{y} - \frac{y}{x}. Which of the following equations must be true for all non-zero real numbers aa, bb, and cc?

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Cevap: ab=(ba)a \star b = -(b \star a)

Cevap

The equation stating that the operation on two numbers is equal to the negative of the operation on those numbers in reverse order, which is ab=(ba)a \star b = -(b \star a)
Applying the definition of the custom operation, the expression for bab \star a is baab\frac{b}{a} - \frac{a}{b}. Factoring out 1-1 from this expression yields (abba)-\left(\frac{a}{b} - \frac{b}{a}\right), which is equivalent to (ab)-(a \star b). Multiplying both sides by 1-1 results in the equation ab=(ba)a \star b = -(b \star a), which must be true for all non-zero real numbers aa and bb.

Adım Adım Çözüm

1
Evaluate the expression for bab \star a using the custom operation definition.
ba=baabb \star a = \frac{b}{a} - \frac{a}{b}
To analyze the result of reversing the order of operands.
2
Factor out a negative sign from the right-hand side of the evaluated expression.
ba=(ba+ab)=(abba)b \star a = -\left(-\frac{b}{a} + \frac{a}{b}\right) = -\left(\frac{a}{b} - \frac{b}{a}\right)
To align the expression's terms with the definition of aba \star b.
3
Substitute the definition of aba \star b back into the expression.
ba=(ab)b \star a = -(a \star b)
To establish the relationship between the two permutations of the operation.
4
Negate both sides of the equation to find the equivalent representation.
ab=(ba)a \star b = -(b \star a)
To match the final equation with the options.

Anahtar Kavram

Algebraic properties of custom operations and order of operations

Alternatif Yöntem

Instead of algebraic proof, substitute small, distinct non-zero integers (e.g., a=2a = 2, b=1b = 1, c=3c = 3) to evaluate the expressions in each option, enabling the elimination of equations that do not hold.
Tahmini Süre:1m 30s
Soru 27Soru

For all non-zero real numbers xx, yy, and zz, which of the following mathematical equations must be true?

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Cevap: x+yz=xz+yz\frac{x + y}{z} = \frac{x}{z} + \frac{y}{z}

Cevap

The equation x+yz=xz+yz\frac{x + y}{z} = \frac{x}{z} + \frac{y}{z} must be true.
The equation stating that a sum in the numerator divided by a single term in the denominator can be split into two separate fractions is correct because division distributes over addition from the right side. This can be verified by rewriting the division as multiplication by the reciprocal: x+yz=(x+y)1z=x1z+y1z=xz+yz\frac{x + y}{z} = (x + y) \cdot \frac{1}{z} = x \cdot \frac{1}{z} + y \cdot \frac{1}{z} = \frac{x}{z} + \frac{y}{z}.

Adım Adım Çözüm

1
Analyze the properties of division and addition in the equation x+yz=xz+yz\frac{x + y}{z} = \frac{x}{z} + \frac{y}{z}.
The division of a sum by a number can be rewritten as the multiplication of the sum by the reciprocal of that number: (x+y)1z(x + y) \cdot \frac{1}{z}.
To apply the distributive property of multiplication over addition.
2
Distribute the term 1z\frac{1}{z} to both xx and yy.
(x+y)1z=x1z+y1z=xz+yz(x + y) \cdot \frac{1}{z} = x \cdot \frac{1}{z} + y \cdot \frac{1}{z} = \frac{x}{z} + \frac{y}{z}.
The distributive property states that a(b+c)=ab+aca(b + c) = ab + ac for any real numbers aa, bb, and cc.
3
Confirm that this identity holds for all non-zero real numbers xx, yy, and zz.
Since z0z \neq 0, the denominators are defined, and the relation x+yz=xz+yz\frac{x + y}{z} = \frac{x}{z} + \frac{y}{z} is always true.
To establish that the statement must be true under the given conditions.

Anahtar Kavram

Distributive Property of Real Numbers

Alternatif Yöntem

We can plug in simple numbers (e.g., x=2x = 2, y=3y = 3, z=4z = 4) to test each option and eliminate those that do not produce a true statement.
Tahmini Süre:1m 0s
Soru 28Soru

Let the values of three mathematical expressions be represented by AA, BB, and CC, where:

A=32(24)2÷3×2A = -3^2 - ( -2 - 4 )^2 \div 3 \times 2
B=5(3)24÷(2)3×(47)B = |-5 - (-3)| - 2^4 \div (-2)^3 \times (4 - 7)
C=43×222(1)5×3C = \frac{4 - 3 \times 2^2}{2} - ( -1 )^5 \times 3

Arrange the expressions AA, BB, and CC in order from least to greatest numerical value.

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Cevap

Expression A, Expression B, Expression C
Evaluating each expression using correct PEMDAS order of operations yields A=33A = -33, B=4B = -4, and C=1C = -1. Comparing these values gives the order from least to greatest as Expression A, followed by Expression B, followed by Expression C.

Adım Adım Çözüm

1
Evaluate Expression A by applying order of operations.
A=33A = -33
Simplify the grouping (24)=6(-2 - 4) = -6. Then apply exponents: 32=9-3^2 = -9 and (6)2=36(-6)^2 = 36. Perform division and multiplication from left to right: 36÷3×2=12×2=2436 \div 3 \times 2 = 12 \times 2 = 24. Subtract to find 924=33-9 - 24 = -33.
2
Evaluate Expression B by applying order of operations.
B=4B = -4
Simplify grouping terms: 5(3)=2|-5 - (-3)| = 2 and (47)=3(4 - 7) = -3. Evaluate exponents: 24=162^4 = 16 and (2)3=8(-2)^3 = -8. Perform division and multiplication from left to right: 16÷(8)×(3)=2×(3)=616 \div (-8) \times (-3) = -2 \times (-3) = 6. Subtract: 26=42 - 6 = -4.
3
Evaluate Expression C by applying order of operations.
C=1C = -1
Simplify the numerator: 43×22=412=84 - 3 \times 2^2 = 4 - 12 = -8, so the fraction is 4-4. Evaluate the exponent: (1)5=1(-1)^5 = -1. Multiply: 1×3=3-1 \times 3 = -3. Subtract: 4(3)=1-4 - (-3) = -1.
4
Compare the resulting values to determine the correct order from least to greatest.
Expression A (33-33) < Expression B (4-4) < Expression C (1-1)
Comparing negative integers, 33-33 is the smallest value and 1-1 is the largest value.

Anahtar Kavram

Order of Operations and Number Properties
Soru 29Soru

What is the value of the expression (2)43×12182+5×(35)3(-2)^4 - 3 \times \frac{|12 - 18|}{-2} + 5 \times (3 - 5)^3?

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Cevap: -15

Cevap

The correct answer is -15.
Evaluating the expression according to order of operations yields -15. First, simplify inside the grouping symbols to obtain (35)=2(3 - 5) = -2 and 1218=6|12 - 18| = 6. Next, evaluate exponents to obtain (2)4=16(-2)^4 = 16 and (2)3=8(-2)^3 = -8. After this, multiply and divide from left to right to obtain 3×62=9-3 \times \frac{6}{-2} = 9 and 5×(8)=405 \times (-8) = -40. Finally, add and subtract from left to right to obtain 16+940=1516 + 9 - 40 = -15.

Adım Adım Çözüm

1
Evaluate expressions inside grouping symbols.
The grouping symbols evaluate to (35)=2(3 - 5) = -2 and 1218=6=6|12 - 18| = |-6| = 6.
Operations inside parentheses and absolute value bars are prioritized first in the order of operations.
2
Evaluate the exponential terms.
(2)4=16(-2)^4 = 16 and (2)3=8(-2)^3 = -8.
Exponents must be calculated after grouping symbols and before multiplication or division.
3
Evaluate multiplication and division from left to right.
3×62=9-3 \times \frac{6}{-2} = 9 and 5×(8)=405 \times (-8) = -40.
Multiplication and division are equal in precedence and must be executed in order from left to right.
4
Perform addition and subtraction from left to right.
16+940=1516 + 9 - 40 = -15.
Addition and subtraction are the final operations performed, in order from left to right.

Anahtar Kavram

Order of operations with exponents, absolute values, and signed numbers.
Soru 30Soru

What is the value of the expression 3×(4210)5×23 \times (4^2 - 10) - 5 \times |-2|?

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Cevap: 8

Cevap

The correct value of the expression is 8.
Evaluating the expression following the order of operations (parentheses, exponents, multiplication/division, and addition/subtraction) results in 8.

Adım Adım Çözüm

1
Evaluate the exponent inside the parentheses
42=164^2 = 16
Exponents must be evaluated before basic arithmetic operations inside parentheses.
2
Subtract the numbers within the parentheses
1610=616 - 10 = 6
Operations enclosed in parentheses are prioritized first.
3
Evaluate the absolute value term
2=2|-2| = 2
The absolute value of a negative number is its positive distance from zero.
4
Perform the multiplications from left to right
3×6=183 \times 6 = 18 and 5×2=105 \times 2 = 10
Multiplications are performed before addition and subtraction.
5
Perform the final subtraction
1810=818 - 10 = 8
Subtraction is performed last according to the order of operations.

Anahtar Kavram

Order of Operations and Number Properties
Soru 31Soru

A baker has 1212 chocolate cupcakes and 1515 vanilla cupcakes. She wants to package them into boxes such that each box has the same number of chocolate cupcakes and the same number of vanilla cupcakes, with no cupcakes left over. What is the greatest number of boxes she can make?

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Cevap: 33

Cevap

The greatest number of boxes she can make is 33.
The greatest number of boxes that can be made is found by calculating the greatest common factor (GCF) of the two cupcake quantities. The factors of 1212 are 1,2,3,4,6,1, 2, 3, 4, 6, and 1212. The factors of 1515 are 1,3,5,1, 3, 5, and 1515. The greatest factor common to both lists is 33. This allows the baker to make 33 boxes, each containing 44 chocolate cupcakes and 55 vanilla cupcakes.

Adım Adım Çözüm

1
Identify that the problem requires finding the greatest common factor (GCF) of 1212 and 1515 to distribute the cupcakes evenly into the maximum number of boxes.
The problem is recognized as a greatest common factor (GCF) calculation.
We need the largest integer that divides both 1212 and 1515 with no remainder.
2
List the factors of 1212 and 1515.
Factors of 1212 are 1,2,3,4,6,121, 2, 3, 4, 6, 12. Factors of 1515 are 1,3,5,151, 3, 5, 15.
Listing the factors helps identify all shared divisors.
3
Find the greatest common factor shared by both lists.
The common factors are 11 and 33, so the greatest common factor is 33.
The greatest common factor is the largest number of identical groups we can form.

Anahtar Kavram

Factors, Multiples, and Prime Factorization
Tahmini Süre:45s
Soru 32Soru

What is the value of the expression 3×(47)2+24234-3 \times (4 - 7)^2 + \frac{24}{2^3 - 4}?

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Cevap: 21-21

Cevap

The correct answer is 21-21.
Following the order of operations, we first compute the term inside the parentheses: 47=34 - 7 = -3. Next, we evaluate the exponents: (3)2=9(-3)^2 = 9 and 23=82^3 = 8. This simplifies the expression to 3×9+2484-3 \times 9 + \frac{24}{8 - 4}. Simplifying the denominator gives 84=48 - 4 = 4. We then perform the multiplication and division: 3×9=27-3 \times 9 = -27 and 244=6\frac{24}{4} = 6. Adding these results together yields 27+6=21-27 + 6 = -21.

Adım Adım Çözüm

1
Evaluate the subtraction inside the parentheses.
47=34 - 7 = -3
According to the order of operations, grouping symbols such as parentheses must be evaluated first.
2
Evaluate the exponential terms in the expression.
(3)2=9(-3)^2 = 9 and 23=82^3 = 8
Exponents must be evaluated after parentheses and before multiplication, division, addition, or subtraction.
3
Simplify the denominator of the fraction.
84=48 - 4 = 4
The denominator must be fully simplified before dividing the numerator by it.
4
Perform multiplication and division from left to right.
3×9=27-3 \times 9 = -27 and 244=6\frac{24}{4} = 6
Multiplication and division have higher priority than addition and subtraction.
5
Perform the final addition.
27+6=21-27 + 6 = -21
Addition and subtraction are performed last.

Anahtar Kavram

Order of Operations (PEMDAS)
Soru 33Soru

For a positive integer nn, the greatest common factor of nn and 120120 is 1515, and the least common multiple of nn and 120120 is 360360. What is the value of nn?

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Cevap: 45

Cevap

45
The correct answer is 45. The relationship between two positive integers aa and bb and their GCF and LCM is a×b=GCF(a,b)×LCM(a,b)a \times b = \text{GCF}(a, b) \times \text{LCM}(a, b). Substituting a=na = n, b=120b = 120, GCF=15\text{GCF} = 15, and LCM=360\text{LCM} = 360 gives n×120=15×360n \times 120 = 15 \times 360. Dividing both sides of the equation by 120 yields n=45n = 45.

Adım Adım Çözüm

1
Identify the given values and the mathematical relationship between two positive integers, their greatest common factor (GCF), and their least common multiple (LCM).
Given a=na = n, b=120b = 120, GCF(n,120)=15\text{GCF}(n, 120) = 15, and LCM(n,120)=360\text{LCM}(n, 120) = 360. The relationship is a×b=GCF(a,b)×LCM(a,b)a \times b = \text{GCF}(a, b) \times \text{LCM}(a, b).
This formula provides a direct algebraic path to solve for the unknown integer when the other parameters are known.
2
Substitute the given values into the relationship formula.
n×120=15×360n \times 120 = 15 \times 360
To set up an equation containing only the unknown variable nn.
3
Isolate and solve for nn.
n=15×360120=15×3=45n = \frac{15 \times 360}{120} = 15 \times 3 = 45
To find the specific integer value of nn.

Anahtar Kavram

The product of two positive integers is equal to the product of their greatest common factor (GCF) and their least common multiple (LCM).

Alternatif Yöntem

Another way to solve this is to write the prime factorizations. Since 120=23×3×5120 = 2^3 \times 3 \times 5, and their GCF is 15=3×515 = 3 \times 5, nn must contain 3×53 \times 5 but cannot contain any factor of 2. Since their LCM is 360=23×32×5360 = 2^3 \times 3^2 \times 5, nn must contain 323^2 because 120 only has 313^1. Thus, the prime factorization of nn is 32×5=453^2 \times 5 = 45.
Tahmini Süre:1m 0s
Soru 34Soru

What is the value of the expression below?

2412+(2)3(1)5×32(2)3÷(131) \frac{-2^4 - |-12 + (-2)^3|}{(-1)^5 \times 3^2 - (-2)^3} \div \left( \frac{1}{3} - 1 \right)
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Cevap: 54-54

Cevap

54-54
Evaluating the numerator gives 36-36, and the denominator simplifies to 1-1, resulting in a fraction of 3636. Dividing 3636 by (1/31)=2/3(1/3 - 1) = -2/3 is performed by multiplying 3636 by the reciprocal 3/2-3/2, which yields the final result of 54-54.

Adım Adım Çözüm

1
Evaluate the numerator of the first fraction.
Numerator = 36-36
First, evaluate the exponent inside the absolute value: (2)3=8(-2)^3 = -8. Next, evaluate the expression inside the absolute value: 12+(8)=20-12 + (-8) = -20. Taking the absolute value gives 20=20|-20| = 20. Separately, evaluate the exponent 24=(24)=16-2^4 = -(2^4) = -16 because exponentiation has priority over negation. Finally, subtract the absolute value term from this to get 1620=36-16 - 20 = -36.
2
Evaluate the denominator of the first fraction.
Denominator = 1-1
Evaluate the exponents first: (1)5=1(-1)^5 = -1, 32=93^2 = 9, and (2)3=8(-2)^3 = -8. Then, perform the multiplication: 1×9=9-1 \times 9 = -9. Finally, perform the subtraction: 9(8)=9+8=1-9 - (-8) = -9 + 8 = -1.
3
Simplify the first fraction.
Fraction = 3636
Divide the numerator by the denominator: 361=36\frac{-36}{-1} = 36.
4
Evaluate the expression inside the divisor parentheses.
Divisor = 23-\frac{2}{3}
Perform the fraction subtraction: 131=1333=23\frac{1}{3} - 1 = \frac{1}{3} - \frac{3}{3} = -\frac{2}{3}.
5
Divide the simplified fraction by the divisor.
Final Value = 54-54
To divide by a fraction, multiply by its reciprocal: 36÷(23)=36×(32)=18×(3)=5436 \div \left(-\frac{2}{3}\right) = 36 \times \left(-\frac{3}{2}\right) = 18 \times (-3) = -54.

Anahtar Kavram

Order of Operations (PEMDAS) and Number Properties
Soru 35Soru

What is the sum of the distinct prime factors of 3030?

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Cevap: 10

Cevap

The sum of the distinct prime factors of 3030 is 1010.
The prime factorization of 3030 is 2×3×52 \times 3 \times 5. The distinct prime factors are 22, 33, and 55, and their sum is 1010.

Adım Adım Çözüm

1
Find the prime factorization of 3030.
30=2×3×530 = 2 \times 3 \times 5
To break the composite number 3030 down into its prime components.
2
Identify the distinct prime factors.
The distinct prime factors are 22, 33, and 55.
Only prime numbers that divide 3030 should be included in the sum.
3
Add the distinct prime factors.
2+3+5=102 + 3 + 5 = 10
To calculate the final sum as requested by the question.

Anahtar Kavram

Prime factorization is the process of factoring a composite number into a product of prime numbers. The distinct prime factors of a number are the unique prime numbers that divide it.
Soru 36Soru

On a standard number line, point AA is located at 7-7 and point BB is located at 55. What is the distance between point AA and point BB?

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Cevap: 12

Cevap

The distance between the two points is 12.
The distance between two points on a number line is the absolute value of their difference. Calculating 75|-7 - 5| yields 12|-12|, which is 1212. Alternatively, subtracting the lesser coordinate from the greater coordinate gives 5(7)=5+7=125 - (-7) = 5 + 7 = 12.

Adım Adım Çözüm

1
Identify the coordinates of the two points on the number line.
The coordinates are 7-7 for point AA and 55 for point BB.
These coordinates represent the positions from which we need to find the distance.
2
Apply the absolute value formula for the distance between two points, ab|a - b|.
The expression is 75|-7 - 5|.
Distance on a number line is always non-negative and is defined by the absolute value of the difference between the two coordinates.
3
Perform the subtraction and find the absolute value.
12=12|-12| = 12.
Subtracting 55 from 7-7 gives 12-12, and the absolute value of 12-12 is 1212.

Anahtar Kavram

The distance between two points aa and bb on a number line is given by ab|a - b|.
Tahmini Süre:45s
Soru 37Soru

An algebra student is simplifying the expression a(bc)d(ef)a(b - c) - d(e - f) by applying the distributive property. Instead of distributing correctly, the student incorrectly writes the expansion as a(bc)dedfa(b - c) - de - df. If a=2a = 2, b=3b = 3, c=5c = 5, d=3d = -3, e=4e = 4, and f=2f = -2, what is the absolute difference between the student's incorrect result and the correct value of the expression?

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Cevap: 12

Cevap

The correct answer is 12.
The correct expression evaluates to 14, and the incorrect expression evaluates to 2. The absolute difference between them is 142=12|14 - 2| = 12.

Adım Adım Çözüm

1
Evaluate the correct expression a(bc)d(ef)a(b - c) - d(e - f) using the given values.
14
To find the mathematically correct value of the expression.
2
Evaluate the incorrect expression a(bc)dedfa(b - c) - de - df using the same values.
2
To find the value resulting from the student's distribution error.
3
Find the absolute difference between the correct value and the incorrect value.
12
To determine the error magnitude as requested by the question.

Anahtar Kavram

Distributive Property and Order of Operations
Soru 38Soru

A student is adding the fractions 512\frac{5}{12} and 718\frac{7}{18}. What is the least common denominator they should use to add these fractions?

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Cevap: 36

Cevap

36
To find the least common denominator of the two fractions, find the least common multiple (LCM) of the denominators, 12 and 18. The prime factorization of 12 is 22×32^2 \times 3, and the prime factorization of 18 is 2×322 \times 3^2. The LCM is found by taking the highest power of each prime factor that appears in either factorization: 22×32=4×9=362^2 \times 3^2 = 4 \times 9 = 36.

Adım Adım Çözüm

1
Identify the denominators of the fractions to find their least common denominator.
The denominators are 12 and 18.
The least common denominator of two fractions is equal to the least common multiple (LCM) of their denominators.
2
Find the prime factorization of each denominator.
12=22×312 = 2^2 \times 3 and 18=2×3218 = 2 \times 3^2
Prime factorization helps systematically determine the least common multiple.
3
Calculate the least common multiple by multiplying the highest power of each prime factor present.
22×32=4×9=362^2 \times 3^2 = 4 \times 9 = 36
This yields the smallest positive integer that is divisible by both 12 and 18.

Anahtar Kavram

Finding the least common denominator by calculating the least common multiple (LCM) of the denominators.
Tahmini Süre:45s
Soru 39Soru

If xx, yy, and zz are integers such that 5x<y<z5-5 \leq x < y < z \leq 5, what is the minimum possible value of the expression (xy)2z(yx)xyz(x - y)^2 - z(y - x) - |x| \cdot |y - z|?

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Cevap: -49

Cevap

The minimum possible value of the expression is 49-49.
The correct value is 49-49. By setting d1=yx1d_1 = y - x \geq 1 and d2=zy1d_2 = z - y \geq 1, we can rewrite the expression as d12zd1xd2d_1^2 - z d_1 - |x| d_2. Substituting z=x+d1+d2z = x + d_1 + d_2 gives xd1d2(d1+x)-x d_1 - d_2(d_1 + |x|). To minimize this, we choose the smallest possible value for xx, which is 5-5. This gives 5d1d2(d1+5)5d_1 - d_2(d_1 + 5). Since x=5x = -5 and z5z \leq 5, we have d1+d210d_1 + d_2 \leq 10. Substituting d2=10d1d_2 = 10 - d_1 yields 5d1(10d1)(d1+5)=d12505d_1 - (10 - d_1)(d_1 + 5) = d_1^2 - 50. The minimum value of this quadratic expression for integer d11d_1 \geq 1 occurs at d1=1d_1 = 1, giving 1250=491^2 - 50 = -49. This corresponds to x=5,y=4,z=5x = -5, y = -4, z = 5. Evaluating the expression directly confirms this result: (5(4))25(4(5))545=1545=49(-5 - (-4))^2 - 5(-4 - (-5)) - |-5| \cdot |-4 - 5| = 1 - 5 - 45 = -49.

Adım Adım Çözüm

1
Define variables for the differences between the ordered integers.
Let d1=yx1d_1 = y - x \geq 1 and d2=zy1d_2 = z - y \geq 1, which implies y=x+d1y = x + d_1 and z=x+d1+d2z = x + d_1 + d_2.
Using differences simplifies the inequality constraints and allows us to express the objective function in terms of positive integers d1d_1 and d2d_2.
2
Substitute the differences into the given expression (xy)2z(yx)xyz(x - y)^2 - z(y - x) - |x| \cdot |y - z|.
The expression becomes d12(x+d1+d2)d1xd2=xd1d2(d1+x)d_1^2 - (x + d_1 + d_2)d_1 - |x|d_2 = -x d_1 - d_2(d_1 + |x|).
This rewrites the expression in terms of the initial variable xx and the positive differences d1d_1 and d2d_2.
3
Analyze how to minimize xd1d2(d1+x)-x d_1 - d_2(d_1 + |x|) given the boundaries.
Setting x=5x = -5 makes the expression 5d1d2(d1+5)5d_1 - d_2(d_1 + 5). Since x=5x = -5 and z5z \leq 5, we have d1+d210d_1 + d_2 \leq 10.
Choosing the minimum value for xx maximizes the positive coefficient of d1d_1 and the term x|x| in the negative product, leading to the smallest possible value.
4
Maximize d2d_2 by setting d2=10d1d_2 = 10 - d_1 and substitute it into the expression.
The expression becomes 5d1(10d1)(d1+5)=d12505d_1 - (10 - d_1)(d_1 + 5) = d_1^2 - 50.
Since d2d_2 has a negative coefficient, maximizing d2d_2 minimizes the overall expression.
5
Minimize d1250d_1^2 - 50 subject to d11d_1 \geq 1.
The minimum occurs at d1=1d_1 = 1, yielding 1250=491^2 - 50 = -49, which corresponds to x=5,y=4,z=5x = -5, y = -4, z = 5.
Since d12d_1^2 is strictly increasing for positive integers, the minimum value of the quadratic is achieved at the smallest boundary value of d1d_1.

Anahtar Kavram

Order of Operations and Number Properties
Soru 40Soru

Given the algebraic expression A=xy×z2A = x - y \times z^2, evaluate the expression for each of the following sets of values for (x,y,z)(x, y, z) and arrange the sets in order of their resulting values of AA from least to greatest.

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Cevap

The correct order of the sets from least to greatest is: (x,y,z)=(5,1,2)(x, y, z) = (-5, 1, 2) resulting in 9-9, followed by (x,y,z)=(2,3,1)(x, y, z) = (-2, 3, -1) resulting in 5-5, then (x,y,z)=(8,4,0)(x, y, z) = (8, 4, 0) resulting in 88, and finally (x,y,z)=(4,2,3)(x, y, z) = (4, -2, 3) resulting in 2222.
The correct order follows from evaluating the algebraic expression for each set of values according to the order of operations (PEMDAS): exponentiation first, then multiplication, and finally subtraction. This yields values of 9-9, 5-5, 88, and 2222, which are ordered from least to greatest.

Adım Adım Çözüm

1
Evaluate the expression A=xy×z2A = x - y \times z^2 for the set (x,y,z)=(5,1,2)(x, y, z) = (-5, 1, 2).
A=9A = -9
According to the order of operations, evaluate the exponent first: 22=42^2 = 4. Then perform multiplication: 1×4=41 \times 4 = 4. Finally, perform subtraction: 54=9-5 - 4 = -9.
2
Evaluate the expression A=xy×z2A = x - y \times z^2 for the set (x,y,z)=(2,3,1)(x, y, z) = (-2, 3, -1).
A=5A = -5
Evaluate the exponent first: (1)2=1(-1)^2 = 1. Next, multiply: 3×1=33 \times 1 = 3. Finally, subtract: 23=5-2 - 3 = -5.
3
Evaluate the expression A=xy×z2A = x - y \times z^2 for the set (x,y,z)=(8,4,0)(x, y, z) = (8, 4, 0).
A=8A = 8
Evaluate the exponent first: 02=00^2 = 0. Next, multiply: 4×0=04 \times 0 = 0. Finally, subtract: 80=88 - 0 = 8.
4
Evaluate the expression A=xy×z2A = x - y \times z^2 for the set (x,y,z)=(4,2,3)(x, y, z) = (4, -2, 3).
A=22A = 22
Evaluate the exponent first: 32=93^2 = 9. Next, multiply: 2×9=18-2 \times 9 = -18. Finally, subtract: 4(18)=4+18=224 - (-18) = 4 + 18 = 22.
5
Arrange the resulting values from least to greatest.
9<5<8<22-9 < -5 < 8 < 22
Comparing the four calculated values shows that 9-9 is the least, followed by 5-5, then 88, and 2222 is the greatest.

Anahtar Kavram

Order of Operations (PEMDAS)

Alternatif Yöntem

To verify the calculations, substitute each set of coordinates carefully, using parentheses around negative values. Evaluate each term step-by-step: first compute z2z^2, then multiply by yy, and finally subtract this result from xx.
Tahmini Süre:1m 30s
ÖncekiSayfa 2 / 21Sonraki
Pre-Algebra Alıştırma Soruları — ACT — Sayfa 2 | Examkin