Pre-Algebra

419 soru

Soru 41Soru

The prime factorization of a positive integer NN is 2a×3b×5c2^a \times 3^b \times 5^c, where aa, bb, and cc are positive integers. If NN has exactly 1212 distinct positive factors, what is the least possible value of NN?

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Cevap: 60

Cevap

60
The number of distinct positive factors of N=2a×3b×5cN = 2^a \times 3^b \times 5^c is given by the formula (a+1)(b+1)(c+1)(a+1)(b+1)(c+1). Given that NN has exactly 1212 positive factors and a,b,ca, b, c are positive integers (each at least 11), we must factor 1212 into three integers that are each at least 22. The only way to do this is 2×2×32 \times 2 \times 3. This means the set of exponents {a,b,c}\{a, b, c\} must be {1,1,2}\{1, 1, 2\}. To minimize the value of NN, we pair the largest exponent 22 with the smallest prime base 22, and the exponents of 11 with the prime bases 33 and 55. This yields the minimum value 22×31×51=602^2 \times 3^1 \times 5^1 = 60.

Adım Adım Çözüm

1
Determine the formula for the number of positive factors of NN.
The number of positive factors is (a+1)(b+1)(c+1)=12(a+1)(b+1)(c+1) = 12.
For any integer expressed as a product of prime powers, the number of positive factors is the product of each exponent increased by 1.
2
Find the possible values for the exponents aa, bb, and cc.
Since a,b,c1a, b, c \ge 1, we must have a+12a+1 \ge 2, b+12b+1 \ge 2, and c+12c+1 \ge 2. The only factorization of 1212 into three integers each at least 22 is 2×2×32 \times 2 \times 3. Thus, the exponents {a,b,c}\{a, b, c\} must be {1,1,2}\{1, 1, 2\} in some order.
We must find a set of integer values for the exponents that satisfy the factor count constraint.
3
Minimize the value of NN by assigning exponents to the prime bases.
Assign the largest exponent (22) to the smallest base (22), and the smaller exponents (11) to the larger bases (33 and 55). This gives a=2,b=1,c=1a=2, b=1, c=1, so N=22×31×51=60N = 2^2 \times 3^1 \times 5^1 = 60.
To minimize the total product, the largest power must be applied to the smallest base.

Anahtar Kavram

Finding the number of factors of a positive integer using its prime factorization.
Tahmini Süre:1m 15s
Soru 42Soru

What is the value of the expression 15+7-|-15 + 7|?

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Cevap: 8-8

Cevap

8-8
To find the value of 15+7-|-15 + 7|, we first evaluate the expression inside the absolute value bars: 15+7=8-15 + 7 = -8. Next, we take the absolute value of that result: 8=8|-8| = 8. Finally, we apply the negative sign that is outside the absolute value bars, which gives 8-8.

Adım Adım Çözüm

1
Evaluate the expression inside the absolute value bars.
15+7=8-15 + 7 = -8
Before applying the absolute value, the terms inside the vertical bars must be simplified according to the order of operations.
2
Find the absolute value of the result from Step 1.
8=8|-8| = 8
The absolute value of a number represents its distance from zero on a number line, which is always non-negative.
3
Apply the negative sign that is outside the absolute value bars.
(8)=8- (8) = -8
The negative sign outside acts as multiplication by 1-1 after the absolute value has been evaluated.

Anahtar Kavram

Evaluating expressions involving absolute values and negative numbers
Soru 43Soru

Let SS be the set of all positive integers nn such that the least common multiple of nn and 4040 is 360360, and the greatest common divisor of nn and 100100 is a prime number. What is the sum of all possible values of nn in set SS?

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Cevap: 63

Cevap

63
To find the sum of all possible values of nn, we first analyze the prime factorizations: 40=23×540 = 2^3 \times 5 and 360=23×32×5360 = 2^3 \times 3^2 \times 5. The least common multiple of nn and 4040 is 360360, meaning nn must be of the form 2a×32×5c2^a \times 3^2 \times 5^c where 0a30 \le a \le 3 and 0c10 \le c \le 1. Testing the candidate values against the condition that GCD(n,100)\text{GCD}(n, 100) must be a prime number (where 100=22×52100 = 2^2 \times 5^2) reveals that only n=18n = 18 (with GCF of 22) and n=45n = 45 (with GCF of 55) satisfy the conditions. The sum of these values is 18+45=6318 + 45 = 63.

Adım Adım Çözüm

1
Find the prime factorizations of the given numbers: 4040 and 360360.
40=23×540 = 2^3 \times 5 and 360=23×32×5360 = 2^3 \times 3^2 \times 5.
Expressing the numbers in their prime factorizations helps determine the required prime factors of nn to satisfy the least common multiple condition.
2
Determine the constraints on the prime factorization of nn based on LCM(n,40)=360\text{LCM}(n, 40) = 360.
nn must be of the form 2a×32×5c2^a \times 3^2 \times 5^c, where 0a30 \le a \le 3 and 0c10 \le c \le 1.
Since the least common multiple is the product of the highest powers of all prime factors present in either number, nn must provide 323^2 (as 4040 has 303^0), can have 2a2^a up to 232^3, and can have 5c5^c up to 515^1.
3
List all 8 possible candidate values for nn.
For c=0c=0: n{9,18,36,72}n \in \{9, 18, 36, 72\}. For c=1c=1: n{45,90,180,360}n \in \{45, 90, 180, 360\}.
Evaluating all combinations of the exponents aa and cc generates the complete list of candidates.
4
Calculate the greatest common divisor of each candidate nn with 100=22×52100 = 2^2 \times 5^2, and check if the result is prime.
GCD(9,100)=1\text{GCD}(9, 100) = 1 (not prime); GCD(18,100)=2\text{GCD}(18, 100) = 2 (prime); GCD(36,100)=4\text{GCD}(36, 100) = 4 (not prime); GCD(72,100)=4\text{GCD}(72, 100) = 4 (not prime); GCD(45,100)=5\text{GCD}(45, 100) = 5 (prime); GCD(90,100)=10\text{GCD}(90, 100) = 10 (not prime); GCD(180,100)=20\text{GCD}(180, 100) = 20 (not prime); GCD(360,100)=20\text{GCD}(360, 100) = 20 (not prime). The valid values for nn are 1818 and 4545.
Only n=18n = 18 and n=45n = 45 satisfy the condition that their greatest common divisor with 100100 is a prime number (22 and 55, respectively).
5
Calculate the sum of the possible values of nn.
18+45=6318 + 45 = 63.
Summing the identified valid values yields the final answer.

Anahtar Kavram

Determining possible values of an unknown integer using prime factorization constraints from least common multiple (LCM) and greatest common divisor (GCD) conditions.
Soru 44Soru

A positive integer nn has exactly two distinct prime factors, pp and qq, such that p+q=12p + q = 12. If nn has exactly 8 positive factors, what is the least possible value of nn?

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Cevap: 875

Cevap

875
The prime factors of the number must be 5 and 7 since they are the only prime numbers that sum to 12. For a number with prime factorization 5a×7b5^a \times 7^b, the number of factors is (a+1)(b+1)=8(a+1)(b+1) = 8. Since both prime factors must be present, the exponents must be 1 and 3. The two possible numbers are 53×71=8755^3 \times 7^1 = 875 and 51×73=1,7155^1 \times 7^3 = 1,715. The least value is 875.

Adım Adım Çözüm

1
Find the two prime numbers pp and qq that sum to 12.
The prime factors are 5 and 7.
Since pp and qq are prime and p+q=12p + q = 12, we test pairs of positive integers. The only pair of prime numbers that sums to 12 is 5 and 7.
2
Express the number of factors of nn using the prime factorization formula.
The number of factors is (a+1)(b+1)=8(a + 1)(b + 1) = 8.
For any positive integer n=pa×qbn = p^a \times q^b, the number of positive factors is given by the formula (a+1)(b+1)(a + 1)(b + 1).
3
Determine the possible values for the exponents aa and bb.
The set of exponents {a,b}\{a, b\} must be {1,3}\{1, 3\}.
Since nn must contain both prime factors, a1a \ge 1 and b1b \ge 1, which means (a+1)2(a + 1) \ge 2 and (b+1)2(b + 1) \ge 2. The only factor pair of 8 where both factors are at least 2 is 2×42 \times 4. Thus, one exponent must be 1 and the other must be 3.
4
Calculate the possible values of nn and identify the least value.
The least value is 875.
The two possible values for nn are 53×71=125×7=8755^3 \times 7^1 = 125 \times 7 = 875 and 51×73=5×343=1,7155^1 \times 7^3 = 5 \times 343 = 1,715. The least possible value is 875.

Anahtar Kavram

Factors, Multiples, and Prime Factorization
Soru 45Soru

What is the least common multiple of 1515 and 2020?

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Cevap: 60

Cevap

The least common multiple of 1515 and 2020 is 6060.
The correct answer is 6060. The least common multiple is the smallest positive integer that is divisible by both 1515 and 2020. By listing multiples or using prime factorization (22×3×52^2 \times 3 \times 5), we arrive at 6060.

Adım Adım Çözüm

1
Find the prime factorization of 1515 and 2020.
15=3×515 = 3 \times 5 and 20=22×520 = 2^2 \times 5.
Decomposing numbers into their prime factors makes it straightforward to compute their least common multiple.
2
Identify the highest exponent for each prime factor appearing in the prime factorizations.
The prime factors present are 22, 33, and 55. The highest powers are 222^2, 313^1, and 515^1.
The least common multiple must contain all prime factors of both numbers at their maximum frequency to be divisible by both.
3
Calculate the product of these highest powers of the prime factors.
22×3×5=4×3×5=602^2 \times 3 \times 5 = 4 \times 3 \times 5 = 60.
Multiplying these factors yields the smallest positive integer that is a multiple of both original numbers.

Anahtar Kavram

Least Common Multiple (LCM)
Tahmini Süre:45s
Soru 46Soru

Two cyclists, Alan and Beatrice, begin riding laps around a circular track at the same time, starting from the same line and traveling in the same direction. Alan completes one lap every 40 seconds, and Beatrice completes one lap every 50 seconds. What is the number of laps Beatrice will have completed the next time they both cross the starting line at the same instant?

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Cevap: 4

Cevap

Beatrice will have completed 4 laps.
The correct answer is 4. The two cyclists will meet at the starting line after a period of time that is a multiple of both of their lap times. The first time they meet after starting is the least common multiple (LCM) of 40 and 50, which is 200 seconds. Dividing the total time of 200 seconds by Beatrice's lap time of 50 seconds yields 4 laps.

Adım Adım Çözüm

1
Find the prime factorizations of both lap times to determine their least common multiple (LCM).
The prime factorization of 40 is 23×512^3 \times 5^1, and the prime factorization of 50 is 21×522^1 \times 5^2.
They will cross the starting line together at times that are common multiples of their individual lap times.
2
Calculate the LCM by taking the highest power of each prime factor present in either factorization.
LCM(40,50)=23×52=8×25=200\text{LCM}(40, 50) = 2^3 \times 5^2 = 8 \times 25 = 200 seconds.
The least common multiple represents the minimum amount of time that must pass before both cyclists reach the starting line at the same time.
3
Divide the total time elapsed by Beatrice's time per lap to find the number of laps she completes.
200 seconds÷50 seconds per lap=4200 \text{ seconds} \div 50 \text{ seconds per lap} = 4 laps.
This converts the total time until they meet into the number of laps completed specifically by Beatrice.

Anahtar Kavram

Least Common Multiple (LCM) and rate calculations
Tahmini Süre:1m 0s
Soru 47Soru

If the mathematical expression below is simplified using the standard order of operations, what is the result?

126÷2×3+42 12 - 6 \div 2 \times 3 + 4^2
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Cevap: 19

Cevap

The correct result of the expression is 19.
The correct value is obtained by first evaluating the exponent (42=164^2 = 16), then performing the division and multiplication from left to right (6÷2=36 \div 2 = 3, followed by 3×3=93 \times 3 = 9), and finally performing the subtraction and addition from left to right (129=312 - 9 = 3, followed by 3+16=193 + 16 = 19).

Adım Adım Çözüm

1
Evaluate the exponent term.
42=164^2 = 16
Exponents must be evaluated before multiplication, division, addition, and subtraction.
2
Perform multiplication and division from left to right.
6÷2×3=3×3=96 \div 2 \times 3 = 3 \times 3 = 9
Multiplication and division have equal precedence, so they are processed in order from left to right.
3
Perform addition and subtraction from left to right.
129+16=3+16=1912 - 9 + 16 = 3 + 16 = 19
Addition and subtraction have equal precedence, so they are processed in order from left to right.

Anahtar Kavram

Order of Operations (PEMDAS)
Soru 48Soru

For all real numbers aa and bb, which of the following expressions is equivalent to ab[a(ba)]b2a - b[a - (b - a)] - b^2?

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Cevap: a2aba - 2ab

Cevap

The expression a2aba - 2ab
To simplify the expression, we begin inside the innermost grouping symbols (the parentheses) and work outward. First, we distribute the negative sign to simplify the term inside the brackets: a(ba)=ab+a=2aba - (b - a) = a - b + a = 2a - b. Next, we distribute the b-b term outside the brackets to get b(2ab)=2ab+b2-b(2a - b) = -2ab + b^2. Substituting this back into the main expression gives a2ab+b2b2a - 2ab + b^2 - b^2. Combining the like terms b2b2=0b^2 - b^2 = 0 simplifies the expression to a2aba - 2ab.

Adım Adım Çözüm

1
Simplify the expression inside the brackets by distributing the negative sign across the parentheses.
a(ba)=ab+a=2aba - (b - a) = a - b + a = 2a - b
According to the order of operations, terms inside parentheses must be simplified first.
2
Substitute the simplified bracket expression back into the main expression.
ab[2ab]b2a - b[2a - b] - b^2
This sets up the expression for the next operation, which is multiplication.
3
Distribute the term b-b across the bracketed expression.
b(2ab)=2ab+b2-b(2a - b) = -2ab + b^2
Multiplication must be performed before subtraction. Multiplying two negative signs yields a positive term.
4
Combine the distributed terms back into the full expression and simplify like terms.
a2ab+b2b2=a2aba - 2ab + b^2 - b^2 = a - 2ab
Combining the positive and negative b2b^2 terms results in 00, leaving the fully simplified expression.

Anahtar Kavram

Order of Operations and Number Properties

Alternatif Yöntem

Instead of simplifying algebraically, you can substitute simple numbers for aa and bb. Let a=2a = 2 and b=3b = 3. Evaluating the original expression: 23[2(32)]32=23[21]9=23(1)9=102 - 3[2 - (3 - 2)] - 3^2 = 2 - 3[2 - 1] - 9 = 2 - 3(1) - 9 = -10. Substituting a=2a = 2 and b=3b = 3 into the correct option a2aba - 2ab gives 22(2)(3)=212=102 - 2(2)(3) = 2 - 12 = -10. This numerical substitution confirms the correct algebraic simplification.
Tahmini Süre:1m 30s
Soru 49Soru

What is the value of the mathematical expression below?

32+4×[183×(84)]÷2 -3^2 + 4 \times [18 - 3 \times (8 - 4)] \div 2
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Cevap: 3

Cevap

The correct value of the expression is 3.
Following the standard order of operations, we first simplify the nested parentheses (84)=4(8 - 4) = 4. Next, we evaluate the expression inside the brackets [183×4]=[1812]=6[18 - 3 \times 4] = [18 - 12] = 6. We then evaluate the exponent 32=9-3^2 = -9. We perform the multiplication and division from left to right: 4×6÷2=124 \times 6 \div 2 = 12. Finally, adding 9+12-9 + 12 yields the correct result of 3.

Adım Adım Çözüm

1
Simplify the innermost parentheses.
32+4×[183×4]÷2-3^2 + 4 \times [18 - 3 \times 4] \div 2
According to the order of operations (PEMDAS), operations inside parentheses or grouping symbols must be performed first.
2
Simplify the expression inside the square brackets by performing multiplication before subtraction.
32+4×6÷2-3^2 + 4 \times 6 \div 2
Multiplication has a higher precedence than subtraction.
3
Evaluate the exponent 32-3^2.
9+4×6÷2-9 + 4 \times 6 \div 2
The exponent applies only to the base 3, not to the negative sign, because there are no parentheses around 3-3.
4
Perform multiplication and division from left to right.
9+12-9 + 12
Multiplication and division have the same precedence and must be evaluated in order from left to right.
5
Add the remaining values.
33
Addition is the final operation to perform.

Anahtar Kavram

Order of operations (PEMDAS) dictates the sequence in which operations must be performed to evaluate an expression: Parentheses/Brackets, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).
Soru 50Soru

What is the value of the expression 12715|-12| - |7 - 15|?

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Cevap: 4

Cevap

The value of the expression is 4.
The absolute value of a number represents its distance from zero on a number line, so 12=12|-12| = 12. Simplifying inside the second term gives 715=87 - 15 = -8, and the absolute value 8=8|-8| = 8. Subtracting these two results yields 128=412 - 8 = 4.

Adım Adım Çözüm

1
Evaluate the first term
12=12|-12| = 12
The absolute value of a number is its distance from zero on the number line, which is always non-negative.
2
Simplify the expression inside the second absolute value
715=87 - 15 = -8
Subtracting 15 from 7 yields a negative difference of -8.
3
Evaluate the second absolute value term
8=8|-8| = 8
The absolute value of -8 is 8.
4
Subtract the two evaluated terms
128=412 - 8 = 4
Subtracting 8 from 12 gives the final simplified value of 4.

Anahtar Kavram

Evaluating expressions with absolute values requires simplifying the terms inside the absolute value grouping symbols first, taking the absolute value of the result, and then performing the subtraction.
Soru 51Soru

A positive integer NN has the prime factorization N=2a×3b×5cN = 2^a \times 3^b \times 5^c, where aa, bb, and cc are positive integers. The greatest common divisor of NN and 360360 has exactly 1212 positive factors, and the least common multiple of NN and 360360 has exactly 7272 positive factors. How many positive factors does NN have?

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Cevap: 36

Cevap

The positive integer NN has exactly 36 positive factors.
By writing the prime factorization of 360360 as 23×32×512^3 \times 3^2 \times 5^1 and expressing the GCD and LCM of NN and 360360 in terms of the minimum and maximum exponents of their prime factors, we establish a system of equations for the exponents. Solving this system yields two cases: either a=2a = 2, b=1b = 1, and c=5c = 5, or a=1a = 1 with (b+1)(c+1)=18(b + 1)(c + 1) = 18. In both cases, the formula for the number of positive factors of NN, which is (a+1)(b+1)(c+1)(a + 1)(b + 1)(c + 1), evaluates to exactly 36.

Adım Adım Çözüm

1
Find the prime factorization of 360360.
360=23×32×51360 = 2^3 \times 3^2 \times 5^1.
This allows us to write the greatest common divisor (GCD) and least common multiple (LCM) of NN and 360360 in terms of their prime factors.
2
Express the number of factors of GCD(N,360)\text{GCD}(N, 360) using the minimum exponents.
(min(a,3)+1)(min(b,2)+1)(min(c,1)+1)=12(\min(a, 3) + 1)(\min(b, 2) + 1)(\min(c, 1) + 1) = 12. Since c1c \ge 1, we have min(c,1)=1\min(c, 1) = 1, which simplifies the equation to (min(a,3)+1)(min(b,2)+1)=6(\min(a, 3) + 1)(\min(b, 2) + 1) = 6.
The GCD of two numbers is found by taking the minimum of their exponents for each prime factor.
3
Solve for the possible values of aa and bb from the GCD factor equation.
Since a,b1a, b \ge 1, the only integer pairs for the factors of 66 are: Case 1: a=2a = 2 and b=1b = 1, or Case 2: a=1a = 1 and b2b \ge 2.
We analyze the possible values of min(a,3)\min(a, 3) and min(b,2)\min(b, 2) that multiply to 66 under the constraints a,b1a, b \ge 1.
4
Apply the LCM condition to find the number of factors of NN for both cases.
For Case 1: LCM(N,360)\text{LCM}(N, 360) has factors count (3+1)(2+1)(c+1)=72    c=5(3+1)(2+1)(c+1) = 72 \implies c = 5, giving d(N)=(2+1)(1+1)(5+1)=36d(N) = (2+1)(1+1)(5+1) = 36. For Case 2: LCM(N,360)\text{LCM}(N, 360) has factors count (3+1)(b+1)(c+1)=72    (b+1)(c+1)=18(3+1)(b+1)(c+1) = 72 \implies (b+1)(c+1) = 18, giving d(N)=(1+1)(b+1)(c+1)=2×18=36d(N) = (1+1)(b+1)(c+1) = 2 \times 18 = 36.
The LCM uses the maximum of the exponents, which allows us to relate the remaining unknown exponents to the total factor count.

Anahtar Kavram

Factors, Multiples, and Prime Factorization
Soru 52Soru

For all real numbers xx and yy, two custom operations, \oplus and \otimes, are defined as follows:

xy=x+y1x \oplus y = x + y - 1
xy=xyxy+2x \otimes y = xy - x - y + 2

Which of the following statements about these operations must be true for all real numbers aa, bb, and cc?

I. a(bc)=(ab)ca \oplus (b \oplus c) = (a \oplus b) \oplus c
II. ab=baa \otimes b = b \otimes a
III. a(bc)=(ab)(ac)a \otimes (b \oplus c) = (a \otimes b) \oplus (a \otimes c)

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Cevap: I, II, and III

Cevap

The statement containing all three Roman numerals, I, II, and III, is correct because the associative, commutative, and distributive properties all hold true under these custom definitions.
All three statements are true. First, the operation \oplus is associative because both a(bc)a \oplus (b \oplus c) and (ab)c(a \oplus b) \oplus c simplify to a+b+c2a + b + c - 2. Second, the operation \otimes is commutative because ab=abab+2a \otimes b = ab - a - b + 2 and ba=baba+2b \otimes a = ba - b - a + 2 are algebraically identical. Third, the operation \otimes distributes over \oplus because both a(bc)a \otimes (b \oplus c) and (ab)(ac)(a \otimes b) \oplus (a \otimes c) simplify to ab+ac2abc+3ab + ac - 2a - b - c + 3. Therefore, the statement including all three Roman numerals is correct.

Adım Adım Çözüm

1
Evaluate Statement I for associativity by expanding a(bc)a \oplus (b \oplus c) and (ab)c(a \oplus b) \oplus c.
Both expressions simplify to a+b+c2a + b + c - 2.
Since both groupings yield the same algebraic expression, the operation \oplus is associative.
2
Evaluate Statement II for commutativity by comparing aba \otimes b and bab \otimes a.
ab=abab+2a \otimes b = ab - a - b + 2 and ba=baba+2b \otimes a = ba - b - a + 2.
Since multiplication and addition of real numbers are commutative (ab=baab = ba and ab=ba-a - b = -b - a), the two expressions are equal, meaning the operation \otimes is commutative.
3
Evaluate Statement III for distributivity by expanding both sides of a(bc)=(ab)(ac)a \otimes (b \oplus c) = (a \otimes b) \oplus (a \otimes c).
The left side expands to ab+ac2abc+3ab + ac - 2a - b - c + 3. The right side also expands to ab+ac2abc+3ab + ac - 2a - b - c + 3.
Because both sides simplify to the exact same expression, the operation \otimes distributes over \oplus.

Anahtar Kavram

Testing the definitions of the commutative, associative, and distributive properties using custom operations.
Soru 53Soru

A teacher has a bag of marbles to distribute to a class. If the marbles are divided equally among 88 students, there are 66 marbles left over. If the marbles are divided equally among 99 students, there are 77 marbles left over. What is the least possible number of marbles in the bag?

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Cevap: 70

Cevap

The least possible number of marbles in the bag is 70.
The correct answer is 70. The problem describes a situation where the number of marbles, NN, leaves a remainder of 66 when divided by 88, and a remainder of 77 when divided by 99. This means N+2N + 2 is a multiple of both 88 and 99. The smallest positive integer that is a multiple of both 88 and 99 is their least common multiple, which is 7272. Therefore, N+2=72N + 2 = 72, which gives N=70N = 70.

Adım Adım Çözüm

1
Analyze the relationship between the divisors and their respective remainders.
For divisor 88, the remainder is 66, which is 86=28 - 6 = 2 less than the divisor. For divisor 99, the remainder is 77, which is 97=29 - 7 = 2 less than the divisor. Therefore, adding 22 to the total number of marbles creates a number that is exactly divisible by both 88 and 99.
This establishes that the target number plus 22 must be a common multiple of the two divisors.
2
Calculate the least common multiple (LCM) of the divisors 88 and 99.
The prime factorization of 88 is 232^3 and of 99 is 323^2. The LCM is the product of the highest powers of all prime factors involved: 23×32=8×9=722^3 \times 3^2 = 8 \times 9 = 72.
To find the smallest positive common multiple of 88 and 99.
3
Subtract 22 from the LCM to find the least possible number of marbles.
722=7072 - 2 = 70.
Since the bag is 22 marbles short of having a multiple of both 88 and 99, we subtract 22 from the least common multiple.

Anahtar Kavram

Least Common Multiple (LCM) application with remainders
Soru 54Soru

A woodworker has two wooden boards. One board is 4242 inches long, and the other is 7070 inches long. She wants to cut both boards into shorter pieces of equal length, with no wood left over. What is the greatest possible length, in inches, of each shorter piece?

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Cevap: 14

Cevap

14
To find the greatest possible length of the pieces, we need to find the greatest common factor (GCF) of the two board lengths, 4242 and 7070. The prime factorization of 4242 is 2×3×72 \times 3 \times 7, and the prime factorization of 7070 is 2×5×72 \times 5 \times 7. The common prime factors are 22 and 77. Multiplying these common prime factors gives the GCF: 2×7=142 \times 7 = 14. Therefore, the greatest possible length of each piece is 1414 inches.

Adım Adım Çözüm

1
Identify the mathematical concept needed to solve the problem.
Since we need to cut two boards of lengths 4242 and 7070 into equal shorter pieces with no left over wood, we need to find a common factor of 4242 and 7070. To find the greatest possible length, we must calculate their Greatest Common Factor (GCF).
This translates the word problem into a clear mathematical operation.
2
Find the prime factorizations of both numbers.
42=2×3×742 = 2 \times 3 \times 7 and 70=2×5×770 = 2 \times 5 \times 7.
Prime factorization helps systematically identify all factors of the two numbers.
3
Determine the common prime factors and multiply them.
The common prime factors are 22 and 77. Multiplying them gives 2×7=142 \times 7 = 14.
The GCF is the product of all shared prime factors.

Anahtar Kavram

Greatest Common Factor (GCF)
Soru 55Soru

Let f(n)f(n) represent the number of positive factors of a positive integer nn. If n=2x×3yn = 2^x \times 3^y, where xx and yy are positive integers such that x+y=7x + y = 7, what is the maximum possible value of f(n)f(n)?

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Cevap: 20

Cevap

The maximum possible value of f(n)f(n) is 2020.
The number of positive factors of n=2x×3yn = 2^x \times 3^y is (x+1)(y+1)(x + 1)(y + 1). Since xx and yy are positive integers that sum to 7, the possible pairs for (x,y)(x, y) are (1,6)(1, 6), (2,5)(2, 5), and (3,4)(3, 4) (and their reversals). The products (x+1)(y+1)(x+1)(y+1) for these pairs are 2×7=142 \times 7 = 14, 3×6=183 \times 6 = 18, and 4×5=204 \times 5 = 20. The maximum value is 20.

Adım Adım Çözüm

1
Determine the formula for the number of factors of nn.
f(n)=(x+1)(y+1)f(n) = (x + 1)(y + 1)
For any positive integer expressed in its prime factorization pa×qbp^a \times q^b, the total number of positive factors is (a+1)(b+1)(a + 1)(b + 1).
2
Identify the possible values for xx and yy given the constraints.
(x,y){(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)}(x, y) \in \{(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)\}
The exponents xx and yy must be positive integers (x,y1x, y \geq 1) that sum to 7.
3
Calculate (x+1)(y+1)(x + 1)(y + 1) for each pair to find the maximum product.
The maximum product is 4×5=204 \times 5 = 20.
Evaluating the products: 2×7=142 \times 7 = 14, 3×6=183 \times 6 = 18, and 4×5=204 \times 5 = 20. The product of two integers with a fixed sum is maximized when the integers are as close as possible.

Anahtar Kavram

Calculating the number of positive factors of an integer from its prime factorization and maximizing the count under exponent constraints.
Tahmini Süre:1m 30s
Soru 56Soru

The temperature at the top of a mountain is 14C-14^\circ\text{C}, and the temperature at the base of the mountain is 8C8^\circ\text{C}. What is the absolute difference, in degrees Celsius, between these two temperatures?

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Cevap: 22

Cevap

22
The correct answer is 22 because the absolute difference between 88 and 14-14 is 8(14)=8+14=22=22|8 - (-14)| = |8 + 14| = |22| = 22. This represents the total distance of 22 units between the two temperatures on a number line.

Adım Adım Çözüm

1
Translate the problem into a mathematical expression using absolute value for the difference between the two temperatures.
The absolute difference is given by 8(14)|8 - (-14)| or 148|-14 - 8|.
The absolute difference between two numbers aa and bb on a number line is defined as ab|a - b|.
2
Simplify the subtraction inside the absolute value.
8(14)=8+14=228 - (-14) = 8 + 14 = 22 (or 148=22-14 - 8 = -22).
Subtracting a negative number is equivalent to adding its positive counterpart.
3
Evaluate the absolute value.
22=22|22| = 22 (or 22=22|-22| = 22).
The absolute value of a number represents its non-negative distance from zero.

Anahtar Kavram

Integers, Absolute Value, and Number Lines
Tahmini Süre:45s
Soru 57Soru

Four mathematical expressions are shown below:

* Expression 1: 3212÷3×2-3^2 - 12 \div 3 \times 2
* Expression 2: 42×3+(2)3-| -4 - 2 \times 3 | + (-2)^3
* Expression 3: 43(232)4 - 3(2 - 3^2)
* Expression 4: 24÷8×(11)2-2^4 \div 8 \times (-1 - 1)^2

Order the expressions by their simplified numerical values from least to greatest.

Öğeleri doğru sıraya koymak için sürükleyin

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Cevap

The correct order of the expressions from least to greatest value is Expression 2, Expression 1, Expression 4, and Expression 3.
Evaluating each expression using the correct order of operations yields: Expression 1 equals 17-17, Expression 2 equals 18-18, Expression 3 equals 2525, and Expression 4 equals 8-8. Arranging these values from least to greatest results in 18<17<8<25-18 < -17 < -8 < 25, corresponding to the sequence: Expression 2, Expression 1, Expression 4, Expression 3.

Adım Adım Çözüm

1
Evaluate Expression 1.
17-17
Apply the order of operations: first evaluate the exponent 32=9-3^2 = -9. Next, perform multiplication and division from left to right: 12÷3=412 \div 3 = 4, and 4×2=84 \times 2 = 8. Finally, perform the subtraction: 98=17-9 - 8 = -17.
2
Evaluate Expression 2.
18-18
Simplify inside the absolute value first by performing multiplication before subtraction: 2×3=62 \times 3 = 6, and 46=10-4 - 6 = -10. The absolute value of 10-10 is 1010, which becomes 10-10 due to the negative sign outside. Next, evaluate the exponent: (2)3=8(-2)^3 = -8. Finally, add the terms: 10+(8)=18-10 + (-8) = -18.
3
Evaluate Expression 3.
25
Simplify inside the parentheses first, evaluating the exponent before subtracting: 32=93^2 = 9, and 29=72 - 9 = -7. Next, perform the multiplication: 3×(7)=213 \times (-7) = -21. Finally, subtract: 4(21)=4+21=254 - (-21) = 4 + 21 = 25.
4
Evaluate Expression 4.
8-8
Simplify the expression inside the parentheses: 11=2-1 - 1 = -2. Next, evaluate the exponents: 24=16-2^4 = -16 and (2)2=4(-2)^2 = 4. Perform division and multiplication from left to right: 16÷8=2-16 \div 8 = -2, and 2×4=8-2 \times 4 = -8.
5
Compare the simplified values to order them from least to greatest.
18<17<8<25-18 < -17 < -8 < 25
Comparing the results shows that the values in ascending order are 18-18 (Expression 2), 17-17 (Expression 1), 8-8 (Expression 4), and 2525 (Expression 3).

Anahtar Kavram

Order of Operations and Number Properties
Tahmini Süre:2m 30s
Soru 58Soru

Four distinct integers, pp, qq, rr, and ss, are represented on a standard number line. The distance between pp and qq is 3, the distance between qq and rr is 4, and the distance between rr and ss is 5. What is the minimum possible distance between pp and ss?

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Cevap: 2

Cevap

The minimum possible distance between pp and ss is 2.
By setting p=0p = 0 as a reference point, the coordinate for qq must be either 33 or 3-3. Assuming q=3q = 3 by symmetry, rr must be either 1-1 or 77 because it is at a distance of 4 from qq. From r=7r = 7, a distance of 5 leads to ss being at 22 or 1212. From r=1r = -1, a distance of 5 leads to ss being at 44 or 6-6. All of these positions result in four distinct integers. The distances between pp and ss are the absolute values of their coordinates, which are 1212, 22, 66, and 44. The minimum of these distances is 22.

Adım Adım Çözüm

1
Establish a coordinate system on the number line.
Let pp be at position 0. Since the distance between pp and qq is 3, qq is at either 33 or 3-3. By symmetry, we assume q=3q = 3.
Setting one point at the origin simplifies the relative distance calculations for all other points.
2
Find the possible coordinates of rr.
Since the distance between qq and rr is 4, rr is at 34=13 - 4 = -1 or 3+4=73 + 4 = 7.
The absolute value equation qr=4|q - r| = 4 has two solutions for rr given q=3q = 3.
3
Find the possible coordinates of ss for each case of rr.
If r=7r = 7, then ss can be at 75=27 - 5 = 2 or 7+5=127 + 5 = 12. If r=1r = -1, then ss can be at 15=6-1 - 5 = -6 or 1+5=4-1 + 5 = 4. All generated sets contain distinct values, satisfying the requirement.
The absolute value equation rs=5|r - s| = 5 has two solutions for ss for each candidate coordinate of rr.
4
Determine the minimum distance between pp and ss.
The possible values for the distance ps|p - s| are 02=2|0 - 2| = 2, 012=12|0 - 12| = 12, 0(6)=6|0 - (-6)| = 6, and 04=4|0 - 4| = 4. The minimum value is 2.
Comparing all possible valid configurations ensures we find the true minimum distance.

Anahtar Kavram

Representing distances between points on a number line using absolute values and resolving configurations for distinct integers.
Soru 59Soru

What is the value of the following expression?

32164×52310-3^2 - \frac{16 - 4 \times 5}{2^3 - 10}
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Cevap: 11-11

Cevap

11-11
The correct value is 11-11. By following the standard order of operations, we first evaluate the leading term 32=9-3^2 = -9. Next, we evaluate the numerator of the fraction (164×5=1620=416 - 4 \times 5 = 16 - 20 = -4) and the denominator of the fraction (2310=810=22^3 - 10 = 8 - 10 = -2). Simplifying the fraction gives 42=2\frac{-4}{-2} = 2. Finally, subtracting this value from the leading term yields 92=11-9 - 2 = -11.

Adım Adım Çözüm

1
Evaluate the exponent term on the left side of the subtraction.
32=(3×3)=9-3^2 = -(3 \times 3) = -9
According to the order of operations, the exponent applies only to the base 33, not the negative sign, unless parentheses are present.
2
Evaluate the numerator of the fraction by performing multiplication before subtraction.
164×5=1620=416 - 4 \times 5 = 16 - 20 = -4
Multiplication has a higher priority than subtraction in the standard order of operations.
3
Evaluate the denominator of the fraction by evaluating the exponent before subtraction.
2310=810=22^3 - 10 = 8 - 10 = -2
Exponentiation must be performed before subtraction.
4
Divide the simplified numerator by the simplified denominator to find the value of the fraction.
42=2\frac{-4}{-2} = 2
Dividing a negative number by a negative number yields a positive result.
5
Perform the final subtraction using the values from Step 1 and Step 4.
92=11-9 - 2 = -11
Subtracting 22 from 9-9 moves further left on the number line, resulting in 11-11.

Anahtar Kavram

Order of Operations (PEMDAS/BODMAS)
Soru 60Soru

If x=6x = -6, what is the value of the expression 12x312 - |x - 3|?

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Cevap: 3

Cevap

The value of the expression is 3.
Substituting x=6x = -6 into the expression 12x312 - |x - 3| gives 126312 - |-6 - 3|. Simplifying the subtraction inside the absolute value gives 12912 - |-9|. Since the absolute value of 9-9 is 99, the expression simplifies to 12912 - 9, which equals 33.

Adım Adım Çözüm

1
Substitute x=6x = -6 into the expression.
126312 - |-6 - 3|
Substitute the given value of the variable into the algebraic expression.
2
Simplify the expression inside the absolute value symbol.
12912 - |-9|
Subtracting 3 from 6-6 results in 9-9.
3
Calculate the absolute value.
12912 - 9
The absolute value represents the distance from zero on the number line, so 9=9|-9| = 9.
4
Subtract the numbers to find the final value.
33
129=312 - 9 = 3.

Anahtar Kavram

Evaluating algebraic expressions involving integers and absolute values.
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