Integers, Absolute Value, and Number Lines

41 soru

Soru 1Soru

On a standard number line, point AA is located at 7-7 and point BB is located at 55. What is the distance between point AA and point BB?

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Cevap: 12

Cevap

The distance between the two points is 12.
The distance between two points on a number line is the absolute value of their difference. Calculating 75|-7 - 5| yields 12|-12|, which is 1212. Alternatively, subtracting the lesser coordinate from the greater coordinate gives 5(7)=5+7=125 - (-7) = 5 + 7 = 12.

Adım Adım Çözüm

1
Identify the coordinates of the two points on the number line.
The coordinates are 7-7 for point AA and 55 for point BB.
These coordinates represent the positions from which we need to find the distance.
2
Apply the absolute value formula for the distance between two points, ab|a - b|.
The expression is 75|-7 - 5|.
Distance on a number line is always non-negative and is defined by the absolute value of the difference between the two coordinates.
3
Perform the subtraction and find the absolute value.
12=12|-12| = 12.
Subtracting 55 from 7-7 gives 12-12, and the absolute value of 12-12 is 1212.

Anahtar Kavram

The distance between two points aa and bb on a number line is given by ab|a - b|.
Tahmini Süre:45s
Soru 2Soru

What is the value of the expression 15+7-|-15 + 7|?

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Cevap: 8-8

Cevap

8-8
To find the value of 15+7-|-15 + 7|, we first evaluate the expression inside the absolute value bars: 15+7=8-15 + 7 = -8. Next, we take the absolute value of that result: 8=8|-8| = 8. Finally, we apply the negative sign that is outside the absolute value bars, which gives 8-8.

Adım Adım Çözüm

1
Evaluate the expression inside the absolute value bars.
15+7=8-15 + 7 = -8
Before applying the absolute value, the terms inside the vertical bars must be simplified according to the order of operations.
2
Find the absolute value of the result from Step 1.
8=8|-8| = 8
The absolute value of a number represents its distance from zero on a number line, which is always non-negative.
3
Apply the negative sign that is outside the absolute value bars.
(8)=8- (8) = -8
The negative sign outside acts as multiplication by 1-1 after the absolute value has been evaluated.

Anahtar Kavram

Evaluating expressions involving absolute values and negative numbers
Soru 3Soru

What is the value of the expression 12715|-12| - |7 - 15|?

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Cevap: 4

Cevap

The value of the expression is 4.
The absolute value of a number represents its distance from zero on a number line, so 12=12|-12| = 12. Simplifying inside the second term gives 715=87 - 15 = -8, and the absolute value 8=8|-8| = 8. Subtracting these two results yields 128=412 - 8 = 4.

Adım Adım Çözüm

1
Evaluate the first term
12=12|-12| = 12
The absolute value of a number is its distance from zero on the number line, which is always non-negative.
2
Simplify the expression inside the second absolute value
715=87 - 15 = -8
Subtracting 15 from 7 yields a negative difference of -8.
3
Evaluate the second absolute value term
8=8|-8| = 8
The absolute value of -8 is 8.
4
Subtract the two evaluated terms
128=412 - 8 = 4
Subtracting 8 from 12 gives the final simplified value of 4.

Anahtar Kavram

Evaluating expressions with absolute values requires simplifying the terms inside the absolute value grouping symbols first, taking the absolute value of the result, and then performing the subtraction.
Soru 4Soru

The temperature at the top of a mountain is 14C-14^\circ\text{C}, and the temperature at the base of the mountain is 8C8^\circ\text{C}. What is the absolute difference, in degrees Celsius, between these two temperatures?

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Cevap: 22

Cevap

22
The correct answer is 22 because the absolute difference between 88 and 14-14 is 8(14)=8+14=22=22|8 - (-14)| = |8 + 14| = |22| = 22. This represents the total distance of 22 units between the two temperatures on a number line.

Adım Adım Çözüm

1
Translate the problem into a mathematical expression using absolute value for the difference between the two temperatures.
The absolute difference is given by 8(14)|8 - (-14)| or 148|-14 - 8|.
The absolute difference between two numbers aa and bb on a number line is defined as ab|a - b|.
2
Simplify the subtraction inside the absolute value.
8(14)=8+14=228 - (-14) = 8 + 14 = 22 (or 148=22-14 - 8 = -22).
Subtracting a negative number is equivalent to adding its positive counterpart.
3
Evaluate the absolute value.
22=22|22| = 22 (or 22=22|-22| = 22).
The absolute value of a number represents its non-negative distance from zero.

Anahtar Kavram

Integers, Absolute Value, and Number Lines
Tahmini Süre:45s
Soru 5Soru

Four distinct integers, pp, qq, rr, and ss, are represented on a standard number line. The distance between pp and qq is 3, the distance between qq and rr is 4, and the distance between rr and ss is 5. What is the minimum possible distance between pp and ss?

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Cevap: 2

Cevap

The minimum possible distance between pp and ss is 2.
By setting p=0p = 0 as a reference point, the coordinate for qq must be either 33 or 3-3. Assuming q=3q = 3 by symmetry, rr must be either 1-1 or 77 because it is at a distance of 4 from qq. From r=7r = 7, a distance of 5 leads to ss being at 22 or 1212. From r=1r = -1, a distance of 5 leads to ss being at 44 or 6-6. All of these positions result in four distinct integers. The distances between pp and ss are the absolute values of their coordinates, which are 1212, 22, 66, and 44. The minimum of these distances is 22.

Adım Adım Çözüm

1
Establish a coordinate system on the number line.
Let pp be at position 0. Since the distance between pp and qq is 3, qq is at either 33 or 3-3. By symmetry, we assume q=3q = 3.
Setting one point at the origin simplifies the relative distance calculations for all other points.
2
Find the possible coordinates of rr.
Since the distance between qq and rr is 4, rr is at 34=13 - 4 = -1 or 3+4=73 + 4 = 7.
The absolute value equation qr=4|q - r| = 4 has two solutions for rr given q=3q = 3.
3
Find the possible coordinates of ss for each case of rr.
If r=7r = 7, then ss can be at 75=27 - 5 = 2 or 7+5=127 + 5 = 12. If r=1r = -1, then ss can be at 15=6-1 - 5 = -6 or 1+5=4-1 + 5 = 4. All generated sets contain distinct values, satisfying the requirement.
The absolute value equation rs=5|r - s| = 5 has two solutions for ss for each candidate coordinate of rr.
4
Determine the minimum distance between pp and ss.
The possible values for the distance ps|p - s| are 02=2|0 - 2| = 2, 012=12|0 - 12| = 12, 0(6)=6|0 - (-6)| = 6, and 04=4|0 - 4| = 4. The minimum value is 2.
Comparing all possible valid configurations ensures we find the true minimum distance.

Anahtar Kavram

Representing distances between points on a number line using absolute values and resolving configurations for distinct integers.
Soru 6Soru

If x=6x = -6, what is the value of the expression 12x312 - |x - 3|?

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Cevap: 3

Cevap

The value of the expression is 3.
Substituting x=6x = -6 into the expression 12x312 - |x - 3| gives 126312 - |-6 - 3|. Simplifying the subtraction inside the absolute value gives 12912 - |-9|. Since the absolute value of 9-9 is 99, the expression simplifies to 12912 - 9, which equals 33.

Adım Adım Çözüm

1
Substitute x=6x = -6 into the expression.
126312 - |-6 - 3|
Substitute the given value of the variable into the algebraic expression.
2
Simplify the expression inside the absolute value symbol.
12912 - |-9|
Subtracting 3 from 6-6 results in 9-9.
3
Calculate the absolute value.
12912 - 9
The absolute value represents the distance from zero on the number line, so 9=9|-9| = 9.
4
Subtract the numbers to find the final value.
33
129=312 - 9 = 3.

Anahtar Kavram

Evaluating algebraic expressions involving integers and absolute values.
Soru 7Soru

Let xx, yy, and zz be integers such that x<y<z|x| < |y| < |z|, x+y+z=3x + y + z = -3, and xyz>0xyz > 0. What is the smallest possible value of xy+yz+zx|x - y| + |y - z| + |z - x|?

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Cevap: 12

Cevap

12
The correct answer is 12. To satisfy the given conditions, the product xyz>0xyz > 0 means either all three numbers are positive, or exactly two are negative. Since they sum to 3-3, they cannot all be positive. Letting two be negative and one positive, we find that the integer set {1,2,4}\{-1, 2, -4\} satisfies 1<2<4|-1| < |2| < |-4| (or 1<2<41 < 2 < 4), has a sum of 3-3, and a product of 8>08 > 0. The sum of the absolute differences is 12+2(4)+4(1)=3+6+3=12|-1 - 2| + |2 - (-4)| + |-4 - (-1)| = 3 + 6 + 3 = 12, which is the minimum possible value.

Adım Adım Çözüm

1
Analyze the sign constraints from the product condition xyz>0xyz > 0.
Since the product of xx, yy, and zz is positive, either all three integers are positive, or exactly two are negative and one is positive.
The product of three numbers is positive if there are zero or two negative factors.
2
Evaluate the case where all three integers are positive.
If all three are positive, then x,y,z1x, y, z \geq 1. This implies their sum x+y+z3x+y+z \geq 3, which contradicts the constraint x+y+z=3x+y+z = -3. Thus, this case is impossible.
Positive integers cannot sum to a negative number.
3
Analyze the case where two integers are negative and one is positive, and express them in terms of their absolute values.
Let the negative integers be u-u and v-v (with u>v>0u > v > 0) and the positive integer be p>0p > 0. The sum constraint becomes uv+p=3-u - v + p = -3, which simplifies to p=u+v3p = u + v - 3. The absolute values are uu, vv, and pp, which must be three distinct positive integers satisfying x<y<z|x| < |y| < |z|.
This translates the constraints into positive integer variables representing the absolute values.
4
Determine the values of u,v,pu, v, p that minimize the maximum difference between any two of the three integers x,y,zx, y, z.
For v=1v = 1: if u=4u = 4, then p=2p = 2. The absolute values {1,2,4}\{1, 2, 4\} are distinct. The corresponding integers are x=1x = -1, y=2y = 2, and z=4z = -4. Their sum is 3-3 and product is 8>08 > 0. The difference between the maximum and minimum values is 2(4)=62 - (-4) = 6. For v=2v = 2: if u=4u = 4, then p=3p = 3. The absolute values {2,3,4}\{2, 3, 4\} are distinct, giving the integers 4,2,3-4, -2, 3, with a maximum difference of 3(4)=73 - (-4) = 7. For higher values, the difference only increases.
The expression xy+yz+zx|x - y| + |y - z| + |z - x| is equal to twice the difference between the maximum and minimum of the three integers.
5
Calculate the minimum value of the expression.
Using the optimal set x=1,y=2,z=4x = -1, y = 2, z = -4, the value of the expression is 12+2(4)+4(1)=3+6+3=12|-1 - 2| + |2 - (-4)| + |-4 - (-1)| = 3 + 6 + 3 = 12.
This is the smallest possible sum of the absolute differences.

Anahtar Kavram

Using absolute values and sign analysis to solve system of constraints on integers and distances on a number line.
Soru 8Soru

What integer represents the midpoint between 9-9 and 77 on a standard number line?

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Cevap: 1-1

Cevap

The midpoint coordinate is 1-1.
The midpoint of two numbers on a number line is their mathematical average. Adding the coordinates 9-9 and 77 gives a sum of 2-2. Dividing this sum by 22 yields the midpoint coordinate of 1-1.

Adım Adım Çözüm

1
Identify the coordinates of the two endpoints on the number line.
The endpoints are 9-9 and 77.
Before calculating the midpoint, we must identify the values of the two points given in the problem.
2
Find the average of the two coordinates using the midpoint formula a+b2\frac{a + b}{2}.
9+72=22=1\frac{-9 + 7}{2} = \frac{-2}{2} = -1.
The midpoint of any two coordinates on a number line is their arithmetic mean.

Anahtar Kavram

Finding the midpoint between two integers on a number line
Tahmini Süre:45s
Soru 9Soru

Let xx and yy be integers such that x4|x| \leq 4 and y4|y| \leq 4. How many distinct pairs of integers (x,y)(x, y) satisfy the inequality xy2||x| - |y|| \geq 2?

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Cevap: 36

Cevap

There are 36 distinct pairs of integers (x,y)(x, y) that satisfy the inequality.
By analyzing the possible values for x|x| and y|y| within the set {0,1,2,3,4}\{0, 1, 2, 3, 4\}, we identify the 12 pairs that satisfy the inequality xy2||x| - |y|| \geq 2. When mapping these absolute values back to the actual integer coordinates, we account for the single option when a coordinate is 0 and the two positive/negative options when a coordinate is non-zero. Summing these possibilities yields exactly 36 distinct pairs.

Adım Adım Çözüm

1
Determine the range of absolute values for the integers.
The possible values for x|x| and y|y| are {0,1,2,3,4}\{0, 1, 2, 3, 4\}.
Since xx and yy are integers satisfying 4x,y4-4 \leq x, y \leq 4, their absolute values must be non-negative integers up to 4.
2
Find the pairs of absolute values (x,y)(|x|, |y|) that satisfy the inequality.
The valid pairs are: (0,2),(0,3),(0,4),(1,3),(1,4),(2,0),(2,4),(3,0),(3,1),(4,0),(4,1),(4,2)(0, 2), (0, 3), (0, 4), (1, 3), (1, 4), (2, 0), (2, 4), (3, 0), (3, 1), (4, 0), (4, 1), (4, 2).
We test all combinations of u,v{0,1,2,3,4}u, v \in \{0, 1, 2, 3, 4\} such that uv2|u - v| \geq 2.
3
Calculate the number of integer coordinate pairs (x,y)(x, y) corresponding to each absolute value pair.
Pairs with one zero value yield 2 integer solutions (e.g., u=0,v=2(0,2),(0,2)u=0, v=2 \Rightarrow (0, 2), (0, -2)). Pairs with both non-zero values yield 4 integer solutions (e.g., u=1,v=3(1,3),(1,3),(1,3),(1,3)u=1, v=3 \Rightarrow (1, 3), (1, -3), (-1, 3), (-1, -3)).
An absolute value of 0 corresponds to only 1 integer (00), whereas any positive absolute value kk corresponds to 2 integers (kk and k-k).
4
Sum the number of integer pairs for all valid cases.
Total pairs = (3×2)+(3×2)+(6×4)=6+6+24=36(3 \times 2) + (3 \times 2) + (6 \times 4) = 6 + 6 + 24 = 36.
There are 3 pairs with u=0u=0 (66 solutions), 3 pairs with v=0v=0 (66 solutions), and 6 pairs with both u,v>0u, v > 0 (2424 solutions).

Anahtar Kavram

Solving nested absolute value inequalities with integer constraints and counting solution pairs systematically.
Soru 10Soru

Point PP is located at 14-14 on a standard number line. Point QQ is located 88 units from point PP in the positive direction. Point RR is located 1111 units from point QQ in the negative direction. What integer represents the location of point RR?

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Cevap: -17

Cevap

The position of point RR is represented by the integer 17-17.
To find the location of point RR, we first determine the location of point QQ by moving 88 units in the positive direction (right) from point PP (at 14-14), which gives 14+8=6-14 + 8 = -6. Next, we find the location of point RR by moving 1111 units in the negative direction (left) from point QQ (at 6-6), which gives 611=17-6 - 11 = -17.

Adım Adım Çözüm

1
Calculate the position of point QQ.
6-6
Since point QQ is 88 units from point PP (which is at 14-14) in the positive direction, we add 88 to 14-14: 14+8=6-14 + 8 = -6.
2
Calculate the position of point RR.
17-17
Since point RR is 1111 units from point QQ (which is at 6-6) in the negative direction, we subtract 1111 from 6-6: 611=17-6 - 11 = -17.

Anahtar Kavram

Adding and subtracting integers on a number line to find positions relative to a starting point.
Tahmini Süre:45s
Soru 11Soru

On a standard number line, the distance between two points, AA and BB, is 1212 units. If the coordinate of point AA is 18-18, which of the following is a possible coordinate for point BB?

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Cevap: 30-30

Cevap

30-30
The correct answer is 30-30 because the distance between two points on a number line is found by taking the absolute value of the difference between their coordinates. Setting up the relation b(18)=12|b - (-18)| = 12 simplifies to b+18=12|b + 18| = 12. Solving this absolute value equation yields two possible locations: b+18=12b + 18 = 12 (which gives b=6b = -6) and b+18=12b + 18 = -12 (which gives b=30b = -30). Among the choices, 30-30 is the only possible coordinate listed.

Adım Adım Çözüm

1
Set up the absolute value equation representing the distance between point A and point B on the number line.
Let bb be the coordinate of point BB. The distance between AA and BB is given by 18b=12|-18 - b| = 12.
On a standard number line, the distance between any two coordinates xx and yy is given by the absolute value of their difference, xy|x - y|.
2
Solve the absolute value equation for the two possible cases.
Case 1: 18b=12b=30b=30-18 - b = 12 \Rightarrow -b = 30 \Rightarrow b = -30. Case 2: 18b=12b=6b=6-18 - b = -12 \Rightarrow -b = 6 \Rightarrow b = -6.
An equation of the form x=d|x| = d (where d0d \geq 0) splits into two distinct equations: x=dx = d and x=dx = -d.
3
Compare the possible solutions with the given options.
The value 30-30 is one of the possible coordinates and is listed in the options.
To identify which of the two mathematically correct coordinates (-30 or -6) is provided as an answer choice.

Anahtar Kavram

The distance between two points on a number line with coordinates xx and yy is represented by the absolute value of their difference, xy|x - y|.
Tahmini Süre:45s
Soru 12Soru

Three distinct integers, aa, bb, and cc, lie on a standard number line such that a<b<ca < b < c. The distance between aa and bb is 33 times the distance between bb and cc. If a=15|a| = 15, c=7|c| = 7, and b<0b < 0, what is the value of bb?

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Cevap: -9

Cevap

The value of bb is 9-9.
The correct answer is 9-9. By interpreting a=15|a| = 15 and c=7|c| = 7 with the constraint a<b<ca < b < c, we find a=15a = -15. Testing the possible values for cc, when c=7c = -7, we set up the distance equation b(15)=3(7b)b - (-15) = 3(-7 - b), which simplifies to b+15=213bb + 15 = -21 - 3b, giving 4b=364b = -36 and b=9b = -9. This satisfies all constraints, including bb being a negative integer.

Adım Adım Çözüm

1
Find the possible coordinates for aa and cc based on their absolute values.
a{15,15}a \in \{-15, 15\} and c{7,7}c \in \{-7, 7\}.
The absolute value of a number represents its distance from zero, so x=d    x=±d|x| = d \implies x = \pm d.
2
Use the ordering condition a<b<ca < b < c to eliminate invalid combinations.
a=15a = -15 and c{7,7}c \in \{-7, 7\}.
Since aa must be less than cc, aa cannot be 1515 because both possible values of cc (7-7 and 77) are less than 1515.
3
Set up an equation representing the distance relationship on the number line.
b+15=3(cb)    4b=3c15b + 15 = 3(c - b) \implies 4b = 3c - 15.
For points on a number line ordered a<b<ca < b < c, the distance between aa and bb is bab - a, and the distance between bb and cc is cbc - b.
4
Substitute each possible value of cc and solve for bb to find the one that yields a negative integer.
For c=7c = -7, b=9b = -9.
If c=7c = 7, b=1.5b = 1.5, which is not an integer. If c=7c = -7, b=9b = -9, which is a negative integer, satisfying all given conditions.

Anahtar Kavram

Using absolute values and relative order to determine integer positions and distances on a number line.
Soru 13Soru

On a standard number line, the coordinates of three distinct points AA, BB, and CC are represented by the integers aa, bb, and cc, respectively, such that a<b<ca < b < c. The distance between each point and the origin is represented by its absolute value, and these distances satisfy the inequality a<b<c|a| < |b| < |c|. If the product of the three coordinates is negative (abc<0abc < 0) and the sum of their absolute values is 2020, what is the maximum possible value of the coordinate bb?

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Cevap: 9

Cevap

9
The correct answer is 9. By analyzing the signs of the coordinates, we determine that only aa is negative, so a<0<b<ca < 0 < b < c. Since aa is a negative integer, the minimum value of a|a| is 1. Under the constraint a<b<c|a| < |b| < |c| and a+b+c=20|a| + |b| + |c| = 20, we let x=ax = -a, y=by = b, and z=cz = c. We have x+y+z=20x + y + z = 20 with 1x<y<z1 \le x < y < z. Since z>yz > y, we get 20=x+y+z>1+2y20 = x + y + z > 1 + 2y, which implies 2y<192y < 19, or y<9.5y < 9.5. The maximum integer value for yy (which is bb) is 9, achieved when the coordinates are -1, 9, and 10.

Adım Adım Çözüm

1
Determine the signs of the coordinates based on the given constraints.
The sign configuration must be a<0<b<ca < 0 < b < c.
Since the product abc<0abc < 0, either all three coordinates are negative or exactly one is negative. If all three were negative (a<b<c<0a < b < c < 0), their absolute values would satisfy a>b>c|a| > |b| > |c|, which contradicts a<b<c|a| < |b| < |c|. Thus, exactly one coordinate (aa) is negative, and the other two (bb and cc) are positive.
2
Translate the absolute values and sum constraint into algebraic terms.
a+b+c=20-a + b + c = 20, where a<0a < 0 and b,c>0b, c > 0.
For a negative number aa, the absolute value a=a|a| = -a. For positive numbers bb and cc, b=b|b| = b and c=c|c| = c. Therefore, the sum a+b+c=20|a| + |b| + |c| = 20 simplifies to a+b+c=20-a + b + c = 20.
3
Set up inequalities to bound the coordinate of the middle point.
1a<b<c1 \le -a < b < c.
Since aa is a non-zero negative integer, the smallest possible value for its absolute value a=a|a| = -a is 11. The condition a<b<c|a| < |b| < |c| then becomes 1a<b<c1 \le -a < b < c.
4
Use the constraints to find the maximum value of bb.
The maximum possible value of bb is 99.
Let x=ax = -a, y=by = b, and z=cz = c. We have x+y+z=20x + y + z = 20 with 1x<y<z1 \le x < y < z. Since z>yz > y, we have 20=x+y+z>x+2y1+2y20 = x + y + z > x + 2y \ge 1 + 2y. This simplifies to 19>2y19 > 2y, or y<9.5y < 9.5. Since yy must be an integer, the maximum possible value for yy (which is bb) is 99. We can verify this maximum by setting a=1a = -1, b=9b = 9, and c=10c = 10, which perfectly satisfies all conditions.

Anahtar Kavram

Analyzing coordinate signs and absolute value inequalities on a number line to perform optimization under integer constraints.
Soru 14Soru

Let SS be the set of all integers nn that satisfy the inequality n3+n+512|n - 3| + |n + 5| \leq 12. What is the sum of the absolute values of all integers in set SS?

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Cevap: 43

Cevap

43
The correct answer is 43. Solving the inequality n3+n+512|n - 3| + |n + 5| \leq 12 by casework on the number line yields the solution set of integers S={7,6,5,4,3,2,1,0,1,2,3,4,5}S = \{-7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5\}. Summing the absolute values of these elements gives 7+6+5+4+3+2+1+0+1+2+3+4+5=437 + 6 + 5 + 4 + 3 + 2 + 1 + 0 + 1 + 2 + 3 + 4 + 5 = 43.

Adım Adım Çözüm

1
Divide the number line into intervals to remove the absolute value bars based on critical points n=3n = 3 and n=5n = -5.
Three cases to analyze: Case 1 (n3n \geq 3), Case 2 (5n<3-5 \leq n < 3), and Case 3 (n<5n < -5).
Evaluating absolute values requires knowing the signs of the expressions inside them.
2
Solve the inequality n3+n+512|n - 3| + |n + 5| \leq 12 for each case.
For Case 1 (n3n \geq 3): (n3)+(n+5)122n+212n5(n - 3) + (n + 5) \leq 12 \Rightarrow 2n + 2 \leq 12 \Rightarrow n \leq 5, yielding integers {3,4,5}\{3, 4, 5\}. For Case 2 (5n<3-5 \leq n < 3): (n3)+(n+5)12812-(n - 3) + (n + 5) \leq 12 \Rightarrow 8 \leq 12 (always true), yielding integers {5,4,3,2,1,0,1,2}\{-5, -4, -3, -2, -1, 0, 1, 2\}. For Case 3 (n<5n < -5): (n3)(n+5)122n2122n14n7-(n - 3) - (n + 5) \leq 12 \Rightarrow -2n - 2 \leq 12 \Rightarrow -2n \leq 14 \Rightarrow n \geq -7, yielding integers {7,6}\{-7, -6\}.
Determining the integer values of nn that satisfy the inequality in each segment of the number line.
3
Combine the intervals to construct the complete set SS.
S={7,6,5,4,3,2,1,0,1,2,3,4,5}S = \{-7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5\}.
The union of all valid cases gives the entire set of solutions.
4
Compute the sum of the absolute values of the integers in SS.
7+6+5+4+3+2+1+0+1+2+3+4+5=7+6+5+4+3+2+1+0+1+2+3+4+5=43|-7| + |-6| + |-5| + |-4| + |-3| + |-2| + |-1| + |0| + |1| + |2| + |3| + |4| + |5| = 7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 + 1 + 2 + 3 + 4 + 5 = 43.
Adding the absolute values of each element in the solution set.

Anahtar Kavram

Solving multi-interval absolute value inequalities with integers and finding absolute values
Tahmini Süre:2m 0s
Soru 15Soru

On a standard number line, the coordinate of point PP is an integer xx. If the sum of the distances from PP to 2-2 and from PP to 44 is equal to the distance from PP to 1010, what is the sum of all possible values of xx?

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Cevap: -4

Cevap

The sum of all possible values of the integer xx is 4-4.
The correct answer is 4-4. The distance between any two coordinates aa and bb on a number line is defined as ab|a - b|. Translating the problem gives the equation x+2+x4=x10|x + 2| + |x - 4| = |x - 10|. Breaking the number line into intervals around the critical points x=2x = -2, x=4x = 4, and x=10x = 10 yields two valid integer solutions: x=8x = -8 and x=4x = 4. The sum of these values is 8+4=4-8 + 4 = -4.

Adım Adım Çözüm

1
Express the distances on the number line using absolute values.
The distance from P(x)P(x) to 2-2 is x(2)=x+2|x - (-2)| = |x + 2|. The distance from P(x)P(x) to 44 is x4|x - 4|. The distance from P(x)P(x) to 1010 is x10|x - 10|. The equation is x+2+x4=x10|x + 2| + |x - 4| = |x - 10|.
The absolute value ab|a - b| represents the distance between points aa and bb on a standard number line.
2
Solve the equation by testing the intervals defined by the critical points x=2x = -2, x=4x = 4, and x=10x = 10.
We analyze the four intervals:
- For x<2x < -2: (x+2)(x4)=(x10)    2x+2=x+10    x=8-(x + 2) - (x - 4) = -(x - 10) \implies -2x + 2 = -x + 10 \implies x = -8. Since 8<2-8 < -2, this is a valid solution.
- For 2x<4-2 \leq x < 4: (x+2)(x4)=(x10)    6=x+10    x=4(x + 2) - (x - 4) = -(x - 10) \implies 6 = -x + 10 \implies x = 4. Since 44 is not in [2,4)[-2, 4), there is no solution in this interval.
- For 4x<104 \leq x < 10: (x+2)+(x4)=(x10)    2x2=x+10    3x=12    x=4(x + 2) + (x - 4) = -(x - 10) \implies 2x - 2 = -x + 10 \implies 3x = 12 \implies x = 4. Since 44 is in [4,10)[4, 10), this is a valid solution.
- For x10x \geq 10: (x+2)+(x4)=x10    2x2=x10    x=8(x + 2) + (x - 4) = x - 10 \implies 2x - 2 = x - 10 \implies x = -8. Since 8<10-8 < 10, there is no solution in this interval.
Absolute value terms change sign at their critical points, requiring case-by-case evaluation.
3
Sum all valid integer solutions.
The valid values for xx are 8-8 and 44. Their sum is 8+4=4-8 + 4 = -4.
The problem asks for the sum of all possible values of xx.

Anahtar Kavram

Representing geometric distances on a number line using absolute value equations and solving them using interval analysis.
Soru 16Soru

An explorer records the elevation, in meters relative to sea level, of four research stations: WW, XX, YY, and ZZ. Station WW is located at an elevation of 15-15 meters. The elevation of Station XX is the absolute value of the elevation of Station WW. The elevation of Station YY is 88 meters lower than the elevation of Station XX. Station ZZ is at an elevation such that the distance between the elevations of Station YY and Station ZZ on a vertical number line is exactly 1212 meters. Which of the following could be the elevation, in meters, of Station ZZ?

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Cevap: 5-5

Cevap

The correct elevation of Station Z could be 5-5 meters.
The correct answer is 5-5 meters. First, we find the elevation of Station X, which is the absolute value of Station W's elevation: 15=15|-15| = 15 meters. Next, we determine the elevation of Station Y, which is 88 meters lower than Station X: 158=715 - 8 = 7 meters. Finally, we find the possible elevations for Station Z. The distance between Station Y and Station Z is 1212 meters, which can be represented by the equation Z7=12|Z - 7| = 12. This gives two possible elevations: Z=7+12=19Z = 7 + 12 = 19 meters or Z=712=5Z = 7 - 12 = -5 meters. Among the choices, only 5-5 is listed.

Adım Adım Çözüm

1
Find the elevation of Station X by taking the absolute value of the elevation of Station W.
The elevation of Station X is 15=15|-15| = 15 meters.
The problem states that the elevation of Station X is the absolute value of the elevation of Station W, which is 15-15 meters.
2
Calculate the elevation of Station Y by subtracting 8 meters from the elevation of Station X.
The elevation of Station Y is 158=715 - 8 = 7 meters.
Station Y is 8 meters lower than Station X, which is at 15 meters.
3
Set up the absolute value equation representing the distance of 12 meters between Station Y and Station Z, and solve for the two possible values of Z.
Z7=12|Z - 7| = 12, which yields Z7=12    Z=19Z - 7 = 12 \implies Z = 19 or Z7=12    Z=5Z - 7 = -12 \implies Z = -5.
The distance between two points aa and bb on a number line is given by ab|a - b|. Since the distance between Y and Z is 12, we solve the equation to find all possible elevations.

Anahtar Kavram

Absolute value represents the distance of a number from zero on a number line, and the distance between two numbers aa and bb is given by ab|a - b|.
Tahmini Süre:2m 0s
Soru 17Soru

On a standard number line, points AA, BB, CC, and DD have distinct integer coordinates aa, bb, cc, and dd, respectively, such that a<b<c<da < b < c < d. The distance between AA and BB is equal to the distance between CC and DD. The distance between BB and CC is 23\frac{2}{3} of the distance between AA and BB. If the average (arithmetic mean) of the four coordinates is 00 and ad=24|a - d| = 24, what is the coordinate of BB?

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Cevap: -3

Cevap

The coordinate of BB is 3-3.
The coordinate of BB is found by setting the segment lengths to 3k3k, 2k2k, and 3k3k based on the given ratio. Using the absolute value distance ad=24|a - d| = 24, we find k=3k = 3, meaning the segments are 99, 66, and 99. Using the coordinate sum of 00, we get 4a+48=0    a=124a + 48 = 0 \implies a = -12. Substituting this back gives the coordinate of BB as 3-3.

Adım Adım Çözüm

1
Define segment lengths using a variable kk based on the given ratio.
Let the distance AB=CD=3kAB = CD = 3k and BC=2kBC = 2k.
This allows us to write all distances as integer multiples of a single variable since the ratio of BCBC to ABAB is 23\frac{2}{3}.
2
Set up an equation for the total distance from AA to DD using the absolute value ad=24|a - d| = 24.
Since a<da < d, da=ad=24d - a = |a - d| = 24. The sum of the segments is 3k+2k+3k=8k3k + 2k + 3k = 8k. Solving 8k=248k = 24 yields k=3k = 3.
The absolute value of the difference between the outermost points represents the total length of the number line segment containing all four points.
3
Express the coordinates of bb, cc, and dd in terms of aa using the calculated segment lengths.
b=a+9b = a + 9, c=a+15c = a + 15, and d=a+24d = a + 24.
Since the points are in order a<b<c<da < b < c < d, we add the segment lengths successively to find the coordinates.
4
Apply the average condition to solve for the coordinate aa.
The sum of the coordinates is 4×0=04 \times 0 = 0, so a+(a+9)+(a+15)+(a+24)=4a+48=0a + (a + 9) + (a + 15) + (a + 24) = 4a + 48 = 0, giving a=12a = -12.
An average of 00 for four numbers means their sum must be 00.
5
Find the coordinate of BB by substituting the value of aa into the expression for bb.
b=12+9=3b = -12 + 9 = -3.
This yields the specific coordinate requested by the question.

Anahtar Kavram

Using absolute value as distance on a number line and expressing relationships between ordered coordinates algebraically.
Soru 18Soru

A scientist monitors the temperature in three different chambers, AA, BB, and CC. The temperature in Chamber BB is TCT^\circ\text{C}. The temperature in Chamber AA is always 5C5^\circ\text{C} colder than the temperature in Chamber BB, and the temperature in Chamber CC is always 9C9^\circ\text{C} warmer than the temperature in Chamber BB. If TT must be an integer, and the sum of the absolute values of the temperatures in all three chambers is minimized, what is the value of TT?

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Cevap: 0

Cevap

The correct answer is 00.
The correct answer is the value 00. The sum of the absolute values of the temperatures in all three chambers is represented by the function S(T)=T5+T+T+9S(T) = |T - 5| + |T| + |T + 9|. Geometrically, this sum represents the total distance from a point TT to the coordinates 55, 00, and 9-9 on a number line. For any set of points, the sum of absolute differences is minimized at their median. The median of the set {9,0,5}\{-9, 0, 5\} is 00. Evaluating the sum at T=0T = 0 yields 05+0+0+9=5+0+9=14|0 - 5| + |0| + |0 + 9| = 5 + 0 + 9 = 14. Any other integer choice yields a larger sum (for example, a value of 11 or 1-1 yields a sum of 1515).

Adım Adım Çözüm

1
Write expressions for the temperatures of the three chambers in terms of TT.
The temperature in Chamber AA is T5T - 5, in Chamber BB is TT, and in Chamber CC is T+9T + 9.
To represent the temperature of each chamber relative to Chamber BB.
2
Write the sum of the absolute values of the three temperatures.
The sum is represented by the expression S(T)=T5+T+T+9S(T) = |T - 5| + |T| + |T + 9|.
To formulate the function that needs to be minimized.
3
Find the key values that make each absolute value term zero.
The points are 55, 00, and 9-9. Ordered on a number line, these points are 9-9, 00, and 55.
The sum of absolute differences is geometrically equivalent to the sum of distances on a number line, which is minimized at the median of the points.
4
Evaluate the sum of absolute values at the median value, T=0T = 0, and compare it to other values.
For T=0T = 0, S(0)=5+0+9=14S(0) = |-5| + |0| + |9| = 14. For T=1T = 1, S(1)=4+1+10=15S(1) = |-4| + |1| + |10| = 15. For T=1T = -1, S(1)=6+1+8=15S(-1) = |-6| + |-1| + |8| = 15. Thus, the minimum sum occurs at T=0T = 0.
To verify that the median yields the minimum sum of absolute values.

Anahtar Kavram

Minimizing the sum of absolute values of linear terms by finding the median of their zero-points on a number line.
Soru 19Soru

Two integers, xx and yy, are positioned on a number line. The distance between xx and 11 is twice the distance between yy and 22. If the distance between xx and yy is exactly 55 units, what is the sum of all possible values of x+yx + y?

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Cevap: 17

Cevap

The sum of all possible values of x+yx + y is 1717.
Representing the distances algebraically yields the system x1=2y2|x - 1| = 2|y - 2| and xy=5|x - y| = 5. Since xx and yy must be integers, splitting these equations into positive and negative cases yields exactly three valid integer coordinate pairs: (13,8)(13, 8), (5,0)(5, 0), and (7,2)(-7, -2). The sums (x+yx + y) for these pairs are 2121, 55, and 9-9, respectively. Adding these possible sums together gives a final total of 1717.

Adım Adım Çözüm

1
Set up the absolute value expressions representing the distances.
x1=2y2|x - 1| = 2|y - 2| and xy=5|x - y| = 5
Distance on a number line between two points aa and bb is mathematically defined as ab|a - b|.
2
Split the distance condition xy=5|x - y| = 5 into two coordinate cases.
x=y+5x = y + 5 or x=y5x = y - 5
An absolute value equation of the form A=B|A| = B splits into A=BA = B or A=BA = -B.
3
Substitute x=y+5x = y + 5 into the first equation and solve for integer values of yy.
y=8y = 8 (which gives x=13x = 13) and y=0y = 0 (which gives x=5x = 5)
This generates the first set of valid integer coordinates satisfying all constraints.
4
Substitute x=y5x = y - 5 into the first equation and solve for integer values of yy.
y=2y = -2 (which gives x=7x = -7); the second algebraic option y=10/3y = 10/3 is discarded because it is not an integer
This generates the remaining valid integer coordinates satisfying all constraints.
5
Sum the value of x+yx + y for all three valid coordinate pairs.
(13+8)+(5+0)+(72)=21+59=17(13 + 8) + (5 + 0) + (-7 - 2) = 21 + 5 - 9 = 17
The question asks for the sum of all possible values of the expression x+yx + y.

Anahtar Kavram

Using absolute value to represent distances on a number line and solving systems of absolute value equations under integer constraints.
Tahmini Süre:2m 30s
Soru 20Soru

A chemical mixture is kept in a temperature-controlled chamber where the temperature TT, in degrees Celsius, is restricted to the range 10T10-10 \le T \le 10. The mixture remains stable as long as the temperature satisfies the inequality:

23T2102 - 3|T - 2| \ge -10

What is the sum of all integer values of TT in this range for which the mixture is stable?

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Cevap: 18

Cevap

18
The correct answer is 18. Subtracting 2 from both sides of the inequality 23T2102 - 3|T - 2| \ge -10 gives 3T212-3|T - 2| \ge -12. Dividing by 3-3 and reversing the inequality sign yields T24|T - 2| \le 4, which expands to the compound inequality 4T24-4 \le T - 2 \le 4. Adding 2 to all parts gives 2T6-2 \le T \le 6. All integers in this range (2,1,0,1,2,3,4,5,6-2, -1, 0, 1, 2, 3, 4, 5, 6) are within the chamber's allowed range of [10,10][-10, 10]. Their sum is (2)+(1)+0+1+2+3+4+5+6=18(-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 = 18.

Adım Adım Çözüm

1
Isolate the absolute value expression by subtracting 2 from both sides.
3T212-3|T - 2| \ge -12
To solve an absolute value inequality, we must first isolate the absolute value term on one side.
2
Divide both sides by 3-3 and reverse the inequality sign.
T24|T - 2| \le 4
Dividing or multiplying an inequality by a negative number reverses the direction of the inequality sign.
3
Rewrite the absolute value inequality as a compound inequality.
4T24-4 \le T - 2 \le 4
An inequality of the form xa|x| \le a (where a0a \ge 0) is equivalent to axa-a \le x \le a.
4
Solve for TT by adding 2 to all three parts of the inequality.
2T6-2 \le T \le 6
Adding 2 isolates the variable TT to find the range of stable temperatures.
5
Identify all integer values of TT in the stable range and calculate their sum.
Sum = 18
The integers in the interval [2,6][-2, 6] are 2,1,0,1,2,3,4,5,6-2, -1, 0, 1, 2, 3, 4, 5, 6. Since the chamber is restricted to [10,10][-10, 10], all of these values are valid. Summing them: (2)+(1)+0+1+2+3+4+5+6=18(-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 = 18.

Anahtar Kavram

Solving absolute value inequalities and performing operations with signed integers.
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