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Zorluk: OrtaProperties of Matter

A naval technician inspects a solid aluminum component intended for an aircraft assembly. The component has a mass of 162 g162\text{ g} and the density of aluminum is 2.7 g/cm32.7\text{ g/cm}^3. What is the volume of the component in cubic centimeters (cm3\text{cm}^3)?

Cevap: 60 cm^3

Cevap

The volume of the aluminum component is 60 cm360\text{ cm}^3.
Density is defined by the formula ρ=mV\rho = \frac{m}{V}. Rearranging algebraically to solve for volume yields V=mρV = \frac{m}{\rho}. Substituting the given values: V=162 g2.7 g/cm3=60 cm3V = \frac{162\text{ g}}{2.7\text{ g/cm}^3} = 60\text{ cm}^3.

Adım Adım Çözüm

1
Identify the relevant physical formula and isolate the unknown variable
Volume=MassDensity\text{Volume} = \frac{\text{Mass}}{\text{Density}}
Density (ρ\rho) is a characteristic physical property defined as mass per unit volume (ρ=mV\rho = \frac{m}{V}).
2
Substitute the measured mass and known density to calculate volume
Volume=162 g2.7 g/cm3=60 cm3\text{Volume} = \frac{162\text{ g}}{2.7\text{ g/cm}^3} = 60\text{ cm}^3
Dividing 162162 by 2.72.7 gives 6060, with units simplifying to cm3\text{cm}^3.

Anahtar Kavram

Density as a fundamental physical property relating mass and volume
Tahmini Süre:1m 0s
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Konular

Properties of Matter

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