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Zorluk: ZorSeries Circuits

A direct current (DC) circuit consists of a 48 V48\text{ V} power supply connected in series with three resistors: R1=12 ΩR_1 = 12\ \Omega, R2=24 ΩR_2 = 24\ \Omega, and R3=24 ΩR_3 = 24\ \Omega. In its baseline operating state, the total circuit resistance is RT=60 ΩR_T = 60\ \Omega and the circuit loop current is I=0.8 AI = 0.8\text{ A}.

Match each circuit alteration on the left to its corresponding electrical outcome on the right.

  • A zero-resistance jumper wire (short circuit) is placed directly across resistor R3R_3.Total resistance decreases to 36 Ω36\ \Omega, loop current rises to approximately 1.33 A1.33\text{ A}, and the voltage drop across R3R_3 drops to 0 V0\text{ V}.
  • Resistor R2R_2 burns out internally, creating an open circuit condition.Circuit current drops to 0 A0\text{ A}, voltage across R1R_1 drops to 0 V0\text{ V}, and the entire supply voltage of 48 V48\text{ V} appears across the faulty component.
  • A fourth resistor with a value of R4=20 ΩR_4 = 20\ \Omega is connected in series with the existing chain.Total resistance increases to 80 Ω80\ \Omega, reducing the loop current to 0.6 A0.6\text{ A} and the voltage drop across R1R_1 to 7.2 V7.2\text{ V}.
  • The power supply voltage is increased from 48 V48\text{ V} to 72 V72\text{ V} while keeping all components unchanged.Total resistance remains 60 Ω60\ \Omega, loop current increases to 1.2 A1.2\text{ A}, and the voltage drop across R2R_2 increases to 28.8 V28.8\text{ V}.

Cevap

The correct matches pair: (1) shorting resistor R3R_3 with total resistance dropping to 36 Ω36\ \Omega, current rising to 1.33 A1.33\text{ A}, and 0 V0\text{ V} across R3R_3; (2) an open at R2R_2 with loop current dropping to 0 A0\text{ A} and 48 V48\text{ V} appearing across R2R_2; (3) adding a 20 Ω20\ \Omega series resistor with total resistance rising to 80 Ω80\ \Omega, current dropping to 0.6 A0.6\text{ A}, and 7.2 V7.2\text{ V} across R1R_1; and (4) raising the source to 72 V72\text{ V} with total resistance remaining 60 Ω60\ \Omega, current rising to 1.2 A1.2\text{ A}, and 28.8 V28.8\text{ V} across R2R_2.
Each modification directly follows the governing principles of series DC circuits. In series circuits, total resistance equals the direct sum of all individual resistances (RT=R1+R2+⋯+RnR_T = R_1 + R_2 + \dots + R_n), and current is constant throughout the single loop (IT=VTRTI_T = \frac{V_T}{R_T}). Short circuits eliminate individual component resistance and drop component voltage to zero while raising loop current. Open circuits eliminate current entirely and place full source voltage across the open terminals. Adding series resistance reduces current throughout the loop, and increasing source voltage increases current and all individual voltage drops proportionally.

Adım Adım Çözüm

1
Analyze the short circuit condition across R3R_3
RT=12+24=36 ΩR_T = 12 + 24 = 36\ \Omega; I=4836≈1.33 AI = \frac{48}{36} \approx 1.33\text{ A}; V3=0 VV_3 = 0\text{ V}
A short circuit bypasses the component with zero resistance, eliminating its resistance from the total series sum and producing zero potential difference across itself.
2
Analyze the open circuit condition at R2R_2
I=0 AI = 0\text{ A}; V1=0 VV_1 = 0\text{ V}; V3=0 VV_3 = 0\text{ V}; V2=48 VV_2 = 48\text{ V}
An open in a series circuit interrupts the sole conductive loop, causing current to cease everywhere; infinite resistance across the open component causes the full source potential to appear across the gap.
3
Analyze the addition of a fourth series resistor (R4=20 ΩR_4 = 20\ \Omega)
RT=60+20=80 ΩR_T = 60 + 20 = 80\ \Omega; I=4880=0.6 AI = \frac{48}{80} = 0.6\text{ A}; V1=0.6×12=7.2 VV_1 = 0.6 \times 12 = 7.2\text{ V}
In series circuits, equivalent resistance is additive (RT=∑RR_T = \sum R). Increasing total resistance reduces total current according to Ohm's Law (I=VRTI = \frac{V}{R_T}), which proportionally reduces individual component voltage drops.
4
Analyze the voltage source increase to 72 V72\text{ V}
RT=60 ΩR_T = 60\ \Omega; I=7260=1.2 AI = \frac{72}{60} = 1.2\text{ A}; V2=1.2×24=28.8 VV_2 = 1.2 \times 24 = 28.8\text{ V}
Resistor values are independent of source voltage. Applying Ohm's Law with higher voltage across constant resistance yields directly proportional increases in loop current and individual voltage drops.

Anahtar Kavram

Series Circuit Governing Rules: Additive Resistance, Current Continuity, Ohm's Law, and Fault Dynamics
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