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A military supply truck has a fuel tank capacity of 45 gallons45 \text{ gallons}. The truck operates with a fuel efficiency of 8 kilometers per liter8 \text{ kilometers per liter}. Assuming the truck starts with a full tank of fuel, what is its maximum driving range in miles? (Use 1 gallon=3.8 liters1 \text{ gallon} = 3.8 \text{ liters} and 1 mile=1.6 kilometers1 \text{ mile} = 1.6 \text{ kilometers})

  1. A
    85.5
  2. 855Cevap
  3. C
    1,368
  4. D
    2,188.8

Cevap

855
To find the range in miles, first convert the tank capacity to liters by multiplying 45 gallons by 3.8 liters/gallon to get 171 liters. Then, find the range in kilometers by multiplying 171 liters by 8 kilometers/liter, which equals 1,368 kilometers. Finally, convert the distance from kilometers to miles by dividing 1,368 by 1.6, resulting in exactly 855 miles.

Adım Adım Çözüm

1
Convert the fuel tank capacity from gallons to liters.
45 gallons×3.8 liters/gallon=171 liters45 \text{ gallons} \times 3.8 \text{ liters/gallon} = 171 \text{ liters}
The fuel efficiency is given in kilometers per liter, so the total fuel volume must be in liters to find the total distance.
2
Calculate the maximum driving range in kilometers.
171 liters×8 km/liter=1,368 kilometers171 \text{ liters} \times 8 \text{ km/liter} = 1,368 \text{ kilometers}
Multiplying the total volume of fuel by the fuel efficiency yields the total distance the truck can travel in kilometers.
3
Convert the maximum driving range from kilometers to miles.
1,368 kilometers÷1.6 km/mile=855 miles1,368 \text{ kilometers} \div 1.6 \text{ km/mile} = 855 \text{ miles}
The question asks for the final distance in miles, requiring division by the conversion factor.

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