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Zorluk: OrtaSolving One-Variable Inequalities
7(y−2)−4y>5y+107(y - 2) - 4y > 5y + 10

What are all the possible values of yy that satisfy the inequality shown above?

  1. y<−12y < -12Cevap
  2. B
    y>−12y > -12
  3. C
    y<12y < 12
  4. D
    y>2y > 2

Cevap

The correct solution set is y<−12y < -12.
The correct answer is found by properly applying the distributive property, grouping like terms, isolating the variable, and correctly reversing the inequality sign when dividing by -2.

Adım Adım Çözüm

1
Distribute the 7 to both terms inside the parentheses.
7y−14−4y>5y+107y - 14 - 4y > 5y + 10
This clears the parentheses, allowing the variable terms to be grouped.
2
Combine the like terms on the left side of the inequality.
3y−14>5y+103y - 14 > 5y + 10
Subtracting 4y4y from 7y7y simplifies the left side to 3y3y.
3
Subtract 5y5y from both sides to group the variable terms on the left.
−2y−14>10-2y - 14 > 10
This moves all terms containing yy to one side of the inequality.
4
Add 14 to both sides to isolate the variable term.
−2y>24-2y > 24
This leaves the −2y-2y term by itself on the left side.
5
Divide both sides by -2 and reverse the inequality sign.
y<−12y < -12
According to the properties of inequalities, multiplying or dividing by a negative number requires flipping the direction of the inequality symbol.

Anahtar Kavram

Solving One-Variable Inequalities
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