Calculate the total effort force required for each scenario and arrange the following inclined plane configurations in order from the GREATEST required effort force to the LEAST required effort force.
- 1A crate moved up a ramp to a height of , with a constant friction force of .
- 2A crate moved up an ramp to a height of , assuming perfectly frictionless conditions.
- 3A crate moved up a ramp to a height of , with a constant friction force of .
- 4A crate moved up a ramp to a height of , with a constant friction force of .
Cevap
The correct sequence from greatest to least effort force is: 240 lb crate (90 lb effort), 160 lb crate (80 lb effort), 300 lb crate (75 lb effort), and 450 lb crate (70 lb effort).
The total effort force required is the sum of the ideal effort (weight divided by IMA) and the friction force. For the 240 lb crate, the total effort is 90 lb. For the 160 lb crate, it is 80 lb. For the 300 lb crate, it is 75 lb. For the 450 lb crate, it is 70 lb. Arranging these from greatest to least yields the sequence of 90 lb, 80 lb, 75 lb, and 70 lb.
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Anahtar Kavram
Calculating total required effort force on an inclined plane by combining Ideal Mechanical Advantage (IMA) and frictional forces.