Arrange the following vehicle scenarios in order from the lowest acceleration to the highe… — Armed Services Vocational Aptitude Battery (ASVAB)

Arrange the following vehicle scenarios in order from the lowest acceleration to the highest acceleration.

1A forklift maintaining a constant speed of $5 \text{ m/s}$ down a straight warehouse aisle.
2A motorized cart accelerating from rest to $6 \text{ m/s}$ in $3 \text{ seconds}$ .
3A delivery van increasing its speed from $10 \text{ m/s}$ to $22 \text{ m/s}$ over $3 \text{ seconds}$ .
4A sports car accelerating from rest to $15 \text{ m/s}$ in $3 \text{ seconds}$ .

The correct sequence from lowest to highest acceleration is: the forklift (

0 \text{ m/s}^2

), the motorized cart (

2 \text{ m/s}^2

), the delivery van (

4 \text{ m/s}^2

), and the sports car (

5 \text{ m/s}^2

By applying the acceleration formula

a = \frac{\Delta v}{t}

to each scenario, we find the respective accelerations are

0 \text{ m/s}^2

2 \text{ m/s}^2

4 \text{ m/s}^2

, and

5 \text{ m/s}^2

. Placing them in ascending numeric order yields the correct sequence.

Calculate the acceleration of the forklift.

a = 0 \text{ m/s}^2

Because the forklift maintains a constant speed in a straight line, its velocity does not change.

Calculate the acceleration of the motorized cart.

a = 2 \text{ m/s}^2

Using the formula

a = \frac{v_f - v_i}{t}

, we get

\frac{6 - 0}{3} = 2

Calculate the acceleration of the delivery van.

a = 4 \text{ m/s}^2

Using the formula

a = \frac{v_f - v_i}{t}

, we get

\frac{22 - 10}{3} = 4

Calculate the acceleration of the sports car.

a = 5 \text{ m/s}^2

Using the formula

a = \frac{v_f - v_i}{t}

, we get

\frac{15 - 0}{3} = 5

Acceleration is the rate at which an object changes its velocity, calculated by dividing the change in velocity by the elapsed time.

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