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Zorluk: KolaySpeed, Velocity, and Acceleration

A cargo aircraft accelerates from rest to a final velocity of 90 m/s90 \text{ m/s} in exactly 3 minutes3 \text{ minutes}. What is the average acceleration of the aircraft in m/s2\text{m/s}^2?

  1. A
    30 m/s230 \text{ m/s}^2
  2. B
    2.0 m/s22.0 \text{ m/s}^2
  3. 0.5 m/s20.5 \text{ m/s}^2Cevap
  4. D
    270 m/s2270 \text{ m/s}^2

Cevap

The average acceleration of the aircraft is 0.5 m/s20.5 \text{ m/s}^2.
The correct average acceleration is found by first converting the given time of 3 minutes into 180 seconds. Then, using the kinematic formula for acceleration (change in velocity divided by time), dividing the final velocity of 90 m/s90 \text{ m/s} by 180 seconds results in 0.5 m/s20.5 \text{ m/s}^2.

Adım Adım Çözüm

1
Convert the time from minutes to seconds.
3 minutes×60 seconds/minute=180 seconds3 \text{ minutes} \times 60 \text{ seconds/minute} = 180 \text{ seconds}.
Acceleration is requested in m/s2\text{m/s}^2, so the time variable must be in seconds.
2
Apply the formula for average acceleration: a=vf−vita = \frac{v_f - v_i}{t}.
a=90 m/s−0 m/s180 sa = \frac{90 \text{ m/s} - 0 \text{ m/s}}{180 \text{ s}}.
This formula determines the rate of change of velocity over the given time period.
3
Calculate the final acceleration value.
a=0.5 m/s2a = 0.5 \text{ m/s}^2.
Dividing 9090 by 180180 yields 0.50.5.

Anahtar Kavram

Calculating average acceleration requiring unit conversion.
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