An industrial control circuit uses a relay (K1) to control a DC motor. The circuit is wired as follows:
- A normally closed (NC) 'Stop' pushbutton is wired in series with a momentary normally open (NO) 'Start' pushbutton and the K1 relay coil.
- A normally open (NO) contact from the K1 relay is wired in parallel across the 'Start' pushbutton.
- A second normally open (NO) contact from the K1 relay connects the motor to the power supply.
If a short circuit develops directly across the two terminals of the 'Stop' pushbutton, how will the circuit respond when an operator presses and releases the 'Start' button, and then later presses the 'Stop' button?
- The motor will start and continue running, but pressing the Stop button will fail to stop it.Cevap
- BThe circuit's protective device will trip immediately when power is applied because of the short circuit.
- CThe motor will start when the Start button is pressed, but will immediately shut off when the Start button is released.
- DThe motor will fail to start entirely because the shorted Stop button creates an open circuit condition.
Cevap
The motor will start and continue running, but pressing the Stop button will fail to stop it.
The circuit described is a classic motor starter latching circuit. The parallel NO contact acts as a 'seal-in' contact, keeping the relay coil energized after the momentary Start button is released. The NC Stop button is designed to break this latched path. However, a short circuit directly across the Stop button's terminals provides a permanent alternate path for the current to flow, entirely bypassing the button's internal mechanical contacts. When the operator presses Stop, the internal contacts open, but current continues to flow freely through the short circuit. As a result, the relay coil remains energized and the motor cannot be turned off using the intended control.
Adım Adım Çözüm
Anahtar Kavram
Relay Latching Logic and Short Circuit Fault Analysis