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Zorluk: KolayBuoyancy and Archimedes' Principle

A small metal anchor weighs 120 N120 \text{ N} in the air. When the anchor is completely submerged in water, the tension on its lifting cable is measured to be 85 N85 \text{ N}. What is the magnitude of the buoyant force acting on the submerged anchor?

Cevap: 35 N

Cevap

35
According to Archimedes' principle, the upward buoyant force exerted on a submerged object reduces its apparent weight. The buoyant force is equal to the difference between its true weight in the air and its apparent weight in the fluid. Subtracting the apparent weight (85 N) from the true weight (120 N) gives a buoyant force of 35 N.

Adım Adım Çözüm

1
Identify the actual weight and the apparent weight.
Actual weight = 120 N, Apparent weight = 85 N
These values represent the downward force of gravity and the net downward force when submerged, respectively.
2
Calculate the buoyant force.
120 N - 85 N = 35 N
The buoyant force is the upward force that accounts for the reduction in weight. It is found by subtracting the apparent weight from the actual weight.

Anahtar Kavram

Apparent Weight and Buoyant Force
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Konular

Buoyancy and Archimedes' Principle

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