Algebra

282 soru

Soru 161Soru →

Consider the exponential expression (y7)3(y^7)^3. If this expression is rewritten in the equivalent form yny^n, what is the numerical value of nn?

Cevabı ve açıklamayı göster

Cevap: 21; twenty-one; n=21; n = 21

Cevap

The numerical value of the exponent is 21.
When raising a power to another power, the laws of exponents dictate that the two exponents must be multiplied. Multiplying the inside exponent 7 by the outside exponent 3 yields 21.

Adım Adım Çözüm

1
Identify the appropriate exponent rule to simplify the expression (y7)3(y^7)^3.
The expression requires the Power of a Power property.
An exponential term with a base and an exponent is being raised entirely to another power.
2
Apply the Power of a Power rule, which states that (xa)b=xa×b(x^a)^b = x^{a \times b}.
Multiply the inner exponent by the outer exponent: 7×37 \times 3.
To raise a power to another power, you must multiply the exponents together.
3
Calculate the final numerical value.
7×3=217 \times 3 = 21, meaning the expression simplifies to y21y^{21}.
By matching y21y^{21} to the given form yny^n, we determine that n=21n = 21.

Anahtar Kavram

Power of a Power Rule for Exponents
Tahmini Süre:30s
Soru 162Soru →

Evaluate the product of the monomial expressions 4z54z^5 and 2z32z^3. Which of the following represents the simplified result?

Cevabı ve açıklamayı göster

Cevap: 8z88z^8

Cevap

The expression simplifies to 8z88z^8.
When multiplying two monomial expressions, the numerical coefficients are multiplied together (4×2=84 \times 2 = 8), and the exponents of the common variable base are added together according to the product rule for exponents (5+3=85 + 3 = 8). This results in 8z88z^8.

Adım Adım Çözüm

1
Identify the operation to be performed between the two terms.
The terms 4z54z^5 and 2z32z^3 are being multiplied.
Understanding the operation is required to apply the correct mathematical rules for coefficients and exponents.
2
Multiply the numerical coefficients.
4×2=84 \times 2 = 8
Coefficients in a product of monomials are multiplied together normally.
3
Multiply the variable parts by applying the product rule for exponents.
z5×z3=z5+3=z8z^5 \times z^3 = z^{5+3} = z^8
When multiplying exponential expressions with the same base, their exponents must be added.
4
Combine the calculated coefficient and the variable part.
8z88z^8
This brings the simplified pieces together into the final term.

Anahtar Kavram

Operations with Variable Exponents
Soru 163Soru →

Consider the polynomial expression provided below:

(2x−3)(x+4)−2(x2−5x+1) (2x - 3)(x + 4) - 2(x^2 - 5x + 1)

Which of the following represents its fully simplified equivalent?

Cevabı ve açıklamayı göster

Cevap: 15x−1415x - 14

Cevap

The completely simplified equivalent expression is 15x−1415x - 14.
The expression correctly expands to 2x2+5x−122x^2 + 5x - 12 on the left and −2x2+10x−2-2x^2 + 10x - 2 on the right. When adding these together, the x2x^2 terms cancel out, the xx terms sum to 15x15x, and the constants sum to −14-14, leaving 15x−1415x - 14.

Adım Adım Çözüm

1
Expand (2x−3)(x+4)(2x - 3)(x + 4) using the distributive property.
2x2+8x−3x−122x^2 + 8x - 3x - 12, which simplifies to 2x2+5x−122x^2 + 5x - 12.
To eliminate the first set of parentheses by multiplying each term in the first binomial by each term in the second binomial.
2
Distribute −2-2 to each term inside the trinomial (x2−5x+1)(x^2 - 5x + 1).
−2x2+10x−2-2x^2 + 10x - 2.
To eliminate the second set of parentheses, carefully applying the negative sign to all inner terms.
3
Combine the expanded expressions.
(2x2+5x−12)+(−2x2+10x−2)(2x^2 + 5x - 12) + (-2x^2 + 10x - 2).
To prepare the entire expression for the collection of like terms.
4
Group and combine like terms (x2x^2 terms, xx terms, and constants).
(2x2−2x2)+(5x+10x)+(−12−2)=0x2+15x−14=15x−14(2x^2 - 2x^2) + (5x + 10x) + (-12 - 2) = 0x^2 + 15x - 14 = 15x - 14.
To achieve the final simplified standard form.

Anahtar Kavram

Expanding polynomials, distributing negative coefficients, and combining like terms.
Soru 164Soru →

Complete the algebraic equation that accurately translates the given statement.

Aşağıdaki boşlukları doldurun

Statement: 'Five subtracted from four times a number kk equals eleven.'

Equation:
- = 11
Cevabı ve açıklamayı göster

Cevap

The first blank is '4k' and the second blank is '5', forming the correct equation 4k - 5 = 11.
The phrase 'four times a number kk' becomes 4k4k. The phrase 'Five subtracted from' means 5 is taken away from 4k4k, so the 5 must be placed after the minus sign, forming 4k−54k - 5. Finally, 'equals eleven' sets the expression equal to 11. Therefore, to match the provided equation structure of '___ - ___ = 11', the first blank must be filled with '4k' and the second blank must be filled with '5'.

Adım Adım Çözüm

1
Translate the multiplication part of the statement.
'four times a number kk' translates to the algebraic expression 4k4k.
The word 'times' indicates multiplication between the coefficient 4 and the variable kk.
2
Apply the subtraction part of the statement.
'Five subtracted from' means 5 is taken away from the previous term, resulting in 4k−54k - 5.
The phrase 'subtracted from' is a turnaround phrase, which means the 5 must be placed after the minus sign, reversing the spoken order.
3
Complete the equation.
Setting the expression equal to 11 gives the full equation: 4k−5=114k - 5 = 11.
The word 'equals' indicates where the equal sign (=) should be placed in relation to the constant 11.

Anahtar Kavram

Translating turnaround words (like 'subtracted from' or 'less than') and basic multiplication phrases into an algebraic equation.
Tahmini Süre:30s
Soru 165Soru →

Which of the following describes all values of xx that satisfy the inequality below?

2(x−4)−5x<x+4 2(x - 4) - 5x < x + 4
Cevabı ve açıklamayı göster

Cevap: x>−3x > -3

Cevap

The correct solution is x>−3x > -3.
The correct answer accurately simplifies the equation down to −4x<12-4x < 12. Because isolating the variable in the final step requires dividing by −4-4, the less than symbol (<<) must be reversed to a greater than symbol (>>), resulting in x>−3x > -3.

Adım Adım Çözüm

1
Distribute the 2 into the parentheses on the left side.
2x−8−5x<x+42x - 8 - 5x < x + 4
To clear the parentheses and access the terms inside.
2
Combine the like terms (2x2x and −5x-5x) on the left side.
−3x−8<x+4-3x - 8 < x + 4
To simplify the left side of the inequality.
3
Subtract xx from both sides to group the variable terms.
−4x−8<4-4x - 8 < 4
To collect all terms containing xx on one side.
4
Add 8 to both sides of the inequality.
−4x<12-4x < 12
To isolate the term with the variable.
5
Divide both sides by -4 and reverse the inequality sign.
x>−3x > -3
When multiplying or dividing an inequality by a negative number, the inequality symbol must be flipped to maintain a mathematically true statement.

Anahtar Kavram

Solving linear inequalities with variables on both sides requires combining like terms and reversing the inequality symbol when dividing by a negative coefficient.
Soru 166Soru →

Match each unsimplified algebraic expression on the left with its completely simplified equivalent on the right.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

5x−3(2x−4)5x - 3(2x - 4)
3(2m−5n)−2(m−3n)3(2m - 5n) - 2(m - 3n)
4x(x−2)−x2+5x4x(x - 2) - x^2 + 5x
7y−3[y−2(y+1)]7y - 3[y - 2(y + 1)]

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

The correctly simplified expressions are: 5x−3(2x−4)5x - 3(2x - 4) matches with −x+12-x + 12; 3(2m−5n)−2(m−3n)3(2m - 5n) - 2(m - 3n) matches with 4m−9n4m - 9n; 4x(x−2)−x2+5x4x(x - 2) - x^2 + 5x matches with 3x2−3x3x^2 - 3x; and 7y−3[y−2(y+1)]7y - 3[y - 2(y + 1)] matches with 10y+610y + 6.
Each unsimplified expression must be correctly expanded using the distributive property, ensuring that negative multipliers are applied to every term inside the parentheses. After expanding, grouping and adding the coefficients of like terms produces the single correct simplified equivalent provided in the match list.

Adım Adım Çözüm

1
Distribute any coefficients or negative signs immediately outside of parentheses or brackets.
Terms are expanded (e.g., −3(2x−4)-3(2x - 4) becomes −6x+12-6x + 12).
Distribution removes grouping symbols, which is required before combining terms.
2
For expressions with nested grouping symbols, simplify from the innermost parentheses outward.
Complex expressions like 7y−3[y−2(y+1)]7y - 3[y - 2(y + 1)] simplify step-by-step to 7y+3y+67y + 3y + 6.
Following the order of operations ensures accurate distribution of multipliers.
3
Group and combine like terms (terms with the exact same variable and exponent).
The final canonical form is reached for each expression.
Combining like terms fully simplifies the polynomial into standard form.

Anahtar Kavram

Simplifying Algebraic Expressions
Tahmini Süre:1m 30s
Soru 167Soru →

A linear equation is structured as follows:

12(4y−6)−23(9−6y)=2y+15 \frac{1}{2}(4y - 6) - \frac{2}{3}(9 - 6y) = 2y + 15

Based on this relationship, what is the correct value of yy?

Cevabı ve açıklamayı göster

Cevap: 6

Cevap

6
The correct value is found by properly distributing the fractional coefficients, carefully tracking negative signs, and preserving equality to isolate the variable. The operations simplify the initial equation to 6y - 9 = 2y + 15, which reduces to 4y = 24, resulting in 6.

Adım Adım Çözüm

1
Distribute 12 \frac{1}{2} into the first set of parentheses.
2y−3 2y - 3
Applying the distributive property eliminates the first group.
2
Distribute −23 -\frac{2}{3} into the second set of parentheses.
−6+4y -6 + 4y
Multiplying the negative fraction across the terms. Notice that multiplying two negative values (−2/3-2/3 and −6y-6y) yields a positive result (+4y+4y).
3
Combine the distributed terms on the left side of the equation.
(2y+4y)+(−3−6)=6y−9 (2y + 4y) + (-3 - 6) = 6y - 9
Combining like terms simplifies the left side of the equation before attempting to isolate the variable.
4
Set the simplified left side equal to the right side and solve for y.
6y−9=2y+15⇒4y−9=15⇒4y=24⇒y=6 6y - 9 = 2y + 15 \Rightarrow 4y - 9 = 15 \Rightarrow 4y = 24 \Rightarrow y = 6
Using inverse operations groups the variable terms on one side and constant terms on the other to reveal the final value.

Anahtar Kavram

Solving complex linear equations involving fractional distribution and sign management.
Soru 168Soru →

What is the completely simplified form of the algebraic expression 7x−4(2x−3y)+5y7x - 4(2x - 3y) + 5y?

Cevabı ve açıklamayı göster

Cevap: −x+17y-x + 17y

Cevap

−x+17y-x + 17y
To completely simplify the expression, you must first distribute the −4-4 across the terms in the parentheses. Multiplying −4-4 by 2x2x gives −8x-8x, and multiplying −4-4 by −3y-3y gives +12y+12y (since a negative times a negative is a positive). Substituting this back gives 7x−8x+12y+5y7x - 8x + 12y + 5y. Finally, group the like variables: 7x−8x=−x7x - 8x = -x, and 12y+5y=17y12y + 5y = 17y. Combining these gives −x+17y-x + 17y.

Adım Adım Çözüm

1
Distribute the −4-4 to both terms inside the parentheses (2x−3y)(2x - 3y).
−8x+12y-8x + 12y
The distributive property must be applied first to eliminate the parentheses, paying careful attention to the multiplication of two negative numbers (−4-4 and −3y-3y).
2
Rewrite the full expression incorporating the expanded terms.
7x−8x+12y+5y7x - 8x + 12y + 5y
This sets up the expression so that all individual terms are clearly visible for grouping.
3
Combine the like terms for both xx and yy.
−x+17y-x + 17y
Adding the coefficients of identical variables (7x−8x=−x7x - 8x = -x and 12y+5y=17y12y + 5y = 17y) provides the expression in its final standard form.

Anahtar Kavram

Simplifying Algebraic Expressions via Distributive Property and Like Terms
Soru 169Soru →

Pair each basic algebraic expression with its correctly simplified result by applying the fundamental laws of exponents.

Soldaki öğeye tıklayın, sonra eşleşen sağdaki öğeye tıklayın

Öğeler

m6⋅m2m^6 \cdot m^2
n8n5\frac{n^8}{n^5}
(p4)3(p^4)^3
q−5q^{-5}

Eşleşmeler

Cevabı ve açıklamayı göster

Cevap

The correct pairings are: m6⋅m2m^6 \cdot m^2 with m8m^8; n8n5\frac{n^8}{n^5} with n3n^3; (p4)3(p^4)^3 with p12p^{12}; and q−5q^{-5} with 1q5\frac{1}{q^5}.
Each expression can be simplified by directly applying one specific fundamental property of exponents. m6⋅m2m^6 \cdot m^2 uses the product rule. n8n5\frac{n^8}{n^5} uses the quotient rule. (p4)3(p^4)^3 uses the power rule. q−5q^{-5} uses the negative exponent definition.

Adım Adım Çözüm

1
Simplify the product expression m6⋅m2m^6 \cdot m^2.
m8m^8
When bases are identical and multiplied, their exponents are added together.
2
Simplify the quotient expression n8n5\frac{n^8}{n^5}.
n3n^3
When dividing identical bases, the exponent of the denominator is subtracted from the exponent of the numerator.
3
Simplify the nested power expression (p4)3(p^4)^3.
p12p^{12}
When raising an exponent to another power, the two exponents are multiplied.
4
Rewrite the negative exponent expression q−5q^{-5}.
1q5\frac{1}{q^5}
A negative exponent indicates taking the reciprocal of the base raised to the positive exponent.

Anahtar Kavram

Applying fundamental exponent rules (product, quotient, power, and negative exponents) to simplify single-variable expressions.
Soru 170Soru →

Which value of mm is the solution to the equation below?

6m−12=2m+166m - 12 = 2m + 16
Cevabı ve açıklamayı göster

Cevap: 77

Cevap

The correct solution is 77.
By subtracting 2m2m from both sides and then adding 12 to both sides, the equation simplifies to 4m=284m = 28. Dividing by 4 gives the correct result of 77.

Adım Adım Çözüm

1
Subtract 2m2m from both sides of the equation to group the variable terms on the left side.
4m−12=164m - 12 = 16
This keeps all instances of the unknown variable mm on one side.
2
Add 12 to both sides of the equation to isolate the variable term.
4m=284m = 28
This cancels out the constant on the left side, leaving only the term with mm.
3
Divide both sides by 4 to solve for mm.
m=7m = 7
This removes the coefficient, revealing the final value of the variable.

Anahtar Kavram

Solving One-Variable Linear Equations
Tahmini Süre:45s
Soru 171Soru →

Calculate the value of the unknown variable.

Aşağıdaki boşlukları doldurun

Calculate the value of kk that makes the following equation true:

34(8k−12)−25(15−5k)=3(k+2)+4 \frac{3}{4}(8k - 12) - \frac{2}{5}(15 - 5k) = 3(k + 2) + 4

k=k =
Cevabı ve açıklamayı göster

Cevap

5
The correct value is 5. By distributing the fractions on the left, the expression becomes 6k−9−6+2k6k - 9 - 6 + 2k. Combining like terms simplifies this to 8k−158k - 15. On the right side, distributing the 3 results in 3k+6+43k + 6 + 4, which simplifies to 3k+103k + 10. Equating both simplified sides gives 8k−15=3k+108k - 15 = 3k + 10. Subtracting 3k3k from both sides leaves 5k−15=105k - 15 = 10, and adding 1515 to both sides yields 5k=255k = 25. Dividing by 5 results in k=5k = 5.

Adım Adım Çözüm

1
Distribute the fractional terms on the left side of the equation.
6k−9−6+2k6k - 9 - 6 + 2k
Multiplying 34\frac{3}{4} by (8k−12)(8k - 12) yields 6k−96k - 9. Multiplying −25-\frac{2}{5} by (15−5k)(15 - 5k) yields −6+2k-6 + 2k. Paying close attention to the negative sign during distribution is critical.
2
Distribute the terms on the right side of the equation.
3k+6+43k + 6 + 4
Multiplying 33 by (k+2)(k + 2) expands the expression, setting up the right side for simplification.
3
Combine like terms on both sides of the equal sign.
8k−15=3k+108k - 15 = 3k + 10
On the left side, combine the variable terms (6k+2k=8k6k + 2k = 8k) and constant terms (−9−6=−15-9 - 6 = -15). On the right side, combine the constant terms (6+4=106 + 4 = 10).
4
Isolate the variable kk to find its value.
5k=255k = 25, which simplifies to k=5k = 5.
Subtract 3k3k from both sides to group the variables on the left (5k−15=105k - 15 = 10). Then, add 1515 to both sides to group the constants on the right (5k=255k = 25). Dividing both sides by 55 yields the final solution.

Anahtar Kavram

Solving One-Variable Linear Equations
Soru 172Soru →

Determine the numerical value of the variable that satisfies the given linear equation.

Aşağıdaki boşlukları doldurun

For the equation 7k−5=3k+197k - 5 = 3k + 19, the value of kk is .
Cevabı ve açıklamayı göster

Cevap

The correct value for k is 6.
To find the value of kk, we must isolate the variable on one side of the equation. By subtracting 3k3k from both sides, we get 4k−5=194k - 5 = 19. Next, adding 55 to both sides gives 4k=244k = 24. Finally, dividing both sides by 44 results in k=6k = 6.

Adım Adım Çözüm

1
Subtract 3k3k from both sides of the equation.
4k−5=194k - 5 = 19
This groups all variable terms on the left side of the equation.
2
Add 55 to both sides of the equation.
4k=244k = 24
This isolates the variable term by moving the constant to the right side.
3
Divide both sides by 44.
k=6k = 6
This cancels the coefficient on the variable, yielding the final solution.

Anahtar Kavram

Solving linear equations with variables on both sides by using inverse operations to isolate the unknown.
Soru 173Soru →

Which of the following is equivalent to the algebraic expression below after it has been fully simplified?

4k(k−3m)−(2k2−5km+m2)4k(k - 3m) - (2k^2 - 5km + m^2)
Cevabı ve açıklamayı göster

Cevap: 2k2−7km−m22k^2 - 7km - m^2

Cevap

The fully simplified expression is 2k2−7km−m22k^2 - 7km - m^2.
The correct expression is derived by first multiplying 4k4k by both terms in (k−3m)(k - 3m) to get 4k2−12km4k^2 - 12km. Next, distributing the negative sign through the trinomial changes the signs to yield −2k2+5km−m2-2k^2 + 5km - m^2. Finally, grouping and combining like terms yields 4k2−2k2=2k24k^2 - 2k^2 = 2k^2 and −12km+5km=−7km-12km + 5km = -7km. The −m2-m^2 term has no like terms to combine with, leaving it unchanged. The final simplified form is 2k2−7km−m22k^2 - 7km - m^2.

Adım Adım Çözüm

1
Distribute 4k4k into the binomial (k−3m)(k - 3m).
4k2−12km4k^2 - 12km
Expanding the first part of the expression removes the first set of parentheses.
2
Distribute the negative sign across the trinomial (2k2−5km+m2)(2k^2 - 5km + m^2).
−2k2+5km−m2-2k^2 + 5km - m^2
Subtracting a polynomial requires reversing the sign of every term inside the parentheses.
3
Group and combine all like terms.
(4k2−2k2)+(−12km+5km)−m2=2k2−7km−m2(4k^2 - 2k^2) + (-12km + 5km) - m^2 = 2k^2 - 7km - m^2
Expressions are fully simplified when all terms with identical variable combinations are merged.

Anahtar Kavram

Distributing variables and negative signs followed by combining like terms.
Soru 174Soru →

If the equation y8⋅yk=y15y^8 \cdot y^k = y^{15} is true for all non-zero values of yy, what is the value of kk?

Cevabı ve açıklamayı göster

Cevap: 7; seven

Cevap

7
The correct value of kk is 77 because applying the product rule of exponents gives y8⋅y7=y8+7=y15y^8 \cdot y^7 = y^{8+7} = y^{15}.

Adım Adım Çözüm

1
Apply the product rule for exponents to the left side of the equation.
y8⋅yk=y8+ky^8 \cdot y^k = y^{8+k}
When multiplying exponential expressions with the same base, the exponents are added.
2
Set the exponent of the simplified left side equal to the exponent of the right side.
8+k=158 + k = 15
Since the bases are equal and non-zero, their exponents must be equal.
3
Solve the linear equation for kk.
k=7k = 7
Subtracting 8 from both sides of the equation isolates the variable kk.

Anahtar Kavram

Product Rule for Exponents
Soru 175Soru →

Simplify the following algebraic expression completely:

(3a5)2(3a^5)^2

What is the simplified form of this expression?

Cevabı ve açıklamayı göster

Cevap: 9a109a^{10}

Cevap

The simplified expression is 9a109a^{10}.
The correct result is found by distributing the exponent of 2 to both factors inside the parentheses. The coefficient 3 is squared to become 9, and the exponent 5 is multiplied by 2 to become 10, resulting in 9a109a^{10}.

Adım Adım Çözüm

1
Apply the power of a product rule by distributing the outer exponent to both the numerical coefficient and the variable inside the parentheses.
32⋅(a5)23^2 \cdot (a^5)^2
When a product is raised to a power, each independent factor inside the parentheses must be raised to that power.
2
Simplify the numerical coefficient by calculating its square.
9⋅(a5)29 \cdot (a^5)^2
The exponent 2 indicates multiplying the base by itself: 3×3=93 \times 3 = 9.
3
Apply the power of a power rule to the variable by multiplying the inner exponent by the outer exponent.
9a109a^{10}
According to exponent laws, (xm)n=xm⋅n(x^m)^n = x^{m \cdot n}, so the new exponent is 5×2=105 \times 2 = 10.

Anahtar Kavram

Power of a Product and Power of a Power Rules
Soru 176Soru →

An inventory manager calculates the total number of pallets, hh, that can be stored in a warehouse section using the following linear equation:

3h+6=453h + 6 = 45

What is the value of hh?

Cevabı ve açıklamayı göster

Cevap: 13

Cevap

The correct value for the variable is 13.
The correct value is found by performing the inverse operations in the correct order. First, subtract 6 from both sides to get 3h = 39. Then, divide both sides by 3 to find that h = 13.

Adım Adım Çözüm

1
Isolate the term with the variable by subtracting 6 from both sides of the equation.
3h=45−63h = 45 - 6
3h=393h = 39
This removes the constant term from the left side, keeping the equation balanced.
2
Solve for hh by dividing both sides of the equation by 3.
h=393h = \frac{39}{3}
h=13h = 13
Dividing by the coefficient of the variable isolates hh completely.

Anahtar Kavram

Solving basic two-step linear equations by using inverse operations to isolate the variable.
Soru 177Soru →

Solve the following equation for pp:

23(6p−15)+3p=−3(p−8)+2p−10 \frac{2}{3}(6p - 15) + 3p = -3(p - 8) + 2p - 10

What is the final value of pp?

Cevabı ve açıklamayı göster

Cevap: 3

Cevap

The correct value for the variable is 3.
The correct answer is 3. Distributing the terms on both sides yields 4p−10+3p=−3p+24+2p−104p - 10 + 3p = -3p + 24 + 2p - 10. Combining like terms results in 7p−10=−p+147p - 10 = -p + 14. Adding pp to both sides and adding 10 to both sides gives 8p=248p = 24. Dividing by 8 isolates the variable, resulting in p=3p = 3.

Adım Adım Çözüm

1
Distribute the coefficients to remove parentheses on both sides of the equation.
4p−10+3p=−3p+24+2p−104p - 10 + 3p = -3p + 24 + 2p - 10
To simplify the equation, all terms inside parentheses must be multiplied by their outer coefficients. Note that 23×6p=4p\frac{2}{3} \times 6p = 4p and 23×−15=−10\frac{2}{3} \times -15 = -10.
2
Combine like terms on each side of the equation independently.
7p−10=−p+147p - 10 = -p + 14
Combining variable terms and constant terms on the same side simplifies the equation structure before isolating the variable.
3
Move all variable terms to one side of the equation.
8p−10=148p - 10 = 14
Adding pp to both sides cancels the −p-p on the right side, grouping all unknowns on the left.
4
Isolate the variable by moving constants to the other side and dividing.
8p=24⇒p=38p = 24 \Rightarrow p = 3
Adding 10 to both sides moves the constant, and dividing both sides by the coefficient 8 solves for pp.

Anahtar Kavram

Solving complex one-variable linear equations requiring distribution and combining like terms.
Soru 178Soru →

Consider the following algebraic equation, where x≠0x \neq 0:

(3x4)29xk=x5 \frac{(3x^4)^2}{9x^k} = x^5

What is the value of the exponent kk?

Cevabı ve açıklamayı göster

Cevap: 3; k=3; k = 3; three

Cevap

3
First, the numerator (3x4)2(3x^4)^2 simplifies to 9x89x^8. Substituting this back yields 9x89xk=x5\frac{9x^8}{9x^k} = x^5. The coefficients cancel out, and applying the quotient rule to the variables gives x8−k=x5x^{8-k} = x^5. By equating the exponents, we get 8−k=58 - k = 5, which means k=3k = 3.

Adım Adım Çözüm

1
Apply the power of a product rule to the numerator.
(3x4)2=32⋅(x4)2=9x8(3x^4)^2 = 3^2 \cdot (x^4)^2 = 9x^8
When raising a product to a power, you must raise every factor inside the parentheses to that power.
2
Substitute the simplified numerator back into the equation and simplify the numerical coefficients.
9x89xk=x8xk\frac{9x^8}{9x^k} = \frac{x^8}{x^k}
The coefficients 99\frac{9}{9} cancel out to 1, making it easier to isolate the variable base.
3
Apply the quotient rule for exponents on the left side of the equation.
x8xk=x8−k\frac{x^8}{x^k} = x^{8-k}
When dividing exponential expressions with the same base, you subtract the exponent in the denominator from the exponent in the numerator.
4
Set the resulting exponent equal to the exponent on the right side of the original equation and solve for kk.
8−k=5⇒k=38 - k = 5 \Rightarrow k = 3
Since the bases on both sides of the equation are the same (xx), their exponents must be equal.

Anahtar Kavram

Operations with Variable Exponents
Soru 179Soru →

If x=−2x = -2 and y=−3y = -3, what is the value of the expression 2x2−5y2x^2 - 5y?

Cevabı ve açıklamayı göster

Cevap: 23

Cevap

23
The expression is evaluated by first substituting the values and applying the exponent to the base, giving (−2)2=4(-2)^2 = 4. Then, perform the multiplication to get 2(4)=82(4) = 8 and 5(−3)=−155(-3) = -15. Finally, subtracting negative 15 from 8 is the same as adding 15, resulting in 8+15=238 + 15 = 23.

Adım Adım Çözüm

1
Substitute the given values for xx and yy into the expression.
2(−2)2−5(−3)2(-2)^2 - 5(-3)
To evaluate the expression, each variable must be replaced with its corresponding numerical value.
2
Evaluate the exponent.
2(4)−5(−3)2(4) - 5(-3)
According to the order of operations (PEMDAS), exponents must be resolved before multiplication. The square of any non-zero real number is positive, so (−2)2=4(-2)^2 = 4.
3
Perform the multiplication operations.
8−(−15)8 - (-15)
Multiply 22 by 44 to get 88, and 55 by −3-3 to get −15-15.
4
Perform the subtraction.
8+15=238 + 15 = 23
Subtracting a negative number is mathematically identical to adding its positive counterpart.

Anahtar Kavram

Evaluating expressions using substitution and the order of operations.
Soru 180Soru →

A student is asked to simplify the rational algebraic expression shown below.

(3a2b−3)23a−1b−4 \frac{(3a^2b^{-3})^2}{3a^{-1}b^{-4}}

What is the fully simplified form of this expression with positive exponents?

Cevabı ve açıklamayı göster

Cevap: 3a5b2\frac{3a^5}{b^2}

Cevap

3a5b2\frac{3a^5}{b^2}
To simplify the expression, first simplify the numerator by squaring every factor inside the parentheses: (3)2⋅(a2)2⋅(b−3)2(3)^2 \cdot (a^2)^2 \cdot (b^{-3})^2, which yields 9a4b−69a^4b^{-6}. Next, divide this result by the denominator 3a−1b−43a^{-1}b^{-4}. Divide the coefficients: 9÷3=39 \div 3 = 3. Then, apply the quotient rule by subtracting the exponents of like bases: for aa, 4−(−1)=54 - (-1) = 5; for bb, −6−(−4)=−2-6 - (-4) = -2. This gives 3a5b−23a^5b^{-2}. Finally, rewrite the expression with positive exponents by moving b−2b^{-2} to the denominator, resulting in 3a5b2\frac{3a^5}{b^2}.

Adım Adım Çözüm

1
Apply the power of a product and power of a power rules to the numerator: (3a2b−3)2(3a^2b^{-3})^2.
9a4b−69a^4b^{-6}
The exponent outside the parentheses applies to the coefficient and is multiplied by each variable's exponent.
2
Substitute the expanded numerator back into the fraction.
9a4b−63a−1b−4\frac{9a^4b^{-6}}{3a^{-1}b^{-4}}
This sets up the expression for the quotient rule.
3
Divide the numerical coefficients.
9÷3=39 \div 3 = 3
Coefficients are divided normally.
4
Apply the quotient rule by subtracting the denominator's exponents from the numerator's exponents for bases aa and bb.
a4−(−1)=a5a^{4 - (-1)} = a^5 and b−6−(−4)=b−2b^{-6 - (-4)} = b^{-2}
When dividing like bases, exponents are subtracted. Care must be taken with double negative signs.
5
Combine the results and convert any negative exponents to positive exponents by moving them to the denominator.
3a5b−2=3a5b23a^5b^{-2} = \frac{3a^5}{b^2}
Standard mathematical notation requires final answers to be expressed using positive exponents.

Anahtar Kavram

Applying exponent rules (power, product, and quotient) with numerical coefficients and negative integers.
ÖncekiSayfa 9 / 15Sonraki
Algebra Alıştırma Soruları — Armed Services Vocational Aptitude Battery (ASVAB) — Sayfa 9 | Examkin